winch one is biger
4/9 0r 1/12

Answer:

57kg

Step-by-step explanation:

The maximum weight of a shipping container would be 57 kilograms.

The units of measurement are a collection of units used to quantify various physical quantities. Since ancient times, humans have measured these things using a variety of units, including length, mass, volume, current, and temperature.

The maximum weight of a shipping container is 125 pounds which are given in the question.

We have to determine the maximum weight in kilograms

We know that the unit conversion of pounds to kilograms as

1 pound ≈ 0.45359237 kilogram

Multiply by 125 to get

125 pounds = 0.45359237 × 125 kilograms

125 pounds = 56.69904625 kilograms

Round to the nearest kilogram,

125 pounds = 57 kilograms

Therefore, the maximum weight of a shipping container would be 57 kilograms.

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Answer:

  see attached

Step-by-step explanation:

The two inequalities you want to plot are ...

  x + y ≤ 75 . . . . . . . . the auditorium can hold no more than 75 people

  5x +7.5y ≥ 450 . . . a minimum of $450 revenue is needed to cover costs

__

These are probably most easily plotted by graphing their intercepts. The boundary line for the first inequality will have x- and y-intercepts of 75. Shading will be below the line.

The boundary line for the second inequality will have an x-intercept of 450/5 = 90, and a y-intercept of 450/7.5 = 60. Shading will be above the line.

On of the points in the potential solution area is shown in the attached graph:

  (x, y) = (25, 50) . . . . fills the theater, gives $500 revenue

Answer:

Horizontal compression by a factor of 2 followed by a vertical shift by positive 3

Step-by-step explanation:

a*f(k(x-d))+c

k=2

c=3

Answer:

46?

Step-by-step explanation:

23*2=46

Answer:

37.31 cm

Step-by-step explanation:

∡ AB = 180 - 148 = 32° = ∡ DE

∡ CD = 360 - ∡ AE - ∡ AB - ∡ BC - ∡ DE = 360 - 148 - 32 - 87 - 32 =61°

∡ CE = 61 + 32 = 93°

arc length = 2[tex]\pi[/tex]r [tex]\frac{angle}{360}[/tex] = 2×3.14×23×[tex]\frac{93}{360}\\[/tex] = 37.31 cm

Answer:

ab hehehe hende ko Alam hahahah

Hence, the area of the square [tex]AB[/tex]  is [tex]5[/tex]

What is the area of square?

The area of a square is equal to

(side) × (side) square units.

Here given that,

Square [tex]ABCD[/tex] is drawn on the coordinate plane (not shown) with vertex [tex]A(-4,-2)[/tex] and the midpoint of side [tex]AB[/tex] at [tex]B(-1.-6).[/tex]

Given ertices are [tex]A(-4,-2)[/tex] and [tex]B(-1.-6).[/tex]

So,

[tex]AB=\sqrt{(-1+4)^2+(-6+2)^2}\\AB=\sqrt{(3)^2+(-4)^2}\\AB=\sqrt{9+16}\\AB=\sqrt{25}\\AB=5[/tex]

Hence, the area of the square [tex]AB[/tex]  is [tex]5[/tex].

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Answer:

the answer is 10 :)

Step-by-step explanation:

Given that "Jane wrote all the natural numbers from 5 to k. Including 1 and k"

So Jane wrote k numbers.

lets take an example

if k = 10 , then natural numbers between 1 and 10 are 10 numbers that are 1 , 2 , 3 ,4 ,5 ,6 , 7 , 8 ,9 and 10.

Hence she write k numbers.

Jane wrote k - 4 natural numbers for the given condition.

Natural numbers are defined as which range from 1 to infinity and are the most fundamental sort of numbers. Commonly known as positive numbers or counting numbers, these numbers. Natural Numbers are represented by the symbol N.

Jane wrote all the natural numbers from 5 to k, including 5 and k.

So, she wrote the numbers as 5, 6, 7, 8, 9, ..., k.

To find out how many numbers Jane wrote, we have to subtract 4 from each of these numbers because 4 numbers (1, 2, 3, 4) come before 5.

1, 2, 3, 4, 5, ..., k-1

So, there are k-1 - 4 + 1 = k - 4 natural numbers between 5 and k, inclusive.

Therefore, she wrote k - 4 natural numbers.

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Answer:

100.73

Step-by-step explanation:

Area of Rectangle=140

Area of Semi-Circle=39.27

Area of Rectangle-Area of Semi-Cirlce=100.73

Answer:

105°.

Step-by-step explanation:

1) to calculate m(∠ABC): m(∠ABC)=180-m(∠BAC)-m(∠(ACB)=180-90-65=25°;

2) note, m(∠ABC)=m∠(ABD)=25°, then it is possible

3) to calculate m(∠BAD): m(∠BAD)=180-m(∠ABD)-m(∠ADB)=180-25-50=105°.

[tex]35m>-30\\\\\implies \dfrac{35m}{35}>-\dfrac{30}{35}\\\\\implies m>-\dfrac{6}{7}[/tex]

Answer:

if u are asking how many more pages Matthew read then it's 48 pages. If u are asking how many they read all together then it's 144 pages.

Answer:

5

Step-by-step explanation:

When we use the number line, we need to count forward from -10.

Therefore, the distance between -9 and -4 is 6 units.

Hoped this helped.

[tex]-BrainiacUser1357-[/tex]

Answer:

250 boys

Step-by-step explanation:

sum the parts of the ratio, 5 + 3 = 8 parts

Divide the total by 8 to find the value of 1 part of the ratio

400 ÷ 8 = 50 , then

number of boys = 5 × 50 = 250

Answer : There is 250 boys in the sixth grade

Step - by - step explanation :

400 / [ 5 + 3 ] = 400 / 8 = 50

50 x 5 <-- The ratio of boys = 250

Answer:

x=15

Step-by-step explanation:

if you put 8x-10=110 you can solve for x and get 15. this only works because they are opposite & congruent sides

Answer:

a = 22

AB = 50

Step-by-step explanation:

[tex]a-5=17[/tex]

[tex]a=17+5[/tex]

[tex]a=22[/tex]

Line AB=2a+6

[tex]2(22)+6=44+6=50[/tex]

[tex]AB=50[/tex]

Hope this helps

Answer:

Both are false

Step-by-step explanation:

When you dilate something by a number >1 it gets larger.

Answer:

8% annual

Step-by-step explanation:

first find the rate of 1 year. 960/3 = 320.

then find what % of 4,000, 320 is.

8%

Answer: The equation of a line that passes through the point (8,-4) and has a slope of 3 is y = 3x - 28.

Explanation:

y = -4, x = 8

By putting above values in equation (i)

-4 = 3 (8) + b

-4 = 24 + b

-28 = b

b = -28

y = 3x - 28

Answer: D) 10 jerseys

Step-by-step explanation:

Let j represent the number of jerseys and C for total cost

Local company eqn: C = 5.25j + 45

Online company eqn: C = 7.75j + 20

Set both sides equal to solve:

5.25j + 45 = 7.75j + 20

5.25j - 7.75j = 20 -45

- 2.5j = -25

[tex]\frac{-2.5j}{-2.5}=\frac{-25}{-2.5}[/tex]

j = 10

Therefore, the cost is the same for both companies when 10 jerseys are sold

I hope this help too.

Answer:-

The linear sequence 27, 25, 23, 21, 19... is an arithmetic progression with (-2) as the common difference.

The nth term of an arithmetic progression is an=a1+(n−1)da_n=a_1+(n-1)dan​=a1​+(n−1)d, where ana_nan​ is the nth term, a1a_1a1​ is the first term, d is the common difference.

In our case, n=50,a1=27,d=−2n=50, a_1=27, d=-2n=50,a1​=27,d=−2 , hence, we get

a50=27+49⋅(−2);a50=27−98=−71.a_{50}=27+49\cdot(-2);\\ a_{50}= 27-98=-71. a50​=27+49⋅(−2);a50​=27−98=−71.

The 50th term of this sequence is (-71).

Using the normal distribution, it is found that the percentage of their weekly sales over P4,000 is given by:

C. 5.48%

In a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

In this problem, the mean and the standard deviation are, respectively, of [tex]\mu = 3200, \sigma = 500[/tex].

The proportion of their weekly sales over P4,000 is 1 subtracted by the p-value of Z when X = 4000, hence:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{4000 - 3200}{500}[/tex]

[tex]Z = 1.6[/tex]

[tex]Z = 1.6[/tex] has a p-value of 0.9452.

1 - 0.9452 = 0.0548 = 5.48%.

Hence option C is correct.

More can be learned about the normal distribution at https://brainly.com/question/24663213

Answer:

the desired line is y = 3x - 4

Step-by-step explanation:

The slope formula is not needed here.  If the given line is y = 3x - 2, we can see immediately that the slope is 3, in both cases.

Find the y-intercept as follows:

y = mx + b => 5 = 3(3) + b, or b = -4

Then the desired line is y = 3x - 4

Answer:

15

Step-by-step explanation:

Answer:

Step-by-step explanation:

we should divide it by 3 to get a perfect square .and the square root of the perfect square is 49

[tex]\begin{gathered}\:\:\:\:\:\:\:\:\:\:\:\begin{gathered} \begin{array}{c|c} \underline{\sf{3}}& {\sf{ \underline{ \pink{7203} \: } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }} \\ \underline{\sf{7}}&{\sf{ \underline{2401 \: \: \: }\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }} \\\underline{\sf{7}}&{\sf{ \underline{343 \: \: \: \: \: }\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }} \\\underline{\sf{7}}&{\sf{ \underline{49\: \: \: \: \: }\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }} \\\underline{\sf{7}}&{\sf{ \underline{7 \: \: \: \: \: }\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }} \\\underline{\sf{}}&{\sf{ 1 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }} \end{array}\end{gathered}\end{gathered}[/tex]

[tex]\qquad[/tex][tex]\purple{ \bf\longrightarrow 7203 = 3 \times 7 \times 7 \times 7 \times 7} [/tex]

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