Answer:
Approximately [tex]106\; \rm m[/tex], [tex](1/16)[/tex] of the original distance, assuming that the acceleration is constant.
Explanation:
Let [tex]v[/tex] and [tex]u[/tex] denote the final and initial velocity of the vehicle ([tex]v = 0\; \rm m \cdot s^{-1}[/tex] since this vehicle has come to a stop.)Let [tex]a[/tex] denote the acceleration of the vehicle (a constant under the assumption.) Let [tex]x[/tex] denote the displacement of the vehicle.If the acceleration on this vehicle is constant, the SUVAT equations would apply:
[tex]\displaystyle v^{2} - u^{2} = 2\, a\, x[/tex].
Rearrange this equation to find an expression for [tex]x[/tex], the displacement required for the vehicle to come to a stop:
[tex]\begin{aligned} x &= \frac{v^{2} - u^{2}}{2\, a} \\ &= \frac{-u^{2}}{2\, a} && (\text{$v = 0\; \rm m \cdot s^{-1}$})\end{aligned}[/tex].
Thus, under these assumptions, [tex]x[/tex] would be proportional to [tex]u^{2}[/tex]. In other words, the distance required for this vehicle to come to a stop would be proportional to the square of the initial velocity of this vehicle.
If the initial velocity [tex]u[/tex] is reduced to [tex](1/4)[/tex] (a quarter) of the initial value, the distance required for stopping this vehicle would be [tex](1/4)^{2} = (1/16)[/tex] of the initial value:
[tex]\begin{aligned}1,\!697\; {\rm m} \times \frac{1}{16} \approx 106\; \rm m\end{aligned}[/tex].
A block of mass =4.20 kg slides along a horizontal table with velocity 0=3.50 m/s . At =0 , it hits a spring with spring constant =26.00 N/m and it also begins to experience a friction force. The coefficient of friction is given by =0.250 . How far has the spring compressed by the time the block first momentarily comes to rest? Assume the positive direction is to the right.
The distance in which the spring is compressed is 1.065 m.
The given parameters;
mass of the block, m = 4.2 kgvelocity of the block, v = 3.5 m/sspring constant, k = 26 N/mcoefficient of friction, μ = 0.25Apply the principle of conservation of energy to determine the distance in which the spring is compressed.
[tex]K.E = W + U\\\\\frac{1}{2} mv^2 = \mu Fx \ + \ \frac{1}{2} kx^2\\\\\frac{1}{2}(4.2)(3.5)^2 = 0.25(4.2 \times 9.8)(x) \ + \frac{1}{2} (26)(x^2)\\\\25.725 = 10.29x \ + \ 13x^2\\\\13x^2 + 10.29x - 25.725 = 0\\\\[/tex]
solve the quadratic equation using formula method;
a = 13, b = 10.29, c = -25.725
[tex]x = \frac{-b \ \ +/- \ \sqrt{b^2 - 4ac} }{2a} \\\\x = \frac{-(10.29) \ \ +/- \ \sqrt{(10.29)^2 \ - \ 4(13\times 25.725)} }{2(13)} \\\\x = 1.065 \ m, \ \ or \ -1.86 \ m[/tex]
choose positive distance, x = 1.065 m.
Thus, the distance in which the spring is compressed is 1.065 m.
Learn more here:https://brainly.com/question/18722006
describe an experiment that can be used to determine the resistance of a metallic conductor
Answer:
resistance of the metal conductor at different temperature
Explanation:
An experiment used to determine the resistance of a metallic conductor is the resistance of a metallic conductor at different temperatures.
What is Resistance?Resistance is the property of a conductor to oppose the flow of charges through it which is numerically given as the ratio of the potential difference across its length to the current flowing through it.
Resistance of a metallic conductor is the measure of its opposition to the flow of electric current. Resistance is known to be directly proportional to the temperature which means as the temperature is increased, its resistance increases too and vice versa.
Resistance has an inverse relationship with the cross sectional area of a metallic conductor, so if the resistance increases the cross sectional area decreases and vice versa.
Thus, an experiment used to determine the resistance of a metallic conductor is the resistance of a metallic conductor at different temperatures.
Learn more about Resistance, here:
https://brainly.com/question/15742150
#SPJ2
Evidence of liquid water in mars' distant past suggests that it had a substantial atmosphere compared to what it has presently. What happened to its water vapor?.
Answer:
The atmosphere has frozen out into the polar ice caps and permafrost as Mars has cooled.
Explanation: Good luck box BrokenTag27
What is Kepler’s first law?
Answer:
Kepler's First Law: each planet's orbit about the Sun is an ellipse. The Sun's center is always located at one focus of the orbital ellipse. The Sun is at one focus. The planet follows the ellipse in its orbit, meaning that the planet to Sun distance is constantly changing as the planet goes around its orbit.
Answer:
Explanation:
Kepler 's first law - sometimes referred to as the law of ellipses - explains that planets are orbiting the sun in a path described as an ellipse. An ellipse can easily be constructed using a pencil, two tacks, a string, a sheet of paper and a piece of cardboard. Tack the sheet of paper to the cardboard using the two tacks.
Which type of forces creates contact between surfaces?
Answer:
Frictional Force: Frictional force is the force caused by the relative motion of two surfaces that come into contact with each other.
A particular roller coaster has a mass of 3500 kg, a height of 4.0, and a velocity of 12m/s. What is the potential energy? If needed, use g=10.m/s^2
[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]
Gravitational Potential Energy of an object is calculated by formula ~
[tex] \large\boxed{\sf P = mgh}[/tex]
where,
m = mass of the object = 3500 kgg = Acceleration due to gravity = 12 m/s²h = height attained by the object = 4 mNow, let's calculate its potential energy ~
[tex]3500 \times 10 \times 4[/tex][tex]140000 \: \: joules[/tex][tex]140 \: \: kj[/tex]Answer:
Potential Energy of an object is calculated by formula:
Potential Energy (P.E)=m×g×hWhere,
m=mass of bodyg=acceleration due to gravityh=height from the earth surfaceNow, let's solve the question.
Given,
mass(m)=3500 kgheight (h)=4mvelocity (v)=10m/s²Now,
We know that,
Potential Energy (P.E)=mgh
[tex] = 3500 \times 10 \times 4[/tex]
[tex] = 3500 0\times 4[/tex]
[tex] =140000 joules [/tex]
[tex]\mathfrak{\blue{DisneyPrincess29}}[/tex]
. Quỹ đạo chuyển động của một vật là
Answer:
you are very kind Po lang
Help me out with this physics please!!!
Answer: It was on between 7 and 7.30 and also between 8 and 8.30 (when the line on the graph goes up only). So it was on for an hour or 60 minutes
what is the mass of an object if it’s weight on earth is 1150N
Answer:
calculate it by using formula w=m×g
The mass of an object if its weight on earth is 1150N is 117.347 kg.
What is Weight?The weight of an object is defined as the force that acts on the object due to gravity. Sometimes weight is defined as a vector quantity, the force of gravity acting on an object. Others define weight as a scalar quantity, the magnitude of the force of gravity.
It is gravitational force of attraction on an object which is caused by the presence of a massive second object like Earth or Moon. Weight is expressed by multiplying the mass times the acceleration due to gravity.
W=mg
Where, W= weight of the object
m= Mass of the object
g= Acceleration due to gravity i.e. [tex]9.8[/tex] [tex]m/s^2[/tex]
In above information,
W= 1150N
g= [tex]9.8[/tex] [tex]m/s^2[/tex]
Using the formula
m=W/g
m=1150/9.8
m=117.347 kg
Thus, the mass of an object if its weight on earth is 1150N is 117.347 kg.
Learn more about Weight, here:
https://brainly.com/question/23312072
#SPJ2
how do i do this question in science?
simple subtract and ummmmmm.....
How to find average velocity on a graph.
Answer:
Answer is below….
Explanation:
The velocity is represented by the slope of a position-time graph. The faster the motion changes, the steeper the slope. The change in position divided by the corresponding change in time may be used to compute average velocity from a position-time graph.
_________________________________________________________
(hope this helps can I pls have brainlist (crown)☺️
3. A mouse crawls 9 meters left in a tube, pauses and then crawls back 5 meters before
stopping. The entire trip took a total of 7 seconds.
a. What is the average speed of the mouse over these 7 seconds?
b. What is the average velocity of the mouse over these 7 seconds?
c. What was the instantaneous velocity of the mouse when it turned around?
Answer:
A
Explanation:
If it is loooking for a proper question, it wants to know how fast the mouse was going
Answer: The answer for this is A.
Explanation: I know this cause i'm smart and totally didn't copy the other guy just to get points
What is the given formula for acceleration?.
Answer:
a=v/t (searched)
Explanation:
a=acceleration
v=change in velocity
t=time
(searched)
A 0.04 kg honeybee circles a field looking for a flower upon which to land. The radius of the circle she travels is 2.5 m and it takes her 1.57 s to complete the circle.
Find the following:
a) Tangential Velocity
b) Centripetal Acceleration
c) Centripetal Force.
For the honeybee that circles a field looking for a flower upon which to land, we have:
a) The tangential velocity is 10.01 m/s.
b) The centripetal acceleration is 40.1 m/s².
c) The centripetal force is 1.60 N.
a) The tangential velocity can be calculated as follows:
[tex] v = \omega r = \frac{2\pi r}{T} [/tex] (1)
Where:
r: is the radius of the circle = 2.5 m
ω: is the angular velocity = 2π/T
T: is the period = 1.57 s
By entering the above values into equation (1), we have:
[tex] v = \frac{2\pi r}{T} = \frac{2\pi 2.5 m}{1.57 s} = 10.01 m/s [/tex]
Hence, the tangential velocity is 10.01 m/s.
b) The centripetal acceleration is related to the tangential velocity as follows:
[tex] a_{c} = \frac{v^{2}}{r} = \frac{(10.01 m/s)^{2}}{2.5 m} = 40.1 m/s^{2} [/tex]
Therefore, the centripetal acceleration is 40.1 m/s².
c) The centripetal force is given by:
[tex] F = ma_{c} [/tex]
Where:
m: is the honeybee's mass = 0.04 kg
[tex] F = ma_{c} = 0.04 kg*40.1 m/s^{2} = 1.60 N [/tex]
Hence, the centripetal force is 1.60 N.
Find more here:
https://brainly.com/question/823034?referrer=searchResultshttps://brainly.com/question/25776956?referrer=searchResultsI hope it helps you!
A hummingbird flies 6 m along straight path upon spotting flower below it drops directly downward 8 m
What is the displacement and its direction?
Answer:
10m South East
Na + KCL -> K + NaCI reaction type
Explanation:
it is a displacement reaction.
The high energy yields created by nuclear fission are due to
A. Binding nuclei
B. Chain reactions
C. Hydrogen bonding
D. Secondary recovery
Answer:
Nuclear fission of heavy elements produces exploitable energy because the specific binding energy (binding energy per mass) of intermediate-mass nuclei with atomic numbers and atomic masses.
Explanation:
have a great day!! :)
As an aeroplane decelerates, its kinetic energy decreases. Suggest what happens to this energy
they are converted into thermal and sound energy as well as the kinetic energy in the air
Rubies are used in electronics.
Please select the best answer from the choices provided
) Т
) F
How much force is required to move a rock 75m, when using 340J of work?
Answer:
Solution given:
work done=340J
displacement(d)=75m
force[f]=?
we have
work done =Force*displacement
340=Force*75
Force=340/75
Force=4.5N
Given,
Work done = 340 J
Distance = 75 m
Force = work done / distance
Force = 340 / 75
Force = 4.533 Newton (N)
______
RainbowSalt2222
The angular quantities L, omega, and alpha are vectors. The vectors point along the axis of rotation with a direction determined by __________.
The vectors point along the axis of rotation with a direction determined by an arrow.
What is a vector?There are two types of physical quantity one is a scaler and another one is a vector.
The quantity that requires only megnitude to define is known as the scalar quantity. While the vector quantities need both megnitude and the direction to define.
The vector quantity is represented by an arrow. The vectors point along the axis of rotation with a direction determined by an arrow.
The angular quantities L, omega, and alpha are vector quantities.
Hence arrow is the correct answer for the blank.
To learn more about the vector refer to the link;
https://brainly.com/question/13322477
The direction of the vectors of angular momentum and L, angular velocity omega and the mass alpha is determined using the right hand rule.
What is right hand rule?Righthand rule in physics states that, when we curl our right hand fingers, the direction of the angular momentum and velocity will be in the direction of thumb and curl of fingers determine the axis of rotation.
Angular momentum is a vector quantity defined as the product of moment of inertia and angular velocity where, the angular velocity ω is the rotational analogue of linear velocity i.e.. product of the linear velocity and radius of rotational path.
Therefore, the angular quantities L, angular velocity ω along the axis of rotation can be determined using the right hand rule. Where direction of thump represents the direction of vector components.
To find more on right hand rule, refer here:
https://brainly.com/question/9750730
#SPJ2
A chemist is studying an unknown substance and could break the substance into its elemental components only by using chemical means. Based on this observation, how should the unknown substance be classified?
A. impure substance
B. solution
C. mixture
D. pure substance
The answer is D
I took the quiz lol
Hello guys! Can you please help me with physics. I translated it in English. Can yall help me please how much you can!!
A body 60 m above the ground shall be thrown vertically upwards at an initial speed of 20 m / s. Air resistance can be ignored!
1. How high will the body fly from the point of ejection?
2. What is the maximum height it will reach above the ground?
3. How long does it take for the body to reach its highest point from the moment of expulsion?
4. After how long after the expulsion will the body fall to the ground?
5. What is the speed of the body at the moment of falling to the ground?
Answer:
1. 60m
4. its speed is 20m/s . gravity is 10m/s . 20 ÷ 10 = 2 seconds after these 2 sec are over the velocity will be zero thus it would have fallen.
Explanation:
Am sorry these is what i could answer but i will try to research and get answers for the rest of the questions, hope this helps
An ice skater at rest on ice catches a dance partner moving 1.5 m/s during a performance. The ice skater has a mass of 75 kg and the dance partner has a mass of 50 kg. What is the speed of the ice skater and dance partner after the collision?
Tiny mass of 67kg and tubby mass of 83 kg are now on the opposite ends of a see saw and are both 1.4m from the balance point where should their sister teeny whose mass is 32 kg sit so the see saw balances
Answer:
0.7 m between the balance point and Tiny
Explanation:
It's intuitive to say she sould be on the side the smaller mass is placed. How far from the balance point?
Let's call x that distance. and assume that the contraption is "oriented" so that being on the side with tiny (and teeny) gives you a positive distance from the balance point, and negative on the other side.
At equilibrium, the sum of all momentums (momenta?) will be zero:
[tex]67\times 1.4 +32\times x + 83 \times (-1.4) = 0\\32x -16(1.4) = 0 \rightarrow 2x=1.4 x= 0.7[/tex]
In layman's term, she has to be halfway between the balance point and Tiny.
PLEASE HELP!!
Identify how each machine changes the way work is done so as to
be useful.
Bicycle
Ax blade
Car jack
When you pedal a bike with chains attached to it, the wheel spins as you exert force from your body into the pedaling. The chains are connected to an almost circular shape.
How machine changes the way of work?Contrary to popular assumption, using machines does not result in more work being done. They merely alter the method of operation. Machines make work easier by increasing the amount of force used, extending the distance over which the force is exerted, or changing the direction of the force.
Simple machines are helpful because they lessen effort or enable humans to execute things that would normally be beyond their capacity. The wheel and axle, pulley, inclined plane, screw, wedge, and lever are examples of simple devices that are frequently employed.
To learn more about machine changes the way of work refer to:
https://brainly.com/question/902575
#SPJ2
light of wavelength 520 nm falls on a slit that is 3.20 um wide. Estimate how far the first bright-sh difrrection fringe is
Answer:
because of the gravity of the earth
Which type of electromagnetic radiation is commonly used for long-distance communications?
A. infrared radiation
B. radio waves
C. ultraviolet radiation
D. gamma rays
Answer:
B. Radio waves
Explanation:
Radio waves are transmitted easily through air. They do not cause damage if absorbed by the human body, and they can be reflected to change their direction. These properties make them ideal for communications.
Hope this helps!!
Answer:
B
Explanation:
Radio Waves
A driver is moving forward and stepping on the gas pedal. Which
position-time graph best depicts this motion?
Answer:
D
Explanation:
PLEASE HELP!!!!!
How does the law of conservation of energy apply to an object rolling down different surfaces?
Answer:
it states that energy can either be gained or lost but it only changes its form.
Explanation:
for example:as a ball is still on the table it posses a potential energy of 100j and a k.e of 0j,as it falls it gains k.e so the midpoint the p.e is equal to the k.e (50j equally) as it approches the ground it completely gains k.e (100j) and the p.e is 0j.
total energy is 100j so it has been converted from p.e to k.e.
hope u have understood.