wacky wizards offers beginner and advanced magic classes. The beginner class costs 6 more than half the cost of the advanced class.Last week they taught 7 beginner classes and 11 advanced classes and earned $390. Write a system that represents the cost of the beginner class, b and the advanced class, a. HELP!!!!!

A right triangle's hypotenuse is its longest side, its "opposite" side is the one that faces a certain angle, and its "adjacent" side is the one that faces the angle in question.

In a right triangle, the hypotenuse is the longest side, the "opposite" side is the one that faces a particular angle, and the "adjacent" side is the one that faces that angle.

Step 1: Simplify both sides of the equation.

[tex]$$4 g-6=8$$\\Step 2: Add 6 to both sides.$$\begin{aligned}& 4 g-6+6=8+6 \\& 4 g=14\end{aligned}$\\$Step 3: Divide both sides by 4 .$$\begin{aligned}& \frac{4 g}{4}=\frac{14}{4} \\& g=\frac{7}{2}\end{aligned}$$[/tex]

[tex]$g=3 \frac{1}{2}$[/tex]

Therefore, the correct answer is option a)[tex]$g=\frac{7}{2}$[/tex].

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No solution is a fraction that cannot be represented as a fraction of integers.

A fraction is a division of two numbers, and no solution occurs when the divisor is 0, because division by 0 is undefined.

For example, consider the fraction 2/0. This is a fraction with no solution because division by 0 is undefined. To explain this further, let's look at the formula for division: a/b = c. In this formula, a is the dividend, b is the divisor, and c is the quotient. In the fraction 2/0, the dividend is 2 and the divisor is 0, so when we try to calculate the quotient, we get c = 2/0. Since division by 0 is undefined, the result is no solution.

To summarize, no solution occurs when a fraction's divisor is 0 because division by 0 is undefined. This means that no fraction can be represented as a fraction of integers when the divisor is 0 because there is no solution.

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The 3 parts of a quadratic equation are standard form, factored form and vertex form.

A quadratic equation is a polynomial equation of degree two in one variable of type f(x) = ax² + bx + c where a, b, c, ∈ R and a ≠ 0.

There are three forms of quadratic equations

Standard form of quadratic equation y = ax² + bx + c

factored form of quadratic equation y = a(x − r₁)(x − r₂​)

Vertex form of quadratic equation y = a(x − h)² + k

Each of the above quadratic forms looks unique, allowing the different problems to be more easily solved in one form than another.

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Answer:

56a+40b

Step-by-step explanation:

43a plus 13a is 56a, -12b + 52b is 40b, together it's 56a+40b

Answer:

James used 5 yards of fabric to make 7 identical bags, so he used 5/7 yards of fabric per bag.

Step-by-step explanation:

The correct relation which shows the function is,

⇒ (-6, 2), (-2, 3), (2, 7), (6, 2)

Option B is true.

A relation between a set of inputs having one output each is called a function.

Now, We know that;

Function is a relation between a set of inputs having one output each.

So, By given options;

A. (-2, -2), (-6, -5), (2, 8), (2, 2)

Here, Two value of outputs 8, 2 have same input 2.

So, This is not a function.

B. (-6, 2), (-2, 3), (2, 7), (6, 2)

Here, A set of inputs having one output each.

So, This is function.

C. (6, -10), (-6, 7), (6, 6), (-6, 12)

Here, Two value of outputs - 10, 6 have same input 6.

So, This is not a function.

D. (-6, 0), (-2, 5), (-6, -3), (2, 9)

Here, Two value of outputs 0, -3 have same input -6.

So, This is not a function.

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The builder needs building sand weighing 6.3 * 10⁶ g and contains 9 * 10¹⁰ grains

An equation is used to show the relationship between numbers and variables.

A brick layer needs 6300 kg of building sand

The conversion from kg to g is:

1 kg = 1000 g

a) 6300 kg in grams is:

6300 kg = 6300 kg * 1000 g per 1 kg = 6,300,000 g = 6.3 * 10⁶ g

b) 1 grain = 7 * 10⁻⁵ g

6.3 * 10⁶ g = 6.3 * 10⁶ g * 1 grain / (7 * 10⁻⁵ g) = 9 * 10¹⁰ grain

The builder needs 6.3 * 10⁶ g of building sand

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The diameter of the circle C/13

The formula provides the circumference of a circle.

The circumference of any shape in mathematics designates the path or limit that surrounds the shape. In other words, the circumference, sometimes referred to as the perimeter, aids in figuring out how long the contour of a shape is. The size and perimeter of a circle are, as we all know, its two most important properties.

C = pi * d, where d is the diameter and c is the circumference.

C = pi * 13 gives the diameter as 13.

Subtract 13 from each side, C/13 = d.

Dimensions are C/13.

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The smallest base-10 positive integer greater than 5 that is a palindrome when written in both base 2 and 4 is 11.

To compute this, first convert 5 to binary and base-4:

5 in binary: 101

5 in base-4: 11

Since 11 is the same in both bases, the next number that would be a palindrome in both bases is 11.

To find the base 10 number of this palindrome, we convert 11 from binary and base-4 to base 10:

11 in binary: 1011

11 in base-4: 111

Therefore, the smallest base-10 positive integer greater than 5 that is a palindrome when written in both base 2 and 4 is 11.

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Leo's balance after 8 months is $1725.

A geometric sequence is a sequence of numbers in which the ratio between consecutive terms is constant.

Example:

2, 4, 8, 16 is a geometric sequence.

We have,

1500, 1530, and 1560 is a geometric sequence.

First term.

a = 1500

Common ratio.

r = 1.02

The nth term of a geometric sequence is a[tex]r^{n-1}[/tex].

Now,

For n = 8,

8th term.

= 1500 x [tex]1.02^7[/tex]

= 1500 x 1.15

= 1725

Thus,

The balance after 8 months is $1725.

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The annual income of a certain household that has a z-score of 1.5, is 80,000.

The relationship between a value and a group of values' mean is described statistically by the Z-score. Standard deviations from the mean serve as the unit of measurement for Z-score. The score for a data point is equal to the mean score if the Z-score is 0. A value that deviates by one standard deviation from the mean is indicated by a Z-score of 1.0.

Z-scores can either be positive or negative, with a positive value indicating that the score is above the mean and a negative value indicating that the score is below the mean. Z-scores are measurements of an instrument's variability used in investing and trading that traders can use to estimate volatility.

Let the annual income be x.

x has μ = 50000, σ = 20000

We know that for given x, z = (x−μ)/σ

Given that z - score = 1.5

Substituting the values we get

⇒ 1.5 = (x−50000)/20000

​⇒ 1.5 × 20000 = x−50000

​⇒ 30000 = x − 50000

⇒ x = 30000 + 50000

⇒ x = 80,000

Thus, The annual income of a certain household that has a z-score of 1.5, is 80,000.

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One final test that lasts three hours is given in addition to four-hour exams that are given by the teacher. The student's last grade is an 83.29.

The final exam result was an 80, which counts as 31 hour examinations if the exam scores range from 60 to 81, which totals to 97,87. In order to accomplish this, we must multiply three eighty by 62, 81, 97, and 87, which equals a 31-hour exam.

The whole time for the final exam, which is 31 hours, will be added up and divided by 7, giving us an average final grade for the student of 81.To reduce the number's number of significant digits in order to approximate it. Rounding down from 15.4 to 15.5, from 15.51 to 15.5 or 16, from 0.499 to 0, and from 970,000 to 1 million.

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Answer:

Step-by-step explanation:

Let angle A = w - 15 degree , angle B = -w + 1 degree and angle X = w + 34 degrees then:

We know that the exterior angle of a triangle is equal to the sum of two interior opposite angles.

therefore, w + 34 = w - 15 + (-w +1)

w + 34 = w - 15 - w + 1

w = -15 - 34 = - 49 degrees

since angle cannot be negative

therefore w = 49 degrees

The degree of the polynomial [tex]5x^{3} + 4x^{2} + 7x[/tex]  is 3 , that means it is a third degree polynomial called as cubic polynomial  .

What is Degree Of Polynomial ?

The degree of the polynomial is defined as  the highest power of the polynomial expression. But, if the polynomial has multiple variables, the degree of polynomial can be found by adding the powers of the different variables  in the polynomial expression.

For Example : the degree of polynomial ⇒  [tex]9x^{2} + 7x + 2[/tex] is  2 .

The polynomial is given as : [tex]5x^{3} + 4x^{2} + 7x[/tex] , we have to find the degree ,

So , we can see that the the term having the highest power of the given polynomial is [tex]5x^{3}[/tex] , and the degree is 3 .

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Step-by-step explanation:

what do you not understand ? please let me know where you need more instructions.

the basic rule : every term of one side has to be multiplied with every term of the other side, and the results are added (by using the correct signs of the products).

remember :

+ × + = +

- × - = +

+ × - = -

- × + = -

(3x - 3)(5x - 4) = 3x × 5x + 3x × -4 + -3 × 5x + -3 × -4 =

= 15x² - 12x - 15x + 12 = 15x² - 27x + 12

Answer:

v=πr²h

divide both sides by πh

v/πh=r²

r²=v/πh

square root both sides

r=√v/√πh

I hope this helps

To rewrite the inequalities in slope-intercept form, the student would first need to solve for y.

2x + 3y > 6 can be rewritten as 3y > -2x + 6 and then solving for y by dividing both sides by 3, the student can have y > (-2/3)x + 2

x-4y > 8 can be rewritten as -4y > -x + 8, and then solving for y by dividing both sides by -4 , the student can have y < (1/4)x - 2

To graph the inequalities, the student would plot the y-intercepts of the equations, which are (0,2) and (0,-2) and then use the slope to find a second point to plot, and then graph the line. Then, based on the inequality symbol the student should shade the appropriate side of the line. If the inequality is greater than > or less than < then they shade one side, otherwise if the inequality is less than or equal to >= or greater than or equal to <= they shade both sides.

It's also important to remember that the slope intercept form is y=mx+b where m is the slope, and b is the y-intercept, if the student already has the equation in this form, they only need to plot the y-intercept point and use the slope to get a second point.

To solve this equation for y, you can follow these steps:

First, get all the terms with y on one side of the equation and all the other terms on the other side. To do this, you can add 2/5 to both sides to get rid of the 2/5 on the left side:

0.5y - 2 2/5 + 2/5 = 1/2y + 2.4 + 2/5

Simplify the left side of the equation:

0.5y - 2 + 2/5 = 1/2y + 2.4 + 2/5

0.5y - 2 + 2/5 + 2/5 = 1/2y + 2.4 + 2/5 + 2/5

0.5y - 2 + 4/5 = 1/2y + 2.4 + 4/5

Combine like terms on each side:

(0.5y + 4/5) - 2 = (1/2y + 2.4) + 4/5

Simplify:

0.5y + 4/5 - 2 = 1/2y + 2.4 + 4/5

0.5y - 2 + 4/5 = 1/2y + 2.4 + 4/5

Combine like terms on each side:

(0.5y + 4/5) = (1/2y + 2.4) + 4/5

Simplify:

0.5y + 4/5 = 1/2y + 2.4 + 4/5

Combine like terms on each side:

0.5y = 1/2y + 2.4

Subtract 1/2y from both sides:

0.5y - 1/2y = 1/2y - 1/2y + 2.4

0 = 2.4

Solve for y:

0 = 2.4

This equation has no solution, so there is no value of y that satisfies the given equation.

Answer:

Step-by-step explanation:nosoulution

The next operation that should be done when evaluating this expression 9-12+-2+3(-3) is A. 3(-3)=-9

An expression is simply used to show the relationship between the variables that are provided or the data given regarding an information. In this case, it is vital to note that they have at least two terms which have to be related by through an operator. Some of the mathematical operations that are illustrated in this case include addition, subtraction, etc.

In this case, it should be noted that the expression given is written as 9-12+-2+3(-3). In PEDMAS, the first operation is parentheses. Therefore, the number on parentheses will be solved first.

In this case, the number in parentheses will be 3(-3). Therefore, the correct option is A.

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:)

ggggggggggggrssdfffffffffffffffffffffffffffffffffrsssssssssshggh

Answer:

X of M is 6, Y of M is 4, Pair is (6,4)

Step-by-step explanation:

M = 6

M = 4

M (6,4)

The domain and scope of the identity function are the same. Equation for the identity function is  f(x) = x, or y = x.

An statement, rule, or law in mathematics that specifies the connection between an independent variable and a dependent variable (the dependent variable). A relationship between a group of inputs and one output each is referred to as a function. In plain English, a function is an association between inputs in which each input is connected to precisely one output. Y=X2 is an illustration of this. You only receive one output for y if you enter anything for x. The fact that x is the input value leads us to argue that y is a function of x.

identity function are the same.

Equation for the identity function is

f(x) = x, or y = x.

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On solving the provided question, we can say that by unitary method Irene spend on gas =  $ 33.82

The unit technique is an approach to problem-solving that involves first determining the value of a single unit, then multiplying that value to determine the required value. The unit method, to put it simply, is used to extract a single unit value from a supplied multiple. For instance, 40 pens would cost 400 rupees, or the price of one pen. The process for doing this may be standardized. a single country. anything that has an identity element. (mathematics, algebra) (Linear algebra, mathematical analysis, mathematics of matrices or operators) Its adjoint and reciprocal are equivalent.

by unitary method

Irene must pay back the money she used for gas.

Irene filled up her tank with gas for $33.82.

One gallon of gasoline costs $3.80.

There are 6.1 gallons of the petrol Irene purchased in the tank.

amount required = 15 -6.1 = 8.9 gallons

1 gallon = 3.8 dollars

8.9 gallons = $ 33.82

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Answer:

=3/11 of (1×3+5/9)÷9/15

=3/11 of (8/9)÷9/15

=3/11 of 8/9÷9/15

=8/33÷9/15

=8/33×15/9

=40/99

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The graph of the function g(x) is added as an attachment

From the question, we have the following parameters that can be used in our computation:

f(x) equals log2 x

Express the equation properly

So, we have

f(x) = log₂(x)

Also, we have

g(x) = -log₂(x - 3)

The transformation from f(x) to g(x) is that:

This means that

g(x) = -f(x - 3)

So, we apply the above transformations on the graph of f(x) to form g(x)

See attachment for graph of g(x)

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The solution of the function f(x) = 2(x - 3)² is at x = 3 as shown in the graph.

An equation is used to show the relationship between numbers and variables.

Polynomial can be classified based on degree as linear, quadratic, cubic.

Given the function:

f(x) = 2(x - 3)²

The graph of f(x) is plotted. The solution of the graph can be gotten from its x intercept. Hence the solution is at x = 3

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Answer:

Step-by-step explanation:Select any two random points on the graph of the line (preferably with integer coordinates).

Label them as A and B (in any order).

Calculate the "rise" from A to B. While going vertically from A to B, if we have to go

"up", then the rise is positive;

"down", then the rise is negative.

Calculate the "run" from A to B. While going horizontally from A to B, if we have to go

"right", then the run is positive;

"left", then the run is negative.

Now, use the formula: slope = rise/run.

The drama "The Importance of Being Earnest" contains many inconsistencies. Algernon's criticism of the lower class for not providing a better moral example for the upper class is paradoxical because the higher class must set the standard because it is the ruling class.

A remark that logically contradicts itself or runs counter to one's expectations is referred to as a paradox.

It is a claim that, despite appearing to be supported by genuine premises and sound reasoning, leads to a logically untenable or self-contradictory conclusion.

One of the most straightforward yet well-known paradoxes is the liar paradox, sometimes known as the liar's paradox statement.

A paradox exists when someone says, "This statement is a lie" or "This statement is false," because if it were true, the statement would be speaking the truth.

In "The Importance of Being Earnest", the play has multiple contradictions.

Because the upper class is required to lead because it is the governing class, Algernon's dissatisfaction with the lower class for not setting a better moral example for the upper class is paradoxical.

Therefore, the drama "The Importance of Being Earnest" contains many inconsistencies. Algernon's criticism of the lower class for not providing a better moral example for the upper class is paradoxical because the higher class must set the standard because it is the ruling class.

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Answer:

34 + 23 = 57

57 - 5 = 52

Therefore, she has 52 toy horses.

The values of p that satisfy the inequality for all[tex]$q > 0$[/tex] are

[tex]$p > \frac{3+\sqrt{21}}{2}$[/tex]and [tex]$p < -\frac{3+\sqrt{21}}{2}$[/tex]

Given:[tex]$$\frac{3(pq^2 p^2q 3q^2 3pq)}{p q} > 2p^2q^2$$[/tex]

Step 1: Multiply both sides by [tex]$\frac{pq}{3}$[/tex] to get: [tex]$$pq^3 p^2q 3q^2 3pq > 2p^2q^3$$[/tex]

Step 2: Simplify the left side to get: [tex]$$3p^2q^3+3pq^3+3q^2 > 2p^2q^3$$[/tex]

Step 3: Divide both sides by [tex]$q^2$[/tex] to get: [tex]$$3p^2q+3pq+3 > 2p^2$$[/tex]

Step 4: This is a quadratic inequality in[tex]$p$[/tex]with solution[tex]$p > \frac{3+\sqrt{21}}{2}$[/tex] and [tex]$p < -\frac{3+\sqrt{21}}{2}$[/tex]. Therefore, the values of p that satisfy the inequality for all  [tex]$p > \frac{3+\sqrt{21}}{2}$[/tex] and [tex]$p < -\frac{3+\sqrt{21}}{2}$[/tex]

the given inequality can be simplified to a quadratic inequality in p by multiplying both sides by[tex]$\frac{pq}{3}$[/tex], simplifying the left side, and dividing both sides by[tex]$q^2$[/tex] The solution of the quadratic inequality is

[tex]$p > \frac{3+\sqrt{21}}{2}$[/tex] and

[tex]$p < -\frac{3+\sqrt{21}}{2}$[/tex]. Therefore, the values of p that satisfy the inequality for all [tex]$q > 0$[/tex] are

[tex]$p > \frac{3+\sqrt{21}}{2}$[/tex]and

[tex]$p < -\frac{3+\sqrt{21}}{2}$[/tex], which means that any value of p that is greater than[tex]$\frac{3+\sqrt{21}}{2}$[/tex] or less than

[tex]$-\frac{3+\sqrt{21}}{2}$[/tex]will satisfy the inequality for all [tex]$q > 0$[/tex]

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Step-by-step explanation:

Let A be the sum from 100 to 300

so the sum of 97 to 298 =

A - (299+300) + 97 +98

= A - 403