7 pipes fill a tank in 50 minutes. How many minutes does it take if there are 11 pipes?
Give your answer to the nearest minute.

Answer:

10x + 18

Step-by-step explanation:

First, we need to add like terms. Like terms are terms that are alike. For instance 8x and 2x are like terms. 15 and 3 are also like terms.

So, we have to add 8x plus 2x and 15 plus 3. That’s comes out to 10x plus 18.

Therefore, this expression is equivalent to 10x + 18.

Answer:

160 pounds

Step-by-step explanation:

If she has 3 boxes and there's 40 more pounds than if she had one, that means each box is 20 pounds so multiply 20 by 8 and you get 160 pounds

Answer:500(1.2)^x

Plato :)

Answer:

3

Step-by-step explanation:

PLATO

;

Answer:

there is a graph first step to but I cannot draw it on here but you already have your answer without Step 2

Step-by-step explanation:

a simple path in a graph G that passes through every vertex exactly once is called a path . the graph G has no past because any past containing all vertices must contain one of the edges (e, c) (d, f ) and (B, G) move than once .

Answer:

f(x-7) =  x -12

Step-by-step explanation:

horizontal translation 7 units right: f(x-7)

f(x) = x - 5

f(x-7) = x-7 -5 = x -12

Answer:

0.4

Step-by-step explanation:

Answer:

15 fifths

Step-by-step explanation:

Answer:

3

Step-by-step explanation:

3/2 is equal to 1.5 and 3 1.5s can fit in 5 equaling 4.5

Answer:

4:1

Step-by-step explanation:

hope this helps

Answer:

The ratio is 1 hour to 1.5 laptops

Step-by-step explanation:

If you divide the time by amount done, there you have the answer.

Answer:

Step-by-step explanation:

Hi,

1) Find z if the standard normal curve area between -z and z is 0.4530.

Y1 = normalcdf(-x,x,0,1) - .4530 and x = .60226

a. ± 0.118

b. ± 0.398

c. ± 0.602 <==ANSWER

d. ± 0.752

2) If a random variable has the normal distribution with μ = 104.3 and σ = 5.7, find the probability that the value will be greater than 112.3

normalcdf(112.3, 500, 104.3, 5.7) = .08023

a. 0.08 <==ANSWER

b. 0.09

c. 0.10

d. 0.11

3) Determine a 90% confidence interval for μ if σ = 5, \bar{x} = 70, and n = 82. Answer interval rounded to two decimal places.

70 ± 1.645 (5/√82) or 69.09 to 70.91 <==ANSWER

I hope that helps!! :-)

Answer:

5 x 3/4 < 5

2 x 4/3 > 2

6 x 5/5 = 6

4/7 x 1/8 < 4/7

2/5 x 7/7 = 2/5

1/3 x 6/4 > 1/3

Answer: B. 77

Sub x =6 into the given expression

4x^2 - 12x + 5

= 4(6)^2 - 12(6) + 5

= 144 - 72 + 5

= 77

[tex]\\ \sf\longmapsto 4x^2-12x+5[/tex]

[tex]\\ \sf\longmapsto 4(6)^2-12(6)+5[/tex]

[tex]\\ \sf\longmapsto 4(36)-72+5[/tex]

[tex]\\ \sf\longmapsto 144-67[/tex]

[tex]\\ \sf\longmapsto 77[/tex]

Answer:

hope my answer is helpful to you

plz mark me as brainlist and also follow me

As QR is parallel to ST Rs is parallel TU QS is congruent to SU the measure of their included angle is also same ∠QRS ≅ ∠STU.

We know two similar planer figures are congruent when we have sides or angles or both that are the same as the corresponding sides or angles or both.

Given, Line segment QR is parallel to line segment ST.

Line segment RS is parallel to line segment TU, And line segment QS is similar to line segment SU.

So, The included angle of two pairs of parallel lines will also be the same as

line segment QS is similar to line segment SU.

∴ ∠QRS is similar to ∠STU.

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Answer:

D

Step-by-step explanation:

Connect the point already at (0, –2) to a new point at (2, 0), connect

(2, 0) to (2, 4), and then connect (2, 4) to (–2, 4).

Im pretty sure

Answer:

D

Step-by-step explanation:

Answer:

90

Step-by-step explanation:

Answer:

90 cupcakes

Step-by-step explanation:

So, to solve this question all we have to do is add the number of cupcakes that Dan brought and the number of cupcakes that his friend bought.

So the expression would look like this:

36 + 49 + 5 = 90

So, in conclusion, the bake sale had 90 cupcakes to sell

plz mark me brainliest if correct :)

The scale factor of PQRS to JKLM is 4/5 and the values of w, x and y are 20, 12.5 and 20 respectively.

A scale drawing is a drawing made by enlarging or reducing the size of the original object.

The factor by which the drawing is enlarged or reduced is called the scale factor.

Given two quadrilaterals PQRS and JKLM.

Since the shape is similar, the angles are equal and thus are similar figures.

The corresponding sides of two similar figures are proportional.

Scale factor of PQRS to JKLM = QR / KL = 12 / 15 = 4/5

Using the proportional rule for similar figures,

KL / QR = LM /RS  = MJ / SP = JK / PQ

15 / 12 = x / 10 = y / 16 = 25 / w

Scale factor = 15/12 = 5/4

Consider 15 / 12 = x / 10.

12x = 150

x = 12.5

Consider 15 / 12 = y / 16

12y = 15 × 16

y = 20

Consider 15 / 12 = 25 / w

15w = 12 × 25

w = 20

Hence the option d is the correct answer.

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Answer:

21

Step-by-step explanation:

set up proportion and solve

18/12=x/14 (cross multiply)

252=12x

21=x

Answer:

Factoring the trinomial: [tex]x^2+13x+12[/tex] we get the factors [tex]\mathbf{(x+1)(x+12)}[/tex]

Step-by-step explanation:

We need to factor the trinomial: [tex]x^2+13x+12[/tex]

We can factor the trinomial by breaking the middle term i.e 13x

Such that adding or subtracting gets the both terms we get 13x and multiplying both terms we get 12x^2

We can break 13x as: 12x and x

Adding them we get 13x and multiplying them we get 12x^2

So,

[tex]x^2+13x+12\\=x^2+12x+x+12\\=x(x+12)+1(x+12)\\=(x+1)(x+12)[/tex]

So, Factoring the trinomial: [tex]x^2+13x+12[/tex] we get the factors [tex]\mathbf{(x+1)(x+12)}[/tex]

Answer:

89.14

Step-by-step explanation:

[tex]{\underline{\underline{\bf{Given:}}}}[/tex]

[tex]{\underline{\underline{\bf{Need\:to\:find:}}}}[/tex]

[tex]{\underline{\underline{\bf{Formula\:to\:be\:used:}}}}[/tex]

Pythagorean Theorem:

[tex]\underline{\boxed{\sf{{Base}^{2}+{Perpendicular}^{2}={Hypotenuse}^{2}}}}[/tex]

[tex]{\underline{\underline{\bf{Solution:}}}}[/tex]

According to the given data, we know the measures of Perpendicular and Hypotenuse. Hence, the measure of the base (Side FE) can be found by substituting the given measures in Pythagorean Theorem.

[tex]\implies{\sf{{Base}^{2}+{Perpendicular}^{2}={Hypotenuse}^{2}}}[/tex]

[tex]\implies{\sf{{EF}^{2}+{DF}^{2}={DE}^{2}}}[/tex]

[tex]\implies{\sf{{EF}^{2}+{(13.6)}^{2}={(16.2)}^{2}}}[/tex]

[tex]\implies{\sf{ EF = \sqrt{ {(16.2)}^{2} - {(13.6)}^{2} } }}[/tex]

[tex]\implies{\sf{ EF = \sqrt{ 262.44 - 184.96 } }}[/tex]

[tex]\implies{\sf{ EF = \sqrt{77.48 } }}[/tex]

[tex]\implies{\sf{EF=\red{\underline{\underline{8.802\:m}}}}}[/tex]

[tex]{\underline{\underline{\bf{Required\:answer:}}}}[/tex]

Answer:

1 and 2 are not polyhedrons, as a circle has infinite sides

1. cone, 1 vertex

2. sphere, nothing

3. pentagonal prism?

wait but can't every face be a base???

anyway 7 faces, 10 vertices

4. triangular prism

5 faces, 6 vertices

Step-by-step explanation:

We have given the figure

We have to determine whether each solid is a polyhedron.

Then identify the solid.

If it is a polyhedron, name the bases, and faces.

edges, and vertices.

A vertex is a point of where the first derivative of curvature is zero. This is typically a local maximum or minimum of curvature, and some authors define a vertex to be more specifically a local extremum of curvature.

1 and 2 are not polyhedrons, as a circle has infinite sides

1. cone, 1 vertex

2. sphere, nothing

3. pentagonal prism

anyway 7 faces, 10 vertices

4. triangular prism

5. faces, 6 vertices

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Given:

Figure of a triangle.

To find:

The values of x.

Solution:

In the figure, we have an angle bisector.

According to the angle bisector theorem, an angle bisector of a triangle always divides the opposite side into two segments that are proportional to the other two sides of the triangle.

Using angle bisector theorem, we get

[tex]\dfrac{x}{7}=\dfrac{15}{14}[/tex]

Multiply both sides by 7.

[tex]x=\dfrac{15}{14}\times 7[/tex]

[tex]x=\dfrac{15}{2}[/tex]

[tex]x=7.5[/tex]

Therefore, the value of x is 7.5 units.

Answer:

8000

Step-by-step explanation:

Answer:

x²/4 + y²/16 = 1

Step-by-step explanation:

Foci on the y axis: major axis parallel to y axis

x²/b² + y²/a² = 1

x²/4 + y²/16 = 1

The required equation of an ellipse is given by x²/4 + y²/16 = 1

Given that,
Length of the major axis: 4 Length of the minor axis: 2 Foci are on the y-axis with center (0,0)​, the equation of the ellipse is to be determined.0

Ellipse is defined as the cross-section of the cone when cutting it with a plane parallel to its base.

Here,
Standard equation of the ellipse with origin as the center,
x²/a² + y²/b² = 1
where a and b are the minor and major axis of the ellipse.
From the given, we have a = 2 and b = 4
So the equation of the ellipse,
x²/4 + y²/16 = 1

Thus, the required equation of an ellipse is given by x²/4 + y²/16 = 1.

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