PLEASE HELP i’m giving 32 points!!

1.) How many grams of
potassium chloride (KCI)
can be dissolved at 80°C?

2.) At 50°C, how much potassium chlorate (KCIO3) can be dissolved in 300 grams of water?

PLEASE HELP Im Giving 32 Points!!1.) How Many Grams Ofpotassium Chloride (KCI)can Be Dissolved At 80C?2.)

Answers

Answer 1

Answer: 1 How many grams of KCl will dissolve in 1 liter of H2O at 50 °C? 5. 58.0 g of K2Cr2O7 is added to 100 g H2O at. 0 °C. With constant stirring, to what temp-.                                                                                                                                     2  34 °C? 4. How many grams of KCl will dissolve in 1 liter of H2O at 50 °C? 5. 58.0 g of ... A saturated solution of KClO3 was made with 300 g of H2O at. 34 °C.

Explanation:

Answer 2
first person is right :)

Related Questions

Which list is in order from biggest to smallest? A. Earth Solar system Nebula Galaxy O O B. Universe - Galaxy Solar system Earth O C. Universe Earth Solar system Nebula O D. Solar system som Galaxy – Nebula Earth​

Answers

Answer:B, universe, galaxy, solar system, earth

Explanation:

A p e x

Answer:

universe, Galaxy, solar system, earth

Explanation:

A P E X

A 2kg object is tied to the end of a cord and whirled in a horizontal circle of radius 2 m. If the body makes three complete revolutions every second,

what is its linear speed?

And what is its centripetal acceleration?

Answers

Answer:

a) 37.70 m/s

b)710.6 m/s²

Explanation:

Given that ;

Mass of object = 2 kg

Radius of the motion = 2m

Frequency of motion = 3 rev/s

The formula to apply is;

v= 2πrf   where v is linear speed

v = 2×π×2×3 =12π = 37.70 m/s

Centripetal acceleration is given as;

a= 4×π²×r×f²  

a= 4×π²×2×3²

a=710.6 m/s²

Anthony is standing on the top of a building 10 m high holding a 7 kg
bowling ball. Mildred dug a 2-m-deep hole next to the base of the
building. What is the gravitational potential energy of the bowling ball
relative to the bottom of the hole?
I reallly need help!!

Answers

Answer:

548.8 J

Explanation:

PLEASE ANSWER FAST ill give brainliest

Answers

The answer best that best describes the relationship between DNA replication and daughter cells is the last one! (DNA replication ensures that each daughter cell has enough chromosomes after mitosis)

Two asteroids begin to gravitationally attract one another. If one asteroid has twice the mass of the other, which one experiences the greater force

Answers

Answer:

F = G  \frac{2 m^{2} }{r^{2} }

action and reaction forces with the same magnitude, but in the opposite direction, one applied to each body.

Explanation:

The force between the asteroids is given by the law of universal gravitation

           F = G m₁ m₂ / r²

in this case they give us the mass of each asteroid

           m₁ = m

           m₂ = 2m

we substitute

           F = G m 2m / r²

           F = G 2 m² / r²

            [tex]F = G \frac{2 m^{2} }{r^{2} }[/tex]

Let's analyze this expression, this is the force that one asteroid exerts on the other, therefore there are two forces, one applied to each asteroid, as the order of the products does not affect the result, the magnitude of the force is the same on each asteroid.

These are action and reaction forces with the same magnitude, but in the opposite direction, one applied to each body.

Consequently the two asteroid experiences the same magnitude of force

3. A coil of 100 turns encloses an area of 100 cm2. It is placed at an angle of 700 with a
magnetic field of 0.1 Wbm-2. What is the magnetic flux through the coil? If the magnetic
field is reduced to zero in 10-3s, what emf is induced in the coil?​

Answers

Explanation:

Given that,

Number of turns in the coil, N = 100

Area of the coil, A = 100 cm² = 0.01 m²

It is placed at an angle of 70°.

Magnetic field, B = 0.1 Wb/m²

We need to find the magnetic flux through the coil and the emf is induced in the coil after 10⁻³ s.

Magnetic flux is given by :

[tex]\phi =BA\cos\theta\\\\\text{For N turns},\\\phi =NBA\cos\theta \\\\\phi=100\times 0.1\times 0.01\times \cos(70)\\\\=0.034\ Wb[/tex]

So, the magnetic flux through the coil is 0.1 Wb.

Emf induced in the coil is :

[tex]\epsilon=\dfrac{-d\phi}{dt}\\\\=\dfrac{0.034}{10^{-3}}\\\\=34\ V[/tex]

So, 34V of emf is induced in the coil.

Question 2 (10 points)
A football player kicks a ball with a mass of 0.5 kg. The average acceleration of the football was 15 m/s/s. How much force did the kicker apply to the football?

Question 2 options:

15.5 N


30 N


7.5 N


14.5 N

Answers

Answer:

7.5N

Explanation:

Given parameters:

Mass of the ball  = 0.5kg

Acceleration  = 15m/s²

Unknown:

Force exerted by the kicker = ?

Solution:

To know the force exerted by the kicker, we use the mathematical expression below:

 Force  = mass x acceleration

This is based on Newton's second law of motion;

Now insert the parameters and solve;

  Force  = 0.5 x 15  = 7.5N

Two inductors are connected in parallel to a 120 volt, 60 Hz line. The values are 5 H and 2 H. The total inductive reactance is

Answers

Answer:Total Inductive reactance XL =538.63 Ω

Explanation:

Parallel combination for Effective inductance is calculated as

L total =  [tex]\frac{1}{1/L1 + 1/L2 + ... 1/Ln}[/tex]

=[tex]\frac{1}{1/5 + 1/2}[/tex]

[tex]\frac{1}{0.2 + 0.5 \\}[/tex]

=[tex]\frac{1}{0.7}[/tex]

=1.42857H

Inductive reactance XL = 2 πFL

where f= frequency= 60Hz

L=  Effective inductance=1.42857H

Inductive reactance , XL = 2 X 3.142 X 60 X 1.42857

=538.63Ω

A 1,000 kg truck initially had a velocity of 9 m/s. A force acts on it for a duration of time. After that force, the truck now has a velocity of 17 m/s. What is the impulse that the truck experienced?

Answers

Answer:

8000Ns

Explanation:

Given parameters:

Mass of the truck  = 1000kg

Initial velocity  = 9m/s

Final velocity  = 17m/s

Unknown:

Impulse  = ?

Solution:

The impulse experienced by the truck is the the change in momentum of the body.

  Impulse  = Ft

        Momentum  = m(v  - u)

        Ft  = m( v - u )

 F is the force

 t is the time

 m is the mass

  v is the final velocity

 u is the initial velocity

     Impulse  = 1000(17 - 9) = 8000Ns

How much power is generated if a person applies 220 N of force to move a bicycle 5 min 10 s?

Answers

Complete question :

How much power is generated if a person applies 220 N of force to move a bicycle 5m in 10 s?

Answer:

Explanation:

Given that :

Force = 220N

Time = 10 seconds

Distance = 5 m

Power = Workdone / time

********************PLEASE HELP******************************************
In your own words, explain why different locations on Earth experience different seasons on any given date.
Be sure your explanation includes the following concepts:

revolution of Earth around the Sun
tilt of the Earth
angle insolation
focus/spread of Sun’s rays
temperature
You must also explain how you know that seasons are not caused by the Earth’s slight changes in distance from the Sun throughout the year.

Answers

With the tilt of the earth that is how we have seasons
In east Asia monsoons happen a lot
Hurricanes happen in the Atlantic

Super fine 40-gauge copper wire has a diameter of only and weighs only . Suppose a spool of 40-gauge wire weighs less after some wire is pulled off to wind a magnet. How could you calculate how much wire was used

Answers

This question is incomplete, the complete question is;

Super fine 40-gauge copper wire has a diameter of only 0.080 mm and weighs only 44.5 g/km. Suppose a spool of 40-gauge wire weighs 205 g less after some wire is pulled off to wind a magnet. How could you calculate how much wire was used ?

Answer: length of wire to be used is 4.6067 km

Explanation:

Circular diameter = d mm

Linear mass density of wire = μ g/km

let m be the mass of wire un-winded from spool to wind a magnet.

If M is mass of wire initially

then

Δm = M - m  { which represents decrease of mass }

Also if L rep the length of wire pulled off,

then

Δm = μ × L grams

⇒ L = Δm/μ km

now given that weight Δm = 205 g and length per unit weight μ = 44.5 g/km

we substitute

L = 205 g  / 44.5 g/km

L =  4.6067 km

Therefore length of wire to be used is 4.6067 km

A Nov-Dec power bill shows that a home uses 1355 kwh over a 30-day period. Find the energy used (in kJ) for the 30-day period.

Answers

Answer:

The energy used for the 30-day period is 4878000 kilojoules.

Explanation:

According to the power bill, 1355 kilowatt-hours was used over a 30-day period. A kilowatt-hour is equal to 3600 kilojoules. Then, we calculate the energy used, measured in kilojoules, is determined by simple rule of three:

[tex]E = 1355\,kWh\times \frac{3600\,kJ}{1\,kWh}[/tex]

[tex]E = 4878000\,kJ[/tex]

The energy used for the 30-day period is 4878000 kilojoules.

The football team is selling mulch as a fundraiser. Which two options are
advantages of putting the order form online?
A. This information is transmitted using analog signals, so more
information can be sent.
B. This information is transmitted digitally, making it more reliable.
C. Any noise affecting the analog signal can be easily interpreted
correctly.
O D. Noise does not affect the digital signal, making it more reliable.

Answers

Answer:

Noise does not affect the digital signal, making it more reliable.                               This information is transmitted digitally, making it more reliable

Explanation:

Just did it on Ape.x

This information is transmitted digitally, making it more reliable. Noise does not affect the digital signal, making it more reliable. The correct options are B and D.

What is digital transmission?

The transfer and reception of data in the form of a digital bitstream or a digitized analogue signal transmitted through a point-to-point or point-to-multipoint communication channel is known as data transmission and reception, or, more broadly, data communication or digital communications.

Because digital switching systems are substantially less expensive than analogue switching systems, digital transmission is used to achieve high reliability.

However, the analogue signals that make up the majority of speech, radio, and television must be used for digital transmission.

This information is more dependable because it is conveyed digitally. The digital signal is unaffected by noise, increasing its dependability.

Thus, B and D are the correct options.

For more details regarding digital transmission, visit:

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A horizontal force of 90.7 N is applied to a 40.5 kg crate on a rough, level surface. If the crate accelerates at 1.08 m/s, what is the magnitude of the force of kinetic friction (in N) acting on the crate?

Answers

Mhide,

if the mass of 60 kg is having an acceleration of 1.2 m/s², we have:

F = m . a

60 x 1.2 = 72 N

That is, the resultant force is 72 newtons.

If the applied force is 95 N, we come to the conclusion that 95 - f = 72

Or,

f = 23 newtons, or 23 N, of kinetic friction.

A car stopped at a red light, begins to accelerate with a constant acceleration of 7.4 m/s^2 during a
time of 2.4 seconds. If the speed limit of the road is 35 mph (about 15.64 m/s), is the car
considered to be speeding at any point?

Answers

Answer:

The car is considered to be speeding

Explanation:

The following data were obtained from the question:

Constant acceleration (a) = 7.4 m/s²

Time (t) = 2.4 s

Speed limit = 15.64 m/s

To know if the car speeding at any point, we shall determine the velocity of the car.

This can be obtained as follow:

Constant acceleration (a) = 7.4 m/s²

Time (t) = 2.4 s

Constant velocity (v) =?

a = v/t

7.4 = v / 2.4

Cross multiply

v = 7.4 × 2.4

v = 17.76 m/s

Thus, the velocity of the car is 17.76 m/s.

Comparing the velocity of the car (i.e 17.76 m/s) with the speed limit (i.e 15.64 m/s), we can see that the velocity of the car is higher than the speed limit. Therefore, the car is considered to be speeding.

Show how multiplying both sides of the acceleration equation a equals F net over in Byam results in the net force equation F net equals MA

Answers

What are u trying to solve

In order to find the formula for net force, multiply both sides by mass.

What is Newton's Second law of motion?

Newton's second law of motion states that the rate of change of momentum is directly proportional to the force applied.

Given is the acceleration as the ratio of net force and mass.

We can write acceleration as -

a = F[net]/m

If we have to find the formula for net force, we will multiply both sides by mass (m). Therefore -

a x m = (F[net]/m) x m

am = F[net]

or

F[net] = ma

Therefore, in order to find the formula for net force, multiply both sides by mass.

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How fast is a 30 kg child runnning if her kinetic energy is 500 J?

Answers

Answer:

[tex]\displaystyle v = 5.7735 \ m/s[/tex]

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Equality Properties

Physics

SI Units

Speed is m/s (meters per second)Energy is J (Joules), equal to 1 N/m (newton per meter)Mass is kg (kilograms)

Energy

Kinetic Energy Formula: [tex]\displaystyle KE = \frac{1}{2} mv^2[/tex]

KE is Kinetic Energy (in J)m is mass (in kg)v is velocity (in m/s)Explanation:

Step 1: Define

Mass m = 30 kg

Kinetic Energy KE = 500 J

Step 2: Solve for v

Substitute [KEF]:                     [tex]\displaystyle 500 = \frac{1}{2}(30)v^2[/tex]Multiply:                                   [tex]\displaystyle 500 = 15v^2[/tex]Isolate v term:                         [tex]\displaystyle \frac{100}{3} = v^2[/tex]                      Isolate v:                                 [tex]\displaystyle \frac{10\sqrt{3} }{3} = v[/tex]Rewrite:                                  [tex]\displaystyle v = \frac{10\sqrt{3} }{3} \ m/s[/tex]Evaluate:                                [tex]\displaystyle v = 5.7735 \ m/s[/tex]

Identify one major challenge of conducting developmental research and provide an example of how a researcher can overcome it.

Answers

Answer: pointing back

Explanation:

Brainstorming seems to be the one that is the hardest and the most time consuming part. After you brainstorm, everything just falls in place with the information you have obtained researching for ideas

Calculate the density of water in kg/m3. Express your answer in kilograms per cubic meter using three significant figures.

Answers

Answer:

This question appear incomplete

Explanation:

This question appear incomplete. However, the density of water is generally known to be 997 kg/m³. The formula used to determine density is mass ÷ volume. In the case of the density of water, the mass is measured in kilograms (kg) while the volume is measured in cubic meter (m³).

A 3.8kw elective motor powers an inclined conveyer belt. It is designed to lift heavy boxes from the warehouse floor to loading bay. Answer the following:
a)State the energy conversion performed by the motor
b) Calculate the work done by the motor in 14 s
c) If the conveyer belt takes 14 to lift its load vertically by 5.3m, calculate the maximum mass that can carried by the conveyer belt maximum mass that can be carried by the conveyer belt
d) If a small box were to fall off the conveyer belt and hit the floor, calculate the speed at which it would hit the ground if falls from a vertical height of 4.7m

Answers

Answer:

See the answer below

Explanation:

To solve this problem we must use the definition of power and work in physics.

a)

The function of the conveyor belt is to carry the boxes from an initial point that is at low altitude to an end point that is at high altitude. In this way the conveyor belt prints a speed to the box to be able to raise it to the required vertical distance.

Since we have a velocity at the beginning and then we place the box at a high position, where then the box remains at rest, we can say that it converts kinetic energy to potential energy.

b)

Power is defined as the relationship of work over time. Therefore we have:

[tex]P=W/t[/tex]

where:

P = power = 3.8 [kW] = 3800 [W]

W = work [J]

t = time = 14 [s]

[tex]W=P*t\\W=3800*14\\W= 53200[J] = 53.2[kJ][/tex]

c)

Since the given time is equal to the given time at Point b, we can use the same work calculated.

We know that work is defined as the product of force by the distance traveled.

[tex]W =F*d[/tex]

So, the force is equal to:

[tex]F=W/d\\F=53200/5.3\\F=10037.73[N][/tex]

Now we know that force is defined as the product of mass by gravitation acceleration.

[tex]F =m*g[/tex]

where:

F = force or weight = 10037.73 [N]

g = gravity acceleration = 9.81 [m/s²]

m = mass [kg]

[tex]m=F/g\\m = 10037.73/9.81\\m = 1023.2 [kg][/tex]

d)

This part can be solved by means of the energy conservation theorem, where the potential energy is transformed into kinetic energy or vice versa.

[tex]E_{pot}=m*g*h = E_{kin}=0.5*m*v^{2}[/tex]

where:

h = elevation = 4.7 [m]

v = velocity [m/s]

[tex]m*g*h=0.5*m*v^{2}\\g*h=0.5*v^{2} \\v=\sqrt{\frac{g*h}{0.5} } \\v=\sqrt{\frac{9.81*4.7}{0.5} } \\v = 9.6 [m/s][/tex]

You throw a baseball straight up in the air with an initial velocity of 41 m/s What is the maximum height the baseball reaches above your hand?

Answers

Answer:

85.77 m

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 41 m/s

Final velocity (v) = 0 m/s (at maximum height)

Acceleration due to gravity (g) = 9.8 m/s²

Maximum height (h) =?

The maximum height reached by the ball can be obtained as follow:

v² = u² – 2gh (since the ball is going against gravity)

0² = 41² – (2 × 9.8 × h)

0 = 1681 – 19.6h

Collect like terms

0 – 1681 = –19.6h

–1681 = –19.6h

Divide both side by –19.6

h = –1681 / –19.6

h = 85.77 m

Thus, the maximum height reached by the ball is 85.77 m

WILL GIVE BRAINLIEST IF CORRECT!
Estimate the weight of a 1000-kg car that is accelerating at 3m/s/s.


(Use g=10m/s/s)

Answers

Answer:

10000N

Explanation:

Given parameters:

Mass of the car  = 1000kg

Acceleration = 3m/s²

g  = 10m/s²

Unknown:

Weight of the car  = ?

Solution:

To solve this problem we must understand that weight is the vertical gravitational force that acts on a body.

 Weight  = mass x acceleration due to gravity

So;

    Weight  = 1000 x 10  = 10000N

When the Moon is at a distance of 0.25 D from the Earth, the gravitational force on the Moon from the Earth is 16.00 F. At what distance will the force on the Moon be 4.00 F?

Answers

Answer:

On the way to the Moon the Apollo astronauts reached a point where the. Moon's gravitational pull became stronger, than the Earth's. (a) Determine the distance of ...

Explanation:

Answer right I will cashapp $5

Someone made a copy of an analog wave and a digital wave. Compare the copies
with the original waves. Then, explain which type of wave is a more reliable way to
encode and transmit information.

Answers

Analog transfer information quicker, example electromagnetic waves which are used in our modern day phones.

Answer:

The original analog sound waves are perfect but the copy is not because most analog waves have wavelengths that are too long to reproduce in copies

The original digital waves and the copy are perfect because with digital waves no information gets lost in the transfer of data, and there is no additional noise added to the copy.

Analog refers to audio recorded using methods that replicate the original sound waves. Digital audio is recorded by taking samples of the original sound wave at a specified rate.

Explanation:

i dont need $5

i wrote this using information from go ogle and some from brai nly. I hope it helps.

Are the coils in an electric heater blackbody radiators? Why?
A. No, because they do not emit different wavelengths of light
B. Yes, because they glow more brightly as they increase in
temperature
O C. No, because they absorb no energy and emit no light
D. Yes, because they reflect most of the energy they receive

Answers

Answer:

B. Yes, because they glow more brightly as they increase in

temperature

Explanation:

Did the test !!

The coils in an electric heater blackbody are not radiators. Because, they absorb no energy and emit no light. Thus, the correct option is C.

What is an electric heater?

Electric heating is a process in which the electrical energy is converted directly into the heat energy at around about 100% efficiency, using rather the cheap devices. Common applications which are included are space heating, cooking, water heating and industrial processes.

A radiator is the key component of the engine's cooling system. Radiator has the main role to disperse a mix of antifreeze and water molecules throughout the fins, which releases some of the engine's heat energy while taking in the cool air before continuing to pass the rest of the electric engine.

Therefore, the correct option is C.

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what is kinetic energy

Answers

Answer:

Kinetic energy is energy of motion

Explanation:

Of potential energy which is energy that is stored

When a falling meteor is at a distance above the Earth's surface of 2.98 times the Earth's radius, what is its free-fall acceleration caused by the gravitational force exerted on it

Answers

Answer:

0.63 m/s²

Explanation:

Given that

Distance of meteor from earth's surface, r = 2.98R,

where R = radius of the Earth.

The force of the meteor due to the Earth is usually given by

F = GMM(a)/(R + r)² where

F = force exerted

G = gravitational constant

M = Mass of the earth

M(a) = mass of meteor

Remember that F = Ma, so applying that here, we have

acceleration of meteor = GM/(R + r)²

where r = 2.98R so that

acceleration of meteor = GM/(R + 2.98R)²

acceleration of meteor = GM/(3.98R)²

acceleration of meteor = GM / 15.84R²

It should be noted that GM/R² = 10, so

acceleration of meteor = 10/15.84

acceleration of meteor = 0.63 m/s²

Therefore as calculated, the acceleration of the meteor is 0.63 m/s²

Do you know how to do this clever ones hmmm?? Describe and explain the motion of a small ball floating on a pond when waves travel across the pond.​

Answers

Answer:

Ball moves up and down repeatedly on surface because waves consist of successive crests and troughs moving across surface, each crest pushes ball up and each trough allows it to move down.

Explanation:

Which type of telescope is best used to detect distant planets?​

Answers

I believe the answer would be, refractor type telescopes because these are best used for planetary observations.
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