A RL circuit is driven by an AC generator as shown in the figure. sin(ot) The voltages across the resistor and generator are ??.
O always out of phase O always in phase sometimes in phase and O sometimes out of phase Submit

The velocity of the object is 7.74m/s

Though it may sound sophisticated, velocity is simply the rate at which an object's location changes with regard to a frame of reference and time. Since it is a vector quantity, the definition of velocity requires both magnitude (speed) and direction.

We are given that,

Acceleration = 12m/s²

Radius = r = 5.0m

Velocity = v = ?

The velocity of the object can be calculated by the formula ,

a = v²/r

v = √ar

v = √12m/s²× 5m

v = √60m²/s²

v= 7.74m/s

Thus , the velocity of the object would be 7.74m/s.

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Two charged particles are located on the x axis.

What are charged particles?

Charged particles are particles that have either a positive or negative electrical charge. These particles can be found in many forms in nature, such as electrons, protons, and ions. These particles are a key component of electricity, and can be used as a source of energy. Charged particles can be found in atoms and molecules, where they interact with other particles and affect their behavior. They can also be found in plasma, a state of matter that is made up of ions and electrons.

1. Start by writing out the equation for the electric field at the origin:

E = (kQ)/r^2

2. Substitute in the values for Q, k, and r, and solve for the unknown charge:

E = (2keQ)/a^2

E = (2k(+Q))/(3a)^2

+Q = (2kE)/(3a)^2

Since the electric field has a magnitude of 2keQ / a2, the unknown charge can be either positive or negative:

+Q = ±(2kE)/(3a)^2

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It is important to note that the dot product and cross product of any two non-zero vectors cannot both be zero therefore  A×B and A·B cannot both be zero.

In vector space, a non-zero vector. V is a vector that differs from the zero vector in V. If u is a non-zero vector in V and an is a scalar, i.e. an element of the field over which V is defined, then au=0 is only possible if a=0.

The product of any two non-zero vectors is non-zero in this vector context. It is referred to as Hamilton's Quaternions. Over the real numbers, quaternions form a four-dimensional vector space, and their multiplication is a combination of dot product and cross product.

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The horizontal displacement of the cannonball  is  65.75 meter.

Speed is characterized as the rate at which an object's position changes in any direction. The distance travelled in relation to the time it took to travel that distance is how speed is defined. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.

original speed: u= 35.9 m/s.

acceleration due to gravity: g = 9.8 m/s².

Initial height of the cannonball = 166 m.

Hence,  the horizontal displacement of the cannonball = u²/2g

= 35.9²/(2×9.8) meter

= 65.75 meter.

so, the displacement of the cannonball  is  65.75 meter.

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When feelings of anxiety and worry become excessive, out of control, and interfere with daily life, they can develop into pathological diseases called anxiety disorders. So the correct option is (c).

Anxiety disorders are characterized by feelings of apprehension and fear, which are normal human emotions. However, when these feelings become excessive, uncontrollable, and affect daily life, they can be considered a pathological disorder. Anxiety disorders can affect a person's ability to perform daily activities, such as work or school, and can also cause physical symptoms such as insomnia, muscle tension, and fatigue. These disorders can be recurrent, but they need to be excessive, uncontrollable, and affect daily life in order to be considered pathological.

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The mass of water displaced when the mass of bird bone in water and air is given, is calculated to be 43.4 g.

Given that,

Weight of bird bone in air = True weight = 47 g

Apparent weight of the bird bone when submerged = 3.6 g

The equation for apparent weight is known to be,

Apparent weight = True weight - Buoyant force

Making Buoyant force as subject, we have,

Buoyant force = 47 g - 3.6 g = 43.4 g

F b = mw × g = (m wat - m air)× g

mw = m wat - m air = 47 g - 3.6 g = 43.4 g

Thus, the mass of the water displaced is 43.4 g.

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The definition of constant velocity is the speed of a moving object that doesn't change over time. The system travelling at a constant speed is subject to zero net acceleration.

In contrast to instantaneous velocity, which is determined by slope of tangent line, average speed is defined as the shift in location (or displacement) during the course of transit.

Speed is the measure of velocity in magnitude. As a result, it is impossible to have two objects moving at the same velocity. The right response is therefore option A.

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The correct option is A, B, and C. A block resting on a slope is Weight, static friction, and Normal force.

Static friction is a force that continues an item at relaxation. Static friction definition can be written as: The friction skilled while individuals try to move a desk-bound object on a surface, without surely triggering any relative movement between the frame and the surface on which it's miles.

Static friction is a form of friction force that acts on a body when there's no relative motion between the object and the surface. So, it can act even if the frame is in motion however there should be no relative motion.

A pressure acting on an item is said to be a static force if it no longer exchanges the scale, function, or route of that precise object. The pressure implemented to a structure acts as a load to that precise structure, that is why static force is likewise called a static load.

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Complete Question:

A block is resting on a slope. (Figure 3) Which of the following forces act on the block?

Check all that apply.

A). Weight

B). Static friction

C). Normal force

D). Kinetic friction

E). Force of push

As Projectile range is independent of mass, so They all will have same range.

When an object is close to Earth's surface, its gravitational attraction is calculated using the formula F = mg, where m is the object's mass and g is a constant whose value varies depending on the location. On the surface of the earth, it averages 9.81 meters per second. And when one moves away from the surface in either an inner or an outward direction, this value drops.

Although the strength of the earth's gravitational pull changes depending on the mass of the object, the acceleration caused by it is constant (of course close to the surface). Consequently, when two items of different masses are dropped from the same height, they hit the ground simultaneously (neglect air resistance).

Any motion of a projectile simply consists of vertical and horizontal motion. Regardless of the direction the projectile is going in, gravity controls vertical motion since it only acts in that direction. Additionally, the acceleration caused by gravity is not reliant on the mass of the item. Therefore, the mass has no bearing on the vertical motion.

A projectile moves horizontally in a very straightforward manner. A projectile is not affected by horizontal forces. As a result, its horizontal velocity does not change. Additionally, the range is influenced by horizontal velocity and flying time. Flight time is influenced by vertical motion.

We now know that mass has no bearing on flying duration or range. And if you run into a projectile motion problem, simply divide the problem into horizontal and vertical motions. And handle it the same way you would a single-direction motion. greatly simplifies matters.

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Answer:

6.9 m/s

Explanation:

This is a conservation of momentum problem, so the total momentum before the collision must equal the total momentum after the collision.

P = mv

m1v1 + m2v2 (before) = m1v1 + m2v2 (after)

(3250kg)(25.0 m/s) + (2820 kg)(0m/s) = (3250 kg)(19.0 m/s) + (2820 kg)(v2)

Now you can solve for the v of the car after the collision:

81250 kg·m/s + 0 = 61750 kg·m/s + (2820 kg)v2

19500 kg·m/s = (2820 kg)v2

v2 = 19500 kg·m/s / 2820 kg = 6.9 m/s

The statement is not correct the mass of the jam is 500g and the density of the jam is 0.125gm/cm³

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The gravitational force on the car is 23000 N, the vertical normal (support/reaction) force acting on the car is 0 N, and the horizontal force on the car's tyres from the road is 5460 N.

Mass of the car, m = 2300 kg

Force acting on the car, F = 5000 N

The initial speed of the car, u = 10 m/s

The final speed of the car, v = 14 m/s

Time, t = 20 s

The gravitational force on the car is calculated by the formula given as

F = mg

F = 2300 × 10

F = 23000 N

Now, as there is no vertical movement in the car therefore the vertical force acting on the car is 0 N.

The horizontal force on the car's tyres from the road

= force acting on the car + net force on the car

= 5000 + ma

= 5000 + 2300 × (v-u)/t

= 5000 + 2300 × (14 - 10)/20

= 5000 + 2300 × 4/20

= 5000 + 460

= 5460 N

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The seatback must be adjusted far enough for your wrist to rest on the top of the steering wheel when your arm is comfortably extended.

The majority of modern automobiles, compact trucks, and SUVs have a rack and pinion steering. This transforms the steering wheel's rotational action into the linear motion which rotates the wheels and directs your course. A steering pinion, a circular gear, is used in the system to lock teeth on a rod (the rack).

The basic device at work in steering, doorknobs, turbines, and bicycle wheels is a wheel and axle. An inclined plane wound around a cylinder is known as a screw.

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Answer:

23.4 kg m/s

Explanation:

p = mv = 0.013kg × 1800m/s = 23.4 Kg.m/s

The current through the bottom of the wire is 0.415 A and the negative sign of the current indicates that current flows from left to right from the bottom wire.

The current through various parts of the circuit is as shown in figure.

Here we have to calculate the current I_5.

Applying Kirchoff's loop rule on each of the loops in the circuit, Consider the left triangle, for it, we have

[tex]$$\begin{aligned}& \left(I_1\right) 6 \Omega+\left(I_3\right) 12 \Omega-9 \mathrm{~V}=0 \\& \Rightarrow 6 I_1+12 I_3=9 \\& \Rightarrow I_1=\frac{9}{6}-\frac{12}{6} I_3 \\& \Rightarrow I_1=1.5-2 I_3-----(1)\end{aligned}$$[/tex]

For the centre of the triangle, we have

[tex]$$\begin{aligned}& \left(I_4\right) 24 \Omega-\left(I_3\right) 12 \Omega=0 \\& \Rightarrow I_4=\frac{12}{24} I_3 \\& \Rightarrow I_4=\frac{I_3}{2}-----(2)\end{aligned}$$[/tex]

And for the right triangle, we have

[tex]$$\begin{aligned}& \left(I_2\right) 10 \Omega+\left(I_4\right) 24 \Omega-15 \mathrm{~V}=0 \\& \Rightarrow I_2=\frac{15}{10}-\frac{24}{10} I_4 \\& \Rightarrow I_2=1.5-2.4 I_4------(3)\end{aligned}$$[/tex]

The junction rule applied at the left corner gives

I_1  =I_3+I_5

=I_5  =I_1-I_3

=1.5-2 I_3-(I_3)=1.5-3 I_3--------(4)

And applying the junction rule at the right corner,

I_4 =I_2+I_5

I_5 =I_4-I_2

=I_4-(1.5-2.4 I_4)=3.4 I_4-1.5-------(5)

Using equation (2) [tex]$I_4=\frac{I_3}{2}$[/tex], equation (5) can be written as

[tex]$$\begin{aligned}I_5 & =3.4\left(\frac{I_3}{2}\right)-1.5 \\\end{aligned}$$[/tex]==1.7 I_3-1.5

Solving equations (4) and (6), we have

1.5-3 I_3=1.7 I_3-1.5

(1.5+1.5)=(1.7+3.0) I_3

3.0=4.7 I_3

[tex]\Rightarrow I_3=\frac{3.0}{4.7} \mathrm{~A}[/tex]

Hence the current in the bottom wire is given by

[tex]I_5 & =1.7\left(\frac{3.0}{4.7}\right)-1.5 \\[/tex] =1.085-1.5 =-0.415 A

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Answer: -39200.45 Nm^2/C^2       This is rough work

Explanation:

So, the net force will be felt on particle [tex]\sf{q_1}[/tex] approximately 15.39 N to the right.

Hi! Here I will explain the net force of three charges that interacts. Remember that this question can be solved using Coulomb's Law. Coulomb's Law states that the interaction force between two interacted charges will be proportional to the magnitude of the charges that have specific interaction but inversely proportional to the square of the value of the distance between each other. So, with this concept, we can calculate the magnitude of coulomb force with this equation:

[tex] \boxed{\sf{\bold{F = k \cdot \frac{q_1 \cdot q_2}{(r_{12})^2}}}} [/tex]

On this condition, the net force will be felt only by the first charge, so we must define the position of the first charge as a fixed one. So, we can calculate the magnitude of coulomb force concerning the first charge with this equation:

[tex] \boxed{\sf{\bold{\sum F_{q1} = k \cdot (\frac{q_1 \cdot q_2}{(r_{12})^2} + \frac{q_1 \cdot q_3}{(r_{13})^2})}}} [/tex]

With the following condition:

[See the attached image to know how to solve this problem]

So, the net force will be felt on particle [tex]\sf{q_1}[/tex] approximately 15.39 N to the right.

The expression for drag force that is proportional to the speed of the object is known as linear drag, while the expression that is proportional to the square of the speed is known as quadratic drag.

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R= 2+4=6Ω

in series connection, same current and different voltage

total voltage= total current × total resistance

6=I×6

I=6/6= 1A

voltage across 4Ω resistor= 1×4=4v

Therefore, heat dissipated by the 4Ω resistor in 5s= (v²/R)×t= (4²/4)× 5 = 16/4 × 5 = 20J

Static stretching and passive stretching are very similar in that they both involve moving the limbs into and holding the stretch posture.

Static stretching involves the individual holding their own limbs in place, while passive stretching involves a partner assisting with the movement and holding of limbs. When you stretch to your limit and hold that position, you are engaging in a form of stretching known as static stretching. Passive stretching, on the other hand, is also a form of static stretching; however, during this technique, you remain relaxed and do not actively participate in increasing your range of motion.

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The final speed of the second car is '2v' and the collision is elastic collision.

The elastic collision is one in which the system does not experience a net loss of kinetic energy as the result of a collision. In elastic collisions, momentum & kinetic energy are both conserved.

v′ = m1v1 + m2v2 /m1+m2

v ′ = m 1 v 1 + m 2 v 2/ m 1 + m 2

in which m1 is mass of body 1, v1 is its initial speed, m2 is mass of body 2, & v2 is the final speed at which the two objects will be moving after colliding.

m1v +0 = mv/3 +m/3v2

v2 = 2v

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it takes about 26 seconds for speed of light with approximate speed of 3\times10^5  kilometers per second to reach Jupiter.

To calculate the time it takes light to reach Jupiter, we need to know the distance between the Sun and Jupiter. The average distance between the Sun and Jupiter is approximately 778 million kilometers. We can use the formula distance = speed x time to calculate the time it takes for sunlight to reach Jupiter. We know that the speed of light is approximately 3x10^5 kilometers per second and the distance between the Sun and Jupiter is 778 million kilometers.time = distance / speed

time = (77810^6 km) / (310^5 km/s)

time = 26 sec (approximately)

Therefore, it takes about 26 seconds for light to reach Jupiter.

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Answer:

27s

Explanation:

Time = distance/speed

Time = 219/8

Time = 27.375 s

Answer:

To solve this problem, you can use the formula F = ma, where F is the force applied to an object, m is the mass of the object, and a is the acceleration of the object. In this case, the force applied to the object is 51.3 newtons and the acceleration of the object is 48.7 m/s2. So, you can set up the equation like this:

51.3 newtons = m x 48.7 m/s2

To solve for the mass of the object, you can divide both sides of the equation by 48.7 m/s2:

51.3 newtons / 48.7 m/s2 = m x 48.7 m/s2 / 48.7 m/s2

This simplifies to:

1.05 kg = m

So, the mass of the softball is approximately 1.05 kilograms.

Mechanical energy is used to start the Ferris wheel, providing the initial rotation and motion to the wheel.

The motion of the wheel then causes the lights along the seats to be powered, allowing them to light up as the wheel turns. The wheel is then able to generate kinetic energy as it moves, which it then uses to continue turning.

As the wheel turns, it transfers its energy from mechanical to kinetic, and this energy is used to keep the wheel moving from start to finish. Kinetic energy is also used to power the centrifugal force which keeps the riders in their seats as the wheel turns, allowing them to enjoy the ride.

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According to Ohm's Law, the total current flowing through a circuit with a resistance of 1200 ohms and a 12 V power supply is equal to 0.01 ampere.

Electric current is inversely correlated with resistance according to Ohm's Law and proportionate to voltage. 'The law can be expressed mathematically as V = IR, in which 'V' is the voltage variation 'I' is the flowing current in amps, & the resistance (R) in ohm.

Given data :

Resistance = 1200 ohm

power supply = 12 V

By using Ohm's law

V = I × R

I = V / R

I = 12 / 1200

I = 0.01 ampere.

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The minimum force needed to apply a torque of 90 N.m to the screw using a wrench that is 30 cm long is 300 N.

What is force?

Force is a quantity that describes the interaction between two objects or systems. It is a vector quantity, meaning it has both magnitude (size or strength) and direction. Forces can cause changes in an object's motion, shape, or internal energy.

To find the minimum force needed to tighten the loose screw, we can use the equation:

F = T / r

where F is the force, T is the torque (90 N.m in this case), and r is the distance from the center of the screw to the point where the force is applied (the length of the wrench, 30 cm in this case).

We need to convert the length of the wrench from cm to meters before calculating the force:

r = 30 cm / 100 cm/m = 0.3 m

Now we can plug in the values into the equation and find the force:

F = 90 N.m / 0.3 m = 300 N

So the minimum force needed to apply a torque of 90 N.m to the screw using a wrench that is 30 cm long is 300 N.

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Dynamic flexibility tests are not used as often as static flexibility tests because dynamic flexibility tests involve more subjective measurements.

Static flexibility tests are more common in comparison to dynamic tests because static flexibility tests are easier to replicate. It is difficult to standardize motion-based tests such as dynamic flexibility tests between various subjects, while static flexibility tests are simple and easy to standardize it is because the metrics are fixed and not open to interpretation.

Since, dynamic flexibility tests are hard to perform because they measure the amount of stress on a muscle that is in motion. And it is difficult to assess this among multiple people and to get an accurate picture. That is why these tests are not used as often as static flexibility tests.

"

Complete question

Why are dynamic flexibility tests not used as often as static flexibility tests?

"

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Answer:

Work done is 2280 Joules.

Explanation:

Work done can be found using the formula

[tex]W=Fs\\[/tex]

where:
W is work done ( in Joules)
F is force ( in Newtons)
s is displacement ( in Meters)

Assuming we are on Earth, we can find the force acting on the object using the mass with the following:

Mass × 10 = Force

12.0 × 10 = 120N

Moreover, we can find displacement by simply subtracting the final distance from the starting distance:

22.0m - 3.00m = 19.0m

Therefore,

 [tex]W = Fs[/tex]

[tex]W = 120N[/tex] × [tex]19m[/tex]

[tex]W= 2280J[/tex]