Zinc sulfate is a 2-ion electrolyte,
dissociating 40% in a
certain concentration. Calculate its
dissociation (i) factor.
On the basis of 40% dissociation, 100
particles of zinc sulfate
will yield:
40zinc ions
40 sulfate ions
60undissociated particles
Jo 11:03

Answers

Answer 1

Answer: The value of i is 1.4 and 40% dissociation of 100 particles of zinc sulfate will yield 60 undissociated particles.

Explanation:

The equation used to calculate the Vant' Hoff factor in dissociation follows:

[tex]\alpha =\frac{i-1}{n-1}[/tex]

where,

[tex]\alpha [/tex] = degree of dissociation = 40% = 0.40

i = Vant' Hoff factor

n = number of ions dissociated = 2

Putting values in above equation, we get:

[tex]0.40=\frac{i-1}{2-1}\\\\0.40=i-1\\\\i=1.4[/tex]

The equation used to calculate the degee of dissociation follows:

[tex]\alpha =\frac{\text{Number of particles dissociated}}{\text{Total number of particles taken}}[/tex]

Total number of particles taken = 100

Degree of dissociation = 40% = 0.40

Putting values in above equation, we get:

[tex]0.40=\frac{\text{Number of particles dissociated}}{100}\\\\\text{Number of particles dissociated}=(0.40\times 100)=40[/tex]

This means that 40 particles are dissociated and 60 particles remain undissociated in the solution.

Hence, 40% dissociation of 100 particles of zinc sulfate will yield 60 undissociated particles.


Related Questions

You have 4 litres of a 3.0 mol/L solution of NaCl in a
chemical store room.
How many moles of NaCl are present? *

0.75 mol

1.33 mol

12 mol

Answers

Given:

M = 3.0 mol/L

V = 4 L

Required:

n

Solution:

M = n / V

n = MV

n = (3.0 mol/L)(4 L)

n = 12 mol

Therefore, the number of moles of NaCl present is 12 mol.

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#ILoveYouShaina

Answer 12 mol

Explanation: [tex]C_{M} = \frac{n}{V} ==> n = C_{M} *V=4*3=12 mol[/tex]

NaOH is an Arrhenius base because it increases the concentration of hydroxide ions when dissolved in solution. (3 points) True False

Answers

When NaOH is an Arrhenius base so it is dissociated in water so the given statement is false.

NaOH is an Arrhenius base:

It is this base since it dissociates in water to provide the hydroxide (OH-) and sodium (Na+) ions.

It is the substance that is ionized at the time when it is dissolved in water to provide the hydrogen ion.

hence, the given statement is false.

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Answer:

true

Explanation:

i took the test and got it right the other guy is wrong

What is the limiting reagent when 22 g of sodium is added to 28 g water?

Answers

Answer:

Limiting reagent is Na

Explanation:

Reaction of Na with water is:

Na + H₂O →  NaOH  +  H₂

It is a very exothermic reaction.

The correctly balanced equation is:

2Na + 2H₂O →  2NaOH  +  H₂

Ratio is 2:2, between reactants, according to stoichiometry.

We convert mass to moles:

22 g . 1 mol / 23 g = 0.956 moles of Na

28 g . 1mol / 18 g = 1.56 moles of water.

Certainly the limiting reagent is sodium. For 1.56 moles, we need the same amount of sodium and we only have 0.956 moles.

We do not have enough sodium to complete the reaction.

Write a summary of the science of muscle growth?

Answers

Answer:Muscle growth or “skeletal muscle hypertrophy,” as it's called at science parties) is the result of a complex process that adds more myosin “filaments” to each muscle fiber. This makes the “engine” of the cell bigger and stronger over time. ... This process is called muscle protein synthesis, or MPS. Skeletal muscle is composed of thread-like myofibrils and sarcomeres that form a muscle fiber and are the basic units of contraction. The 650 skeletal muscles in the human body contract when they receive signals from motor neurons, which are triggered from a part of the cell called the sarcoplasmic reticulum.

Hexane, C6H14, is a(n)
hydrocarbon.
Saturated or Unsaturated

Answers

Answer:

Like any compound ending in '-ane', hexane is an alkane. It is commonly referred to as n-hexane and classified as a saturated hydrocarbon

Answer:

its saturated

cus its like

CnH2n+2

A 1.0 g sample of propane, C3H8, was burned in calorimeter. The temperature rose from 28.5 0C to 32.0 0C and heat of combustion 10.5 kJ/g. Calculate the heat capacity of the calorimeter apparatus in kJ/0C

Answers

Answer:

A 1.0 g sample of propane, C3H8, was burned in the calorimeter.

The temperature rose from 28.5 0C to 32.0 0C and the heat of combustion 10.5 kJ/g.

Calculate the heat capacity of the calorimeter apparatus in kJ/0C

Explanation:

[tex]Heat of combustion = heat capacity of calorimeter * deltaT\\[/tex]

Given,

The heat of combustion = 10.5kJ/g.

[tex]deltaT = (32.0-28.5)^oC\\deltaT = 3.5^oC[/tex]

Substitute these values in the above formula to get the value of heat capacity of the calorimeter.

[tex]deltaT =heat capacity of calorimeter * (change in temperature)\\10.5kJ/g = heat capacity of calorimeter * (3.5^oC)\\\\=>heat capacity of calorimeter = \frac{10.5kJ/g}{3.5^oC} \\=>heat capacity of calorimeter = 3.0 kJ/g.^oC[/tex]

Answer:

The heat capacity of the calorimeter is [tex]3.0kJ/g.^oC.[/tex]

Which molecule is pentanoic acid?
ОА.
Н
1
НЕС-ОН
ОВ.
Н
ОН
ор.н.н

Answers

Answer:

PubChem CID 7991

Structure Find Similar Structures

Chemical Safety Laboratory Chemical Safety Summary (LCSS) Datasheet

Molecular Formula C5H10O2 or CH3(CH2)3COOH

Synonyms Valeric acid PENTANOIC ACID n-Valeric acid 109-52-4 n-Pentanoic acid More.

Fire a single electron towards the hydrogen atom. Describe what happens in a step by step fashion. [N.B. - It may be helpful to utilize the Run in Slow Motion option for this part.]

Answers

Answer:

The electrons will be added by the hydrogen.

Explanation:

If we fire a single electron towards the hydrogen atom, the hydrogen atoms added the electron to its shell by applying force of attraction and becomes stable as well as non reactive in nature because the hydrogen attains the electronic configuration of helium which is a noble gas and have completed its outermost shell. The proton that is present in the nucleus attracts this electron and compel it to add in the electron.

How much work (in J) is involved in a chemical reaction if the volume decreases from 4.35 to 1.20 L against a constant pressure of 0.822 atm?
Express your answer to three significant figures and include the appropriate units.

Answers

Answer:

W = -262 J.

Explanation:

Hello there!

In this case, according to the given information, we can recall the definition of work in terms of constant pressure and variable volume as follows:

[tex]W=P(V_2-V_1)[/tex]

So we plug in the given pressure and volumes to obtain:

[tex]W=0.822atm(1.20L-4.35L)\\\\W=-2.60atm*L[/tex]

Now, we convert this number to J (Pa*m³) by using the shown below conversion factor:

[tex]W=-2.60atm*L*\frac{101325Pa}{1atm} *\frac{1m^3}{1000L}\\\\W=-262J[/tex]

Regards!

eeeasdaaaa asdsaa asdsaaa asdsaaa asdsaaa asdsaaa asdsaaa asdsaaa asdsaaa asdsaaa asdsaa

Answers

Please note that Brainly is not for spamming purposes. Thank you for your cooperation.

Use the periodic table to determine the electron configuration for aluminum (Al) and arsenic (As) in noble-gas notation.

Al:

Answers

Explanation:

2,8,3

don't know .............

.....how

Which is most likely the first step in a basic food chain?

1. The snake obtain energy by eating the mouse

2. Plants make energy-rich food using sunlight

3. The hawk obtains energy by eating the snake

4. The sun emits energy.

Answers

Answer:

4

Explanation:

define molecular formula?​

Answers

A molecular formula is an expression that states the number and type of atoms present in a molecule of a substance.

Example : H2O (water) There are 2 atoms of Hydrogen and 1 atom of Oxygen in this substance

A solution of which of the following coordination compounds will form a precipitate when treated with aqueous AgNO3?
a. [Cr(NH3)3C13]
b. All will form a precipitate
c. Na3[Cr(CN)6]
d. Na3[CrCl6]
e. [Cr(NH3)6.]C13

Answers

Answer:

[Cr(NH3)6.]C13

Explanation:

Alfred Werner's coordination theory (1893) recognized two kinds of valency;

Primary valency which are nondirectional and secondary valency which are directional.

Hence, the number of counter ions precipitated from a complex depends on the primary valency of the central metal ion in the complex.

We must note that it is only these counter ions that occur outside the coordination sphere that can be precipitated by AgNO3.

If we consider the options carefully, only [Cr(NH3)6.]C13 possess counter ions outside the coordination sphere which can be precipitated when treated with aqueous AgNO3.


Gaseous ethane (CH,CH,) will react with gaseous oxygen (02) to produce gaseous carbon dioxide (CO2) and gaseous water (H,0). Suppose 4.21 g of
ethane is mixed with 31. 9 of oxygen. Calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction. Be sure your answer has
the correct number of significant digits.


Answers

Answer: The mass of [tex]CO_2[/tex] produced is 12.32 g

Explanation:

The number of moles is defined as the ratio of the mass of a substance to its molar mass.  The equation used is:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] ......(1)

For ethane:

Given mass of ethane = 4.21 g

Molar mass of ethane = 30 g/mol

Putting values in equation 1, we get:

[tex]\text{Moles of ethane}=\frac{4.21g}{30g/mol}=0.140mol[/tex]

For oxygen gas:

Given mass of oxygen gas = 31.9 g

Molar mass of oxygen gas= 32 g/mol

Putting values in equation 1, we get:

[tex]\text{Moles of oxygen gas}=\frac{31.9g}{32g/mol}=0.997mol[/tex]

The chemical equation for the combustion of ethane follows:

[tex]2C_2H_6+7O_2\rightarrow 4CO_2+6H_2O[/tex]

By stoichiometry of the reaction:

If 2 moles of ethane reacts with 7 moles of oxygen gas  

So, 0.140 moles of ethane will react with = [tex]\frac{7}{2}\times 0.140=0.49mol[/tex] of oxygen gas

As the given amount of oxygen gas is more than the required amount. Thus, it is present in excess and is considered as an excess reagent.

Thus, ethane is considered a limiting reagent because it limits the formation of the product.

By the stoichiometry of the reaction:

If 2 moles of ethane produces 4 moles of [tex]CO_2[/tex]

So, 0.140 moles of ethane will produce = [tex]\frac{4}{2}\times 0.140=0.28mol[/tex] of [tex]CO_2[/tex]

We know, molar mass of [tex]CO_2[/tex] = 44 g/mol

Putting values in above equation, we get:

[tex]\text{Mass of }CO_2=(0.28mol\times 44g/mol)=12.32g[/tex]

Hence, the mass of [tex]CO_2[/tex] produced is 12.32 g

how many hydrogen atoms are in one mole of caffeine

Answers

[tex] \huge \mathbb{ HI !!}[/tex]

My Answer

10

My Explanation

Although caffeine (a stimulant found in coffee and tea) is a relatively complicated molecule, it's only eight atoms of carbon, ten of hydrogen, four of nitrogen and two of oxygen – C8H10N4O2. This kind of representation is called a molecular formula – it tells us what kind of atoms we have, and how many of each.

#CarryOnLearning

There are 10 hydrogen atoms in one mole of caffeine.

What is caffeine?

Caffeine belongs to the methylxanthine category of nervous system stimulants. It's just a cognitive booster that improves alertness but also attentional performance.

Caffeine's chemical formula would be C8H10N4O2, that indicates it contains eight carbon atoms, ten hydrogen atoms, four nitrogen atoms, and two oxygen atoms.

So it can be seen that , 10 hydrogen resent in caffeine molecule.

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Will mark Brainlest ( molecular weight of ammonium sulphate)
step by step​

Answers

Answer:

132 amu

Explanation:

ammonium sulphate is [tex](NH_4)_{2} SO_4[/tex]

to calculate molecular weight we need

atomic weight of the element of the compound

here ammonium sulphate is formed by two elements

2 nitrogen , 8 hydrogen , 1 sulphur amd 4 oxygen

atonomic number of nirogen is 14 , hydrogen is 1 , sulphur has 32 and oxygen has 16

so lets calculate molecular weight of ammonium sulphate

2*14 + 8*1 + 1*32 + 4*16

28 + 8 + 32 + 64

132 amu

15.4 g of methanol (CH3OH) reacts completely according to the following reaction:
CH3OH (g) → CH2O (g) + H2 (g)
If 12.35 g of formaldehyde (CH2O) is produced, what is the percent yield for this reaction?

Answers

Explanation:

hope the working on picture helps :)

93.5 is the percent yield for this reaction.

What is a theoretical yield?

The theoretical yield is the maximum possible mass of a product that can be made in a chemical reaction.

Step 1: Solve for the mass of CH_2O produced.

Mass [tex]CH_2O[/tex] = 15.4 g [tex]CH_3OH[/tex] × (1 mol [tex]CH_3OH[/tex] ÷ 32.04 g [tex]CH_3OH[/tex]) × (1 mol [tex]CH_2O[/tex] ÷ 1 mol [tex]CH_3OH[/tex]) × (30.03 g [tex]CH_2O[/tex] ÷ 1 mol [tex]CH_2O[/tex])

Mass [tex]CH_2O[/tex]= 14.43 g

Step 2: Determine the theoretical yield.

Theoretical yield = mass [tex]CH_2O[/tex]

Theoretical yield = 14.43 g

Step 3: Solve for the percent yield.

Percent yield = (actual yield ÷ theoretical yield) × 100

Percent yield = (13.5 g ÷ 14.43 g) × 100

Percent yield = 0.9355509356 × 100 =93.5  percent

Hence, 93.5 is the percent yield for this reaction.

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5.96 g of ammonia reacts completely according to the following reaction:
2 NH, (g) + Co, (g) → CN,OH, (s) + H20 (1)
(a) What is the theoretical yield of urea (CN,OH,) for this reaction?
(b) If 13.74 g of urea are produced, what is the percent yield for this equation?

please show work, will give brainliest

Answers

Explanation:

this explanation may help u to understand:)

what are the characteristics of primary standard substances?​

Answers

Answer:

the characteristics of primary standard substances are:

1.High purity.

2.Stability (low reactivity)

3.Low hygroscopicity

4.High equivalent weight

5.Non-toxicity.

Ready and cheap availability.

3. Available energy increases as it is transferred from one organism to another in food chain.

True or false

Answers

Answer:

False

Explanation:

Gets used by other animals.

Imagine that one night on the news, you saw a report that chemists had discovered a medicine to cure cancer. Would you believe that this report was true? What questions would you want to see answered in the report to help you make your decision? Answer in two to three paragraphs.

Answers

Answer:

Yes I would believe that this report was true, because nobody would lie on a news channel that they cured cancer and then not cure it. That would completely ruin their credibility as well as the news channels credibility. So no news channel would take the story if it was made up.

I would like to see there studies on how the medicine kills off the cancer and the side effects of the medicine on the human body. I would want to know how the medicine is made, if its FDA approved, and how the medicine will be distributed across the globe and at what prices, as well as how easily the medicine expires.

Answer:

Explanation:

I will probably believe the report but want to find out more details. First is cure for which cancer has been found. Cancer is a general name for a large family of different diseases. So it is very likely that the cure is for some specific cancers.

Secondly I want to know if the cure has any side effect. The typical treatments for cancer now are radiation and chemo therapy. Both can cause serious side effects.

Lastly the cost of cure is important. New drugs with patent protection can be very expensive which limit on how many people can afford the treatment.

why hydride ion is strong base than hydroxide ion?

Answers

Answer:

The hydride ion,H−is a stronger base, so it will abstract a proton from the water. As the water will give protons, so water will work as an acid and an acid-base reaction will take place. Hydride ions get protons from water and form hydrogen gas and hydroxide ions.

Sodium hydride is the chemical compound with the empirical formula NaH. This alkali metal hydride is primarily used as a strong yet combustible base in organic synthesis. NaH is a saline (salt-like) hydride, composed of Na+ and H− ions, in contrast to molecular hydrides such as borane, methane, ammonia, and water.

The rate equation for a reaction between substances C and D is:
rate = k[C]^2 [D]^2
The initial rate is found to be 7.5 x 10^-3mol dm^-3s^-1when the initial concentration of
C is of 0.25 mol dm^-3and the initial concentration of D is 0.50 mol dm^-3.
Calculate the value of the rate constant, k, at this temperature and deduce its units.
*Important Asap please *

Answers

Answer:

[tex]rate = k[C] {}^{2} [D] {}^{2} \\ 7.5 \times {10}^{ - 3} = k {(0.25)}^{2} {(0.50)}^{2} \\ k = \frac{7.5 \times {10}^{ - 3} }{ {(0.25)}^{2} {(0.50)}^{2} } \\ k = 0.48 \: {mol}^{ - 3} {dm}^{9} {s}^{ - 1} [/tex]

What determines the ending units of a stoichiometry problem?

Answers

Answer:

1.Write the balanced chemical equation.

2.Convert the units of the given substance (A) to moles.

3.Use the mole ratio to calculate the moles of wanted substance (B).

4.Convert moles of the wanted substance to the desired units.

Explanation:

14. Which block in the periodic table contains the metalloids?
O A. p block
OB. s block
O C. d block
D. f block

Answers

The p block contains the metalloids

Answer

the answer is p block

Write the first step of this elimination using curved arrows to show electron reorganization. Remember that a mechanism step may require more than one curved arrow.

Answers

Answer:

Explanation:

The missing image can be seen below.

From the given information:

The elimination process follows E2 mechanism which is a 2nd order kinetics.

At E2 mechanism, the base attaches with the beta hydrogen while also removing the leaving group in the same process. In the given compound 2-chloro-2-methylpropane, chloride is the leaving group that results in the product; 2-methylprop-1-ene.

The mechanism is seen in the second image,

Which of the following is a testable hypothesis

Answers

Answer:

C

Explanation:

Answer:

C.

Explanation:

Brainiest?

What volume of 6.49 MHCl is needed to prepare 2.11 L of 1.07 MHCl? Your answer should have three significant figures.

Answers

Answer:

0.348 L

Explanation:

Step 1: Given data

Concentration of the concentrated solution (C₁): 6.49 MVolume of the concentrated solution (V₁): ?Concentration of the dilute solution (C₂): 1.07 MVolume of the dilute solution (V₂): 2.11 L

Step 2: Calculate the volume of the concentrated solution

We want to prepare a dilute solution from a concentrated one. We can calculate the volume of the concentrated solution using the dilution rule.

C₁ × V₁ = C₂ × V₂

V₁ = C₂ × V₂ / C₁

V₁ = 1.07 M × 2.11 L / 6.49 M = 0.348 L

21.5g of sodium chloride dissolves in 60g of water at25C. Calculate the concentration of the solution.

Answers

The answer will be:
Solubility of the mixture = 21.5/60 x 25 = 8.96
Hope this helps.
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