Find the missing angle measurement in each set of supplementary angles.
Supplementary angles sum up to 180°. Take the missing angle as 'x'.
148 + x = 180
x = 180 - 148
x = 32°
=》 Angle ABD = 32°
_________
Hope it helps!
RainbowSalt2222 ☔
Answer:
32 degrees
Step-by-step explanation:
Hi there!
Angle ABC measures 180 degrees since it's a straight line.
To find angle ABD, we simply subtract the given angle that measures 148 degrees from 180:
180-148 = 32
Therefore, angle ABD measures 32 degrees.
I hope this helps!
what is 4xy - 5y² - 3x² from 5x + 3y² - xy ?
[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]
The equivalent expression is ~
[tex] \boxed{ \sf8 {y}^{2} + 3 {x}^{2} + 5x - 5xy}[/tex]
[tex] \large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}[/tex]
Let's solve ~
[tex]5x² + 3 {y}^{2} - xy - (4xy - 5y {}^{2} - 3 {x}^{2} )[/tex][tex]5x² + 3 {y}^{2} - xy - 4xy +5 {y}^{2} + 3 {x}^{2} [/tex][tex]3 {y}^{2} + 5 {y}^{2} + 3 {x}^{2} + 5x² - xy - 4xy[/tex][tex]8 {y}^{2} + 8 {x}^{2} - 5xy[/tex]Task 2: Components of Your Will
Describe the components of your will and how you will specify each one.
Type your response here:
20 points answer please
Answer:
just d
Step-by-step explanation:
Hope this helps!❆
Which situation can be represented by this inequality?
135 ≤ 10r + 15
Question 6 options:
A-Hugo has 10 songs in his music player. He will add 15 songs every month. Hugo collects songs for r months. For what values of r will Hugo have at most 135 songs?
B-Hugo has 10 songs in his music player. He will add 15 songs every month. Hugo collects songs for r months. For what values of r will Hugo have at least 135 songs?
C-Hugo has 15 songs in his music player. He will add 10 songs every month. Hugo collects songs for r months. For what values of r will Hugo have at most 135 songs?
D-Hugo has 15 songs in his music player. He will add 10 songs every month. Hugo collects songs for r months. For what values of r will Hugo have at least 135 songs?
The true option is: (d) Hugo has 15 songs in his music player. He will add 10 songs every month. Hugo collects songs for r months. For what values of r will Hugo have at least 135 songs?
The inequality is given as:
[tex]\mathbf{135 \le 10r + 15}[/tex]
Rewrite as:
[tex]\mathbf{10r + 15\ge 135 }[/tex]
From the options, we can see that the inequality represents songs in a music player.
Linear inequalities can be represented as:
[tex]\mathbf{mx + b \ge y}[/tex]
Where:
m represents the rate i.e. 10
b represents the y-intercept or base i.e. 15
>= represents at least
So, the inequality can be interpreted as:
10 songs are added every monthThe base number of songs is 15He wants to have at least 135 songsHence, the true option is (d)
Read more about linear inequalities at:
https://brainly.com/question/11897796
С
12 yd.
5 yd.
What is the length of the hypotenuse? If necessary, round to the nearest tenth.
C=
yards
Answer:
C = 13
Step-by-step explanation:
A²+B²=C²
where c is the hypothenuse
5²+12²=c²
25+144=c²
169=c²
√169 = c
13 = c
(PICTURE PROVIDED)
HELPPPPPPPPP PLS
the average adult human has approximately 2.5 x10^13 red blood cells and 7 x 10^9 white blood cells ,about how many times greater is the number of red blood cells as the number of white blood cells
Step-by-step explanation:
The no. of red blood cells is 2.4993*10^13 more than the no. of white blood cells
pls help with this question asap!
Answer:
ggggggggggggggggggggg
explain each step please :)
Answer:
u need to use the quadratic formula
Step-by-step explanation:
I think this is about it
What is product in math.
Answer:
so when you Mutpliy #*# = #product
Step-by-step explanation:
EX: 3*4=12
(x+a)^2 -7 = x^2 +10x +b
Work out the value of a and b.
Answer:
(x+a)²-7=x²+10x+b
simplifying,we get
x²+2ax+a²-7=x²+10x+b
the coefficient of x on both sides should be equal
therefore
2a=10
a=10/2=5
also for b
a²-7=b
5²-7=25-7=b
b=18
a=5
What will be displayed when the following code is executed? number = 6 while number > 0: number -= 3 print(number, end = ' ').
With number = 6, the while condition is satisfied. Then number is decremented by 3, meaning we replace the value of number (6) with its current value minus 3 6 - 3 = 3.
Then with number = 6, we still have number > 0, so we decrement again and end up with number = 0.
With number = 0, number > 0 is no longer true, so we exit the loop.
Then the print statement simply prints the current value of number, which is 0.
Solve.
x−(−2 3/8)=−1/4
What is the solution to the equation?
Enter your answer as a simplified mixed number in the box.
X= ??
Please help if you can! A photographer rented a booth at an art fair for $630. The photographer sold each photograph for $45 and made a total of $1,980 after paying for the booth. How many photographs did the photographer sell at the fair?
He needed to make a total of 1980 + 630 = $2610
$2610 / 45 = 58
Answer: 58
What is the equation for the line in slope-intercept form?
Enter your answer in the box. I'll give you 100 points
Answer:
y = -4x + 5.
Explanation:
Count rise/run to find the slope, find the y-intercept.
Answer:
y = -4x + 3
Step-by-step explanation:
First, find the slope using two points [(-2, 13), (0, 5)] and the formula [ y2-y1/x2-x1 ].
5-13/0-(-2)
-8/2
-4
Second, find the y-intercept which we know is (0, 5) since we used it in the previous part.
Third, input everything we found.
y = -4x + 5
Best of Luck!
Owen had 8,452 books donated to our school. If he shares with with 23 classes about how many books does each class get? Again assesment due tom :,)
Answer:
327.5
Step-by-step explanation:
8452/23 = 327.478
Round to about 327.5 books per class
Answer:
each class gets 367 books
1) -x2
-Х2
I need help with this problem
Let A be a given matrix below. First, find the eigenvalues and their corresponding eigenspaces for the following matrices. Then, find an invertible matrix P and a diagonal matrix such that A = PDPâ’1.
(a) [ 3 2 2 3 ]
(b) [ 1 â 1 2 â 1 ]
(c) [1 2 3 0 2 3 0 0 3]
(d) [3 1 1 1 3 1 1 1 3]
It looks like given matrices are supposed to be
[tex]\begin{array}{ccccccc}\begin{bmatrix}3&2\\2&3\end{bmatrix} & & \begin{bmatrix}1&-1\\2&-1\end{bmatrix} & & \begin{bmatrix}1&2&3\\0&2&3\\0&0&3\end{bmatrix} & & \begin{bmatrix}3&1&1\\1&3&1\\1&1&3\end{bmatrix}\end{array}[/tex]
You can find the eigenvalues of matrix A by solving for λ in the equation det(A - λI) = 0, where I is the identity matrix. We also have the following facts about eigenvalues:
• tr(A) = trace of A = sum of diagonal entries = sum of eigenvalues
• det(A) = determinant of A = product of eigenvalues
(a) The eigenvalues are λ₁ = 1 and λ₂ = 5, since
[tex]\mathrm{tr}\begin{bmatrix}3&2\\2&3\end{bmatrix} = 3 + 3 = 6[/tex]
[tex]\det\begin{bmatrix}3&2\\2&3\end{bmatrix} = 3^2-2^2 = 5[/tex]
and
λ₁ + λ₂ = 6 ⇒ λ₁ λ₂ = λ₁ (6 - λ₁) = 5
⇒ 6 λ₁ - λ₁² = 5
⇒ λ₁² - 6 λ₁ + 5 = 0
⇒ (λ₁ - 5) (λ₁ - 1) = 0
⇒ λ₁ = 5 or λ₁ = 1
To find the corresponding eigenvectors, we solve for the vector v in Av = λv, or equivalently (A - λI) v = 0.
• For λ = 1, we have
[tex]\begin{bmatrix}3-1&2\\2&3-1\end{bmatrix}v = \begin{bmatrix}2&2\\2&2\end{bmatrix}v = 0[/tex]
With v = (v₁, v₂)ᵀ, this equation tells us that
2 v₁ + 2 v₂ = 0
so that if we choose v₁ = -1, then v₂ = 1. So Av = v for the eigenvector v = (-1, 1)ᵀ.
• For λ = 5, we would end up with
[tex]\begin{bmatrix}-2&2\\2&-2\end{bmatrix}v = 0[/tex]
and this tells us
-2 v₁ + 2 v₂ = 0
and it follows that v = (1, 1)ᵀ.
Then the decomposition of A into PDP⁻¹ is obtained with
[tex]P = \begin{bmatrix}-1 & 1 \\ 1 & 1\end{bmatrix}[/tex]
[tex]D = \begin{bmatrix}1 & 0 \\ 0 & 5\end{bmatrix}[/tex]
where the n-th column of P is the eigenvector associated with the eigenvalue in the n-th row/column of D.
(b) Consult part (a) for specific details. You would find that the eigenvalues are i and -i, as in i = √(-1). The corresponding eigenvectors are (1 + i, 2)ᵀ and (1 - i, 2)ᵀ, so that A = PDP⁻¹ if
[tex]P = \begin{bmatrix}1+i & 1-i\\2&2\end{bmatrix}[/tex]
[tex]D = \begin{bmatrix}i&0\\0&i\end{bmatrix}[/tex]
(c) For a 3×3 matrix, I'm not aware of any shortcuts like above, so we proceed as usual:
[tex]\det(A-\lambda I) = \det\begin{bmatrix}1-\lambda & 2 & 3 \\ 0 & 2-\lambda & 3 \\ 0 & 0 & 3-\lambda\end{bmatrix} = 0[/tex]
Since A - λI is upper-triangular, the determinant is exactly the product the entries on the diagonal:
det(A - λI) = (1 - λ) (2 - λ) (3 - λ) = 0
and it follows that the eigenvalues are λ₁ = 1, λ₂ = 2, and λ₃ = 3. Now solve for v = (v₁, v₂, v₃)ᵀ such that (A - λI) v = 0.
• For λ = 1,
[tex]\begin{bmatrix}0&2&3\\0&1&3\\0&0&2\end{bmatrix}v = 0[/tex]
tells us we can freely choose v₁ = 1, while the other components must be v₂ = v₃ = 0. Then v = (1, 0, 0)ᵀ.
• For λ = 2,
[tex]\begin{bmatrix}-1&2&3\\0&0&3\\0&0&1\end{bmatrix}v = 0[/tex]
tells us we need to fix v₃ = 0. Then -v₁ + 2 v₂ = 0, so we can choose, say, v₂ = 1 and v₁ = 2. Then v = (2, 1, 0)ᵀ.
• For λ = 3,
[tex]\begin{bmatrix}-2&2&3\\0&-1&3\\0&0&0\end{bmatrix}v = 0[/tex]
tells us if we choose v₃ = 1, then it follows that v₂ = 3 and v₁ = 9/2. To make things neater, let's scale these components by a factor of 2, so that v = (9, 6, 2)ᵀ.
Then we have A = PDP⁻¹ for
[tex]P = \begin{bmatrix}1&2&9\\0&1&6\\0&0&2\end{bmatrix}[/tex]
[tex]D = \begin{bmatrix}1&0&0\\0&2&0\\0&0&3\end{bmatrix}[/tex]
(d) Consult part (c) for all the details. Or, we can observe that λ₁ = 2 is an eigenvalue, since subtracting 2I from A gives a matrix of only 1s and det(A - 2I) = 0. Then using the eigen-facts,
• tr(A) = 3 + 3 + 3 = 9 = 2 + λ₂ + λ₃ ⇒ λ₂ + λ₃ = 7
• det(A) = 20 = 2 λ₂ λ₃ ⇒ λ₂ λ₃ = 10
and we find λ₂ = 2 and λ₃ = 5.
I'll omit the details for finding the eigenvector associated with λ = 5; I ended up with v = (1, 1, 1)ᵀ.
• For λ = 2,
[tex]\begin{bmatrix}1&1&1\\1&1&1\\1&1&1\end{bmatrix}v = 0[/tex]
tells us that if we fix v₃ = 0, then v₁ + v₂ = 0, so that we can pick v₁ = 1 and v₂ = -1. So v = (1, -1, 0)ᵀ.
• For the repeated eigenvalue λ = 2, we find the generalized eigenvector such that (A - 2I)² v = 0.
[tex]\begin{bmatrix}1&1&1\\1&1&1\\1&1&1\end{bmatrix}^2 v = \begin{bmatrix}3&3&3\\3&3&3\\3&3&3\end{bmatrix}v = 0[/tex]
This time we fix v₂ = 0, so that 3 v₁ + 3 v₃ = 0, and we can pick v₁ = 1 and v₃ = -1. So v = (1, 0, -1)ᵀ.
Then A = PDP⁻¹ if
[tex]P = \begin{bmatrix}1 & 1 & 1 \\ 1 & -1 & 0 \\ 1 & 0 & -1\end{bmatrix}[/tex]
[tex]D = \begin{bmatrix}5&0&0\\0&2&0\\0&2&2\end{bmatrix}[/tex]
PLS HELP WILL MARK BRAINLIEST, PLS HURRY
Answer:
B
Step-by-step explanation:
p=5(q-2r)/r
solve for r
Answer:
r = 5q / (p + 10)
Step-by-step explanation:
p = 5(q - 2r)/r
multiply both sides by r
pr = 5(q - 2r)
distribute
pr = 5q - 10r
add 10r to both sides
pr + 10r = 5q
Factor out r
r(p + 10) = 5q
divide both sides by p + 10
r = 5q / (p + 10)
what is the simplified fractional equivalent of the terminating decimal 0.12?
Answer:
6/50
Step-by-step explanation:
0.12 as a fraction is 6/50.
Answer:
3/25
Step-by-step explanation:
12/100=6/50=3/25 .
Of the following sets which are equivalent to the set S = {an even number less than 10 } is
A = {Prime number less than 10 }
B = {Odd factor less than 15}
C= {Odd numbers less than 7}
D ={An even number between 10 and 15}
E ={An odd number between 10 and 16}
Answer:
A, 2
Step-by-step explanation:
We can immediately rule out B and C; they are odd numbers while S is an even number.
We can also rule out D and E. This is because D and E are greater than or equal to 10, while S is less than 10.
A number that can fulfill the requirements for both A and S is 2
How is the graph of g(x) = [tex](x-10)^{2}[/tex] related to the graph of f(x)= [tex]x^{2}[/tex]
(x - 10)² is the graph x² by translation of 10 units moved to the right.
What is the slope of the line?
Answer:
2
Step-by-step explanation:
Slope equals rise over run. use the slope formula
slope= (y2-y1)/(x2-x1)
find two points on the line. I used points (0,1) and points (1,3)
0=x1
1=y1
1=x2
3=y2
plug into the equation and you get
(3-1)/(1-0)=2
What sentence represents this equation?
912=15−x
912 is the same as a number decreased by 15.
912 is the same as 15 decreased by a number.
15 decreased by 912 is the same as a number.
A number is the same as the difference of 15 and 912.
The sentence representing the equation is 912 is the same as 15 decreased by a number.
What is an equation?An equation is a mathematical statement that shows that two mathematical expressions are equal.
Given an equation, 912 = 15 − x
Here, 912 is equal to a number which is being subtracted from 15.
Hence, The sentence representing the equation is 912 is the same as 15 decreased by a number.
For more references on equation, click;
https://brainly.com/question/10413253
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There are only red sweets and yellow sweets in a bag.
There are n red sweets in the bag.
There are 8 yellow sweets in the bag.
Sajid is going to take at random a sweet from the bag and eat it.
7
He says that the probability that the sweet will be red is
10
7
10
(a) Show why the probability cannot be
Using the probability concept, it is found that since the number of red sweets would be a decimal number, the probability cannot be [tex]\frac{7}{10}[/tex]
A probability is the number of desired outcomes divided by the number of total outcomes.
In this problem:
In total, there are 8 + n sweets in the bag.Of those, n are red.The probability of red is:
[tex]p = \frac{n}{n + 8}[/tex]
Supposing [tex]p = \frac{7}{10}[/tex], we solve for n:
[tex]\frac{n}{n + 8} = \frac{7}{10}[/tex]
[tex]10n = 7n + 56[/tex]
[tex]3n = 56[/tex]
[tex]n = \frac{56}{3}[/tex]
[tex]n = 18.67[/tex]
Since the number of red sweets would be a decimal number, the probability cannot be [tex]\frac{7}{10}[/tex]
A similar problem is given at https://brainly.com/question/15536019
Which is the better deal? $39.55 for 7 pairs of jeans OR $22.48 for 4 pairs of jeans
Answer:
$22.48 for 4 pairs of jeans is a better deal.
Step-by-step explanation:
To find the price of one pair of jeans, you divide.
39.55 ÷ 7 = price of 1 pair of jeans
39.55 ÷ 7 = $5.65
22.48 ÷ 4 = price of 1 pair of jeans
22.48 ÷ 4 = $5.62
The price difference between the two prices is 3 cents. So, $22.48 for 4 pairs is a better deal that $39.55 for 7 pairs of jeans.
Hope this helps!
b) Express 0.6363......as a rational number in its lowest term.
Answer:
[tex]\frac{7}{11}[/tex]
Step-by-step explanation:
We require 2 equations with the repeating digits (63) placed after the decimal point.
let x = 0.636363..... (1) multiply both sides by 100
100x = 63.6363... (2)
Subtract (1) from (2) thus eliminating the repeating digits
99x = 63 ( divide both sides by 99 )
x = [tex]\frac{63}{99}[/tex] = [tex]\frac{7}{11}[/tex] ← in simplest form
kokokokokkokokokokokookokokk.
Answer:
OMG️️
Step-by-step explanation:
What is this❓
what have you wrote✍️
Answer:
hye nice what have written tell then I will answer you.