This college has one of the highest median graduation rates and the best consistency in graduation rates over time.

Answer:

$889.94 after six years

Step-by-step explanation:

The equation is I=P(1-r)^t so after six years it would be worth $889.94. Every year the value depreciates by $4,130.

Answer:

The speed is 60 mph.

Step-by-step explanation:

distance = 42 miles

Let he drove with speed v and time is t.

distance = speed x time

42 = v t ..... (1)

42 = (v + 10)(t - 1/10) ..... (2)

[tex]42 = 42 -\frac{v}{10}+ 10 t - 1\\\\t =\frac{10+v}{100}\\\\Put in (1)\\\\42 = \frac{v(10+v)}{100}\\\\v^2 + 10 v - 4200 = 0 \\\\v = \frac{-10\pm \sqrt{100+4\times 4200}}{2}\\\\v =\frac{- 10 \pm 130}{2}\\\\v =- 70 mph, 60mph[/tex]

So, the speed cannot be negative so the speed is 60 mph.

Answer:

5940

Step-by-step explanation:

The first '6' represents '6000' and the second represents '60.'

Thus the difference of the values of the two '6s' is 6000 - 60 = 5940.

Answer:

"Clustering sampling" is the correct answer.

Step-by-step explanation:

9514 1404 393

Answer:

 $27,026.90

Step-by-step explanation:

The future value formula can be solved to find the present value required.

  FV = P(1 +r)^t . . . future value of P compounded at annual rate r for t years

  $100,000 = P(1 +0.08)^17

  P = $100,000/3.70002 . . . . divide by the coefficient of P

  P = $27,026.90

You would need to deposit #27,026.90 now to reach this goal.

Answer:

A) 1

Step-by-step explanation:

A) 27 ÷ 13 = 1

B) if you take away 2 from "27", "13" times you will get 1 as the final answer.

I hope this helps, if I'm wrong please do correct me.

9514 1404 393

Answer:

  (b)  27.8

Step-by-step explanation:

The relevant trig relation is ...

  Cos = Adjacent/Hypotenuse

  cos(22°) = a/30

  a = 30×cos(22°) ≈ 27.8

Answer and explanation:

Question isn't complete but explanation is given below based on what you may be asking.

Answer and Explanation:

First, An object is a data type but is quite different from the usual or primitive data types such as string or integers. An object is based on object oriented programming(OOP) and is a sort of abstract data type which is usually defined by the programmer(some are inbuilt in the language). Objects are usually defined using classes and then become instances of those classes. Objects have identities(e.g- a dog has a name Zeus) and be compared to other objects of same class(other instances) while data types are not as well equipped to have identities, properties or methods that are user defined in order to make comparisons.

Answer:

1.5

Step-by-step explanation:

Let's begin by dividing each side by 4.

You get 18/4 or 4.5.

m+3=4.5

Now subtract 3 to each side.

m=1.5

Answer:

[tex]4(m + 3) = 18 \\ 2(m + 3) = 9 \\ 2m + 6 = 9 \\ 2m = 3 \\ m = \frac{3}{2} \\ m = 1.5[/tex]

Answer:

idfk lol hehe hope this helps

Step-by-step explanation:

Answer:

61 , 63 , 65 , 67

Step-by-step explanation:

Let the least even number be denoted by x. The sum of the four consecutive even numbers would be:

(x) + (x + 2) + (x + 4) (x + 6) = 256

First, simplify. Combine all like terms:

x + x + x + x + 2 + 4 + 6 = 256

4x + 12 = 256

Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.

First, subtract 12 from both sides of the equation:

4x + 12 (-12) = 256 (-12)

4x = 256 - 12

4x = 144

Next, divide 4 from both sides of the equation:

(4x)/4 = (144)/4

x = 144/4

x = 61

61 is your first number. Find the next 3 consecutive numbers:

x = 61

x + 2 = 63

x + 4 = 65

x + 6 = 67

Check:

61 + 63 + 65 + 67 = 256

256 = 256

~

Answer:

the equation is sin−1 (8/11)

Answer:

60 different permutations of these letters can be made.

Step-by-step explanation:

Permutations formula:

The number of possible permutations of x elements from a set of n elements is given by the following formula:

[tex]P_{(n,x)} = \frac{n!}{(n-x)!}[/tex]

How many different permutations of these letters can be made if no letter is used more than once?

3 letters from a set of 5. So

[tex]P_{(5,3)} = \frac{5!}{(5-3)!} = \frac{5!}{2!} = 5*4*3 = 60[/tex]

60 different permutations of these letters can be made.

Work Shown:

c(x) = (x+6)^2+14

c(x) = (x+6)(x+6)+14

c(x) = x(x+6)+6(x+6)+14

c(x) = x^2+6x+6x+36+14

c(x) = x^2+12x+50

Answer:

jk

Step-by-step explanation:

Answer:

30

Step-by-step explanation:

Have a nice day ;]

Answer:

The number is obviously 30 as the prime factors of 30 are 5 and 6 again 5 and 6 can also be factors of any multiples of 30 such as 60 180 900

Hope it helps

Step-by-step explanation:

A. 2(x+4)=2x+8

=G

B. 3(2x-1)=6x-3

=I

C. 4(x+2)=4x+8

=J

D. 2(x+3)=2x+6

=K

E. 3(4x+1)=12x+3

=H

A - G

B - I

C - J

D - K

E - H

HOPE IT HELP

Answer:

X=4

Step-by-step explanation:

(5+4+3+2x)/4=5

(12+2x)/4=5

12+2x=20

2x=8

X=4

Answer:

13

Step-by-step explanation:

3y+2x=13

2y+3x=0

∴3y+2x+2y+3x=13+0

∴3y+2y+2x+3x=13

∴5y+5x=13

Hope this helps you mate!

Pls mark as Brainliest

Answer:

the above ans is true

Step-by-step explanation:

uu can do it

Answer:

6

Step-by-step explanation:

In a circle equation, the radius can be found by taking the square root of the r² value.

In this equation, the r² value is 36.

Take the square root:

√36

= 6

So, the radius is 6.

The answer of s is 79'

Good luck :)))

Answer:

[tex]Area = 138in^2[/tex]

Step-by-step explanation:

Given

[tex]L = 9; W =3; H =3\frac{1}{2}[/tex]

Required

The surface area

This is calculated as:

[tex]Area = 2(LW + LH + WH)[/tex]

So:

[tex]Area = 2(9*3 + 9*3\frac{1}{2} + 3*3\frac{1}{2})[/tex]

[tex]Area = 2(27 + 31\frac{1}{2} + 10\frac{1}{2})[/tex]

[tex]Area = 2*69[/tex]

[tex]Area = 138in^2[/tex]

Answer:

253.90

Step-by-step explanation:

The temperature rose so you add the amount it rose to the starting temperature

68.7 + 9 = 77.7 degrees

It then dropped so mow you subtract t the amount it dropped:

77.7 - 12.3 = 65.4 degrees

The answer is 65.4 degrees

Answer:

Kindly check explanation

Step-by-step explanation:

Ordered data:

54, 55, 56, 57, 58, 58, 58, 59, 61, 63, 63, 63, 64, 65, 75

Sample size, n = 15

Q1 = 1/4(n+1)th term

Q1 = 16/4 = 4th term = 57

Q2 = 1/2(n+1) th term

Q2 = 16/2 = 8th term = 59

Q3 = 3/4(n+1)th term

Q3 = 3/4(16) = 12 th term = 63

Interquartile range = Q3 - Q1 = 63 - 57 = 6

Outlier :

LOWER = Q1 - (1.5 * IQR) = 57 - (1.5*6) = 48 ; values below 48

UPPER = Q3 + (1.5 * IQR) = 63 + (1.5*6) = 72 ;

Values above 72

Outlier = 75

Answer:

The 95% confidence the proportion of the population that does have at least one bilingual operator is (0.2359, 0.4307).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].

90 companies. 30 have at least one billingual operator.

This means that [tex]n = 90, \pi = \frac{30}{90} = 0.3333[/tex]

95% confidence level

So [tex]\alpha = 0.05[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.05}{2} = 0.975[/tex], so [tex]Z = 1.96[/tex].

The lower limit of this interval is:

[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.3333 - 1.96\sqrt{\frac{0.3333*0.6667}{90}} = 0.2359[/tex]

The upper limit of this interval is:

[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.3333 + 1.96\sqrt{\frac{0.3333*0.6667}{90}} = 0.4307[/tex]

The 95% confidence the proportion of the population that does have at least one bilingual operator is (0.2359, 0.4307).