Answer:
Δx=7.35m
Explanation:
This is a free fall problem (g= -9.8 m/s²).
Displacement: ? <--- what you're trying to find (max height)
Initial Velocity: 12 m/s
Final Velocity: 0 m/s <-- since the can will land back in your hands
Time: Missing <-- not needed to solve
Acceleration: -9.8 m/s²
The equation that you will use is vf²=vi²+2aΔx
Now plug the information into the equation!
(0m/s)²=(12m/s)²+2(-9.8m/s²)Δx
Multiply the 2 with the acceleration (-9.8m/s²)
(0m/s)²=(12m/s)²-19.6m/s²Δx
Now you need to square the final and initial velocity
0m/s=144m/s-19.6m/s²Δx
Move 144 to the other side of the equal sign
-144m/s=-19.6m/s²Δx
Divide both sides by -19.6m/s²
7.346m=Δx
You can round it to the tenth or hundreth place, up to you!
For this example, I'll round to the hundredth...
Δx=7.35m
I would double check this answer or review it yourself to see if it's correct.
Good luck with your studies!
NO LINKS! What are the definitions of initial horizontal velocity and initial vertical velocity? Please help! This like is my 10th time asking this question because many people have been scamming me...
Answer:
Additionally, the initial horizontal velocity may be calculated by measuring the diameter d of the ball and dividing the result by the amount of time t required for the ball to pass across the photogate. Vo = d/t is the formula.
Initial vertical velocity is the vertical component of the initial velocity: v 0 y = sin 0 sin 0 = (30.0 m/s) sin 45° = 21.2 m/s
Explanation:
Hope it helps:)
This should be pretty easy i think.
Describe the components within the system involved in the collision between pilot and landing zone.
Answer:
its a sure for not but i think its a 192583
A 0.5kg ball falls from a building that Is 50m high. how much kinetic energy will it have when it has fallen half way to the ground?
A child sits on a rotating merry-go-round, 2.1 m from its center. If the speed of the child is 2.2 m/s, what is the minimum coefficient of static friction between the child and the merry-go-round that will prevent the child from slipping?
We have that the the minimum coefficient of static friction is mathematically given as
[tex]\mu= 0.235[/tex]
ForceGenerally the equation for the Force is mathematically given as
[tex]F=n\mu\\\\Where\\\\n = mg\\\\Given\\\\Fc = m(vt2/R)\\\\Therefore\\\\\mu = vt2/gR\\\\\mu = 2.22/(9.8(2.1)) \\\\[/tex]
[tex]\mu= 0.235[/tex]
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People who drink coffee are more likely to develop cancer
Answer:
The answer is False
Football players boots have spikes at their sole
Give reason
Answer:
it prevents slipping on the grass while playing
Answer:
to keep their grip on the ground so they won't fall
A student did 24 J of work on a chair. She applied a force of 12 N and moved the chair 2 m. What else do you need to know to determine the amount of power used?
Answer:
time
Explanation:
power = work done ÷ time
6. Explain the importance of the law of conservation of mass.
Answer:
According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants. The law of conservation of mass is useful for a number of calculations and can be used to solve for unknown masses, such the amount of gas consumed or produced during a reaction.
Explanation:
<3
Please help! Question is attached.
Answer:
a. 6
b. 6 m/s²
c. 300 m to the right
d. 30 secs
Explanation:
slope = rise /run
60-0/10-0
= 6
b. slope = acceleration = 6 m/s²
c. d=ut+1/2at²
t=10 (segment A last for 10 secs)
u - initial velocity = 0
so d = 0(10)+1/2*6*10²
=300 m
A 34. 8 n object is in free fall. What is the magnitude of the net force which acts on the object? answer in units of n.
Answer:
-34.8n
Explanation:
when object in free fall, only force is the Force by weight,
which is 34.8 and direction is down.
Why are people so rude???
Answer:
It could be low self-esteem
Explanation:
There probably insecure have problems and issues of their own could be that were abused growing up and weren’t treated right who knows.
Help me quick!!! please!!
Calculate the power of an engine which raises a mass of 1000 kg to a height of 40 m in 10 s.
Answer:
39.240 W
Explanation:
Let's start by calculating the work done by the engine. We can assume that it is the same work done by the weight of the object to bring it from 40m to the surface: as much energy it takes to bring it up, the same ammount it takes to bring it down. Said work is [tex]w= \vec F\cdot \vec{h} = mg h = 1000 \times 9.81\times 40 = 392.400 J[/tex]
At this point we can simply apply the definition of power, that is [tex]P = \frac wt[/tex], to get the power of the engine is [tex]39.240 W[/tex]
Answer:
P=39200W
Explanation:
P=(mgh)/t
P=(40×9.8×1000)/10
P=39200W
A ball is projected at an immovable wall with a speed vi and bounces back the wall in such a manner that it only has 1/3 of its original linear momentum. a) Determine what fraction of the kinetic energy is lost in the collision.
The fraction of the kinetic energy of the ball lost during the collision is [tex]\frac{1}{3}[/tex].
The given parameters;
initial speed of the ball, = vifinal momentum of the ball, Pf = ¹/₃PiThe initial and final momentum of the ball is calculated as;
[tex]P_i = m_ivi[/tex]
[tex]P_f = m_fv_f = \frac{1}{3} m_iv_i[/tex]
The initial and final kinetic energy of the ball is calculated as;
[tex]K.E_i = \frac{1}{2} m_iv_i^2 = \frac{1}{2} P_iv_i\\\\K.E_f = \frac{1}{2} m_fv_f^2= \frac{1}{2} (\frac{1}{3} P_iv_i)= \frac{1}{6} P_iv_i[/tex]
The change in the kinetic energy is calculated as;
[tex]\Delta K.E = K.E_f - K.E_i \\\\\Delta K.E = \frac{1}{6} P_iv_i - \frac{1}{2} P_iv_i = \frac{1}{3} P_iv_i[/tex]
Thus, the fraction of the kinetic energy of the ball lost during the collision is [tex]\frac{1}{3}[/tex].
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A 30 kg boy stands on rough horizontal ground. The coefficient of
static friction,
us is 0.8. The present static friction between the boy and the ground is
?
Answer:
0n
Explanation:
what is potentiometer
Answer:
potentiometer is a device used to measure potential difference across the circuit
What would be the acceleration of a block sliding down an inclined plane that makes an angle of 45° with the horizontal if the coefficient of sliding friction between two surfaces in 0.3? 141
Ans: 4.95 m/sec?
Answer:
unfortunately we have not received a reply to the park yet but
Explanation:
mohamedz and he had killed him
a gas increases in pressure from 2.00 atm to 6.00 atm at a constant volume of 1.00 m3 and then expands at constant pressure to a volume of 3.00 m3 before returning to its initial state as shown in the figure below. how much work is done in one cycle?
The work done on the given gas in one cycle is -405.3 kJ.
The given parameters;
initial pressure of the gas, P₁ = 2 atmfinal pressure of the gas, P₂ = 6 atminitial volume of the gas, V₁ = 1 m³final volume of the gas, V₂ = 3 m³Convert the pressure to Pascal (N/m²);
1 atm = 101325
The work done in one cycle is the area of the triangle and it is calculated as follows
[tex]Area = \frac{1}{2} \times base \times height\\\\Area = \frac{1}{2} \times (3 \ m^3\ -\ 1 \ m^3)\times (6 \ atm \ - \ 2 \ atm)\\\\Area = 4 \ atm -m^3\\\\Area = 4 \ atm -m^3 \ \times \frac{101325 \ Pa}{1 \ atm} \\\\Area = 405,300 \ m^3.Pa\\\\Area = 405,300 \ m^3. (N/m^2)\\\\Area = 405,300 \ Nm\\\\Area = 405,300 \ J\\\\Area = 405.3 \ kJ[/tex]
the net work done on the gas = - 405.3 kJ
Thus, the work done on the given gas in one cycle is -405.3 kJ.
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If force F, volume V and density D are taken as fundamental quantities, then the representation of pressure P will be
Using the principle of dimensional analysis, the representation of Pressure would be [tex] P = F^{1}V^{-\frac{2}{3}}D^{0}[/tex]
Pressure is related to Force, Volume and Density thus :
[tex] Pressure, P = F^{a}V^{b}D^{c}[/tex]
Using dimensional analysis :
Pressure, P = ML¯¹T¯²Substituting the dimension into the relation :
[tex] ML^{-1}T^{-2}= [MLT¯²]^{a} [L³]^{b} [ML¯³]^{c} [/tex]
[tex] ML^{-1}T^{-2} = M^{a+c}L^{a+3b-3c}T^{-2a} [/tex]
Equating the power ;
a + c = 1 - - - (1)
a + 3b - 3c = - 1 - - - (2)
-2a = - 2
a = - 2/-2
a = 1
From (1)
1 + c = 1
c = 1 - 1 = 0
c = 0
From (2) :
1 + 3b - 3(0) = - 1
1 + 3b = - 1
3b = - 2
b = - 2/3
Hence, [tex] P = F^{1}V^{-\frac{2}{3}}D^{0}[/tex]
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The representation of pressure is:
[tex]P=FV^{-\frac{2}{3} }[/tex]
Given that:
Force F, volume V and density D are taken as fundamental quantities, hence pressure P is:
[tex]P=F^aV^bD^c\\\\(ML^{-1}T^{-2})=(MLT^{-2})^a(L^3)^b(ML^{-3})^c\\\\\\(ML^{-1}T^{-2})=(M)^{a+c}(L)^{a+3b-3c}(T)^{-2a}[/tex]
Hence:-
2 = -2a
a = 1
a + c = 1
1 + c = 1
c = 0
a + 3b - 3c = -1
1 + 3b - 3(0) = -1
3b = -2b = -2/3
Hence the representation of pressure is:
[tex]P=FV^{\frac{-2}{3} }D^{0}\\\\P=FV^{\frac{-2}{3} }[/tex]
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someone throws a rubber ball vertically upward from the roof of a building 8.2m in height. the ball rises, then falls.it just misses the edge of the roof, and strikes the ground.if the ball is in the air for 6.2s, what was its initial velocity?(disregard air resistance. a=-g=-10m/s²
Answer:
H = V t - 1/2 g t^2 V and g are in different directions
-8.2 = V * 6.2 - 1/2 * 10 * 6.2*2 = 6.2 V - 192.2
V = 184 / 6.2 = 29.7 m/s
Check: find time for ball to return to zero height
0 = 29.7 T - 5 T^2
T = 29.7 / 5 = 5.94 sec
The ball must have fallen 8.2 m in (6.2 - 5.94) sec = .26 sec
S = 29.7 * .26 + 5 * .26^2 = 8.1
I will give 100 Points, 5-stars, and Brainliest
Direct contact is necessary for which type of energy transfer?
A. Conduction
B. Sound Waves
C. Conduction
D. Convection
Answer:
Conduction
Explanation:
Because when a molecule is transferred to another molecule then this in going into direct contact
For example if we have a pan and it is boiling well the heat that is on the pan holder that stays in place and it won`t move anywhere else like there is Radiation and Convection but for this question the answer would be Conduction
Wire coils spinning between two magnets will produce …?
A: cold
B : electricity
C: chemicals
D: Steam
Answer:
B
Explanation:
I don't know but its b
Guys plz i need those answers as soon as possible
9) a) formula = h(ρ)g by default g=9.8m/s²
Pressure = 2×1000×9.8 = 19600Pa
b)
1. Look at this data table
What data seems to be inconsistent with the rest? What are 2 different explanations for this data?
Using visual inspection and knowledge of linear regression , the inconsistent input is the last data point (30, 12.0).
Looking at the data, there is a negative relationship between the depth of water sample and the amount of dissolved oxygen. As the depth increases, the amount of dissolved oxygen decreases. However, the last data point does not concur with this trend. This might have been caused by imputation error or error in the measuring device used.Therefore, the inconsistent data point is (30, 12.0)
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Which of the following processes generated heat during earths formation that is still a source of heat in earths interior
Answer:
There are three main sources of heat in the deep earth: (1) heat from when the planet formed and accreted, which has not yet been lost; (2) frictional heating, caused by denser core material sinking to the center of the planet; and (3) heat from the decay of radioactive elements28
If it takes 1,697 m to stop a car initially moving at 46 m/s, what distance is required to stop a car moving at a quarter
of the initial speed under the same conditions?
Answer:
Approximately [tex]106\; \rm m[/tex], [tex](1/16)[/tex] of the original distance, assuming that the acceleration is constant.
Explanation:
Let [tex]v[/tex] and [tex]u[/tex] denote the final and initial velocity of the vehicle ([tex]v = 0\; \rm m \cdot s^{-1}[/tex] since this vehicle has come to a stop.)Let [tex]a[/tex] denote the acceleration of the vehicle (a constant under the assumption.) Let [tex]x[/tex] denote the displacement of the vehicle.If the acceleration on this vehicle is constant, the SUVAT equations would apply:
[tex]\displaystyle v^{2} - u^{2} = 2\, a\, x[/tex].
Rearrange this equation to find an expression for [tex]x[/tex], the displacement required for the vehicle to come to a stop:
[tex]\begin{aligned} x &= \frac{v^{2} - u^{2}}{2\, a} \\ &= \frac{-u^{2}}{2\, a} && (\text{$v = 0\; \rm m \cdot s^{-1}$})\end{aligned}[/tex].
Thus, under these assumptions, [tex]x[/tex] would be proportional to [tex]u^{2}[/tex]. In other words, the distance required for this vehicle to come to a stop would be proportional to the square of the initial velocity of this vehicle.
If the initial velocity [tex]u[/tex] is reduced to [tex](1/4)[/tex] (a quarter) of the initial value, the distance required for stopping this vehicle would be [tex](1/4)^{2} = (1/16)[/tex] of the initial value:
[tex]\begin{aligned}1,\!697\; {\rm m} \times \frac{1}{16} \approx 106\; \rm m\end{aligned}[/tex].
What is the difference between a low tide and a high tide
Answer:
High water level during a tide is called High tide.
Low water level during a tide is called Low tide.
State a hypothesis about your estimated daily water use.
Answer
Estimates vary, but, on average, each person uses about 80-100 gallons of water per day, for indoor home uses.
Explanation:
A copper (Young's modulus 1.1 x 1011 N/m2) cylinder and a brass (Young's modulus 9.0 x 1010 N/m2) cylinder are stacked end to end, as in the drawing. Each cylinder has a radius of 0.24 cm. A compressive force of F = 7900 N is applied to the right end of the brass cylinder. Find the amount by which the length of the stack decreases.
We have that for the Question, it can be said that the amount by which the length of the stack decreases is
[tex]dl'=3.621*10^{-4}m[/tex]
From the question we are told
A copper (Young's modulus 1.1 x 1011 N/m2) cylinder and a brass (Young's modulus 9.0 x 1010 N/m2) cylinder are stacked end to end, as in the drawing. Each cylinder has a radius of 0.24 cm.
A compressive force of F = 7900 N is applied to the right end of the brass cylinder. Find the amount by which the length of the stack decreases.
Generally the equation for copper cylinder is mathematically given as
[tex]dl=\frac{Flo}{yA}[/tex]
[tex]dl=\frac{7900*3*10^-^2}{1.1*10^{11}*\pi(0.24*10^{-2})^2}[/tex]
[tex]dl=1.19064778*10^-^4[/tex]
Generally the equation for brass cylinder is mathematically given as
[tex]dl=\frac{7900*5*10^-^2}{9*10^{10}*\pi(0.24*10^{-2})^2}[/tex]
[tex]dl=2.43*10^{-4}[/tex]
Therefore Total change in length
[tex]dl'=1.191*10^-^4+(2.43*10^{-4})[/tex]
[tex]dl'=3.621*10^{-4}m[/tex]
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The horizontal movement of air from an area of high pressure to an area of lower pressure
options:
wind
weather
heat
conduction
Answer:
Explanation:
A wind is the horizontal movement of air from an area of high pressure to an area of lower pressure. Winds are caused by differences in air pressure. Most differences in air pressure are caused by unequal heating of the atmosphere
Hello everyone, I just want to know the formula to solve this problem:
What is the speed of sound at 62°C?
and how to solve this kind of problem? My brain isn't working.. :)
Answer:
367 m/sExplanation:
Use simplified formula:
[tex]v=331.3\sqrt{1+T/273.15}[/tex] , where T- temperature in Celsius