Given: △ABC, m∠A=60°,
m∠C=45°, AB=9
Find: Perimeter of △ABC,
Area of △ABC
Pleas be sure to answer BOTH PARTS ... thank you!

Answers

Answer 1

Answer:

p = 32.317

A = 47.911

Step-by-step explanation:

given ∠A = 60

∠C = 45

AB = 9

From sum of all angles in triangle is 180

∠A + ∠B + ∠C = 180

60 + ∠B + 45 = 180

∠B = 180 - 105 = 75

∠B = 75

from sine rule in ΔABC

AB / sin C = BC / sin A

=> 9 / sin 45 = BC / sin 60

=> 9 / 1/[tex]\sqrt{2}[/tex] = BC / [tex]\sqrt{3} / 2[/tex]

=> [tex]9\sqrt{2} = BC * 2 / \sqrt{3}[/tex]

BC = [tex]9\sqrt{2} * \sqrt{3} / 2\\[/tex]

BC = 11.023

length of AC is

AC / sin B = AB / sin C

AC / sin 75 = 9 / sin 45

AC = 9 / 1/[tex]\sqrt{2} * sin 75[/tex]

= [tex]9\sqrt{2} * sin 75\\12.294[/tex]

perimeter of ΔABC

AB + BC + CA

= 9 + 11.023 + 12.294

= 32.317

Area of ΔABC is

= 1/2 * AB * AC * sin A

= 1/2 * 9 * 12.294 * sin 60

= 1/2 * 9 * 12.294 * √3/2

= 47.911


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Answer: does that “-4” count? 1/2 + 2 3/4 mixed number equations are easy. Switch the other way so it should be 2 3/4 + 1/2. The 2 whole remains. 3 - 1 = 2. Dont subtract the denominator. Final is 2_2/4. Not 100% sure if im correct though, i might need more studying

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Answers

Answer:

answer given in step by step...

Step-by-step explanation:

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Answers

Answer: 51% were males

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

Hi there!

We are given the line y=-4x+1, and we want to write the equation of the line that is parallel to that line and that also passes through the point (2, 0)

Parallel lines have the same slope, so it makes sense to find the slope of the line y=-4x+1

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It's also the slope of the line parallel to it.

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Answers

Answer:

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Step-by-step explanation:

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-Chetan K

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Step-by-step explanation:

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Answers

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Answers

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Step-by-step explanation:

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Step-by-step explanation:

Answer:

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