Answer:
23.33 kgExplanation:
The mass of the object can be found by using the formula
[tex]m = \frac{f}{a} \\ [/tex]
f is the force
a is the acceleration
From the question we have
[tex]m = \frac{42}{1.8} = 23.3333... \\ [/tex]
We have the final answer as
23.33 kgHope this helps you
Answer:
[tex]\boxed {\boxed {\sf C. \ 23.33 \ kg}}[/tex]
Explanation:
According to Newton's Second Law of Motion, force is the product of mass and acceleration.
[tex]F=ma[/tex]
The mass of the ball is unknown. The ball is accelerating at 1.8 meters per second squared. An unbalanced force of 42 Newtons is applied to the ball.
Convert the units of force. 1 Newton is equal to 1 kilogram meter per second squared, so our answer of 42 Newtons is equal to 42 kg*m/s².
F= 42 kg*m/s² a= 1.8 m/s²Substitute the values into the formula.
[tex]42 \ kg*m/s^1 = m * 1.8 \ m/s^2[/tex]
We are solving for the mass, so we must isolate the variable m. It is being multiplied by 1.8 meters per second squared. The inverse operation of multiplication is division. Divide both sides by 1.8 m/s².
[tex]\frac {42 \ kg*m/s^2}{1.8 \ m/s^2} = \frac{a*1.8 \ m/s^2}{1.8 \ m/s^2}[/tex]
[tex]\frac {42 \ kg*m/s^2}{1.8 \ m/s^2} =m[/tex]
The units of meters per second squared cancel.
[tex]\frac {42 \ kg}{1.8 } =m[/tex]
[tex]23.3333333 \ kg=m[/tex]
Round to the hundredth place. The 3 in the thousandth place tells us to leave the 3 in the hundredth place.
[tex]23.33 \ kg \approx m[/tex]
The mass of the ball is approximately 23.33 kilograms.
Determine the elastic energy U stored in
the compressed spring.
Answer:
Answer: The spring constant of the spring is k = 800 N/m, and the potential energy is U = 196 J. To find the distance, rearrange the equation: The equation to find the distance the spring has been compressed is therefore: The spring has been compressed 0.70 m, which resulted in an elastic potential energy of U = 196 J being stored.
Explanation:
ECONOMIC Q‼️
Which of these is a common concern of an economist ?
A-The distributions of populations and earths resources
B-How people have organized the rules and laws of their societies
C-The cultural habits and social customs of societies
D-How well resources are used by a society
Answer:
D-How well resources are used by a society
Explanation:
Most economists are concerned with practical applications of economic policy in a particular area, such as finance, labor, agriculture, transportation...
Hope this helps luvv :)
if you dropped a ball and you dropped a hammer will the two objects fall at the same speed or will they fall at a different speed
Answer:
they would fall at different speeds
Explanation:
The speed at which each falls is dependent on air resistance
7. A bus covers a certain distance in 60 minutes if it runs at a speed of 60 km/hr.
What must be the speed of the bus in order to reduce the time of journey by 40
minutes?
Answer:
90 Km/h
Explanation:
60 mins is 1 hr
so in an hour bus covers 60 Km
so new speed:
d/t
(60km/40mins)*60mins/h
90Km/h
Tommy does 45 Joules of work to push the pencil over 3 meter. How much force did he use?
Answer:
Work = Force × Distance
Therefore Force = Work/Distance
= 45 joules/3 metres
= 15 newton
Explanation:
Answer:
15
Explanation:
15
Which molecule is a high-energy output of the light reactions?.
Answer:
Gallium Arsenine
Explanation:
Name two processes that release nuclear energy?
Answer: Nuclear energy is released from an atom through one of two processes: nuclear fusion or nuclear fission. In nuclear fusion, energy is released when the nuclei of atoms are combined or fused together. This is how the sun produces energy. In nuclear fission, energy is released when the nuclei of atoms are split apart.
Let me know if it helps!
When the atmosphere is absolutely unstable, the environmental lapse rate is ________ the dry adiabatic lapse rate.
Answer: greater than
Explanation:
A cyclist is coasting at 12 m/s when she comes to a muddy stretch with an effective coefficient of friction of 0.60. Will the cyclist be able to get out of the muddy stretch without having to pedal if it lasts 10 meters
The cyclist will make it since the distance traveled by the cyclist is greater than the length of the muddy stretch.
The given parameters;
speed of the cyclist, u = 12 m/scoefficient of friction, μ = 0.6length of the muddy stretch, L = 10 mThe effective acceleration of the cyclist at the given coefficient of friction is calculated as follows;
[tex]a = \ \mu g\\\\a = 0.6 \times 9.8\\\\a = 5.88 \ m/s^2[/tex]
The distance traveled by the cyclist at the give speed and acceleration is calculated as;
[tex]v^2 = u^2 + 2as\\\\12^2 = 0 + 2(5.88)s \\\\ 11.76 s = 144\\\\ s = \frac{144}{11.76} \\\\a = 12.24 \ m[/tex]
Thus, we can conclude that the cyclist will make it since the distance traveled by the cyclist is greater than the length of the muddy stretch.
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if a car travels around a circular track with a radius of 100 m once every 10s what will its average angular velocity around the track be?
Answer:
0.628 radians per second
Explanation:
Angular velocity
= 2pi/T
= 2(3.14159)/10
= 0.628 radians per second
The average angular velocity around the track is 62.8 m/s, using the circumference of the track as the total distance.
Average angular velocity:What information do we have?
Radius of track = 100 m
Time taken = 10s
Circumference of track = 2πr
Circumference of track = 2(3.14)(100)
Circumference of track = (2)(314)
Circumference of track = 628 m
Average angular velocity around the track = Circumference of track / Time taken
Average angular velocity around the track = 628 / 10
Average angular velocity around the track = 62.8 m/s
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explain properties and importance of light and how it separates into colours
Answer:
White light can be separated into different colors using a special lens called a prism. As visible light passes from air into the glass, the change in medium causes a change in direction and speed. Refraction causing the separation of white light into its various color wavelengths is called dispersion.
hope this helps
how much force is required to accelerate a 12 kg mass at 5 m/s 2
Answer:
60 N
Explanation:
This is just Newton's Second Law
F = m*a
F = ?
m = 12 kg
a = 5 m/^2
F = 5*12 = 60 Newtons
please answer right please
Answer:
i think its A
Explanation:
I hope this helps :)
Surface ocean currents are generated MOSTLY by A) wind. B) tides. C) water density. D) the Coriolis effect.
Answer:
I think it's D) the Coriolis Effect
Explanation:
Answer: THE ANSWER IS D) the Coriolis effect.
Explanation: I GOT A 100 ON THE TEST
when you hold a spherical concave mirror with a 48.2-cm radius of curvature in front of your face, you see an image of your face that is 61.8 cm in front of the mirror. what is the distance between the mirror and your face?
The distance between the mirror and your face is 39.5 cm
Using the mirror formula 2/r = 1/u + 1/v where r = radius of curvature = - 48.2 cm, u = distance between mirror and your face = object distance and v = distance between image and your face = - 61.8 cm. The distances are negative since the image is in front of the mirror and distances to the left of the mirror are negative.
So, making u subject of the formula, we have
2/r = 1/u + 1/v
1/u = 2/r - 1/v
1/u = (2v - r)/rv
u = rv/(2v - r)
Substituting the values of the variables into the equation, wse have
u = -48.2 cm × -61.8 cm/(2 × -61.8 cm - (-48.2 cm))
u = 2978.76 cm²/(-123.6 cm + 48.2 cm)
u = 2978.76 cm²/-75.4 cm
u = -39.51 cm
u ≅ -39.5 cm (The distance is negative since it is in front of the mirror)
So, the distance between the mirror and your face is 39.5 cm
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What is the number of the of significant figures in 2.50400-.pliz, help me l will mark you the brainest.(⊙_◎)
Answer:
Number of Significant Figures: 6
The Significant Figures are 2 5 0 4 0 0
Explanation:
Non-zero digits are always significant which are in this case 2,5,4, and Any zeros between two significant digits are significant and final zero or trailing zeros are significant therefore making the entire digit significant.
[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]
The number of significant figures in 2.50400 is ~
[tex] \boxed{6}[/tex]I will give a 5-star answer and Brainlest
Direct contact is necessary for which type of energy transfer?
A. Conduction
B. Sound Waves
C. Convection
D. Radiation
Answer:
D
Explanation:
I rode my bicycle to grandmother's house at 6 km/h in a flat road for 5 min before reach a hill. I went at 2 km/h up the hill for 3minutes. I met a friend and stopped to talk for 5 minutes. I went on at 2 km/h to my grandmother's house. Draw (plot) the v against t graph for this motion.
The graph can be plotted based on the given information which are given
in pairs (velocity and time), and which the coordinate pairs are formed.
Please find attached the required v against t graph created with MS ExcelReasons:
The given data are presented in a tabular form as follows;
[tex]\begin{tabular}{|c|c|c}\underline{Duration (Minutes)} & \underline{Speed (km/h)}\\0 - 5 &6 \\5 - 8&2\\8 -13&0&\\13- &2&\end{array}[/tex]
The velocity time graph can be plotted using the above table values on
MS Excel using the above table elaborated as follows;
[tex]\begin{tabular}{|c|c|c}\underline{Duration (Minutes)} & \underline{Speed (km/h)}\\0 &6 \\5&6\\5 &2\\8&2\\8&0\\13&0&\\13 &2&\end{array}[/tex]
The attached graph can then be created using the Insert → Chart menu
after selecting the data above inputted in the spreadsheet button on MS
Excel.
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calculate the density, in g/l, of sf6 gas at 27°c and 0.500 atm pressure.
The density of the SF₆ gas at the given pressure and temperature is 2.96 g/l.
The given parameters:
temperature of the SF₆ gas, T = 27 ⁰C = 273 + 27 = 300 Kpressure of the SF₆ gas, P = 0.5 atmThe molecular mass of the SF₆ gas is calculated as follows;
M of SF₆ = 32 + (6 x 19) = 146 g/mol
The density of the SF₆ gas is calculated by applying ideal gas law as follows;
[tex]PV = nRT\\\\PV = \frac{m}{M} RT\\\\PM = \frac{m}{V} RT\\\\PM = \rho RT\\\\\rho = \frac{PM}{RT}[/tex]
where;
[tex]\rho[/tex] is the density of the gasR is the ideal gas constant = 0.0821 L.atm/mol.K[tex]\rho = \frac{0.5 \times 146}{0.0821 \times 300} \\\\\rho = 2.96 \ g/l[/tex]
Thus, the density of the SF₆ gas at the given pressure and temperature is 2.96 g/l.
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With no friction, you can use the relationship between potential and kinetic energy to predict the speed of the car at the bottom of this hill from its starting height. To do this start by setting the kinetic and potential energy equations equal to one another
The speed of the car at the bottom of the hill is obtained as, [tex]v = \sqrt{2gh}[/tex]
According the principle of conservation of energy, the total potential energy of the car will be converted to maximum kinetic energy when the car is at the bottom of the hill.
[tex]K.E = P.E\\\\\frac{1}{2} mv^2 = mgh\\\\v^2 = 2gh\\\\v= \sqrt{2gh}[/tex]
where;
v is the speed of the car at the bottom of the hillh is the height of the hillg is acceleration due to gravityThus, the speed of the car at the bottom of the hill is obtained as, [tex]v = \sqrt{2gh}[/tex]
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Historia de baloncesto internacional resumen
Answer:
?
Explanation:
4) An 873kg dragster, starting from rest, attains a speed of 26.3m/s in 0.590s.
A) What was the acceleration of the dragster?
B) What was the net force needed to accelerate the dragster?
C) Assume that the driver has a mass of 68.0kg. What horizontal force does the seat exert on
him?
Answer:
A.)a=44.57m/s
B.)f=38,909.61
C.)f=666.4
Explanation:
A.) A=v/t 26.3/0.590=44.57
B.) 873kg x 44.57= 38,909.61
C.) 68kg x 9.8=666.4
The half life of carbon-14 is 5730 years. How old is a bone if it presently contains 0.3125 g of carbon-14, but it was estimated to have originally contained 80 g of carbon-14?
The age of the bone is 45840 years.
We'll begin by calculating the number of half-lives that has elapsed.
Amount remaining (N) = 0.3125 g
Initial amount (N₀) = 80 g
Number of half-lives (n) =?N × 2ⁿ = N₀
0.3125 × 2ⁿ = 80
Divide both side by 0.3125
2ⁿ = 80 / 0.3125
2ⁿ = 256
2ⁿ = 2⁸
n = 8Thus, 8 half-lives has elapsed
Finally, we shall determine the age of the bone.
Half-life (t½) = 5730 years
Number of half-lives (n) = 8
Time (t) =?t = n × t½
t = 8 × 5730
t = 45840 yearsTherefore, the age of the bone is 45840 years.
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It takes 4 seconds for a car to completely stop at a red light from a speed of 24 m/s
The car's acceleration is ____ m/s2. Use No decimal and no unit!
Answer:
6m/s^2
Explanation:
Acceleration is the change in speed/Velocity per unit time. That means the speed divided by the time. 24m/s divided by 4s=6m/s^2
Công thức cộng vận tốc
Answer:
you are very kind except for your habit
CAN YALL GO FOLLOW MY INS PLSS yeabdagod
Answer:
just followed :)
Explanation:
Prove that the two equations shown below are equivalent.
F = ma and F = p/t
Newton’s Second Law of Motion is defined as Force is equal to the rate of change of momentum. For a constant mass, force equals mass times acceleration.
[tex]\Delta p = mv - mu \\\\\implies \Delta p = m(v-u) \\\\F = \dfrac{\Delta p}{\Delta t} = \dfrac{m(v-u)}{\Delta t} = ma[/tex]
F = ma is the formula of Newton’s Second Law of Motion.
To prove Newton's second law of motion,
Given Force F = Δp/Δt
What is relation between F = ma and F = Δp/Δt?Newton’s Second Law of Motion is defined as Force is equal to the rate of change of momentum. The second law of Newton can be described as the acceleration of an object which produces a net force is directly proportional to the magnitude of the net force, in the same path i.e., direction as the net force, and inversely proportional to the mass of the object.As the acceleration has its magnitude and direction it is a vector quantity.Proof for F=ma
Let us consider an object of mass m, moving along a straight line with an initial velocity u, final velocity v and it has some particular time t and thus Momentum can be related as,
For initial velocity u, p1 = m × u
The final velocity v, p2 = m × v
The change in momentum can be expressed as
p2 – p1 = (m × v) – (m × u)
p2 – p1 = m (v – u)
Here, we know that the rate of change of momentum with respect to time is proportional to the applied force.
The applied force F,
F ∝ [m (v – u)]/t
F ∝ m × a
As acceleration (a) is the rate of change of velocity with respect to time.
F = k × m × a
F = ma
where k can be the constant.
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definiciones de estrés
Answer:
dame la marca más inteligente, por favor
Explanation:
En el campo de la medicina, es la respuesta del cuerpo a una presión física, mental o emocional. El estrés produce cambios químicos que elevan la presión arterial, la frecuencia cardíaca y las concentraciones de azúcar en la sangre. También suele producir sentimientos de frustración, ansiedad, enojo o depresión.
Answer:
El estrés es la reacción del cuerpo al sentirse amenazado o bajo presión.
Explanation:
learning task 2: assess your health status by using the question below try to determine if you are capable to do the physical fitness test .write your answer in your answer sheet
To assess your health status, it is necessary to take the physical fitness test, which will determine how healthy you are, according to some questions, such as how often you have seen a doctor, how is your heart, etc.
Some sample questions to assess your health status are:
Have you seen a pshysician?Whats your heart condition according to your physician?Are you recommended to do some physical activity?Do you feel any chest pain if you are not doing physical activity?This past few days, do you feel any chest pain if you are not doing phsysical activity?Do you ever lose consciusness or lose your balance because of dizziness?Do you have any joint or bone injury or problem that could be made worse by performing physical activity?Therefore, the physical fitness test is necessary so that a person can perform physical activities safely, avoiding injuries and other associated risks.
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What kind of force could cause this ball to not be at rest anymore, or cause it to move?
Answer:
friction
Explanation
Answer:
Friction
Explanation:
What force prevents an object at rest?
Sliding Friction While static friction keeps an object at rest, sliding friction slows down an object that slides. If you push an object across a room, you notice the sliding friction between the bottom of the object and the floor. You have to keep pushing to overcome the force of sliding friction.