Answer: To focus on a near object – the lens becomes thicker, this allows the light rays to refract (bend) more strongly. To focus on a distant object – the lens is pulled thin, this allows the light rays to refract slightly.
Explanation:
I WILL MARK BRAINLIEST!!ASAP!!! Wet Lab - Coulomb's Law lab from edge!!
Answer: nah
Explanation:
A wet lab experiment for Coulomb's law involves measuring the force between charged objects immersed in a liquid. The experiment is called a "wet" lab because it involves liquid or aqueous solutions.
What is Coulomb's law?Coulomb's law is an equation that describes the electrostatic force between two charged particles.
It states that "the force is directly proportional to the product of the charges and inversely proportional to the square of the distance between them."
The equation is given by:
F = k×(q₁ × q₂) / r²
Where
F = the electrostatic force,
k =Coulomb's constant,
q₁ and q₂= the charges of the particles,
r =the distance between the.
In this question,
In the experiment, two conductive objects are charged with opposite charges using a high-voltage power supply, which can be controlled to vary the magnitude of the charges.
The two objects are then immersed in a non-conductive liquid, such as oil or water, and positioned a fixed distance apart.
Using a force sensor or a balance, the force between the two objects is measured as they move toward each other. By measuring the force at different distances, the experiment can verify Coulomb's law, which predicts that the force between two charged objects is proportional to the product of their charges and inversely proportional to the square of their separation distance.
The experiment can be performed with different pairs of charged objects with different magnitudes of charge and separation distances, allowing the relationship between the force and these variables to be investigated. This provides insight into the electrostatic interaction between charged objects in a liquid, which has applications in various fields, including electrochemistry, material science, and biophysics.
Therefore, in a wet lab experiment on Coulomb's law, we have to immerse the apparatus in aqueous solutions.
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Which of the following is NOT a way that a machine makes work easier to do?
A. Change the size of a force
B. Change the type of force
C. Change the direction of the force
D. Change distance a force acts
Answer:
c
Explanation:
ur changing the way it move not to make it easier
The direction of the force, has nothing to do with how the machine will work easier. The correct option is C
A machine is any devices that make work easier. An ideal machine takes in small effort to overcome large load.
Since work has to be done in a machine, and work is the product of force and perpendicular distance, for a machine to work easier, the work done will depend on size of the force applied, the type of force applied, and also, the magnitude of the distance involved.
The direction of the force, has nothing to do with how the machine will work easier. Therefore, the correct option is C
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I WILL MARK BRAINLIEST!!ASAP!!! Wet Lab - Coulomb's Law lab from edge!!
Answer:
idek to be honest
Explanation:
The Moon has a radius of 1.7 × 106 m and a mass of 7.3 × 1022 kg. Find the gravitational field on the surface of the Moon.
Answer:
10.7*[tex]10^{6}[/tex]
Explanation:
Question 2 of 10
Which of the following careers would physicists be least qualified to perform,
based on their training?
A. Nuclear engineer
B. Solar panel designer
C. Research lab manager
D. Gardener
Answer:
a and d
Explanation:
a because a nuclear engineer is more on explosions which links to chemistry and d because Gardner is irrelevant
What is the potential energy of a rock that weighs 10.0 kg and is sitting on top of a hill 300 meters high?
The potential energy of a rock that weighs 10.0 kg and is sitting on top of a hill 300 meters high is 29400J
POTENTIAL ENERGY:
Potential energy refers to the energy due to the position of an object. It can be calculated by using the following formula:P.E = m.g.h
Where;
m = mass of the rock
g = gravitational force of Earth (9.8m/s²)
h = height (m)
According to this question, a rock weighs 10.0 kg and is sitting on top of a hill 300 meters high. The potential energy can be calculated as follows:P.E = 10 × 9.8 × 300
P.E = 29400J
Therefore, the potential energy of a rock that weighs 10.0 kg and is sitting on top of a hill 300 meters high is 29400J.Learn more: https://brainly.com/question/15613166?referrer=searchResults
Two bodies made of the same material have same external dimension and appearance, but one is compact solid and other is hollow. When they heated for the same temperature range, is the overall volume expansion the same or different? Explain.
Answer:
Different
Explanation:
The hollow one will expand even more making it have a larger volume then the solid one so they are different
different between si unit and derived unit
Answer:
There are seven base SI units corresponding to different parameters and are considered independent of each other. Derived units are derived from these 7 base units. Derived units are dependent on the base units and are not independent of each other. For example, let us derive the SI units for force. By Newtons Second Law of Motion, the force is same as the product of mass and acceleration of a body. that is, force = mass x acceleration. Also, acceleration is defined as the rate of change of velocity. And velocity is defined as the rate of change of displacement. Thus, force = mass x acceleration = mass x dv/dt = mass x dt2 Mass has SI units of kg, distance is measured in m and t has the SI unit of second. Thus, Sl unit of force is kg.m/s^2 (also known as Newton).
A) 750gm
11. Ifa rectangular solid box of aluminum is heated, which of the following is not true?
A) Its mass remains constant
Cits density increase
B) Its volume increase
Do none of the above
Given :
A rectangular solid box of aluminum is heated.
To Find :
Which of the following is not true.
A) Its mass remains constant
C) its density increase
B) Its volume increase
D) none of the above
Solution :
We know, when an object is heated it expands.
Objects expands means that the volume increases but mass remains same by conservation of mass.
Since mass remains constant and volume increases.
So, density will decrease.
Hence, this is the required solution.
A man carries a load of mass 2.6kg from one end of a uniform pole 100cm long which has a mass 0.4kg. The pole rest on his shoulder at a point 60.0cm from the load and he holds it by the other end. What vertical force must be applied by his hand and what is the force on his shoulder?
Answer:
F = 39.2 N (hand force) and N = 68.6 N (shoulder force)
Explanation:
In this exercise we must use the rotational and translational equilibrium conditions, we have several forces: the weight (W) of the pole applied at its geometric center, the load (w1) at one end, the shoulder support (N) 60 cm from the load and hand force (F) at the other end of the pole
Let's set the reference system at the fit point of the shoulder
∑ τ = 0
We will assume that the counterclockwise turns are positive
w₁ 0.60 + W 0.1 + F₁ 0 - F 0.4 = 0
all distances are measured from the support of the man (x₀ = 0.60 m)
F = (w₁ 0.60 + W 0.1) / 0.4
F = (m₁ 0.6 + m 0.1) g / 0.4
let's calculate
F = (2.6 0.6 + 0.4 0.1) 9.8 / 0.4
F = 39.2 N
this is the force that the hand must exert to keep the system in balance
We apply the translational equilibrium condition
-w₁ -W + N - F = 0
N = w₁ + W + F
N = (m₁ + m) g + F
let's calculate
N = (2.6 + 0.4) 9.8 + 39.2
N = 68.6 N
Una barra de hierro cuya longitud inicial es de 2m se le incrementa su temperatura de 20 °C a 120 °C ¿Cuál es la longitud final de la barra? (considera que el coeficiente de dilatación del hierro) es 1,2 x 10-5 1/°C ( 3 puntos)
Answer:
1.9976 m
Explanation:
An iron bar whose initial length is 2m has its temperature increased from 20 ° C to 120 ° C. What is the final length of the bar? (consider that the coefficient of expansion of iron) is 1.2 x 10-5 1 / ° C (3 points)
Given that,
Initial length of an iron bar, [tex]L_0=2\ m[/tex]
The temperature increased from 20°C to 120°C
The coefficient of expansion of iron is [tex]1.2\times 10^{-5}\ /^{\circ} C[/tex]
We need to find the final length of the bar.
The linear expansion equation is given by :
[tex]\Delta L=\alpha L\Delta T[/tex]
Where [tex]\Delta L[/tex] is the change in length
[tex]\Delta L=1.2\times 10^{-5}\times 2\times (120-20)\\\\=0.0024\ m[/tex]
Also, [tex]\Delta L = L_o-L[/tex]
L is final length
[tex]0.0024= 2-L\\\\L=2-0.0024\\\\=1.9976\ m[/tex]
So, the final length of the bar is 1.9976 m
Which quantities define momentum?
Answer:
velocity and mass
Explanation:
:) apek
A whale travels 112 meters at 14 m/s How long does this take?
Answer:
8
Explanation:
112meters divided by 14
What is the final speed of an object that starts from rest and accelerates uniformly at 3.0 meters per second2 over a distance of 6.0 meters? (1) 8.0 m/s (2) 6 m/s (3) 16 m/s (4) 64 m/s
Answer:
16 m/s sir
Explanation:
because i am in collage
HELP NEEDED ASAP I'M GIVING BRAINLIEST
1) Select the best answer from the choices below. Light has many properties of waves, but sometimes it also behaves like:
a
A photon
b
Polarized light
c
Ultraviolet rays
d
A stream of particles
2) What type of waves transmit signals in satellite communication?
a
Microwaves
b
X-rays
c
Gamma Rays
d
Radio Waves
3) Cell phones use digital signals to send and receive information. These digital signals travel as what kind of wave?
a
Gamma rays
b
X-rays
c
Microwaves
d
Radio waves
Answer:
1.
d . A stream of particles
2. D. Radiowave
3. Microwaves
Answer:
1.
d . A stream of particles
2. D. Radiowave
3. Microwaves
Explanation:
Plz help plllzzzzzzzz
Four examples of second class levers
Answer:
they are :
Explanation:
wheelbarrow bottle opener an oarWhat is the speed in kilometers per hour of a 27.78m/s baseball pitch?
Answer:
100.008 km/h
Explanation:
multiply the speed value by 3.6
how does an air pump work
Answer:
When the piston is pulled up, air gets sucked into the pump through the inlet. The pump chamber depressurizes as it fills with air. When the piston is forced down, the air becomes compressed and closes the inlet. Then the air flows out from the outlet
A car initially traveling at 25 m/s speeds up to 60 m/s under a uniform acceleration of 5.0 m/s2 to avoid being hit by another car. How long does it take the car to speed up and get out of the way? Show your work.
Answer:
The car takes 7 seconds to speed up and get out of the way
Explanation:
Constant Acceleration Motion
It's a type of motion in which the velocity of an object changes uniformly over time.
Having a as the constant acceleration, vo the initial speed, vf the final speed, and t the time, the following relation applies:
v_f=v_o+at
Using the above equation we can solve for t:
[tex]\displaystyle t=\frac{v_f-v_o}{a}[/tex]
The car has an initial speed of vo=25 m/s and ends up at vf=60 m/s with an acceleration of a=5 [tex]m/s^2[/tex].
Given all the appropriate data, calculate t:
[tex]\displaystyle t=\frac{60-25}{5}[/tex]
Calculating:
[tex]\displaystyle t=\frac{35}{5}[/tex]
t = 7 seconds
The car takes 7 seconds to speed up and get out of the way
A 10 V fan with a current of 2 A is turned on for 30 seconds. Calculate the energy transferred in joules,
Answer:
E = 600 J
Explanation:
Given that,
Voltage, V = 10 V
Current, I = 2 A
Time, t = 30 s
We need to find the energy transferred. Energy transferred is calculated as follows :
[tex]E=I^2Rt[/tex]
Ohm's law, V = IR, R = V/I
[tex]E=I^2\times \dfrac{V}{I}\times t\\\\E=IVt\\\\E=2\times 10\times 30\\\\E=600\ J[/tex]
So, 600 J of energy is transferred.
Answer:600J
Explanation:
A dog chases a skateboarder travelling at 10.4m/s.The skateboarder speeds up with a constant acceleration for 39m over 3.3s. We want to find the acceleration of the skateboarder over the 3.3s time interval.
Answer:
The acceleration of the skateboarder over the 3.3s time interval is 3.15 m/s²
Explanation:
Acceleration can be described as the rate of change of velocity (as seen in the question). The formula to be used here to determine the acceleration is
Acceleration (in m/s²) = velocity (m/s) ÷ time (s)
Acceleration = 10.4 ÷ 3.3
Acceleration = 3.15 m/s²
Thus, the acceleration of the skateboarder over the 3.3s time interval is 3.15 m/s²
Inside a car that was at 273 K, a bottle with a pressure at 100,000 pascals warms up to 350 K. If the volume of the bottle remains constant, what is the pressure, in pascals, inside the hot water bottle!
Answer:
128.205.1
Explanation:
Why work and energy both have same unit? Give reasons?
Answer:
Explanation:
both have same unit because energy is defined as the ability to do work and work is the measure of transfer of energy when an objects moved from one place to another place so both are same thats why both have same units
A fossil mammoth bone was found to contain 6.25% carbon-14 percent isotope and 93.75% nitrogen-14 daughter isotope. If the half-life of carbon-14 is 5700 years old, how old is the mammoth bone?
Answer:
The mammoth bone is 22726 years old.
Explanation:
We can find how hold is the mammoth bone using the decay equation:
[tex]N(t) = N_{0}*e^{-\lambda t}[/tex] (1)
Where:
N(t): is the quantity at time t = 6.25%N₀
N₀: is the initial quantity
λ: is the decay constant
First, we need to find λ:
[tex] \lambda = \frac{ln(2)}{t_{1/2}} = \frac{ln(2)}{5700 y} = 1.22 \cdot 10^{-4} y [/tex]
Now, by solving equation (1) for t we have:
[tex]t = \frac{ln(\frac{N(t)}{N_{0}})}{-\lambda} = \frac{ln(0.0625)}{-1.22 \cdot 10^{-4}} = 22726 y[/tex]
Therefore, the mammoth bone is 22726 years old.
I hope it helps you!
How did Robert Whittaker change classification?
He created an organizational hierarchy.
He classified organisms as plants or animals.
He added the Phylum and Family levels.
He reorganized life into five kingdoms.
Answer:
d
Explanation:
Which statement is correct about two objects that have gravitational force?
They have mass.
They move slowly.
They are round in shape.
They have high temperature.
Answer:
1 and 2
Explanation:
The formula itself has nothing to do with shape or temperature. The formula does have mass and the speed depends on the how great the mass/radius is.
Which statements accurately describe matter
A satellite of mass 1000kg is in a circular orbit around a planet. The centripetal acceleration of the satellite in its orbit is 5m/s^2. What is the gravitational force exerted on the satellite by the planet?
A. 0N
B. 200N
C. 5000N
D. 10000N
Answer: 5000N
Explanation:
The basic principle of a circular orbit is that Fg = m × ac, so as we have the mass and the centripetal acceleration (also called normal acceleration) we just have to operate. Fg = 1000kg × 5m/s² = 5000N
The gravitational force exerted on the satellite of mass 1000 kg moving in a circular orbit with a centripetal acceleration of 5 m/s² by the planet is 5000 N (option C).
The gravitational force exerted on the satellite by the planet will be equal to the planet's gravity, which is equal to the centripetal force, so:
[tex] F_{g} = F_{c} = ma_{c} [/tex]
Where:
m: is the mass of the satellite = 1000 kg
[tex]a_{c}[/tex]: is the centripetal acceleration = 5 m/s²
The, the force acting on the satellite is:
[tex] F_{c} = ma_{c} = 1000 kg*5 m/s^{2} = 5000 N [/tex]
Therefore, the gravitational force exerted on the satellite by the planet is 5000 N (option C).
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I need help on this question
Answer:
at rest because time is passing and speed is still at 0
Explanation: