Answer:
a) τ₁ = 660 N m, b) τ’= 686 N m, c) F = 623.6 N
Explanation:
a) For this exercise let's use the concepts of torque and rotational balance.
For this we set a reference system at the base and assuming that the counterclockwise rotations are positive
where the force F = 600 N, the distance to the axis is x = 1.1 m, the mass of the system m = 70g and the weight is placed at the point of the center of gravity x_{cm} = -1.0 m
The torque at the front is
τ₁ = F x
τ₁ = 600 1.1
τ₁ = 660 N m
b) let's write the rotational equilibrium condition
∑ τ = 0
τ'- W x_{cm} = 0
τ ’= mg x_{cm}
τ’= 70 9.8 1.0
τ’= 686 N m
c) the greatest force Matt can apply
τ’= F x
F = τ’/ x
F = 686 / 1.1
F = 623.6 N
An engine applies a force of 500 N on a car for a distance of 275m How much work is done?
Answer: 137500 J = 138 kJ
Explanation: work W= F·s= 500 N · 275 m
how much water makes up earth in percentages? thx?
Answer:
71%
Explanation:
Giving brainliest!! if you answer correctly :)
Answer:
Mechanical Energy- D
Nuclear Energy- C
Thermal Energy- A
Chemical Energy- B
Explanation:
Hope this helps :)
You and a friend each apply 500 N of force to move a cement block 50 cm. How much work was done on the cement block?
Answer:
W = 500 J
Explanation:
Work is defined by
W = F . x
if we develop the dot product
W = F x cos θ
where is the angle between the force and the displacement, in this case the angle is zero, so cos 0 = 1
W = F x
indicate that each person applies a force of 500 N, so the total force is
F = 1000 N
let's reduce the distance to the SI system
x = 50 cm = 0.50 m
let's calculate
W = 1000 0.50
W = 500 J
Iceland is located along the mid Atlantic ridge. Would you predict that Iceland's land mass will expand or contract over the coming millenia? Justify your answer.
26. A liquid with a low viscosity
a. has a definite shape
b. fills its container
c. flows quickly
d. flows slowly
Answer:
flows quickly and needs to be like paper
Answer:
c
Explanation:
it flows very quickly since it has a low viscosity
Use the drop-down menus to identify the part of the ear that performs each function.
Changes sounds to signals that the brain can understand: (Inner ear, middle ear, or outer ear)
Collects sound: (Inner ear, middle ear, or outer ear)
Passes sounds through vibrations: (Inner ear, middle ear, or outer ear)
Answer:
The answers to this question is:
1. inner ear
2. outer ear
3. middle ear
Explanation:
Hope that helps!
Answer:
inner, outer, middle
Explanation:
Standing and holding a barbell that has a mass of 100kg at a height of 2m involves being done on the barbell to maintain
the position.
Answer:
I'm not sure but, this video's pretty cool: gestyy.com/eyRkH2
Explanation:
A wave has a wavelength of 14 m and a frequency of 24 Hz, what is the speed of the wave?
Answer:
v = [tex]\lambda[/tex]xf = 14 x 24 336m/s
Explanation:
If a motorcycle, a car, and a big rig are all moving with a velocity of 100 km/h, which vehicle has the greatest momentum? A motorcycle and rider. A small car. A large 18 wheeler truck.
Answer:
The big rig.
Explanation:
Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.
Mathematically, momentum is given by the formula;
[tex] Momentum = mass * velocity [/tex]
In this scenario, a motorcycle, a car, and a big rig are all moving with a velocity of 100 km/h. Thus, the vehicle which has the greatest momentum is the big rig because its mass is intuitively or logically greater than that of the other vehicle.
Generally, momentum is directly proportional to the mass of a physical object or body.
Answer: A large 18 wheeler truck.
Explanation: Momentum is the measure of the motion of an object found by multiplying the object’s mass and velocity. Momentum is directly proportional to the object's mass and also its velocity. So, the greater an object's mass or the greater its velocity, the greater its momentum. Therefore, since the truck is bigger, it has the greatest mass. This means that the truck the greatest momentum. Correct on Edg 2020.
PLEASE GIVE BRAINLIEST AND RATE MY ANSWER :)
A roller coaster car is traveling at a constant 3 m/s when it reaches a downward slope. On the slope, the car accelerates at a constant rate of 4.5 m/s 2 . The length of the slope is 45 meters. A) Find the velocity of the car at the bottom of the hill. B) Find the time of travel.
Answer:
Velocity of the car at the bottom of the slope: approximately [tex]20.3\; \rm m \cdot s^{-2}[/tex].
It would take approximately [tex]3.9\; \rm s[/tex] for the car to travel from the top of the slope to the bottom.
Explanation:
The time of the travel needs to be found. Hence, make use of the SUVAT equation that does not include time.
Let [tex]v[/tex] denote the final velocity of the car. Let [tex]u[/tex] denote the initial velocity of the car.Let [tex]a[/tex] denote the acceleration of the car. Let [tex]x[/tex] denote the distance that this car travelled.[tex]v^2 - u^2 = 2\, a\cdot x[/tex].
Given:
[tex]u = 3\; \rm m \cdot s^{-1}[/tex].[tex]a = 4.5\; \rm m \cdot s^{-2}[/tex].[tex]x = 45\; \rm m[/tex].Rearrange the equation [tex]v^2 - u^2 = 2\, a\cdot x[/tex] and solve for [tex]v[/tex]:
[tex]\begin{aligned}v &= \sqrt{2\, a \cdot x + u^2} \\ &= \sqrt{2 \times 4.5\; \rm m \cdot s^{-2} \times 45\; \rm m + \left(3\; \rm m \cdot s^{-1}\right)^{2}} \\ &\approx 20.3\; \rm m \cdot s^{-1}\end{aligned}[/tex].
Calculate the time required for reaching this speed from [tex]u = 3\; \rm m \cdot s^{-1}[/tex] at [tex]a = 4.5\; \rm m \cdot s^{-2}[/tex]:
[tex]\begin{aligned}t &= \frac{v - u}{a} \\ &\approx \frac{20.3\; \rm m \cdot s^{-1} - 3\; \rm m \cdot s^{-1}}{4.5\; \rm m \cdot s^{-2}} \approx 3.9\; \rm m \cdot s^{-1}\end{aligned}[/tex].
Determina la fuerza de acción que se presenta entre dos cuerpo cuyas masas son 500 Kg y 900 Kg, si ambos cuerpos se encuentran separados a una distancia de 2 m. Datos Fórmula Sustitución y Operaciones Resultado
Answer:
F = 7.50 10⁻⁶ N
Explanation:
The force of attraction between two bodies is given by the law of universal gravitation
F = [tex]G \frac{m_1m_2}{r^2}[/tex]
where m₁ and m₂ are the masses of the hides, r the distance that separates them and G the constant of attraction that is worth 6.67 10⁻¹¹ N m²/kg²
let's calculate
F = 6.67 10⁻¹¹ 500 900/2²
F = 7.50 10⁻⁶ N
If the area of a concrete slap weighing 300n is 400cm2 ,how much pressure can it apply when kept on the ground
Answer:
7500 N/m²
Explanation:
From the question given above, the following data were obtained:
Force (F) = 300 N
Area (A) = 400 cm²
Pressure (P) =?
Next, we shall convert 400 cm² to m². This can be obtained as follow:
1×10⁴ cm² = 1 m²
Therefore,
400 cm² = 400 cm² × 1 m² / 1×10⁴ cm²
400 cm² = 0.04 m²
Finally, we shall determine the pressure. This can be obtained as follow:
Force (F) = 300 N
Area (A) = 0.04 m²
Pressure (P) =?
P = F/A
P = 300 / 0.04
P = 7500 N/m²
A wheel of mass 500 kg and 1 m diameter makes 500
revolutions per minute. Assuming the mass to be concentrated
along the rim, calculate the angular velocity of wheel.
Answer:
w=120rpm
Considering it a disc
L=Iw
=220×(412)×120×602π
=31.415kgm/s
The angular velocity of wheel should be considered as the 31.415kgm/s when the mass of wheel is 500 and the diameter is 500 revolutions per minute.
Calculation of the angular velocity of wheel:Since
A wheel of mass 500 kg.And 1 m diameter makes 500 revolutions per minute.So here
We know that
w = 120rpm
And,
L = Iw
So,
= 220×(412)×120×602π
= 31.415kgm/s
hence, The angular velocity of wheel should be considered as the 31.415kgm/s.
Learn more about velocity here: https://brainly.com/question/17802937
Two air craft P and Q are flying at the same speed 300m/s. The direction along which P is flying is at right angles to the direction along which Q is flying. Find the magnitude of velocity of the air craft P relative to air craft Q
Answer:
424.26 m/s
Explanation:
Given that Two air craft P and Q are flying at the same speed 300m/s. The direction along which P is flying is at right angles to the direction along which Q is flying. Find the magnitude of velocity of the air craft P relative to air craft Q
The relative speed will be calculated by using pythagorean theorem
Relative speed = sqrt(300^2 + 300^2)
Relative speed = sqrt( 180000 )
Relative speed = 424.26 m/s
Therefore, the magnitude of velocity of the air craft P relative to air craft Q is 424.26 m/s
Hurricanes are powered by heat energy in the atmosphere and the ocean. Typically, one hurricane uses an amount of heat roughly equal to Z thousand atomic bombs. If the excess heat built up in Earth's atmosphere since 1850 went into producing hurricanes, about how many more hurricanes might we expect in the world every year?
Answer:
In an year about 6 major hurricanes and 3 minor storms occurs.
Explanation:
Hurricanes are increasing in number and frequency to the increasing impact of global warming. As current research states that climate change in the tropics results in an increased storm frequency. The presence of extra heat in the air or the oceans form the stoma that leads to the production of such energy. According to o the 200-2007 data shows in the huge increase in the storm frequency and this suggests the impact of climate warming.The linear expansivity of metal P is twice that of another metal Q. When these materials are heated through the same temperature change, their increase in length is the same. Calculate the ratio of the original length of P to Q
Answer:
The answer is 1:2.
The resistivity of a given wire of cross sectional area 0.7mm^2 is 4.9×10^-4ohms mm.Calculate the resistance of a 2ohms length of the wire
Answer:
the resistance of the wire is 1.4 x 10⁻³ ohms.
Explanation:
Given;
resistivity of the wire, ρ = 4.9 x 10⁻⁴ ohms.mm
cross sectional area of the wire, A = 0.7 mm²
length of wire, L = 2 mm
The resistance of the wire is calculated as follows;
[tex]R = \frac{\rho L}{A} \\\\R = \frac{4.9 \times 10^{-4} \times 2}{0.7} \\\\R = 1.4\times 10^{-3} \ ohms[/tex]
Therefore, the resistance of the wire is 1.4 x 10⁻³ ohms.
1. Find the acceleration of an object when the force is 5.2 N and the mass is 2.6 x 10kg.
Answer:
F=ma
5.2N=26a
a=5.2÷26=0.2
Answer:
0.2 metre square
Explanation:
acceleration=force/mass
The negative work done is equal to the difference in the......... Electric potential energy Electric flux Electric potential Electric dipole
Answer:
Electric potential energy
Explanation:
The Electric potential energy of a system is less than that carried out by electrostatic forces during the development of the system (as long as charges are initially cut infinitely).
The change in potential energy between an initial and final configuration is equal to minus the work done by the electrostatic forces.
in your own opinion do you think liquorice all-sorts is a healthy ofor ptions snack
Well its a snack
.
.
.
.
.
.
.
.
.
.
.
.
.
thuli wants to buy tv for R8500.a bank offers to loan her the money at an interest rate of 5%.she decides to pay the tv off in 3 years calculate the simple interest she will have to pay .also calculate the total she will pay
Answer:
The total she has to pay is R8500 plus the 5% interest.
PLEASE ADD BRAINEEST
06
In which diagram is the moment of the force the largest?
©
300 N
300N
300 N
lo
16 cm
A
B
16 cm
A: A
B: B
113
C: C
D: They are all the same
D
Explanation:
The are the same but difference
PLEASE HELP ME ASAP!!!
Answer:
90
Explanation:
The portion where gas turns to liquid
A cloud is drifting across the sky at a constant velocity of 724metersperminute to the east. It is at an altitude of 9,200 meters. How far will the cloud move in 12.5minutes?
Answer:
The cloud moves 9050 meters to the east in 12.5 minutes.
Explanation:
Let suppose that mass of the cloud is negligible. meaning that effects of gravity are negligible and that altitude of the cloud remains constant. If the cloud drifts at constant velocity, travelled distance is defined by following formula:
[tex]\Delta s = v\cdot \Delta t[/tex] (1)
Where:
[tex]v[/tex] - Velocity, in meters per second.
[tex]\Delta t[/tex] - Time, in seconds.
If we know that [tex]v = 724\,\frac{m}{min}[/tex] and [tex]\Delta t = 12.5\,min[/tex], then the travelled distance after 12.5 minutes is:
[tex]\Delta s = 9050\,m[/tex]
The cloud moves 9050 meters to the east in 12.5 minutes.
plz help me
Your friend has a mass of 70 kg and is running at a velocity of 3 m/s. What is their kinetic energy?
Answer:
TINAAA
Explanation:
A business jet of mass 24000kg takes off when the thrust for each of two engines is 34000N. Find the acceleration.
Answer:
1.42 m/s²
Explanation:
From the question,
F = ma.................... Equation 1
Where F = force, m = mass of the jet, a = acceleration of the jet
make a the subject of the equation
a = F/m................. Equation 2
Given: F = 34000 N, m = 24000 kg
Substitute into equation 2
a = 34000/24000
a = 1.42 m/s²
Two beakers are at the same temperature. One beaker has more water than the other. Which one contains more heat? Explain why.
Answer:
I would say the beaker with less water.
Explanation:
I was say this because while they are the same temperature the beaker with more water still has to fluctuate the heat or cold. They do this at the same speed but since there is less water in one beaker it finishes faster where as the beaker with more water will finish later.
AWARDING BRAINLIEST
The distance traveled by an object divided by the time it takes to travel that distance is called
a.
average velocity.
c.
average acceleration.
b.
average speed.
d.
activity.
Answer:
I'm really not that good at this but i think the answer is b
Explanation:
l'm really hoping this helped u
A small pebble and one large boulder start at the same height and begin rolling down the side of a mountain. Which object would have less kinetic energy as it crashes on the road at the bottom of the mountain? Justify your selection.
Answer:
The small pebble
Explanation:
Since the potential energy, P.E lost equals kinetic energy, K.E gained,
P.E = K.E
P.E = mgh = K.E
So, K.E = mgh where g = acceleration due to gravity and h = height of drop
Since h and g are constant
K.E ∝ m
So, the kinetic energy of the object is directly proportional to its mass. Thus, the object with the smaller mass has the lesser kinetic energy.
Since the object with the smaller mass is the small pebble, so the small pebble would have less kinetic energy as it crashes on the road at the bottom of the mountain.