Need help will give 15 points!!

Answer:

D

Step-by-step explanation: We know it's not A or B because a statistical question is a question that will vary. D has that exact response while C is not exactly what a statistical question is.

The student who correctly describes Ms. Ringer's question would say that it is an open-ended question.

A term is composed of one mathematical expression. A single variable (a letter), a single integer (positive or negative), or a number of variables that have been multiplied but never added or subtracted are all examples of single variables. There is a number in front of certain words that are variables. A word or phrase is preceded by a coefficient.

Ms. Ringer asked her class, "What are the favorite colors of the students in our school?"

The student who correctly describes Ms. Ringer's question would say that it is an open-ended question,

as there are many possible answers to the question and it does not have a single, definitive answer.

To learn more about the expression;

brainly.com/question/24242989

#SPJ2

Answer:

3/8 or6/16

Step-by-step explanation:

Answer:

-4.5

Step-by-step explanation:

Answer:

[tex] \huge \boxed{x = \frac{2}{3} y}[/tex]

Answer:

3(3+2b)

or

2b +9

Step-by-step explanation:

Answer:

Step-by-step explanation:

3b+5-9b-9+6b

=3b+6b-9b+5-9=-4

Answer:

125

Step-by-step explanation:

Answer:

L.H.S. = [tex]\frac{1}{cosx} -\frac{sinx}{cosx}sinx[/tex]

= [tex]\frac{1}{cosx} - \frac{sin^2x}{cosx}[/tex]

= [tex]\frac{1-sin^x}{cosx} = \frac{cos^2x}{cos x}[/tex]

= cos x = 1/secx

Step-by-step explanation:

Hey there!

Given;

sec x - tan x . sin x = 1/(sec x).

~ Taking LHS.

= sec x - tan x . sin x

= 1/(cos x) - (sin x/cos x) . sin x { Using formula sec x = 1/cos x and tan x = (sin x/cos x)}

~ Multiply (sin x) and (sin x).

[tex] = \frac{1 - { (\sin(x) )}^{2} }{ \cos(x) } [/tex]

~ Use formula 1-sin²x= cos²x

[tex] = \frac{ {cos}^{2} x}{ \cos(x) } [/tex]

~ Cancel cos x.

= cos x

= 1/sec x { cos x = 1/sec x}

→ RHS proved.

Hope it helps.....

Answer: Graph 2

Step-by-step explanation:

Answer:

804.063

Step-by-step explanation:

just multiply each part and add

800 +4 +.06 +.003

804.063

Answer:

5x and -7x

Step-by-step explanation:

they both end in the variable "x"

Answer:

A

Step-by-step explanation:

A cuz it's accelerate..........

Answer:

The answer to the question provided is 10.

Answer:

No

Step-by-step explanation:

The relation given as represented by the table of values is definitely not a function. This is because, 1 domain value (x-value), is having two range values (y-values), 2 and 5, that are assigned to it.

A function cannot have two y-values assigned to one x-values.

Answer:

there would be 11 accidents of people

Step-by-step explanation:

6+3+1+1= 11

or

6+3+2= 11

or

6+5 =11

Answer:

no

Step-by-step explanation:

1. because 2. i 3. said 4. so

Answer:

3000

Step-by-step explanation:

Answer:3000

Step-by-step explanation:

Answer:

x=2 is the answer to this problem

Answer: x = 3

Step-by-step explanation:

9 - 2x = 4x - 9

18 -2x = 4x

18 = 6x

x = 3

Answer:

1/3

Step-by-step explanation:

you add the 2x onto the 4x to get 6x on one side on the other side you add on the nine so now you have 18=6x then you divide by 18 to get 6/18 or simplified 1/3 also 33.3 as a decimal

Answer:

Below

Step-by-step explanation:

Always

Sometimes

Never

Always

Answer:

always,sometimes,never,always

Step-by-step explanation:

Equilateral triangles are  

always

acute triangles. Yes, because acute is always 60 degrees, and equilateral is basically your average triangle, so its corners have 60 degrees.

Scalene triangles are  

sometimes

acute triangles.      Scalene triangles always dont have that sharp corner..they sometimes do, the sharp turn which is 60 degrees, ACUTE IS ALWAYS 60 DEGREES.

Right triangles are  

never

acute triangles. A right angle cant be a acute, not 60 degrees..

Obtuse triangles are  

always  

isosceles triangles.  Isosceles means atleast 2 of the sides look the same, i included how to recognize obtuse, right,etc

Answer:

[tex]\displaystyle d = \sqrt{89}[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra II

Step-by-step explanation:

Step 1: Define

Point (-6, -5)

Point (2, 0)

Step 2: Find distance d

Simply plug in the 2 coordinates into the distance formula to find distance d

Answer:

CLASS     FREQUENCIES     RELATIVE FREQUENCIES

A                        60                                 0.5

B                        12                                  0.1

C                        48                                 0.4

TOTAL              120                                  1

Step-by-step explanation:

Given that;

the frequencies of there alternatives are;

Frequency A = 60

Frequency B = 12

Frequency C = 48

Total = 60 + 12 + 48 = 120

Now to determine our relative frequency, we divide each frequency by the total sum of the given frequencies;

Relative Frequency A = Frequency A / total = 60 / 120 = 0.5

Relative Frequency B = Frequency B / total = 12 / 120 = 0.1

Relative Frequency C = Frequency C / total = 48 / 120 = 0.4

therefore;

CLASS     FREQUENCIES     RELATIVE FREQUENCIES

A                        60                                 0.5

B                        12                                  0.1

C                        48                                 0.4

TOTAL              120                                  1

Answer:

94.077=90+4+0.07+0.007

Step-by-step explanation:

I hope this answered your question

Answer:

Step-by-step explanation: