Use this table of values for the rate of rainfall over time.
Rate of Rainfall (mm per hour) Time 6:00 am 20 6.15 am 28 630 am 3.0 645 am 35 7:00 am 3.8 7:15 am 42 7:30 am 4.8 7:45 am 5.6 8:00 am 4.0 8.15 am 3.3 8:30 am 1.8 8:45 am 0.4 9:00 am 1.2.
An approximation of the total amount of rainfall that falls between 6:00 a.m. and 9:00 a.m. using a midpoint sum with 6 equal subintervals is
a. 9.3 mm.
b. 9.6 mm.

Answers

Answer 1

Solution :

Here the subintervals of equal length will be :

[tex][6:00, 6:30], [6:30, 7:00], [7:00, 7:30], [7:30, 8:00], [8:00, 8:30], [8:30, 9:00][/tex]

So thee mid points are

[tex]x_1 = 6:15, \ x_2=6:45, \ x_3=7:15, \ x_4=7:45, \ x_5, 8:15, \ x_6 = 8:45[/tex]

The length of each sub-interval is = [tex]\frac{9-6}{6} = \frac{3}{6} = 0.5[/tex]

So, total amount of rainfall will be :

[tex]$=0.5 \sum^6_{i=1} f(x_i)$[/tex]

[tex]$=0.5\left( f(x_1)+f(x_2)+....+ f(x_6)\right)$[/tex]

= 0.5 (2.8 + 3.5 + 4.2 + 5.6 + 3.3 + 0.4)

= 0.5 (19.8)

= 9.9

Answer 2

The total amount of rainfall that falls between 6:00 a.m. and 9:00 a.m. using a midpoint sum with 6 equal subintervals is 9.9.

Given that,

The rate of rainfall (mm per hour) over time.

Rate of rainfall;

6;00 6;15 6;30 6;45 7;00 7;15 7;30 7;45 8;00 8;15 8;30 8;45 9;00

Time  

2.0  2.8   3.0   3.5    3.8    4.2   4.8   5.6   4.0   3.3   1.8  0.4   1.2  

We have to determine,

0.4 9:00 am 1.2.

The total amount of rainfall that falls between 6:00 a.m. and 9:00 a.m. using a midpoint sum with 6 equal subintervals is?

According to the question,

Rate of rainfall;

6;00 6;15 6;30 6;45 7;00 7;15 7;30 7;45 8;00 8;15 8;30 8;45 9;00

Time  

2.0  2.8   3.0   3.5    3.8    4.2   4.8   5.6   4.0   3.3   1.8  0.4   1.2  

Here, the midpoints sum with 6 equal subintervals are,

[tex]\rm x_1 = 6;15, \ x _2 = 6;45, \ x_3 = 7;15, \ x_4 = 7;45, x_5 = 8;15 , \ x_6 = 8;45[/tex]

Then, the length of each subinterval is,

[tex]= \dfrac{9-6}{6}\\\\= \dfrac{3}{6}\\\\= \dfrac{1}{2}[/tex]

The total amount of rainfall that falls between 6;00 to 9;00 am using the midpoint subinterval is,

[tex]\rm = \dfrac{1}{2} \sum^{6}_{i=0} f(x_i)\\\\= \dfrac{1}{2} \sum^{6}_{i=0} f(x_1)+ f(x_2) + f(x_3) + f(x_4) +f(x_5)+f(x_6)\\\\= \dfrac{1}{2} (2.8+ 3.5+4.2+ 5.6+3.3+0.4}\\\\= \dfrac{1}{2} \times 19.8\\\\= 9.9[/tex]

Hence, The total amount of rainfall that falls between 6:00 a.m. and 9:00 a.m. using a midpoint sum with 6 equal subintervals is 9.9.

For more details refer to the link given below.

https://brainly.com/question/795909


Related Questions

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Answer:

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Step-by-step explanation:

Equation of a circle with centre (a, b) and radius ,r :

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Since the circle passes through (-1, -1) , the radius is the distance between the centre and the point.

[tex]distance, r = \sqrt{(-1 -(-1))^2 +(-4 -(-1))^2 }[/tex]

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Substitute the values in (1) :

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Answer:

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To find the number midway between 3/2 and 4/2, add them up and divide by 2

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A) -3+4 = -1
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Jeffery has two pets that he feeds daily. His dog eats 3/4 cup of food. His cat, on the other hand, eats 1/2 of what his dog eats. How much food does his cat eat?​

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Answer:

3/8 cup

Step-by-step explanation:

Dog : 3/4 cup

Cat: 1/2 (Dog) = 1/2 (3/4 cup) = 3/8 cup

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Maya read 40 pages in 60 minutes

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What is the question exactly?


Additional Activities
Directions: Use a non-standard unit of the same material and
size. Which unit will give the greater number for the volume of the
container using ping-pong balls and monggo seeds? Visualize the
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Answer:Ping Pong Balls

Step-by-step explanation:

what Will You nota miss about remote learning​

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Answer:

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Answer:

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Answer:

answer a and d

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Step-by-step explanation:

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Step-by-step explanation:

Answer:

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Answers

Answer:

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Answers

Answer:

17t+6q-6

Step-by-step explanation:

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17t+6q-6

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Step-by-step explanation:

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Answers

Answer:

158 m^2

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Answer:

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Answers

Answer:

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Answers

Answer:

x = y - 6

Step-by-step explanation:

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12. The heights of 53 students at Park School are shown in the histogram below.

Height of Students

18

Number of Students

NA ON

44 46 48 50 52 54 56 58 60

Height (inches)

Based on the data in the histogram, which statement is true?

A There are 12 students between 46 and 50 inches in height.

B. Exactly 18% of the students are between 52 and 54 inches in height.

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Fewer students are between 44 and 52 inches than between 52 and 60 inches in height.

D

Answers

Answer:

Fewer students are between 44 and 52 inches than between 52 and 60 inches in height.

Step-by-step explanation:

Given

See attachment for histogram

Required

Select the true statement

Option A: Class 46-50 = 12 students

From the histogram, we have:'

[tex]Class\ 46 - 48 = 8; Class\ 48 - 50 = 3[/tex]

So:

[tex]Class\ 46 - 48 = Class\ 46 - 48 + Class\ 48 - 50[/tex]

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(a) is false

Option B: %Class 52-54 = 18%

From the histogram, we have:'

[tex]Class\ 52-54 = 18[/tex]

and

[tex]Total = 53[/tex]

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[tex]\% Class\ 52-54 = \frac{Class\ 52-54}{Total}[/tex]

[tex]\% Class\ 52-54 = \frac{18}{53}[/tex]

[tex]\% Class\ 52-54 = 0.3396[/tex]

Express as percentage:

[tex]\% Class\ 52-54 = 33.96\%[/tex]

(b) is false

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[tex]Class\ 54-60 = 4 + 4+3[/tex]

[tex]Class\ 54-60 = 11[/tex]

In (a), we have:

[tex]Class\ 46 - 48 = 11[/tex]

By comparison:

[tex]Class\ 54-60 =Class\ 46 - 48 = 11[/tex]

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Option D: Class 44-52 < Class 52 - 60 students

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[tex]Class\ 44-52 =Class\ 44-56 + Class\ 46-48 + Class\ 48-50 +Class\ 50-52[/tex]

[tex]Class\ 44-52 = 4+8+3+9[/tex]

[tex]Class\ 44-52 = 24[/tex]

[tex]Class\ 52-60 =Class\ 52 - 54 + Class\ 54-56 + Class\ 56-58 + Class\ 58-60[/tex]

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[tex]Class\ 44 - 55 < Class\ 52 - 60[/tex]

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d. 50
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Answers

Answer:

Below

Step-by-step explanation:

The factors of 10 are 1, 2, 5, 10.

The factors of 25 are 1, 5, and 25.

Factors of 36 are 1, 2, 3, 4, 6, 9, 12, 18, and 36

Factors of 50: 1, 2, 5, 10, 25, 50.

Factors of 100: 1, 2, 4, 5, 10, 20, 25, 50, and 100.

12.) The FAA has to periodically revise their rules regarding weight estimates that vary by
season. Airlines currently use an estimate for the weight of an adult male passenger of 190 lbs.
in the summer that assumes
he carries sixteen pounds of baggage and has five pounds of
clothing. According to your textbook, assume that men (not clothed nor carrying baggage) have
weights that are normally distributed with a mean of 188.6 lbs. and a standard deviation of 38.9
lbs.

a.) If one adult male is randomly selected and is assumed to be also carrying 21 lbs. due to
clothing and baggage, find the probability that the total weight is greater than 190 lbs.

b.) What total weight would separate the lower 20% of men carrying 21 lbs. of clothing and
baggage from the top 80%?

Answers

Answer:

a) 0.4856 = 48.56% probability that the total weight is greater than 190 lbs.

b) A total weight of 155.9 lbs.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 188.6 lbs. and a standard deviation of 38.9 lbs.

This means that [tex]\mu = 188.6, \sigma = 38.9[/etx]

21 lbs of baggage are taken into consideration in this estimate.

a.) If one adult male is randomly selected and is assumed to be also carrying 21 lbs. due to clothing and baggage, find the probability that the total weight is greater than 190 lbs.

This is 1 subtracted by the the p-value of Z = 190. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{190 - 188.6}{38.9}[/tex]

[tex]Z = 0.036[/tex]

[tex]Z = 0.036[/tex] has a p-value of 0.5144.

1 - 0.5144 = 0.4856.

0.4856 = 48.56% probability that the total weight is greater than 190 lbs.

b.) What total weight would separate the lower 20% of men carrying 21 lbs. of clothing and baggage from the top 80%?

This is the 20th percentile, which is X when Z has a p-value of 0.2, so X when Z = -0.84.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]-0.84 = \frac{X - 188.6}{38.9}[/tex]

[tex]X - 188.6 = -0.84*38.9[/tex]

[tex]X = 155.9[/tex]

A total weight of 155.9 lbs.

What is the least common multiple (LQM) of 8 and 12?

Answers

Answer:

24

Step-by-step explanation:

The LCM of 8 and 12 is 24. Find least common multiple (LCM) of: 16 & 24 4 & 6 24 & 36 40 & 60 56 & 84 16 & 12 8 & 24 24 & 12 8 & 36 40 & 12 8 & 60 56 & 12 8 & 84

HELPPPPPP don't troll ima report

Answers

Answer:

The x-coordinates for which the gradient of the curve is 5 is at x = -1/2 and x = 1/2.

Step-by-step explanation:

We have the function:

[tex]\displaystyle y=\frac{x^2 -1}{x}[/tex]

And we want to find the x-coordinates for which the gradient (or slope) at the point is 5.

The gradients of a curve at a point is given by its derivative. Find the derivative:

[tex]\displaystyle \frac{dy}{dx}=\frac{d}{dx}\left[\frac{x^2-1}{x}\right][/tex]

Use the quotient rule:

[tex]\displaystyle \frac{dy}{dx}=\frac{(x^2-1)'(x)-(x^2-1)(x)'}{(x)^2}[/tex]

Simplify:

[tex]\displaystyle \frac{dy}{dx}=\frac{(2x)(x)-(x^2-1)(1)}{x^2}[/tex]

Simplify:

[tex]\displaystyle \frac{dy}{dx}=\frac{x^2+1}{x^2}[/tex]

Since the gradient is 5, substitute 5 for dy/dx and solve for x:

[tex]\displaystyle 5=\frac{x^2+1}{x^2}[/tex]

Multiply both sides by (x ≠ 0):

[tex]5x^2=x^2+1[/tex]

Subtract from boths sides:

[tex]4x^2=1[/tex]

Solve for x:

[tex]\displaystyle x=\pm\sqrt{\frac{1}{4}}=\frac{1}{2}\text{ or } -\frac{1}{2}[/tex]

So, the x-coordinates for which the gradient of the curve is 5 is at x = -1/2 and x = 1/2.

can someone please please answer this

Answers

Answer: The sum of the interior angles of this shape is 720°.


Explanation: The formula to find the sum of the interior angles of any shape is: 180°(number of sides-2). The shape in this question has 6 sides, so when you substitute that into the formula, you get:

180°(6-2)
=720°

Therefore, the sum of the interior angles of this shape is 720°.


Hope that helps シ

Answer:

720 degrees

Step-by-step explanation:

sum of interior angles of any polygon is given by the equation

[tex]sum \: = (n - 2) \times 180[/tex]

where n is the number of sides of the polygon. in the question the polygon has 6 sides. hence n = 6 and

[tex]sum \: = (6 - 2) \times 180 \\ = 4 \times 180 \\ = 720 \: degrees[/tex]

Adam is 9 years old and Billy is 11 years old. What will be the ratio of Adams’ age to Billy’s age in exactly one year’s time? Give your answer in its simplest form. *

Answers

Answer:

10 / 12

simplified:

5/6

since 5 is a prime number, we can't simplify this ratio any further

A past study claims that adults in America spend an average of 17 hours a week on leisure activities. A researcher wanted to test this claim. She took a sample of 10 adults and asked them about the time they spent per week on leisure activities. Their responses (in hours) are as follows:13242137152518224032Assume that the times spent on leisure activities by all adults are normally distributed. At the 5% significance level, can you conclude that the claim of this earlier study is true

Answers

Answer:

The claim is false.

Step-by-step explanation:

Given the data :

13 24 21 37 15 25 18 22 40 32

The sample mean and standard deviation can ben calculated for the given sample.

Using calculator :

Sample mean, xbar = 24.7

Sample standard deviation, s = 9.04

Sample size, n = 10

The hypothesis :

H0 : μ = 17

H1 : μ ≠ 17

The test statistic :

(xbar - μ) ÷ (s/√(n))

(24.7 - 17) ÷ (9.04/√(10))

7.7 / 2.8586990

Test statistic = 2.694

We can obtain the Pvalue, at α = 0.05 ; df = n-1 = 9

Pvalue = 0.0246

Since Pvalue < α ; we reject the null ; Hence, there is significant evidence to conclude that an adult American does not spend average of 17 hours in leisure

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