While distributing gifts near the equator, Sneezy will be hanging on a rope with a comparable tension of 413.56 N.
String tension is T = mg at the poles.
where T= tension (N or kg-m/s2)
9.8 m/s2 is the acceleration caused by gravity (g).
m=Tension ÷ gravity
= 415 ÷9.8 kilogram
= 42.34 kilogram
The value of g has now changed at the equator. Earth's rotation causes g to become g'
g' = g - (w^2)×R
w = angular velocity of earth = 7.29×10^-5
R = radius of earth = 6371000metre
Now, the tension
mg' = mg - mw^2 R
= 415 − 42.34×6371000×7.29×10^-5×7.29×10^-5
= T'= 415-(42.34×6371000×7.29(10^(-5)) ×7.29×(10^(-5)))
T' =413.56 N
Gravity: In physics, gravity—also known as gravitation—is the constant force of attraction that pulls all things together.
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Answer:
Weight = 8.162 Newton.
Explanation:
Given the following data;
Mass = 2.2 kg
Acceleration due to gravity = 3.71 N/kg
To find the weight of the textbook;
Weight = mass * acceleration due to gravity
Weight = 2.2 * 3.71
Weight = 8.162 N
Therefore, the weight of the science textbook in mars is 8.162 Newton.
PLEASE HELPPPPPP!ASAPPPPPPP
Answer:
Altitude is the height of landmass calculated from sea level. No it has no effect on weight.
Explanation:
The altitude at sea level is always assumed to be 0°, thus as you move away from altidude is calculated in increments while moving into the sea, the vice versa is true.
32. Assume the helium-neon lasers commonly used in student physics laboratories have power outputs of 0.500 mW. (a) If such a laser beam is projected onto a circular spot 1.00 mm in diameter, what is its intensity
Answer:
636.6 W/m²
Explanation:
From the given information:
The area of the circular spot can be calculated as:
A = πr²
A = π(0.5 × 10⁻³ m)²
A = 7.85 × 10⁻⁷ m²
The intensity can be determined by using the formula:
[tex]I = \dfrac{P}{A}[/tex]
[tex]I = \Big ( \dfrac{0.500 \ mW}{\pi (0.5 \times 10^{-3} \ m )^2} \Big) \Big( \dfrac{10^{-3} \ W}{1\ mW} \Big)[/tex]
[tex]I = \dfrac{0.500 \times 10^{-3} }{\pi(0.25 \times 10^{-6} )}[/tex]
I = 636.6 W/m²
If a wave has a frequency of 5 hertz, the period for one wave cycle will be
Answer:
0.2 seconds
Explanation:
f=1/t
1/5=0.2
A train has a mass of 100000 kilograms.if its kinetic energy is 3mj what velocity is it travelling at
Answer:
V = 7.75 meters per seconds.
Explanation:
Given the following data;
Mass = 100000 Kilograms
Kinetic energy = 3 Megajoules = 3 * 10⁶ Joules
To find the velocity of the train;
Kinetic energy can be defined as an energy possessed by an object or body due to its motion.
Mathematically, kinetic energy is given by the formula;
[tex] K.E = \frac{1}{2}MV^{2}[/tex]
Where;
K.E represents kinetic energy measured in Joules.
M represents mass measured in kilograms.
V represents velocity measured in metres per seconds square.
Substituting into the formula, we have;
[tex] 3000000 = \frac{1}{2}*100000*V^{2}[/tex]
Cross-multiplying, we have;
[tex] 6000000 = 100000V^{2}[/tex]
[tex] V^{2} = \frac{6000000}{100000} [/tex]
[tex] V^{2} = 60 [/tex]
Taking the square root of both sides, we have;
[tex] V = \sqrt {60} [/tex]
V = 7.75 m/s
define the term change and state one negative change you may encounter as a student or as an employee in the future
Answer:
hey iam bored pls join
ID: 724 645 3790
Password: 1111
The term change refers to an alteration of present conditions.
What is change?The term change refers to an alteration of present conditions. When a change occurs, things cease to be the way they were. As a student, the complexity of academic work increases with time. This is a change that has taken place.
As an employee, you are given real world tasks to accomplish rather than mere mental exercises like when you were a student, this is change that has taken place.
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When an object vibrates it goes back and forth rapidly. How would you
describe this motion?
A: it goes below its starting point and back to its starting point
B: it goes passed its starting point in both directions
C: it will go back and fourth forever
D: it actually looks like spikey waves
Answer:
B) It appears to be SHM (simple harmonic motion) which is also the projection of an object moving in a circular path on either the x or y axes.
How do our attitudes help us organize our reality?
Answer:
If we are upset, often our mind cannot think straight. we need to take deep breaths, and focus on reality. When we are upset we do things out of anger.
Explanation:
Hope this helps!
What should stainless steel be considered when using it?
Please help The position of masses 4kg, 6kg, 7kg, 10kg, 2kg, and 12kg are (-1,1), (4,2), (-3,-2), (5,-4), (-2,4) and (3,-5) respectively. Determine the position of the center of mass of this system?
Answer:
(1.9756, -2.1951)
Explanation:
The center of mass equation is: [tex]x_{cm}[/tex] = [tex]\frac{m_{1}x_{1} + m_{2}x_{2} + m_{3}x_{3} + m_{4}x_{4} + m_{5}x_{5} + m_{6}x_{6}}{m_{1} + m_{2} + m_{3} + m_{4} + m_{5} + m_{6}}[/tex], where m represents the masses and x represents the position.
In order to find the coordinates of the center of mass, we need to use this equation for both the x-values and the y-values.
x-values:
[tex]x_{cm}[/tex] = [tex]\frac{m_{1}x_{1} + m_{2}x_{2} + m_{3}x_{3} + m_{4}x_{4} + m_{5}x_{5} + m_{6}x_{6}}{m_{1} + m_{2} + m_{3} + m_{4} + m_{5} + m_{6}}[/tex] = [tex]\frac{4(-1)+6(4)+7(-3)+10(5)+2(-2)+12(3)}{4+6+7+10+2+12}[/tex] = [tex]\frac{(-4)+(24)+(-21)+(50)+(-4)+(36)}{41}[/tex] = [tex]\frac{81}{41}[/tex] = 1.9756
y-values:
[tex]y_{cm}[/tex] = [tex]\frac{m_{1}y_{1} + m_{2}y_{2} + m_{3}y_{3} + m_{4}y_{4} + m_{5}y_{5} + m_{6}y_{6}}{m_{1} + m_{2} + m_{3} + m_{4} + m_{5} + m_{6}}[/tex] = [tex]\frac{4(1)+6(2)+7(-2)+10(-4)+2(4)+12(-5)}{4+6+7+10+2+12}[/tex] = [tex]\frac{(4)+(12)+(-14)+(-40)+(8)+(-60)}{41}[/tex] = [tex]\frac{-90}{41}[/tex] = -2.1951
center of mass:
(1.9756, -2.1951)
can someone please help me !!!!
Answer:
it's A subduction, deep water trench
place the compass at one pole of the bar magnet click flip polarity in the menu what happens to the bar magnet and the compass needle
Answer:
The two poles of the bar magnet change positions. The compass needle spins a half circle.
Explanation:
Answer:
The two poles of the bar magnet change positions. The compass needle spins a half circle.
Explanation:
edmentum answer
Plz help, will Mark brainliest. A 20.0 Ohm and 60.0 Ohm resistor are connected in series to a 9.00 V battery. How much current flows out of the battery?
(Unit = A)
Answer: 0.1125A
Explanation:
We need to know the total resistance which will be:
R = R1+R2
where,
R1 = 20 ohm
R2 = 60 ohm
Therefore, R = 20 + 60 = 80 ohm
We should note that from Ohm's law
v = iR
i = v/R
where,
i = 9/80 = 0.1125 A
Therefore, the current that flows out of the battery is 0.1125A
If a 5-L balloon at 25 degrees celsius were gently heated to 30 degrees celsius, what new volume would the balloon have? Show all work for credi
Answer: 5.08 L.
Explation down below
You are holding a finishing sander with your right hand. THe sander has a flywheel which spins counterclockwise as seen from behind the handle. You are sanding a wall in front of you. as you turn the sander towards the right, you feel a tendency in the sander to...
a. pull away from you
b. turn towards the left
c. turn downward
d. turn upward
e. push toward you
Answer:
c. turn downward
Explanation:
From the information given:
To find the tendency of the sander;
We need to apply the right-hand rule torque; whereby we consider the direction of the flywheel, the direction at which the torque is acting, and the movement of the sander toward the right.
Since the flywheel of the sander is in counterclockwise movement, hence the torque direction will be outward placing on the wall. However, provided that the movement of the sander is toward the right, then there exists an opposite force that turns downward which showcases the tendency in the sander is downward.
3) 4 electrons are placed - one electron per corner - at the corners of a square of side 1 meter. One fixed proton is placed in the middle of the square.The 4 electrons are held in place by some mechanism. The 4 electrons are released by the mechanism at the same time. They move and reach the corners of a square of side 0.8 meters, and keep on moving . Find the velocity of each electron at the corners of the square of side 0.8 meters.
Explanation:
3
i believe that they are all going at 3.2 meters each, I did 4 times 0.8
The velocity of each electron at the corners of the square is 15.92 m/s.
The given parameters;
charge of electron, q = 1.6 x 10⁻¹⁹ Clength of the square, L = 0.8 mThe diagonal length of the square is calculated as;
[tex]d^2 = 0.8^2 + 0.8^2\\\\d = \sqrt{0.8^2 + 0.8^2} \\\\d = 1.13 \ m[/tex]
The distance of each corner charge and the middle charge is calculated as;
[tex]r = \frac{1.13}{2} \\\\r = 0.565 \ m[/tex]
The force between each corner charge and the middle charge is calculated as;
[tex]F= \frac{kq^2}{r^2}[/tex]
The centripetal force on each charge moving around the square is calculated as;
[tex]F = \frac{mv^2}{r}[/tex]
solve the forces together;
[tex]\frac{mv^2}{r} = \frac{kq^2}{r} \\\\v^2 = \frac{kq^2}{m} \\\\v = \sqrt{ \frac{kq^2}{m} } \\\\v = \sqrt{ \frac{(9\times 10^9) \times (1.602\times 10^{-19})^2}{9.11 \times 10^{-31}} } \\\\v = 15.92 \ m/s[/tex]
Thus, the velocity of each electron at the corners of the square is 15.92 m/s.
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The wireless system is operating at 2GHz. A base station and a mobile unit are separated by 16km. The maximum gain of the transmitting antenna at the base station is 20dB. The input power to the transmitter is 100W, and the power received by the antenna is 5nW. The antennas are aligned, and there are no re ections or loses. What will be the received power if the distance between the mobile unit and the base station increases to 20km?
If everything else remains constant, then the received signal power is simply an inverse-square function of its distance from the transmitter.
That is, down 6dB when distance is doubled etc.
If distance increases from 16 to 20, then received power decreases by the factor of (16/20)^2.
That's (0.8)^2 = 0.64
New receive power is 5x0.64 = 3.2 nW
=. ===== ==========
Here's how I do it at my job:
Initial RSL = 5nW ~ - 53 dBm
loss = 20log(20/16)= 20log(1.25)~1.94dB
New RSL = - 54.94 dBm or ~ 3.2 nW .
You are trying to catch the mutated mouse and you have a rope
that both you and the mouse are pulling with a force of 500 Newtons,
but the rope does not move.
How much work is done?
PLS ANSWER ASAP! WILL MARK AS BRAINLYIST!!!!!
time left (5:00)!!
Answer:
none no work cuz no motion
Explanation:
GOOD LUCK
A 3 kg block collides with a massless spring of spring constant 98 N/m attached to a wall. The speed of the block was observed to be 1.5 m/s at the moment of collision. The acceleration of gravity is 9.8 m/s 2 . How far does the spring compress if the surface on which the mass moves is frictionless
Answer: 0.83 m
Explanation:
Given
mass of the block is m=3 kg
spring constant k=98 N/m
The Speed at the time of collision is v=1.5 m/s
Here, the kinetic energy of the block is converted into Elastic potential energy
[tex]\Rightarrow \dfrac{1}{2}mv^2=\dfrac{1}{2}kx^2 \\\\\Rightarrow 3\times 1.5^2=98\times x^2\\\\\Rightarrow x^2=0.6887\\\\\Rightarrow x=0.829\approx 0.83\ m[/tex]
40 POINTS!!! PLEASE HELPP!!!
Please select the word from the list that best fits the definition
One form of energy changes to one other form
(A.) single transformation
(B.) multiple transformation
Answer:
A
Explanation:
if it was B it would say from one to another to another
A fisherman sitting on the end of a pier notices that 6 wave crests pass him in 3 seconds. What is the frequency of the waves?
9.0 Hz
18.0 Hz.
20 Hz
4.5 Hz
The frequency of the waves will be 18 Hz. Then the correct option is B.
What is the frequency?The frequency of a repeated event is its number of instances per unit of time. It differs from angular frequency and is sometimes referred to as temporal frequency for clarification. One event occurs per second when measuring frequency in hertz.
Frequency is the number that represents the number of oscillations or intervals each second. The hertz is the SI unit for frequency (Hz). One cycle per second equals one hertz.
The number of finished waves produced each second is considered the wave frequency.
Six wave crests pass a fisherman sitting at the end of a pier in the span of three seconds.
The frequency of the waves is given as,
f = 6 x 3
f = 18 Hz
The waves will have a frequency of 18 Hz. Then, choice B is the best one.
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Half Time At 3:00 the hour hand and the minute hand of a clock point in directions that are 90.0
apart. What is the first time after 3:00 that the angle between the two hands has decreased by half to 45.0?
The first time after 3:00 that the angle between the two hands has decreased by half to 45.0 is 3:08:11.
Angular velocity of the hour hand
The angular velocity of the hour hand for 12 hours time is calculated as follows;
[tex]\omega_h = \frac{2\pi}{12(3600 \ s)}[/tex]
Angular velocity of the minute handThe angular velocity of the minute hand for 12 hours time is calculated as follows;
[tex]\omega _m = \frac{2\pi}{3600}[/tex]
Difference in the angular velocity[tex]\Delta \omega = \frac{2\pi }{3600} - \frac{2\pi }{12(3600)} = \frac{11(2\pi)}{12(3600)} = \frac{22\pi}{12 (3600)}[/tex]
First angle between the two hands in radians[tex]45^0 = \frac{45}{180} \pi= \frac{\pi}{4}[/tex]
Time after 3:00The time after 3:00 is calculated as follows;
[tex]t =( \frac{\pi}{4}) /\frac{22\pi}{12(3600)} \\\\t = \frac{\pi }{4} \times \frac{12(3600)}{22\pi} \\\\t = 490.91 \ s\\\\t = 8 \min, \ 10.91 \ s[/tex]
[tex]t \approx 8\min, 11 \ s[/tex]
Thus, the first time after 3:00 that the angle between the two hands has decreased by half to 45.0 is 3:08:11.
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MY NOTES A spring with a mass of 2 kg has a damping constant 14 kg/s. A force of 3.6 N is required to keep the spring stretched 0.3 m beyond its natural length. The spring is stretched 0.6 m beyond its natural length and then released. Find the position of the mass at any time t. (Assume that movement to the right is the positive x-direction and the spring is attached to a wall at the left end.)
Which of the following has no energy?"
Amoving ball
Awrecking ball
Non of the above
A roller coaster works by being hoisted to the top of the highest peak on the track and then released. As the roller coaster car moves along the track the energy gets converted back and forth between kinetic and gravitational potential energy. The entire time the roller coaster car is in motion air friction and friction in the wheels act to oppose the motion of the car. At which point during the ride is the total mechanical energy of the roller coaster car the greatest?
a. At the bottom of the first dip in the track when the car is moving the fastest.
b. When the car is exactly at half its original height half way through the ride.
c. At the top of the highest peak as the very start of the ride.
d. At the end of the ride as the car nears the station.
Answer:
a. At the bottom of the first dip in the track when the car is moving the fastest.
Explanation:
P.S - The exact question is -
The correct option is - a. At the bottom of the first dip in the track when the car is moving the fastest.
Reason -
From the diagram , we can see that the total mechanical energy of the roller coaster car is greatest At the bottom of the first dip in the track when the car is moving the fastest.
An empty container is filled with helium to a pressure P at a temperature T. Neon, which has atoms that are 5 times more massive than those of helium, is then added to the container until the new pressure in the container is 2P at the same temperature T. The ratio of the average speed of the helium atoms to the average speed of the neon atoms is:_________
a. 25 to 1
b. 5 to 1
c. 5to 1
d. 2to 1 E
e. 1 to 1
The ratio of the average speed of the helium atoms to the average speed of the neon atoms is 5 to 1 C.
We have that for the Question, it can be said that the ratio of the average speed of the helium atoms to the average speed of the neon atoms is
5:1
Option B
From the question we are told
An empty container is filled with helium to a pressure P at a temperature T. Neon, which has atoms that are 5 times more massive than those of helium, is then added to the container until the new pressure in the container is 2P at the same temperature T. The ratio of the average speed of the helium atoms to the average speed of the neon atoms is:_________
a. 25 to 1
b. 5 to 1
c. 5to 1
d. 2to 1
e. 1 to 1
Generally the equation for the average speed of Molecules is
mathematically given as
[tex]For Helium\\\\C_h=\frac{8P_hV_h}{\pim_h}\\\\Neon gas\\\\C_n=\frac{8P_nV_n}{\pim_n}\\\\Where\\\\Ph=P_n\\\\Vh=Vn\\\\[/tex]
[tex]\frac{C_h}{C_n}=\frac{\frac{8P_hV_h}{\pim_h}}{\frac{8P_nV_n}{\pim_n}}[/tex]
[tex]\frac{C_h}{C_n}=\sqrt{\frac{\frac{1}{5}}{{\frac{1}{5}}}[/tex]
[tex]\frac{C_h}{C_n}=\sqrt{\frac{5}{1}[/tex]
Therefore
The ratio of the average speed of the helium atoms to the average speed of the neon atoms is
5:1
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convert 1 day into seconds.(you will need to show your work to receive credit.) please help thank you
Answer:
the answer is 86400seconds.
Explanation:
1day= 24 hours
24hours to seconds =
24×60×60= 86400 seconds.
( 60 second = 1 minutes)
( 60 minutes = 1 hour)
a
Ten 2.2 v cells each having an internal
resistance of o.1ohms in are connected in series
to a load of 21ohm. Determine
pd at the battery terminals
Answer:
22Volts
Explanation:
The pd at the terminal is known as the emf
Since there are Ten 2.2V cells
Terminal voltage = number of cells * pd of one cell
Terminal voltage = 10 * 2.2
Terminal voltage = 22V
Hence the pd at the battery terminals is 22Volts
Help please & actually answer thank youu :)
Answer:
highest KE and lowest GPE = Dhighest GPE and lowest KE = Asome KE and some PE = B