005 (part 1 of 2) 10.0 points
A runner is jogging in a straight line at a
steady vr= 8.5 km/hr. When the runner is
L=6.4 km from the finish line, a bird begins
flying straight from the runner to the finish
line at vý= 17 km/hr (2 times as fast as the
runner). When the bird reaches the finish
line, it turns around and flies directly back to
the runner
What cumulative distance does the bird
travel? Even though the bird is a dodo, as-
sume that it occupies only one point in space
(a "zero" length bird). travels in a straight
line, and that it can turn without loss of
Speed
Answer:
7.53 km
Explanation:
We at given;
Speed of runner; v_r = 8.5 km/hr
Speed of bird; v_y = 17 km/hr
L = 6.4 km
We know that; time = distance/speed.
We are told that the bird starts from 6.4 km from the start and that it flies back to meet the runner after it reaches the finish line. If the total distance back to the runner is x, it means bird distance is 6.4 + (6.4 - x) = 12.8 - x
Thus;
Time of bird(t_y) = (12.8 - x)/17
Thus,
Time of runner(t_r) = x/8.5 hr
To find x, we have to equate the times of the runner and the bird.
Thus;
x/8.5 = (12.8 - x)/17
Multiply both sides by 17 to get;
2x = 12.8 - x
2x + x = 12.8
3x = 12.8
x = 12.8/3
x = 4.27 km
Thus, cumulative distance traveled by bird is; 12.8 - 4.27 = 7.53 km
Which of the following equations is balanced?
a. 2Al2O3 -----> 3Al + 3O2
b. 3Al2O3 -----> 3Al + 2O2
c. 2Al2O3 -----> 4Al + 3O2
d. 2Al2O3 -----> Al + 3O2
Answer: c
Explanation:
The way to check which one is the correct one is to simply multiply and see if there are the same number of atoms in both sides for each element.
a. 2×2 atoms of Al ≠ 3×1 atoms of Al
2×3 atoms of O = 3×2 atoms of O
BOTH MUST BE EQUAL FOR IT TO BE ADJUSTED!!!!!
b. 3×2 atoms of Al ≠ 3×1 atoms of Al
3×3 atoms of O ≠ 2×2 atoms of O
c. 2×2 atoms of Al = 4×1 atoms of Al
2×3 atoms of O = 3×2 atoms of O
BOTH ARE EQUAL, CORRECT ANSWER!!!
d. 2×2 atoms of Al ≠ 1×1 atoms of Al
2×3 atoms of O = 3×2 atoms of O
11. The professor who first
implemented a scientific approach in
order to investigate a problem, and
who is often referred to as ‘the father
of scientific methodology’, is:
a. Galileo
b. Democritus
c. Newton
d. Einstein
12. Which of the following adjustments
to a pendulum would affect the
period of oscillation?
a. Increasing the mass
b. Decreasing the length
c. Increasing the length
d. Increasing the angle of
displacement
13. The width of a desk was measured
using a meter ruler, which of the
following is the most appropriate
reading expressing the result?
a. 0.724 m
b. 0.7248 m
c. 0.72 m
d. 72 cm
Answer:Newton
Explanation:
Can someone Plzzz help meee.
solid...............
Determine the gain in the potential energy when a 8.0 kg box is raised 17.2 m.
Answer:
The answer is 1376 JExplanation:
The potential energy of a body can be found by using the formula
PE = mgh
where
m is the mass
h is the height
g is the acceleration due to gravity which is 10 m/s²
From the question we have
PE = 8 × 10 × 17.2
We have the final answer as
1376 JHope this helps you
Explanation:
potential energy = mgh
potential energy = 8 * 10 * 17.2
potential energy = 1376 joules
What is an electromagnetic wave?
A. An induced electric current
B. Vibrating electric and magnetic fields
C. Oscillating electric current
D. An electromagnet
A roller coaster is travelling 1 m/s at the top of the track. At the bottom of the track, 5 seconds later, it is travelling 36 m/s. What is the average acceleration?
7.2 m/s2
0.14 m/s2
36 m/s 2
7 m/s2
Answer:
7m/s²
Explanation:
Given parameters:
Velocity at the top = 1m/s
Velocity at the bottom = 36m/s
Time = 5s
Unknown:
Average acceleration = ?
Solution;
Acceleration is the rate of change of velocity with time. It is expressed as;
A = [tex]\frac{v -u}{t}[/tex]
v is the velocity at the top
u is the velocity at the bottom
t is the time taken
Now, insert the parameters and solve;
A = [tex]\frac{36 - 1}{5}[/tex] = 7m/s²
Given values:
Top velocity,
v = 1 m/sBottom velocity,
u = 36 m/sTime,
t = 5 sThe acceleration is:
→ [tex]A = \frac{v -u}{t}[/tex]
By putting the values,
[tex]= \frac{36-1}{5}[/tex]
[tex]= \frac{35}{5}[/tex]
[tex]= 7 \ m/s^2[/tex]
Thus the answer above i.e., "option d" is correct.
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Water boils at 212°F. Which temperature is an equivalent temperature?
[tex]\mathrm {Hey, there!}[/tex]
Let's solve your problem:
We will convert your number, 212°F, to Kelvin and Celsius.
212°F is equal to 100° Celsius.
Now, let's do the Kelvin convert.
To convert Celsius to Kelvin, we have to add 273.5 to the amount of Celsius.
100° + 273.5 = 373.5
We have all our conversions. Finally, let's set them out.
Fahrenheit: 212°F
Celsius: 100°C
Kelvin: 373.5°K
Three vectors , , and , each have a magnitude of 52.0 m and lie in an xy plane. Their directions relative to the positive direction of the x axis are 29.0 ˚, 191 ˚, and 311 ˚, respectively. What are (a) the magnitude and (b) the angle of the vector (relative to the +x direction in the range of (-180°, 180°)), and (c) the magnitude and (d) the angle of in the range of (-180°, 180°)? What are (e) the magnitude and (f) the angle (in the range of (-180°, 180°)) of a fourth vector such that ?
Answer:
a) A´= A
b) θ₁´ = 29º, θ₂´ = - 169º , θ₃´ = -49º
Explanation:
In this exercise you are asked to give the magnitudes and angles of the vectors from another system of
reference
a) The magnitudes
The magnitude of a vector, the size of which is a scalar, this does not depend on the reference system, since it is obtained by subtracting the coordinates of the end point minus the coordinate of the origin of the vector
A = [tex]x_{f}[/tex]- x₀
if the vectors are measured in another reference frame
x_{f}´ = xx_{f}- U
x₀´ = x₀ -U
where U is the distance between the two reference frames
A´ = x_{f}´ - x₀´
we substitute
A´ = (x_{f} - U) - (x₀-U) = x_{f} - x₀
A´ = A
it does not change
b) Angles
The given angles are measured from the positive part of the x axis in a counterclockwise direction, it is asked to give these angles from the x axis
θ₁ = 29º
does not change
θ₁´ = 29º
θ₂ = 191º
we measure clockwise
θ₂´ = θ₂ - 360
θ₂´ = 191 - 360
θ₂´ = - 169º
θ₃ =311º
we measure clockwise
θ₃´ = 311 -360
θ₃´ = -49º
it is harmful to settle near the airport why
2. An object is moving with an initial velocity of 12 m/s. It accelerates at a rate of 1.5 m/s^2 over a distance of 40 m. What is its new velocity?
Answer:
16.2 m/s
Explanation:
2ad=Vf^2-Vi^2
2 (1.5) (40) = Vf^2 -(12)^2
Vf= 16.2 m/s
A car drives 400 meters in 5 seconds. What is the cars speed in m/s?
Answer:
80/1
Explanation:
to figure out the answer of how many miles/meters per second divide the meters/miles by the second
so 400÷5 would be 80
80 meters per second
hope this helps :))
A sample contains 20 kg of radioactive material. The decay constant of the material is 0.179 per second. If the amount of time that has passed
is 300 seconds, how much of the of the original material is still radioactive? Show all work
Answer:
There are [tex]9.537\times 10^{-23}[/tex] kilograms of radioactive material after 300 seconds.
Explanation:
From Physics we know that radioactive materials decay at exponential rate, whose differential equation is:
[tex]\frac{dm}{dt} = -\lambda\cdot m[/tex] (1)
Where:
[tex]\frac{dm}{dt}[/tex] - Rate of change of the mass of the radioactive material, measured in kilograms per second.
[tex]m[/tex] - Current mass of the radioactive material, measured in kilograms.
[tex]\lambda[/tex] - Decay constant, measured in [tex]\frac{1}{s}[/tex].
The solution of the differential equation is:
[tex]m(t) = m_{o}\cdot e^{-\lambda\cdot t}[/tex] (2)
Where:
[tex]m_{o}[/tex] - Initial mass of the radioactive material, measured in kilograms.
[tex]t[/tex] - Time, measured in seconds.
If we know that [tex]m_{o} = 20\,kg[/tex], [tex]\lambda = 0.179\,\frac{1}{s}[/tex] and [tex]t = 300\,s[/tex], then the initial mass of the radioactive material is:
[tex]m(t) = (20\,kg)\cdot e^{-\left(0.179\,\frac{1}{s} \right)\cdot (300\,s)}[/tex]
[tex]m(t) \approx 9.537\times 10^{-23}\,kg[/tex]
There are [tex]9.537\times 10^{-23}[/tex] kilograms of radioactive material after 300 seconds.
When an 8 V battery is connected to a resistor, a 2 A current flows in the resistor. What is the resistor's value?
Ο Α. 2Ω
Ο Β. 4 Ω
Ο C. 8Ω
Ο D. 16 Ω
Answer:
B
Explanation:
V=IR I= curren V=volt R=resistor
8=2.R 8/2=R R=4
Classify each resource as renewable or nonrenewable.
Answer:
coal: nonrenewable
geothermal energy: renewable
wind: renewable
natural gas: nonrenewable
Explanation:
Have a good day
Thanks
Answer:
coal is non-renewable, the wind is renewable, I belive natural gas is not but I'm not to sure with that one. geothermal energy is renewable.
Explanation:
I need help, worth 40 Points!
A plane flies due north (90° from east) with a velocity of 100 km/h for 3 hours. During this time, a steady wind blows southeast at 30 km/h at an angle of 315° from due east. After 3 hours, where will the plane’s position be relative to its starting point?
*Please try to fill the data table.
Answer:
thank you
Explanation:
Split up the two given velocity vectors into horizontal and vertical components.
Plane:
p = (100 km/h) (cos(90°) i + sin(90°) j ) = (100 km/h) j
Its direction is given, 90° relative to east.
Traveling for 3 hours with this velocity results in a displacement of
p * (3 h) = (300 km/h) (3h) j = (900 km) j
meaning that this velocity contributes to a north-facing displacement of 900 km.
Wind:
w = (30 km/h) (cos(315°) i + sin(315°) j ) ≈ (21.2 km/h) i + (-21.2 km/h) j
Its direction is also given, 315° relative to east.
After 3 h, this velocity contributes to a displacement of
w * (3h) ≈ (63.6 km) i + (-63.6 km) j
meaning if the plane had no velocity of its own but somehow stayed in the air, the wind would have pushed it about 63.6 km south and 63.6 km east, which translates to a net displacement of
√((63.6 km)² + (-63.6 km)²) = 90 km
due southeast.
Putting everything together, your table displacement table should read:
. | wind | plane
velocity | 30 | 100 ... km/h
direction | 90° | 315° ... relative to east
x | 63.6 | 0 ... km
y | -63.6 | 900 ... km
The resultant vector is the sum of these, r = p + w :
r ≈ (21.2 km/h) i + (78.8 km/h) j
After 3 h, the resultant displacement is
r * (3h) ≈ (63.6 km) i + (236.4 km) j
with magnitude
√((63.6 km)² + (236.4 km)²) ≈ 244.8 km
and direction θ such that
tan(θ) ≈ (236.4 km) / (63.6 km)
θ ≈ arctan(3.714) ≈ 74.9°
So the resultant table should read
xnet | 63.6 km
ynet | 236.4 km
magnitude | 244.8 km
theta | 74.9° relative to east
for which colour of light is. the index of refraction of glass largest
Answer:
don't know sorry for the irreverent answer..
Answer:
The index of refraction varies with frequency, it doesn't change as light travels from one medium to another, As violet colour has the shortest wavelength and so the refractive index is maximum for it.
A water tank is filled with up to 3.5 m height.Calculate the pressure given by the tank at its bottom
Answer:
96.04Pa
Explanation:
height=3.5m
gravity=9.8%
density=9.8/3.5
=2.8
Preassure=h×g×d
=3.5×9.8×2.8
=96.04Pa
The components of a 15-meters-per-second velocity at an angle of 60.° above the horizontal are (1) 7.5 m/s vertical and 13 m/s horizontal (2) 13 m/s vertical and 7.5 m/s horizontal (3) 6.0 m/s vertical and 9.0 m/s horizontal (4) 9.0 m/s vertical and 6.0 m/s horizontal
Answer:
13 m/s vertical and 7.5 m/s horizontal
Explanation:
❤️
The vertical and horizontal components of a projectile is required.
The correct option is (2) 13 m/s vertical and 7.5 m/s horizontal
u = Initial velocity of projectile = 15 m/s
[tex]\theta[/tex] = Angle of projectile = [tex]60^{\circ}[/tex]
The horizontal component
[tex]u_x=u\cos \theta\\\Rightarrow u_x=15\cos60^{\circ}\\\Rightarrow u_x=7.5\ \text{m/s}[/tex]
The vertical component
[tex]u_y=u\sin \theta\\\Rightarrow u_x=15\sin60^{\circ}\\\Rightarrow u_x=13\ \text{m/s}[/tex]
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What would be the y-component of a velocity vector that had a
magnitude of 37m/s in a direction 30° from the x-axis?
Answer:
18.5 m/s
Explanation:
Just did it on EdPuzzle
The y-component of a velocity vector that had a magnitude of 37 m / s in a direction 30° from the x - axis would be 18.5 m / s .
What is a vector quantity?The quantities that contain the magnitude of the quantities along with the direction are known as the vector quantities.
Examples of vector quantities are displacement, velocity acceleration, force, etc.
As given in the problem we have to find out the y-component of a velocity vector that had a magnitude of 37 m / s in a direction 30° from the x - axis.
The y-component of a velocity vector = 37 × sin 30
= 18.5 m / s
Thus , y-component of a velocity vector that had a magnitude of 37 m / s in a direction 30° from the x - axis would be 18.5 m / s.
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Please help me fast
Answer:
b I think. sorry if it's wrong
Please identify the type of inference happening at letter A and the type of interference happening at letter B. If this was a sound wave, which (A or B) do you think would be louder and why?
Answer:
B i think
Explanation:
B because it travels in the same wavelentgh.............
[tex]gjkrejktg[/tex]
Type A is constructive interference and Type B wave gives destructive interference. The constructive interference would be louder.
What is interfernece?Interference can be described as a natural phenomenon that occurs at every place and at every moment. Interference can be defined as the phenomenon in which two waves superpose to produce the resultant wave of the lower, higher, or same amplitude. Light waves are produced randomly by most of the sources.
The interference of light from the soap bubble which reflects colors when illuminated by a light source. The starting point of the wave produced may be a maximum or a minimum, and there is no way to predict which phase the wave will start.
Interference can either be constructive interference or destructive interference. Constructive interference occurs when the crest of one wave falls on the crest of another wave and the amplitude is maximum.
In destructive interference, when the crest of one wave falls on the trough of another wave and the amplitude is minimum. The phase and displacement of these waves are not the same.
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The flaming gorge bridge, in wyoming rises above a dry gulch. If you throw a rock straight out from the bridge, horizontally, and the rock's horizontal displacement is 255 cm, what was the speed that you thew the rock
Answer:
12.495m/s
Explanation:
Horizontal displacement is the range of the projectile motion.
The range is expressed as;
R = 2U/g
U is the speed at which the rock is thrown (initial speed)
g is the acceleration due to gravity.
Given
R = 255cm = 2.55m
g = 9.8m/s²
Required
Speed U
Substitute the given parameters into the formula as shown;
2.55 = 2U/9.8
Cross multiply
2U = 2.55×9.8
2U = 24.99
U = 24.99/2
U = 12.495m/s
Hence the speed that you thew the rock is 12.495m/s
If an object has a fast velocity, the dots on a ticker tape diagram will be _____.
very long
far apart
very short
close together
Answer:
If an object has a fast velocity, the dots on a ticker tape diagram will be far apart.
A person with a weight of 120 lbs. is standing on a scale. What force is the
scale exerting on the person? *
O Olbs up
O 60 lbs up
O 120 lbs up
240 lbs up
Those 4 numbers are the answer choices plz help
Answer:
The answer is 120lbs
Explanation:
because the scale exerts enough force to equal out to 0 and since the person is putting 120lbs onto the scale it then pushes back enough force to keep them up
The upward force acting on the body is 534 N which is equal to 240 lbs in the upward direction, hence, option d is correct.
What is force?Force is an external agent acting on a body to change it from the state of motion or rest. There are various kind of forces namely, gravitational force, magnetic force, nuclear force etc.
Gravitational force is the force by which an object attracts other objects to its center of mass. Gravitational force depends on the mass of the object and the distance from the surface of earth.
The weight of the person is 120 lbs.
1 Kg = 2.2 lbs
120 lbs = 54.5 Kg.
The force acting on the body by their weight = mg = 54.5 Kg × 9. 8 m/s².
= 534 N.
Hence, 534 N is 240 lbs (534 /2.2 ) of force upward.
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Is Time and Light both connected in anyway?
Answer:
It is not connected by any way
On Planet X, an astronaut has maximum walking speed of 1.9 m/s. The astronaut's legs are each 1.3 m long. What is the constant of acceleration due to gravity on Planet X?
A. 8.3 m/s2
B. 2.8 m/s2
C. 3.8 m/s2
D. 1.1 m/s2
Answer:
Acceleration due to Gravity:
Explanation:
Here g is acceleration due to gravity. So C. 3.8 m/s2
what is electricity
Answer:
Electricity is the flow of electrical power or charge. It is a secondary energy source which means that we get it from the conversion of other sources of energy, like coal, natural gas, oil, nuclear power and other natural sources, which are called primary sources.
List the three astronomical causes for the seasons
s the statement, "You run faster than I do," qualitative or quantitative?
Answer:
qualitative, its an expression, not specific #'s
Explanation:
It is Qualitative
What is Qualitative or Quantitative?Quantitative : Data is number based , countable or measurable
Qualitative : Data is interpretation based , descriptive and relating to language
Since , the statement given in question does not in include any kind of number or measurable quantity and its just an descriptive and relating to language . It is Qualitative
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