Answer:
Explanation:
A decimal number is called a float.
True
False
Answer: True
Explanation:
The term floating point is derived from the fact that there is no fixed number of digits before and after the decimal point; that is, the decimal point can float. There are also representations in which the number of digits before and after the decimal point is set, called fixed-pointrepresentations.
Answer:
It's true
Explanation:
def shared_motif(dna_list):
This function takes in a list of DNA strings and returns the longest common substring. A substring is a contiguous sequence of characters within a string. A common substring is a substring of every element in the given list of DNA strings. Note that the number of DNA strings in the input list is not always the same! There may be multiple solutions, but you only need to return the first one.
Example:
Sample input DNA list:
("GATTACA", "TAGACCA", "ATACA"]
The returned longest common substring:
"TA"
Answer:
Explanation:
The following code is written in Python, the function creates various nested loops to loop through each individual string comparing letter by letter in order to find the longest common substring. Finally, returning the substring itself.
def shared_motif(dna_list):
substr = ''
if len(dna_list) > 1 and len(dna_list[0]) > 0:
for x in range(len(dna_list[0])):
for i in range(len(dna_list[0]) - x + 1):
if i > len(substr) and all(dna_list[0][x:x + i] in y for y in dna_list):
substr = dna_list[0][x:x + i]
return substr
arr = ["GATTACA", "TAGACCA", "ATACA"]
stems = shared_motif(arr)
print(stems)
For the recursive method below, list the base case and the recursive statement, then show your work for solving a call to the recur() method using any parameter value 10 or greater.
public static int recur(int n)
{
if(n < 1)
{
return 3;
}
else
{
return recur(n / 5) + 2;
}
}
Answer:
(a): The base case: if(n<1)
(b): The recursive statement: recur(n / 5)
(c): Parameter 10 returns 7
Explanation:
Given
The above code segment
Solving (a): The base case:
The base case is that, which is used to stop the recursion. i.e. when the condition of the base case is true, the function is stopped.
In the given code, the base case is:
if(n<1)
Solving (b): The recursive statement:
The recursive statement is the statement within the function which calls the function.
In the given code, the recursive statement is:
recur(n / 5)
Solving (c): A call to recur() using 10
The base case is first tested
if (n < 1); This is false because 10 > 1
So, the recursive statement is executed
recur(n/5) +2=> recur(10/5)+2 => recur(2)+2
2 is passed to the function, and it returns 2
if (n < 1); This is false because 2 > 1
So, the recursive statement is executed
recur(n/5) +2=> recur(2/5)+2 => recur(0)+2
2 is passed to the function, and it returns 2
if (n < 1); This is true because 0 < 1
This returns 3
So, the following sum is returned
Returned values = 2 + 2 + 3
Returned values = 7
the first page of a website is what?
Answer:
index.html
Explanation:
The name of the html file for the homepage of a website is usually "index.html"
Define a structure Triangle that contains three Point members. Write a function that computes the perimeter of a Triangle . Write a program that reads the coordinates of the points, calls your function, and displays the result
Answer:
The program in C++ is as follows:
#include <iostream>
using namespace std;
int perimeter(int side1, int side2, int side3){
return side1+side2+side3;
}
struct Triangle {
int side1; int side2; int side3;
};
int main(void) {
int side1, side2, side3;
cout<<"Sides of the triangle: ";
cin>>side1>>side2>>side3;
struct Triangle T;
T.side1 = side1;
T.side2 = side2;
T.side3 = side3;
cout << "Perimeter: " << perimeter(T.side1,T.side2,T.side3) << endl;
return 0;
}
Explanation:
See attachment for complete code where comments are as explanation
You use the fixed manipulator to Group of answer choices round floating-point numbers that are displayed in fixed-point notation to the specified number of decimal places round floating-point numbers that are displayed in scientific notation to the specified number of significant digits format floating-point numbers in fixed-point notation all of the above a and b only
Answer:
format floating-point numbers in fixed-point notation
Explanation:
Required
Function of fixed manipulator
This question will be answered from the perspective of C++ programming language (however, the explanation is applicable to programming languages that uses fixed manipulators)
Fixed manipulators in C++ is used to set floating point numbers to a stated fixed point.
Take for instance;
double pi = 3.1415926534;
cout.precision(2);
cout<< fixed << pi;
The third line of the program where the fixed manipulator is used to format pi to 2 fixed point notation.
Hence, the output will be 3.14
Which XXX completes the definition of the generic method, avgNum?
public class FindAverage { XXX { long tripleSum; tripleSum = item1.longValue() + item2.longValue() + item3.longValue(); return tripleSum / 3; } }
a. public static long avgNum(long item1, long item2, long item3)
b. public static long avgNum(TheType item1, TheType item2, TheType item3)
c. public static long avgNum(TheType item1, TheType item2, TheType item3)
d. public static avgNum(TheType item1, TheType item2, TheType item3)
Answer:
Explanation:
The correct piece of code for the generic method in the question would be the following...
public static <TheType extends Number> long avgNum(TheType item1, TheType item2, TheType item3)
This declaration of the avgNum method declares this method as a Generic TheType method that is a subclass of the Number class. It also takes in generic parameters which are the same as the Generic class that was declared. Finally, outputting a long value which would be tripleSum / 3
3.4 code practice question 2 edhesive
You work at the headquarters of an international restaurant chain. The launch of your mobile ordering app has been well received in your home country, increasing sales and customer satisfaction while decreasing order wait time and operating expenses. Your team is now ready to expand the mobile app into a handful of international markets. However, you first need to strategize what kinds of adjustments and adaptations will be needed to help ensure the app's success in these various cultural environments. Marketing director: Frankly, I'm a little surprised at the success we've seen with this app here at home. But it makes sense to keep buiding on that momentum You Yes, I think today's customers are indigenously comfortable with internet based technologies, an________ is a natural extension of that phenomenon. The challenge is to figure out how easily the app can be adapted to markets
a. e-business
b. global purchasing
c. language diversity
d. model networking
Answer: E-business
Explanation:
Based on the information given, a natural extension of that phenomenon is the E-business. E-business which means electronic business is when business is done through the internet.
It should be noted that e-business processes consist of the purchase and sale of goods and services, the processing of payments, servicing customers, sharing information regarding products, managing production control, etc.
short note about micro miniaturzation
Answer:
the manufacture of extremely small versions of electronic devices.
Explanation:
asks
mxskssssksskwlwslskamzmzmsmsmz
is the minimum level of security mechanism in a
system.
Select one:
O Baseline
O Security model
O Security policy
O Reconnaissance
Answer:
Security policy is the minimum
Explanation:
write a complete program for the following situation related to the setting the speed of a car preset values before starting journey. . if speed is less than lower_set_speed, display the message "accelerate" to the screen, increases the cars speed to the lower set speed and output the new speed to screen .if speeds greater than upper_set_ speed, print the message "apply brake" to the new speed to the screen .Give all necessary documentation in the comments, including the file name. .allow the program to exit at the end. .output the speed to the screen. . how many different initial speeds will you need to test this code?
please help me it means a lot
Answer:
Explanation:
Please specify which programming language this is supposed to be written in.
Without knowing that, only the last part can be answered "how many different initial speeds will you need to test this code?"
You will need to test at least 3 initial speeds: one below the lower-set-speed, one between the lower- and upper-set-speed and last one which is above the upper-set-speed.
HOW TO DOWNLOAD BEAMNG DRIVE
Explanation:
Answer:
Explanation:
on what device
I have some true or false questions I need help with. 9th grade.**
Handware can be tracked back to ancient times. Over six centuries ago.
True or false.
Hardware is only found in computers.
True or false. I know
Instruments and weaving looms where some of the first pieces of hardware.
True or false.
Computers and hardware is the same thing
True or false.
Answer:
Hardware can be traced back to ancient times. False
Hardware is only found in computers. False
Instruments and weaving looms were some of the first pieces of hardware. False
Computers and hardware is the same thing. This question is a bit broad but there's many different types of hardware. From keyboards to printers to speakers.
I tried my best not exactly sure though.
6.12 LAB: Warm up: Parsing strings (1) Prompt the user for a string that contains two strings separated by a comma. (1 pt) Examples of strings that can be accepted: Jill, Allen Jill , Allen Jill,Allen Ex: Enter input string: Jill, Allen (2) Report an error if the input string does not contain a comma. Continue to prompt until a valid string is entered. Note: If the input contains a comma, then assume that the input also contains two strings. (2 pts)
Answer:
Explanation:
The following code is written in Python. It is a loop that asks the user for an input. If it contains a comma then it removes whitespace, splits it into two words, and prints each word seperately, and exits the loop. If it does not contain a comma then it prompts the user for another input.
while True:
string = input("Enter input string: ")
if ',' in string:
string = string.replace(" ", '')
string_split = string.split(',')
print("First word: " + string_split[0])
print("Second word: " + string_split[1])
break
Which of the following best explains how an analog audio signal is typically represented by a computer?
a. An analog audio signal is measured at regular intervals. Each measurement is stored as a sample, which is represented at the lowest level as a sequence of bits.
b. An analog audio signal is measured as a sequence of operations that describe how the sound can be reproduced. The operations are represented at the lowest level as programming instructions.
c. An analog audio signal is measured as input parameters to a program or procedure. The inputs are represented at the lowest level as a collection of variables.
d. An analog audio signal is measured as text that describes the attributes of the sound. The text is represented at the lowest level as a string.
Answer:
A. An analog audio signal is measured at regular intervals. Each measurement is stored as a sample, which is represented at the lowest level as a sequence of bits.
Explanation:
I took the test
Which of the following is the cause of transmission impairment?
Select one:
O Frequency
O Amplitude
O Attenuation
O Phase
Answer:
Attenuation is the cause of transmission impairment.hope it is helpful to you
Rick is a fan of logic-based games. However, he is bored of the classic ones, like Sudoku and Mastermind, since he has solved so many of them. Recently he found a new game in which one is given a string with some question marks in it. The objective is to replace all of the question marks with letters (one letter per question mark) in such a way that no letter appears next to another letter of the same kind.
Write a function:
def solution(riddle)
that, given a string riddle, returns a copy of the string with all of the question marks replaced by lowercase letters (a-z) in such a way that the same letters do not occur next to each other. The result can be any of the possible answers as long as it fulfils the above requirements.
Examples:
1. Given riddle = "ab?ac?", your function might return "abcaca". Some other possible results are 'abzacd", "abfacf".
2. Given riddle = "rd?e?wg??", your function might return "rdveawgab".
3. Given riddle = "????????", your function might return "codility".
Write an efficient algorithm for the following assumptions:
• the length of the string is within the range [1..100,000);
• string riddle consists only of lowercases letters (a - z) or '?';
• it is always possible to turn string 'riddle' into a string without two identical consecutive letters.
1 # you can write to stdout for debugging purposes, e.g.
2 # print("this is a debug message")
3
4 def solution (riddle):
5
6 # write your code in Python 3.6
7 pass
Answer:
The function is as follows:
import random
import string
def solution(riddle):
s = list(riddle)
for i in range(len(riddle)):
alpha = "".join(random.choice(string.ascii_letters) for x in range(1))
alpha = alpha.lower()
if s[i] == '?':
if i > 0 and i < len(s)-1:
if s[i+1] != alpha:
s[i] = alpha
elif s[i-1] != alpha:
s[i] = alpha
else:
i=i
else:
if i == 0:
if s[1] != alpha:
s[i] = alpha
else:
i = i
else:
if s[i-1] != alpha:
s[i] = alpha
else:
i = i
riddle = ""
for ele in s:
riddle+=ele
return riddle
Explanation:
See attachment for explanation where comments are used to explain some lines
In this exercise we have to use the knowledge of the python language to write the code, so we have to:
The code is in the attached photo.
So to make it easier the code can be found at:
import random
import string
def solution(riddle):
s = list(riddle)
for i in range(len(riddle)):
alpha = "".join(random.choice(string.ascii_letters) for x in range(1))
alpha = alpha.lower()
if s[i] == '?':
if i > 0 and i < len(s)-1:
if s[i+1] != alpha:
s[i] = alpha
elif s[i-1] != alpha:
s[i] = alpha
else:
i=i
else:
if i == 0:
if s[1] != alpha:
s[i] = alpha
else:
i = i
else:
if s[i-1] != alpha:
s[i] = alpha
else:
i = i
riddle = ""
for ele in s:
riddle+=ele
return riddle
See more about python at brainly.com/question/26104476
how do engineers communicate their design ideas?
Answer:
Explanation:
Mechanical engineers give Presentations when they work on projects and Proposals. Often, professional Presentations require you to verbally and graphically present preliminary designs to colleagues.
Hope this helped!!!
To specify the data sets you want to see for your particular user, you create or select a
d
Select one:
a. Filter
b. View
c. Switch
d. Scope
Answer:
B
Explanation:
Python program
You are given the following text file called Mytext.txt. Write a Python function called search_file that accepts the name of the file (i.e. filename) and a string to look for in the file (i.e. mystring) as parameters. The function then looks for mystring in the file. Whenever it finds the string in a line, it saves the line number and the text for that line in a dictionary. Finally, it returns the dictionary after reading all the lines in the file and populating the dictionary with all matching line numbers and line text. If an empty string or a blank string is passed as mystring then an empty dictionary is returned.
Sample Input: search_file("Mytext.txt","python")
Sample Input: search_file("Mytext.txt","")
Contents of Mytext.txt
Python is an interpreted, high-level, programming language.
Python is dynamically typed and garbage-collected.
Python was conceived in the late 1980s.
Python 2.0, was released in 2000.
Python 3.0, was released in 2008.
The interpreters are available for many operating systems.
Answer:
The function in Python is as follows:
def search_file(filename,mystring):
my_dict = {}
count = 0
file = open(filename)
lines = file.readlines()
for line in lines:
count+=1
if mystring.lower() in line.lower():
my_dict[count] = line.rstrip('\n')
return my_dict
Explanation:
This defines the function
def search_file(filename,mystring):
This initializes an empty dictionary
my_dict = {}
This initializes the number of lines to 0
count = 0
This opens the file
file = open(filename)
This reads the lines of the file
lines = file.readlines()
This iterates through the lines
for line in lines:
This increments the number line
count+=1
This checks if the string exists in the line
if mystring.lower() in line.lower():
If yes, the line number and the string are added to the dictionary
my_dict[count] = line.rstrip('\n')
This returns the dictionary
return my_dict
Code.org lesson 8 level 5
Answer:
and?
Explanation:
what does this mean on a tamagotchi lol (this is the hello kitty one)
I don't have that tamagotchi
But I do have 2 tamagotchi's
I think it's a cherry on your tamagotchi
Hoped this helped!
Have a wonderful day-
script code written in many languages of the best known: ( C#_PHP_HTML)
Answer:
PHP
Explanation:
The best way to answer this question is to interpret it as, which of the three is a scripting language.
Analyzing each of the languages
1. C#
C# is not a scripting language, but instead it is an object-oriented programming language. Also, c# is a compiled language and one of the features of scripting language is that, they are interpreted.
2. PHP
Basically, PHP are used for server side scripting language because it uses scripts and its programs are not for general purpose runtime environment (but instead for special runtime environments).
3. HTML
HTML is neither a programming language, nor a scripting language because its design pattern does not follow that or programming and scripting languages, and it can not perform what an actual programming and scripting language do.
cmo se puede añadir amigo ??'
Answer:ok
Explanation:
Mark is six years younger than his sister Teri. Their combined ages equals 86. How old are Mark and Teri?
Mark's age = x
Teri's age = y
Answer:
x = 40
y = 46
Explanation is in the image above.
PLEASE HELP ME FIX THIS CODE.
I WANT IT TO HAVE USER INPUT TO CHANGE AND IMAGE FILTER TO BLUE RED OR GREEN.
user_color = input("What color would you like to paint the canvas, blue, red or green?:")
def user_red(pixel):
pixel[0] = 100 + pixel[0]
pixel[1] = 100 - pixel[1]
pixel[2] = 100 - pixel[2]
return pixel
def user_green(pixel):
pixel[0] = 100 + pixel[0]
pixel[1] = 100 - pixel[1]
pixel[2] = 100 - pixel[2]
return pixel
def user_blue(pixel):
pixel[0] = 100 + pixel[0]
pixel[1] = 100 - pixel[1]
pixel[2] = 100 - pixel[2]
return pixel
def custom_filter(image, user_color):
for x in range(image.get_width()):
for y in range(image.get_height()):
pixel = image.get_pixel(x,y)
new_colors = invert_pixel(pixel)
image.set_red(x, y, new_colors[0])
image.set_green(x, y, new_colors[1])
image.set_blue(x, y, new_colors[2])
return image
def change_image():
global image
image = custom_filter(image, user_color)
timer.set_timeout(change_image, IMAGE_LOAD_TIME)
PLEASE HELP ME FIX THIS CODE.
I WANT IT TO HAVE USER INPUT TO CHANGE AND IMAGE FILTER TO BLUE RED OR GREEN.
user_color = input("What color would you like to paint the canvas, blue, red or green?:")
def user_red(pixel):
pixel[0] = 100 + pixel[0]
pixel[1] = 100 - pixel[1]
pixel[2] = 100 - pixel[2]
return pixel
def user_green(pixel):
pixel[0] = 100 + pixel[0]
pixel[1] = 100 - pixel[1]
pixel[2] = 100 - pixel[2]
return pixel
def user_blue(pixel):
pixel[0] = 100 + pixel[0]
pixel[1] = 100 - pixel[1]
pixel[2] = 100 - pixel[2]
return pixel
def custom_filter(image, user_color):
for x in range(image.get_width()):
for y in range(image.get_height()):
pixel = image.get_pixel(x,y)
new_colors = invert_pixel(pixel)
image.set_red(x, y, new_colors[0])
image.set_green(x, y, new_colors[1])
image.set_blue(x, y, new_colors[2])
return image
def change_image():
global image
image = custom_filter(image, user_color)
timer.set_timeout(change_image, IMAGE_LOAD_TIME)
When dragging a sheet tab to move it, the location of the _______ determines where the sheet tab will be moved.
square
line
arrow
last tab
the location of the arrow determines it
Design a class named Complex for representing complex numbers and the methods add, subtract, multiply, divide, abs for performing complex-number operations, and override toString method for returning a string representation for a complex number. The toString method returns a + bi as a string. If b is 0, it simply returns a.
Provide three constructors Complex(a, b), Complex(a), and
Complex(). Complex() creates a Complex object for number 0 and
Complex(a) creates a Complex object with 0 for b. Also provide
the getRealPart() and getImaginaryPart() methods for returning
the real and imaginary part of the complex number, respectively.
Your Complex class should also implement the Cloneable
interface.
Write a test program that prompts the user to enter two complex numbers and display the result of their addition, subtraction, multiplication, and division.
Here is the main class. It cannot be changed.
import java.util.Scanner;
public class Test {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.print("Enter the first complex number: ");
double a = input.nextDouble();
double b = input.nextDouble();
Complex c1 = new Complex(a, b);
System.out.print("Enter the second complex number: ");
double c = input.nextDouble();
double d = input.nextDouble();
Complex c2 = new Complex(c, d);
System.out.println("(" + c1 + ")" + " + " + "(" + c2 + ")" + " = " + c1.add(c2));
System.out.println("(" + c1 + ")" + " - " + "(" + c2 + ")" + " = " + c1.subtract(c2));
System.out.println("(" + c1 + ")" + " * " + "(" + c2 + ")" + " = " + c1.multiply(c2));
System.out.println("(" + c1 + ")" + " / " + "(" + c2 + ")" + " = " + c1.divide(c2));
System.out.println("|" + c1 + "| = " + c1.abs());
Complex c3 = (Complex)c1.clone();
System.out.println(c1 == c3);
System.out.println(c3.getRealPart());
System.out.println(c3.getImaginaryPart());
}
}
Answer:
Explanation:
The following code is written in Java, it creates the entire complex class as requested so that it works with the main method that has been provided in the question without having to change anything in the main method. Proof of output can be seen in the attached picture below
import java.util.Scanner;
class Test implements Cloneable{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.print("Enter the first complex number: ");
double a = input.nextDouble();
double b = input.nextDouble();
Complex c1 = new Complex(a, b);
System.out.print("Enter the second complex number: ");
double c = input.nextDouble();
double d = input.nextDouble();
Complex c2 = new Complex(c, d);
System.out.println("(" + c1 + ")" + " + " + "(" + c2 + ")" + " = " + c1.add(c2));
System.out.println("(" + c1 + ")" + " - " + "(" + c2 + ")" + " = " + c1.subtract(c2));
System.out.println("(" + c1 + ")" + " * " + "(" + c2 + ")" + " = " + c1.multiply(c2));
System.out.println("(" + c1 + ")" + " / " + "(" + c2 + ")" + " = " + c1.divide(c2));
System.out.println("|" + c1 + "| = " + c1.abs());
Complex c3 = c1;
System.out.println(c1 == c3);
System.out.println(c3.getRealPart());
System.out.println(c3.getImaginaryPart());
}
}
class Complex implements Cloneable {
public interface Cloneable { }
private double realPart;
public double getRealPart() {
return realPart;
}
public void setReal(double real) {
this.realPart = real;
}
private double imaginaryPart;
public double getImaginaryPart() {
return imaginaryPart;
}
public void setImaginary(double imaginary) {
this.imaginaryPart = imaginary;
}
public Complex(double a, double b) {
realPart = a;
imaginaryPart = b;
}
public Complex(double a) {
realPart = a;
imaginaryPart = 0;
}
public Complex() { }
public Complex add(Complex comp2) {
double real1 = this.getRealPart();
double real2 = comp2.getRealPart();
double imaginary1 = this.getImaginaryPart();
double imaginary2 = comp2.getImaginaryPart();
return new Complex(real1 + real2, imaginary1 + imaginary2);
}
public Complex abs() {
double real1 = Math.abs(this.getRealPart());
double imaginary1 = Math.abs(this.getImaginaryPart());
return new Complex(real1, imaginary1);
}
public Complex subtract(Complex comp2) {
double real1 = this.getRealPart();
double real2 = comp2.getRealPart();
double imaginary1 = this.getRealPart();
double imaginary2 = comp2.getRealPart();
return new Complex(real1 - real2, imaginary1 - imaginary2);
}
public Complex multiply(Complex comp2) {
double real1 = this.getRealPart();
double real2 = comp2.getRealPart();
double imaginary1 = this.getRealPart();
double imaginary2 = comp2.getRealPart();
return new Complex(real1 * real2, imaginary1 * imaginary2);
}
public Complex divide(Complex comp2) {
double real1 = this.getRealPart();
double real2 = comp2.getRealPart();
double imaginary1 = this.getRealPart();
double imaginary2 = comp2.getRealPart();
return new Complex(real1 / real2, imaginary1 / imaginary2);
}
public String toString() {
String result;
result = realPart + " + " + imaginaryPart + "i";
return result;
}
}
an image can have only one background layer true or false
Answer:
True
Explanation:
The background will always just be the background. You cannot blend two images together to make two background because it would be considered one background nonetheless.