The required longitude of the certain ship when the time of the day is 12 noon at the Prime Meridian is 5 p.m is 75° West.
The sun is highest in London, but will not pass the ship for another 5 hours.
Given that,
The time of day for a certain ship is 12 noon at the Prime Meridian is 5 p.m.
The ship must be five hours west of Greenwich since the sun goes from east to west.
Each hour of sun motion is 15° of longitude. The ship is located at (5 x 15°) = 75° West longitude.
Thus, the ship's longitude is 75° West.
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The Endocrine System
The body is made up of several systems of
that work together to
life. The endocrine
system is one of these.
make up most of the
endocrine system, which is found in the entire body, and the
These glands secrete
that regulate
bodily
and reactions. Hormones are
that tell certain
of the body to do
certain things.
for example, tells the body that
there is a need for physical activity, which is why we feel
while running, dancing, or playing sports.
Hormones are substances that communicate with your organs, skin, muscles, and other tissues through your blood to coordinate various bodily functions.
What are the skin's primary purposes?It serves as a sensory organ (touch, temperature detection), aids in temperature control, protects against mechanical, thermal, and physical injury as well as hazardous substances, prevents moisture loss, reduces the harmful effects of UV radiation, has an immune system that can detect diseases, etc.
The six primary functions of the skin are: protection, absorption, excretion, secretion, regulation, and sensation.
Our first line of defence against harmful chemicals, radiation, and poisons is our skin.
The outside world is kept at bay by a skin barrier. is the first line of defence against potentially harmful microbes.
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The average rate of erosion on the Moon is far less than on Earth because
A) the crust of the Moon is much denser than the Earth's crust.
B) the Moon is much younger than the Earth.
C) the Moon's magnetic field protects it from the solar wind better than ours does.
D) the Moon's mare long ago dried up, so there is no more wave erosion there.
E) the Moon lacks wind, water, and an atmosphere.
E) the Moon lacks wind, water, and an atmosphere. The average rate of erosion on the Moon is far less than on Earth because
What is atmosphere?
Atmosphere is the layer of gases surrounding the Earth, composed of nitrogen, oxygen, and other trace elements. It is held in place by the Earth's gravity and is responsible for the air we breathe, the weather we experience, and the climate of the planet.
The atmosphere is also important for providing protection from harmful ultraviolet radiation from the sun and reducing the temperature extremes on the Earth's surface.
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Ammeters that respond to the average value convert the alternating current into direct current. This value must be increased by a factor of _____ to change the average reading into the rms value for a sine wave current.
The average reading must be multiplied by a multiplier of 1.111 to become the rms value for just a sine wave flow.
Describe the wave current?Wave-current interaction in fluid dynamics is the interaction of a mean flow with surface gravity waves.After the interaction begins, both the waves as well as the average flow are impacted since the contact implies an energy exchange.
What are the tide and the wave?While the tide is a type of vertical motion of the ocean's water, waves and ocean circulation represent horizontal movements of the water.
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find the value of e, the margin of error, for c = 0.99, n = 16 and s = 2.6.
The margin of error is 3.96.
The value of e, or the margin of error, can be calculated using the formula:
e = z*(s/√n)
where:
z = the critical value from a standard normal distribution table (for c = 0.99, z = 2.576)
s = the sample standard deviation (in this case, s = 2.6)
n = the sample size (in this case, n = 16)
So, to find the margin of error for this scenario, we plug the given values into the formula:
e = 2.576*(2.6/√16) = 2.576*(2.6/4) = 2.576*0.65 = 3.96
Therefore, the margin of error is 3.96.
It's worth noting that this value represents the range within which we expect the true population value to fall with a certain level of confidence
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Why is dynamic stretching recommended before activity?
Dynamic stretching is recommended before activity because it helps to prepare the muscles for the upcoming activity.
It increases range of motion, flexibility, and muscular coordination, and also helps to increase blood flow to the muscles. This helps to improve the performance of the muscles and reduce the risk of injury. Additionally, dynamic stretching helps to improve the overall physical conditioning of an individual, which is beneficial for any type of physical activity.
Dynamic stretching is typically recommended for individuals preparing for physical activity. Dynamic stretching involves movements that gradually increase in range of motion and muscle length, such as arm swings, leg swings, and torso twists.
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The image below shows the combined wave for Sound A + B, where Sound A has a higher frequency than Sound B. What is the frequency of Sound A?
The frequency of Sound A is 440.3 Hz.
What is the resultant frequency of the two sound waves?The resultant frequency of the sound A and sound B is calculated as follows;
Mathematically, the relationship between period and frequency of a wave is given as;
F = 1 / T
where;
T is the period of the waveThe resultant frequency from the given graph is calculated as;
The period of the sound in the image = 0.3 s
F = 1 / T
F = 1 / 0.3 s
F = 3.3 Hz
If sound B = 437 Hz, the frequency of sound A which is greater is calculated as;
F ( A ) = 437 Hz + 3.3 Hz
F ( A ) = 440.3 Hz
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An electric dipole is formed from +/- 5. 0 nC point charges spaced 3. 0 mm apart. The dipole is centered at the origin, oriented along the y-axis. Part A What is the electric field strength at point (x, y) = (25 mm, 0 cm)? Express your answer using two significant figures. Part B What is the electric field strength at point (x, y) = (0 cm, 25 mm)? Express your answer using two significant figures
The electric field strength at point (x,y) = ( 25 mm ,0cm) is =16321.0769 N/C
The electric field strength at point (x,y) = (0cm, 25 mm) is =35321.58999 N/
What is meant by electric strength?An insulating substance can withstand a certain voltage at its electric strength before losing its ability to insulate. The thickness of the insulating material, as well as the test technique and conditions, will all affect the value for the electric strength.To avoid flash over before breakdown, samples with a thickness of 2mm or more are often examined in oil. Once the breakdown voltage and sample thickness have been determined, the dielectric strength may be estimated. Dielectric strengths for the majority of polymers range from 10 to 30 kV/mm, which is a respectable value.A material's capacity to withstand large voltage swings without experiencing current breakdown is measured by its dielectric strength.To learn more about electric strength refer to:
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The electric field strength at point (x,y) = ( 20 mm ,0cm) is =16321.0769 N/C
The electric field strength at point (x,y) = (0cm, 20 mm) is =35321.58999 N/C
What distinguishes an electric field from an electric field of strength?A vector is a quantity with both a magnitude and a direction, like the electric field. The vector's magnitude corresponds to the electric field intensity.
What do you mean by electric field?Each point in space has an electric field associated with it when there is charge present in any form. E, often known as electric field strength, electric field intensity, or just the electric field, is a mathematical constant that expresses the strength and direction of an electric field.
Given:
Charge = 5.0 nC
x = 25 mm, y = 0 cm
The electric field at any given point of the dipole is given as:
E= (KP) ÷ (r^2 + a^2)^3/2
Where:
K = 9x10^9 Nm^2/c^2 (coloumb constant)
P = (0.003) (5x10^-9c) which is the movement of the dipole
(0.003) is arrived at when mm is converted to m. 3.0 mm space apart was converted to a meter.
r= the point, in the question above is 20mm = 0.02m
Now, the electric field (E),
E = (KP) ÷ (r^2 + a^2)^3/2
= (9x10^9 Nm^2/c^2) (0.003 m) (5x10^-9c) ÷ [ (0.02m)^2 + (0.003)^2]^3/2
= 0.135 ÷ (8.271513x10^-6)
=16321.0769 N/C
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A skydiver, weighing 180 lb (including equipment) falls vertically downward from an altitude of 6000 ft and opens the parachute after 10 s of free fall. Assume that the force of air resistance, which is directed opposite to the velocity, is of magnitude 0. 75|v| when the parachute is closed and is of magnitude 12|v| when the parachute is open, where the velocity v is measured in ft/s. (A computer algebra system is recommended. Use g = 32 ft/s^2 for the acceleration due to gravity. Round your answers to two decimal places. ) (a) Find the speed of the skydiver when the parachute opens. Ft/s (b) Find the distance fallen before the parachute opens. Ft (c) What is the limiting velocity v_L after the parachute opens? v_L = ft/s (d) Determine how long the sky diver is in the air after the parachute opens
The sky diver falls vertically downward from an altitude of 6000 ft and opens the parachute after 10 s of free fall.
What is Acceleration?
Acceleration is the rate of change of velocity over time. It is basically a vector quantity, meaning it has both magnitude and direction. Acceleration is caused by a force and is measured in meters per second squared (m/s2).
a) The speed of the skydiver when the parachute opens can be found by using the equation
v=gt,
where g is the acceleration due to gravity and t is the time of free fall.
We can substitute the given values into the equation to find the speed.
v=gt
v=(32ft/s^2)(10s)
v=320ft/s
b) The distance fallen before the parachute opens can be found by using the equation
s=1/2gt^2,
where g is the acceleration due to gravity and t is the time of free fall.
We can substitute the given values into the equation to find the distance.
s=1/2gt^2
s=(1/2)(32ft/s^2)(10s)^2
s=16000ft.
c) The limiting velocity after the parachute opens can be found by using the equation
v_L=√(2mg/ρA)
where m is the mass of the skydiver, g is the acceleration due to gravity, ρ is the density of air, and A is the projected area of the parachute.
We can substitute the given values into the equation to find the limiting velocity.
v_L=√(2(180lb)(32ft/s^2)/(1.225kg/m^3)(6m^2))
v_L=30.68ft/s.
d) The time the sky diver is in the air after the parachute opens can be found by using the equation
t=v/a
where v is the initial velocity, and a is the acceleration due to air resistance.
We can substitute the given values into the equation to find the time.
t=v/a
t=(320ft/s)/(12ft/s^2)
t=26.67s.
So, the sky diver is in the air for 26.67s after the parachute opens.
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When using a torque increases with a lever?
Since torque is directly proportional to body mass, while the lever arm remains fixed and the mass of the stone grows, so does the torque.
Lever:
Lever is a type of simple machine composed of a stiff beam and a fulcrum. The fulcrum is the point on which the beam pivots. The effort and load are delivered to either end of the beam. A load is applied to the opposite end of a lever when force is applied to the one end.
The three classes of levers are first, second, and third class levers.
The fulcrum of superior levers is positioned between the weight and the effort.
Levers of inferior quality with weight between the fulcrum and the effort
Third-class levers need effort between movements fulcrum and load.
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Which statements describe properties of stars? Check all that apply.
The properties of stars are: mass, age, distance, metallicity (chemical composition), variability and motion through space.
What is star?An astronomical object known as a star is made up of a bright plasma spheroid that is held together by gravity. The Sun is the star that is closest to Earth.
Other stars are also visible at night with the unaided eye, but because to their great distances from Earth, they appear as stationary points of light. Many of the brightest stars have names, and the most notable stars have been grouped into constellations and asterisms.
Star catalogues have been put out by astronomers that list the known stars and offer standardized stellar labels.
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Answer: Stars produce energy through nuclear fusion.
Stars are massive objects composed of gas.
Stars are composed primarily of hydrogen and helium.
P.S can I get the brainiest?
What type of protein secondary structure does the structure shown here (Fiqure 1) represent? O a-helix O a-sheet
O B- helix O B-sheet O y turn
The correct option is C. β-sheet type of protein secondary structure does the structure shown here (Figure 1) represent.
A shape is an arrangement and organization of interrelated elements in a fabric item or gadget, or the item or system so prepared. material systems encompass guy-made items consisting of homes and machines and natural items which include organic organisms, minerals, and chemical compounds. abstract structures consist of statistics structures in pc science and musical shape.
Sorts of the shape include a hierarchy (a cascade of one-to-many relationships), a network providing many-to-many links, or a lattice presenting connections among additives that can be pals in space.
Built structures are widely divided by using their various design approaches and requirements, into classes together with constructing systems, architectural structures, civil engineering structures, and mechanical structures.
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Complete Question:
What type of protein secondary structure does the structure is shown here (Figure 1) represent?
A). α-helix
B). α-sheet
C). β- helix
D). β-sheet
E). γ turn
When the displacement in SHM is two-thirds the amplitude xm, what fraction of the total energy is kinetic energy
The displacement in SHM is 2/3 of amplitude and the fraction of total kinetic energy is Ek = 5/9.
Let’s derive the equations needed from the first principle. The displacement for SHM with amplitude A and angular speed is:
s = A sin(ωt) ---- (1)
Differentiate the displacement to get the velocity:
v = s′ = A ωcos(ωt)
So for a mass m, the kinetic energy is:
Ek = 1/2 mv²
Ek = 1/2 m × (Aωcos(ωt) )² ---- (2)
At time t = 0 the displacement s = 0 and so all the energy is kinetic. Therefore the total energy is:
E (total) = 1/2m ×( Aωcos(0) )²
E (total) = 1/2m × (Aω)² ---- (3)
We can rephrase the kinetic energy in terms of the total energy by comparing (2) and (3):
Ek = E (total) cos²(ωt)
Using the identity cos² (x) + sin² (x) = 1, we can rewrite this equation as:
Ek = E total (1 − sin²) (ωt)) ---- (4)
Additionally, we are aware that potential energy U = E(total) Ek, so
U = E (total) − E (total) (1 − sin²(ωt) )
U = E (total) sin²(ωt) ---- (5)
Now in this question, we’re given that s = 2/3 A, so from our displacement formula (1) we have:
s = Asin (ωt) = 2/3 A
This is what we get for the kinetic energy when we insert it into equation (4):
Ek = E (total)(1 − (2/3)²)
Ek = 5/9 (E (total) )
Hence, the displacement in SHM is 2/3 of the amplitude, and the fraction of total kinetic energy is Ek = 5/9.
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How far from the base of a building must a 25 ft ladder be placed so that it reaches 15 ft up the wall?
Using the Pythagorean theorem, we can determine that the best distance for the ladder is 20 feet away from the base of the building.
The third side of this triangle is unknown, so we will apply the Pythagorean theorem to determine it. There is 25 feet of ladder available, the wall is 15 feet above the ground, the ladder must be at least that high.
In order to calculate the distance between the ladder and the building =
X = √(25^2) - (15^2)
= 20 feet
Thus, the ladder should be placed 20 feet away from the base of the building.
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The spring in a scale stretches 1 centimeter when a 5-newton object hangs from it. How much does an object weigh if it stretches the spring 2 centimeters
The spring in a scale stretches 1 centimetres when a 5 newton object hangs from it. The required weight of an object is 10 N if it stretches the spring 2 centimetres.
Hooke's law tells us that, F = -kx
where, k is the spring constant
x is the distance stretched by a spring
F is the force
Given that,
Length x₁ = 1 cm
Force F₁ = 5 N
Length x₂ = 2 cm
F₂ = ?
From the above equation, we can write,
F₁/x₁ = F₂/x₂
Making F₂ as subject, we have,
F₂ = F₁/x₁ × x₂ = 5/1 × 2 = 10 N
Thus, the required weight of an object is 10 N if it stretches the spring 2 centimetres.
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A photon is ___________________. a type of wave a form of kinetic energy a quantum of light an electrostatic force
The photon is typically described as an electromagnetic (EM) wave, such as the image below. These are the two components of the wave longitudinal and transverse.
What is a photon?A photon is a particle of light which essentially is a packet of electromagnetic radiation. The energy of the photon depends on its frequency (how fast the electric field and magnetic field wiggle, this needs better wording, for 'fast electric field' and 'wiggle'.
What is a photon made of?A photon is a tiny particle that comprises waves of electromagnetic radiation. As shown by Maxwell, photons are just electric fields traveling through space. Photons have no charge, no resting mass, and travel at the speed of light.
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if energy of 10 watts is transferred into a chamber of helium, how long does it take to vaporize 1 kg of liquid helium
energy takes 25 atmospheres of pressure to evaporate 1 kilogrammes liquid helium, and that pressure must be applied at or below the freezing point of helium, which is 458 °F.
How is helium in liquid form transported?From manufacturing sources to stockpiling and transfill facilities, liquid helium is normally delivered. Tankers with a capacity of 5,000 and 11,000 gallons have an annular space that is vacuum-sealed, nitrogen-shielded, and has multiple layers of insulation.
How is liquid helium produced?You need to chill helium gas to just a few temperatures above absolute zero in order to produce the liquid & superfluid states. By compressing the air and then releasing it through a tiny nozzle, this is accomplished. If you've used any aerosol, you may have noticed that the gas rapidly cools as it expands.
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A meter‑long wire of mass 185 g is attached to a 60. 0 Hz mechanical wave oscillator operating at 139 W. The far end of the wire is strung over a frictionless, massless pulley, and a 306 g mass is hung from it. When the oscillator is turned on, it produces a sinusoidal wave in the wire. Calculate the amplitude of oscillation of the wire. Use the value 9. 81 m/s2 for the acceleration due to gravity
The tension in the wire is 2.99986 N. The amplitude of the oscillation of the wire is approximately 0.01067 meters.
The tension (T) can be calculated using the equation:
T = m × g
T = 0.306 × 9.81
T = 2.99986 N
The linear mass density (μ) of the wire is given by the mass per unit length of the wire. It is calculated as:
μ = m(wire) ÷ L(wire)
μ = 0.185 ÷ 1
μ = 0.185 kg/m
The speed (v) of the wave on the wire can be determined using the equation:
v = √(T ÷ μ)
v = √(2.99986 ÷ 0.185 )
v = 7.351 m/s
The power (P) transmitted by the wave is related to the amplitude (A) and the speed (v) of the wave through the equation:
P = 2π² × μ × v × A² × f²
A² = P ÷ (2π² × μ × v × f²)
A² = 139 ÷ (2π² × 0.185 × 7.351 × (60.0)²)
A² = 1.138 × 10⁻⁴
A = √(1.138 × 10⁻⁴)
A = 0.01067 m
Therefore, The amplitude of the oscillation of the wire is approximately 0.01067 meters.
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What type of stretch stretches would benefit an individual preparing for activity?
Dynamic stretching is typically recommended for individuals preparing for physical activity.
Dynamic stretching involves movements that gradually increase in range of motion and muscle length, such as arm swings, leg swings, and torso twists.
These exercises help to improve flexibility, range of motion, and muscular coordination, as well as increase blood flow to the muscles to prepare them for activity. Static stretching is best done after the activity to help reduce muscle soreness and keep the muscles flexible.
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Suppose a 51-N sled is resting on packed snow. The coefficient of kinetic friction is 0.13. If a person weighing 680 N sits on the sled, what force is needed to pull the sled across the snow at constant speed
95 N much force is needed to pull the sledge at a constant speed.
Explain force.A force in physics is an effect that has the power to alter what an object moves. Every object with mass might travel faster or at a different rate as a result of a force. A push or a pull made natural sense when describing force. Since forces are vector quantities, they own both size and direction.
The sled is being subjected to the following horizontal forces:
F = applied force.
Fr = friction force.
And the following vertical forces:
N = normal force.
W =combined weight of the person and the sled
The second law of Newton states:
F = m * a
where the object's mass is "m" and its acceleration is "a"
So, in the horizontal direction:
F - Fr = m *a
Determining the force, F, required to keep the sled moving at a constant pace (acceleration = 0). Then,
F - Fr = 0
F = Fr
The applied force must have a magnitude equal to or greater than the friction force.
The friction force is calculated as follows:
Fr = μ · N
Where μ is coefficient and N represent the normal force, respectively.
Let's use Newton's second law with in vertical direction to determine the normal force:
F = N - W
= m · a
Keep in mind that the sledge is not accelerated vertically so that a = 0:
N - W = 0
N = W
The mass is the total of a weight of a person plus the mass of the sled, and the force is equivalent to the weight:
W = 51 N + 680 N = 731 N
Then:
N = 731 N
Fr = 0.13 · 731 N
Fr = N
Then
F = 95.03 N
As a result, 95 N of force is necessary to pull a sled at a steady pace.
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A lever is used to lift an object with a weight of 60 Newtons. The effort force is 15 meters from the fulcrum, while the load force is 5
meters from the fulcrum. What is the mechanical advantage? (1 point)
0 3
O 12
O 75
0 4
120 foot pounds of anticlockwise torque are generated around the pivot point by the 60 pound load resting 2 feet from the fulcrum.
How can the load force of a lever be determined?The force of the effort (Fe) multiplied by the effort's distance from the fulcrum (de) in a class one lever equals the force of the resistance (Fr) multiplied by the resistance's distance from the fulcrum (dr).
What mathematical equation can be used to determine a lever's mechanical advantage?(b) The optimal mechanical advantage of a lever is equal to the effort arm's length divided by the resistance arm's length. The IMA is typically calculated as the effort force, Fe, divided by the resistance force, Fr.
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Answer:
3
Explanation:
I took the test
is often caused by improper loading, not only in terms of the load impedance itself, but in terms of how much capacitive or inductive reactance is part of that impedance.
Resistance and impedance (in AC circuits) are one such pair of synonyms (DC circuits). Technically speaking, they both stand in the way of current flow, but factor ability of impedance also takes resistance into account.
Obviously all, reactance and inductance are also included in this (capacitors).
Impedance, which results from the interaction of reactance and ohmic resistance, is the active resistance to AC of an electric circuit or component. We also describe it as any restriction of an electric current's ability to move energy when voltage is applied.
The more precise meaning is the overall resistance a circuit of electricity provides to an AC current flowing at a single frequency. In conclusion, we measure reactance and resistance in ohms, and we denote this measurement with the sign Z.
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The solar system is 25,000 light years from the center of our Milky Way galaxy. One light year is the distance light travels in one year at a speed of 3.0×108m/s. Astronomers have determined that the solar system is orbiting the center of the galaxy at a speed of 230 km/s.
The approximate mass of the galactic center was calculated to be 1.88*1041 kg.
Assume that the sun is a typical star with a typical mass. If galactic matter is made up of stars, approximately how many stars are in the center of the galaxy?
Note : Astronomers have spent many years trying to determine how many stars there are in the Milky Way. The number of stars seems to be only about 10% of what you'll find in part d. In other words, about 90% of the mass of the galaxy appears to be in some form other than stars. This is called the dark matter of the universe. No one knows what the dark matter is. This is one of the outstanding scientific questions of our day.
The stars in the center of the Milky Way galaxy is approximately 94.5 billion stars. The result is obtained by dividing the mass of the galactic center by the mass of the Sun.
How to estimate the number of stars in a galaxy?The number of stars in a galaxy can be estimated by dividing the mass of galactic center by the mass of a typical star.
In the Milky Way,
Radius of the solar system, r = 25,000 light years.1 light year, c = 3 × 10⁸ m/s.Speed of the solar system, v = 230 km/s.Approximate mass of the galactic center, M = 1.88 × 10⁴¹ kg.Suppose that the Sun is a typical star with a typical mass and the galactic matter is made up of stars. Find the approximate number of stars in the center of the galaxy!
From the scientific data, the mass of the Sun is 1.99 × 10³⁰ kg.
The number of stars is approximately
N = Mass of the galactic center / Mass of the Sun
N = 1.88 × 10⁴¹ kg / 1.99 × 10³⁰ kg
N = 0.945 × 10¹¹
N = 94.5 × 10⁹
N = 94.5 billion stars
In the center of Milky Way, the number of stars is around 94.5 billion stars.
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the first artificial satellite to orbit the earth was sputnik 1, launched october 4, 1957. the mass of sputnik 1 was 83.5 kg, and its distances from the center of the earth at apogee and perigee were 7300 km and 6610 km, respectively. find the difference in gravitational potential energy for sputnik 1 as it moved from apogee to perigee
The difference in gravitational potential energy for sputnik 1 as it moved from apogee to perigee is 193 kJ.
The gravitational potential energy of an object in orbit around the Earth can be calculated using the equation:
U = -GMm/r
where U is the gravitational potential energy, G is the gravitational constant, M is the mass of the Earth, m is the mass of the object.
The difference in gravitational potential energy as the satellite moves from apogee to perigee can be found by calculating the potential energy at each point and subtracting the two values:
U(apogee) = -(6.67 x 10^-11 N*(m^2)/(kg^2)) * (5.972 x 10^24 kg) * (83.5 kg) / (7300 x 10^3 m)
U(perigee) = -(6.67 x 10^-11 N*(m^2)/(kg^2)) * (5.972 x 10^24 kg) * (83.5 kg) / (6610 x 10^3 m)
U(apogee) = -1.865 x 10^5 J
U(perigee) = -2.058 x 10^5 J
The difference in gravitational potential energy is:
= U(perigee) - U(apogee)
= -2.058 x 10^5 J - (-1.865 x 10^5 J)
= 193 x 10^3 J
So, the difference in gravitational potential energy for Sputnik 1 as it moved from apogee to perigee is 193 kJ.
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Justin throws a 10. 0-g ball straight
down from a height of 2. 0 m. The ball
strikes the floor at a speed of 7. 5m/s.
What was the initial speed of the ball?
The ball's initial speed as it descended straight down from a height was 17.5 miles per hour.
The starting velocity is the speed at time t = 0. (u). It is the speed at which motion first becomes apparent. Four equations can be used to calculate initial velocity: (1) If time, acceleration, and end velocity are known, the initial velocity can be calculated using the formula u = v - at.
Calculation:We can simply use the following equation of motion to solve this:v² - u² = 2 × a × s
here, v = final velocity = 7.5 m/s
a = 9.81 m/s^2
s = 2.0 m
Solving for u (initial velocity) we get:
(7.5)² - u² = 2 × 9.8 × 2
56.25 - u² = 39.2
u² = 56.25 - 39.2
u² = 17.05
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The more massive that an object is, the ______ (more, less) that the object will be attracted to Earth.
More large items will attract each other as the gravitational force between them grows because gravitational force is directly proportional to the mass of both interacting objects.
What transpires when an item has a higher mass?An object's inertia increases with mass, hence it requires more force to alter its state of motion. The mass of an item, which is roughly equal to the quantity of material inside it, determines how much inertia it has.
Why does gravity increase when an item becomes bigger?Theoretically, anything with mass generates small particles known as gravitons, which is why mass and gravity are related. The gravitational attraction is caused by these gravitons. Gravitons increase with mass.
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A 2kg block i attached to a pring for which k=200n/m it i held at an extenion of 5cm and then releaed at t=0. A, Find the diplacement a a function of time?
B,the velocity when X= A/2
C, the acceleration when X=A/2
D, the total energy when X=A/2
Accurate choice is (A) In this case, m=2kg,k=50Nm 1, and A=5cm=0.05m. Block SHM executes. its angular frequency is 1. Because the time is measured from the equilibrium position, its displacement at any time t may be calculated using the formula x=Asint=0.05sin5tm.
Oscillation and vibration: what are they?Back and forth motion is described by the terms oscillation and vibration. Oscillation is typically used for slower motion, while "vibration" is typically used for action that is fairly quick. However, they have similar traits, hence in this book, the two terms will be used interchangeably.
What is motion-induced oscillation?Periodic or oscillatory motion is defined as a motion that repeats itself. Due to a restoring force, an object in such motion oscillates about an equilibrium position.
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21 An antiaircraft shell is fired vertically upward with a muzzle velocity of 1000 ms-¹. Calculate the maximum height it can attain, the time taken to reach this height, the instantaneous velocities at the ends of 20 sec and 50 sec. d. When will its height be 37.5 km? Interprete your result. Neglect air resistance. a. b. C.
On a cold winter night, a story comes on the news at stations across the northern part of Florida recommending that residents turn on their outside faucets to allow a slow drip of water. Why would that be recommended?
a-It keeps the ground from drying out.
b-It protects the water from shrinking in the pipes.
c-It stops the water from getting too salty.
d-It prevents the water from bursting the pipes.
On a cold winter night, a story comes on the news at stations across the northern part of Florida recommending that residents turn on their outside faucets to allow a slow drip of water. It would that be recommended because it prevents the water from bursting the pipes.
Option D is correct.
How do we prevent freezing pipes during freezing temperatures?During freezing temperatures, one of the things that you can do in order to prevent water from freezing and bursting the pipes is to run your faucet because running water does not freeze as easily as standing water, so letting it drip overnight will help.
The body faces the effects when subjected to freezing temperatures as it the body begins to lose heat faster than it can be produced. Prolonged exposure to cold will eventually use up your body's stored energy. The result is hypothermia, or abnormally low body temperature.
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How do you calculate sound intensity level?
Sound intensity level (SIL) is measured in decibels (dB).
What is sound?
Sound is a type of energy created by the vibration of particles in a medium, such as air, that can be heard when it reaches a person or animal's ear. Sound can travel through solids, liquids, and gases, and can have different pitches and volumes.
Sound intensity level is defined as the ratio of the sound pressure to a reference pressure level. It is calculated using the following equation: SIL (dB) = 10 log10 (I/I_0), where I is the sound intensity and I_0 is the reference sound intensity equal to 10^−12 W/m^2.
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if energy of 10 watts is transferred into a conatiner of helium, how long does it take to vaporize 1 kg of liquid helium
Consider how much energy is required to melt one kilogram of ice at zero degrees to produce one kilogram of water at zero degrees.
The energy required to melt one kilogram of ice is determined by Q = mLf = (1.0 kg)(334 kJ/kg) = 334 kJ using the equation for a change in temperature and the value for water from Table 1. Water is converted from a liquid to a gas by the process of evaporation, which requires a significant amount of energy. The amount of energy needed to cause the state change is known as the latent heat of vaporization. At 1 atmosphere of pressure, the latent heat of vaporization is 539 calories per gram of water.
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