Why would you be unlikely to see an α helix containing only the following amino acids: Arg, Lys, Met, Phe, Trp, Tyr, Val?

Answers

Answer 1

It is unlikely to see an α-helix containing only Arg, Lys, Met, Phe, Trp, Tyr, and Val, due to the unfavorable interactions and steric hindrance caused by the combination of charged and bulky side chains.

An α-helix is a common secondary structure found in proteins, where a single polypeptide chain coils into a right-handed helix. The helix is stabilized by hydrogen bonds between the carbonyl group of one amino acid residue and the amide group of an amino acid residue four residues away.

Arginine (Arg) and lysine (Lys) are positively charged amino acids with bulky side chains, while methionine (Met), phenylalanine (Phe), tryptophan (Trp), tyrosine (Tyr), and valine (Val) are nonpolar amino acids.

The bulky and charged side chains of Arg and Lys would create steric hindrance and repulsion within the helix, making it difficult to form and stabilize the helical structure. The presence of multiple bulky and charged residues in close proximity could also disrupt the hydrogen bonding between the amino acid residues, further destabilizing the helix.

learn more about protein here:

https://brainly.com/question/30434429

#SPJ11


Related Questions

a metal with a threshold frequency of 1.39×10^15 s^−1 emits an electron with a velocity of 6.76×10^5 m/s when radiation of 1.68×10^15 s−1 strikes the metal.
Part A
Calculate the mass of the electron.

Answers

The mass of the electron is approximately 5.69 × 10⁻³⁵ kg.

We can use the Einstein's famous equation relating energy and mass to solve for the mass of the electron:

E = mc²

where E is the energy of the electron, m is its mass, and c is the speed of light.

First, we can find the energy of the incident radiation using Planck's equation:

E = hf

where h is Planck's constant and f is the frequency of the radiation.

E = (6.626 × 10⁻³⁴ J s) × (1.68 × 10^¹⁵ s⁻¹) = 1.11 × 10⁻¹⁸ J

Next, we can find the kinetic energy of the electron using the formula:

KE = 1/2 mv²

where KE is the kinetic energy of the electron, m is its mass, and v is its velocity.

KE = 1/2 × m × v²

We know that the energy of the incident radiation is equal to the work function plus the kinetic energy of the emitted electron:

E = Φ + KE

where Φ is the work function of the metal.

Solving for KE and substituting the given values, we get:

KE = E - Φ = (1.11 × 10⁻¹⁸ J) - h(f0) = (1.11 ×10⁻¹⁸J) - h(1.39 × 10¹⁵ s⁻¹)

KE = 5.11 × 10⁻¹⁹ J

Now, we can solve for the mass of the electron using the formula:

m = KE/c²

m = (5.11 × 10⁻¹⁹ J)/(3.00 × 10⁸ m/s)² = 5.69 × 10⁻³⁵ kg

Therefore, the mass of the electron is approximately 5.69 × 10⁻³⁵ kg.

Learn more about kinetic energy

https://brainly.com/question/26472013

#SPJ4

Highly concentrated nitric acid, HNO3, it’s often need to recover gold powder from the waste sledge of smelting plants.
The first step in the process is summarized in the unbalanced reaction below balance of the reaction.

__HNO3(L) + __Au(s) + __AuNO3(aq) + __H2(g)

What is the reaction tape

Is 13.6 g of gold are to be dissolved how many milliliters of 24 M HNO3 Will be needed?

Answers

We need 5.75 mL of 24 M HNO3 to dissolve 13.6 g of gold.

Concentrated nitric acid reacts with gold to produce gold powder.

2Au(s) + 10H+ + 4NO3- → 4HNO3(L). 2Au(NO3)4- + 4NO2(g) + 6H2O(l)

Nitric acid oxidises gold, forming gold ions in a redox process.

First, we must convert 13.6 g of gold to moles to compute the quantity of 24 M HNO3 required to dissolve it. 13.6 g of gold is 0.069 moles since its molar mass is 196.97 g/mol.

Next, we calculate the HNO3/Au mole ratio using the balanced equation. From the equation, 4 moles of HNO3 dissolve 2 moles of Au. Thus, 0.138 moles of HNO3 dissolves 0.069 moles of Au.

Finally, we determine 24 M HNO3 volume using M = n/V. Solving for V:

V = n/M

where n is 0.138 moles of HNO3 and M is 24 M.

Substituting values yields:

V = 0.138 moles/24 mol/L = 0.00575 L

Multiplying by 1000 converts volume to millilitres:

5.75 mL = 0.00575 × 1000 mL/L.

5.75 mL of 24 M HNO3 dissolves 13.6 g of gold.

Learn more about balancing equation, here
https://brainly.com/question/7181548

#SPJ1

What is the pressure of 2 moles of carbon dioxide at 70 degrees Celsius contained in a 4000 mL container?

Answers

10.6 atm is the pressure of 2 moles of carbon dioxide at 70 degrees Celsius contained in a 4000 mL container.

The physical force applied to an object is referred to as pressure. Per unit area, a perpendicular force is delivered over the surface of the objects. F/A (Force every unit area) is the fundamental formula for pressure. Pressure is measured in Pascals (Pa).

Absolute, atmospheric, differential, as well as gauge pressures are different types of pressure. 'Pressure' is the term used to describe the thrust (force) applied to a surface every unit area. The proportion of the force can the surface area (more than where the pressure is acting) is another way to describe it.

P×V = n×R×T    

P× 4000 = 2×0.821×330

P = 10.6 atm

To know more about pressure, here:

https://brainly.com/question/12971272

#SPJ1

Radium-226 undergoes alpha decay. What will be the products of this nuclear reaction? Explain.

Answers

When Radium-226 undergoes alpha decay an alpha particle (that is a double positively charged helium ion) and radon-222 are produced as products.

Why are radon-222 and a double positively charged helium produced?

When Radium-226 undergoes an alpha decay, it emits an alpha particle which comprises two protons and two neutrons that is equivalent to a helium nucleus. Owing to this nuclear reaction is the formation of a new atom with a mass number that is four units less than that of the original atom here, radium-226, and an atomic number that is two units less than that of the original radium-226.

The balanced chemical reaction for the radioactive decay of radium-226 is:

²²⁶₈₈Ra → ²²²₈₆Rn + ⁴₂He²⁺ + 2e⁻

Masses of the reactants and products are always conserved in any given chemical reaction and so the production of radon-222 must be accompanied by the production of helium ion to balance the masses on both sides.

Learn more about radioactive decay here:

https://brainly.com/question/1770619

#SPJ1

write a complete ionic equation for the following reaction. li2so4(aq)+co(no3)2(aq)→

Answers

Reaction between Li2SO4(aq) and Co(NO3)2(aq):



First, let's write the balanced molecular equation for the reaction:

Li2SO4(aq) + Co(NO3)2(aq) → 2 LiNO3(aq) + CoSO4(aq)

Now, we'll write the complete ionic equation by separating all the soluble ionic compounds into their respective ions:

2 Li⁺(aq) + SO₄²⁻(aq) + Co²⁺(aq) + 2 NO₃⁻(aq) → 2 Li⁺(aq) + 2 NO₃⁻(aq) + Co²⁺(aq) + SO₄²⁻(aq)

As you can see, some ions remain unchanged throughout the reaction. These are called spectator ions, and we can remove them to obtain the net ionic equation:

There are no ions that react to form a product, so the net ionic equation is:

No reaction.

This means that all the ions in this reaction are spectator ions, and there is no net ionic reaction between Li2SO4(aq) and Co(NO3)2(aq).

Learn more about ionic equations: What is the net ionic equation for this reaction? https://brainly.com/question/28193640

#SPJ11

if a jar test demonstrates that the optimum dosage for coagulation is 25 ppm al3 , how many lbs alum are required for a 45 mgd water treatment plant?

Answers

You would need 1,125 pounds of alum per day for a 45 MGD water treatment plant with an optimum coagulation dosage of 25 ppm Al3.

To determine the amount of alum required for a 45 mgd water treatment plant at an optimum dosage of 25 ppm Al3, we need to use a conversion factor. One pound of alum contains 0.553 pounds of Al3. Therefore, we can calculate the amount of alum required as follows:

Alum required (lbs/day) = (Optimum dosage in ppm * Flow rate in MGD * 8.34) / (Al3 content in alum * 1000)

Substituting the values, we get:

Alum required (lbs/day) = (25 * 45 * 8.34) / (0.553 * 1000) = 77.7 lbs/day

Therefore, approximately 77.7 lbs of alum are required per day for a 45 mgd water treatment plant at an optimum dosage of 25 ppm Al3.

Learn more about  coagulation  here:

https://brainly.com/question/12077625

#SPJ11

a rate is equal to 0.0200 m/s. if [a] = 0.100 m and rate = k[a]0, what is the new rate if the concentration of [a] is increased to 0.400 m?

Answers

the new rate when the concentration of A is increased to 0.400 m remains the same as the initial rate, which is 0.0200 m/s.

We are given the following information:
1. The initial rate is 0.0200 m/s
2. The initial concentration of A, [A] = 0.100 m
3. The rate equation is given as rate = k[A]^0

Now, we need to find the new rate when the concentration of A, [A] is increased to 0.400 m.
Step 1: Since the rate equation is given as rate = k[A]^0, we can simplify it to rate = k because any number raised to the power of 0 is 1.

Step 2: Use the initial rate and initial concentration to find the value of k. We are given rate = 0.0200 m/s and [A] = 0.100 m, so:
0.0200 m/s = k

Step 3: Now that we have the value of k, we can use the new concentration of A, [A] = 0.400 m, to find the new rate. Plug in the new concentration into the rate equation:

New rate = k * (0.400 m)^0

Since anything raised to the power of 0 is 1, the equation becomes:

New rate = k

Step 4: Use the value of k from Step 2:

New rate = 0.0200 m/s

To know more about concentration refer to

https://brainly.com/question/17206790

#SPJ11

(2)
if the sample of chips used to make the filtrate weighed 94.0 g how much NaCl is present in one serving (115g) of chips

Answers

To determine the amount of NaCl present in one serving (115g) of chips, you first need to calculate the proportion of NaCl in the 94.0g sample used to make the filtrate.

Let's assume "x" represents the amount of NaCl in the 94.0g sample. Next, set up a proportion with the known values:
x (amount of NaCl) / 94.0g (sample weight) = y (amount of NaCl in one serving) / 115g (serving size)
Once you have the proportion, you can solve for "y" to find the amount of NaCl in one serving of chips. However, without knowing the amount of NaCl (x) in the 94.0g sample, it's not possible to calculate the exact amount of NaCl in a 115g serving.

Learn more about NaCl here:

https://brainly.com/question/18248731

#SPJ11

Report your measurements to the correct number of significant figures. From the procedure 1. Place 30 mL of the cyclohexane and toluene mixture in a 50 mL round bottom flask with a few boiling stones or a stir bar. Volume of the starting solution (mL) Graduated cylinder reading 50 40 30 20

Answers

The  volume of the starting solution is 10.0 mL

How we can cyclohexane and toluene mixture in a 50 mL round bottom flask with a few boiling stones or a stir bar?

The significant figures in a measurement represent the precision of the measurement. In this case, the precision of the measurement is limited by the precision of the graduated cylinder, which is typically accurate to within +/- 0.1 mL. Therefore, we should report the measurements to the nearest 0.1 mL.

The volume of the starting solution can be calculated by subtracting the graduated cylinder reading from 50 mL:

For 50 mL: 50 mL - 40 mL = 10.0 mL

For 30 mL: 30 mL - 20 mL = 10.0 mL

Therefore, the volume of the starting solution is 10.0 mL, which has two significant figures. We should report our measurements to the same number of significant figures as the least precise measurement, which in this case is two significant figures. Therefore, we can report our measurements as:

Learn more about volume.

brainly.com/question/1578538

#SPJ11

why does acetyl chloride (2 carbons with 1 polar functional group) react with water almost violently, but you had to warm and shake the mixture of water and benzoyl chloride (7 carbons)?

Answers

The reason acetyl chloride reacts with water almost violently is because it is a highly reactive compound due to the presence of the polar functional group, chloride.

Chloride ions are highly electronegative and have a strong affinity for water molecules. When acetyl chloride is added to water, the chloride ions attract water molecules, causing the reaction to occur quickly and violently.

On the other hand, benzoyl chloride has a longer carbon chain and is less reactive than acetyl chloride. This means that the reaction with water is slower and requires a higher energy input, such as warming and shaking the mixture. The longer carbon chain also makes it less polar than acetyl chloride, which means it is less attracted to water molecules and therefore does not react as violently.

Learn more about acetyl chloride here:

https://brainly.com/question/30325322

#SPJ11

How many formula units are contained in 1.67 g CaO

Answers

There are approximately 1.79 x 10²² formula units of CaO in 1.67 g of CaO.

What is Avogadro's constant?

Avogadro's constant, also known as Avogadro's number (N_A), is a fundamental physical constant that represents the number of constituent particles (usually atoms or molecules) in one mole of a substance.

The value of Avogadro's constant is approximately 6.022 x 10²³ particles per mole. This means that one mole of any substance contains 6.022 x 10²³ particles. For example, one mole of oxygen gas (O2) contains 6.022 x 10²³ oxygen molecules, and one mole of sodium chloride (NaCl) contains 6.022 x 10²³ sodium ions and 6.022 x 10²³ chloride ions.

To determine the number of formula units of CaO in 1.67 g of CaO, we need to use the molar mass of CaO and Avogadro's number.

The molar mass of CaO is:

CaO = 40.08 g/mol (Ca) + 16.00 g/mol (O) = 56.08 g/mol

Using the molar mass, we can calculate the number of moles of CaO:

n = m/M = 1.67 g / 56.08 g/mol = 0.0298 mol

Finally, we can use Avogadro's number, which is 6.022 x 10²³ formula units/mol, to calculate the number of formula units of CaO:

number of formula units = n x N_A = 0.0298 mol x 6.022 x 10²³ formula units/mol = 1.79 x 10²² formula units.

To know more about Avogadro's number, visit:

https://brainly.com/question/11907018

#SPJ1

calculate the acid dissociation constant ka of hydrocyanic acid (hcn) at 25.0c is 4.9x10^-10

Answers

The acid dissociation constant (Ka) is a measure of the strength of an acid. For hydrocyanic acid (HCN) at 25°C, the Ka is 4.9 x 10^-10. This means that at equilibrium, only a small fraction.

of HCN molecules dissociate into H+ ions and CN- ions. The Ka value can be calculated using the equation Ka = [H+][CN-]/[HCN], where [H+], [CN-], and [HCN] are the molar concentrations of the respective species at equilibrium. The pKa, which is the negative logarithm of The acid dissociation constant (Ka) is a measure of the strength of an acid. For hydrocyanic acid  the Ka value, is a commonly used measure of acid strength. For HCN, the pKa is 9.31, indicating that it is a weak acid. the acid dissociation constant ka of hydrocyanic acid (hcn) at 25.0c is 4.9x10^-10.

Learn more about  acid   here:

https://brainly.com/question/14072179

#SPJ11

write the brønsted acid equation for ch3cooh(aq).color of universal indicator in CH3COOH ____ pH ___color of universal indicator after addition of NaCH3CO2 ____ pHeffect of NaCH3CO2 on the equilibrium. use equation 16.14 to account for your observation,color of universal indicator in water _____

Answers

The Bronsted acid equation for CH3COOH(aq) is:
CH3COOH + H2O ⇌ H3O+ + CH3COO-

The color of the universal indicator in CH3COOH is typically orange-yellow, indicating a pH of around 3-4, the color of the universal indicator may change to green or blue-green after the addition of NaCH3CO2, indicating a higher pH of around 8-9.

This is because NaCH3CO2 is a weak base that can react with the acid CH3COOH to form its conjugate base, CH3COO-, and water:

NaCH3CO2 + H2O  ⇌  CH3COO- + Na+ + OH-The reaction shifts the equilibrium to the right, decreasing the concentration of H3O+ and increasing the concentration of CH3COO-. As a result, the pH increases, and the color of the universal indicator changes.

Using equation 16.14, which relates the equilibrium constant (Ka) for a weak acid to its pKa value, we can account for this observation. The pKa value for CH3COOH is approximately 4.76. When NaCH3CO2 is added, it reacts with CH3COOH to form CH3COO-, which is the conjugate base of a weak acid. The pKa value for CH3COOH and CH3COO- are related by the equation:

pKa(acid) + pKa(base) = 14

Thus, the pKa value for CH3COO- is;

pKa(acid) + pKa(base) = 14

pKa(base) = 14 - pKa(acid)

                 = 14 - 4.76

                 = 9.24

This means that CH3COO- is a weaker acid than CH3COOH, and the equilibrium will shift to the right to favor the formation of CH3COO- and H2O.

In water, the color of the universal indicator is typically green, indicating a neutral pH of around 7.

https://brainly.com/question/31485776

#SPJ11

A silver rod and a standard hydrogen electrode (SHE) are dipped into a saturated aqueous solution of silver oxalate, Ag,CO. at 25°C. The measured potential difference between the rod and SHE IS 0.589V. with the rod being positive. In this problem you will use this voltage to determine K for Ag C 0. Write the overall net reaction that would occur in this cell under standard state conditions and determine cell. Determine the number of electrons transferred in the net reaction. Determine Ag] in the half-cell containing the saturated solution of Ag2C 04, and then determine Ksp

Answers

The overall net reaction that occurs in this cell can be written as:

Ag2C2O4(s) + 2e- -> 2Ag(s) + 2C2O4^2-(aq)

The number of electrons transferred in the net reaction is 2.

Ag] in the half-cell containing the saturated solution of Ag2C 04 is [Ag+] = sqrt(Ksp) and Ksp = [Ag+]^2 = e^(1.66x10^-3)^2 = 1.09 x 10^-5

The cell potential, Ecell, can be calculated using the Nernst equation:

Ecell = E°cell - (RT/nF)lnQ

where E°cell is the standard cell potential, R is the gas electrons, T is the temperature in Kelvin, n is the number of electrons transferred in the net reaction, F is electrons constant, and Q is the reaction quotient.

Under standard state conditions, Q = K, and Ecell = E°cell. Therefore, we can use the measured potential difference between the rod and SHE to determine Ecell:

Ecell = 0.589 V

The standard potential of the SHE is defined to be 0 V, so the standard cell potential, E°cell, is:

E°cell = Ecell + E°SHE = 0.589 V + 0 V = 0.589 V

The number of electrons transferred in the net reaction is 2.

The concentration of Ag+ in the half-cell containing the saturated solution of Ag2C2O4 can be determined from the Nernst equation:

Ecell = E°cell - (RT/nF)lnQ

0.589 V = 0.46 V - (RT/2F)ln[Ag+]^2/[C2O4^2-]

ln[Ag+]^2/[C2O4^2-] = (0.589 V - 0.46 V) x (2F/RT)

ln[Ag+]^2/[C2O4^2-] = 1.66 x 10^-3

[Ag+]^2/[C2O4^2-] = e^1.66x10^-3

[Ag+] = sqrt(Ksp)

where Ksp is the solubility product constant for Ag2C2O4. Therefore, we can calculate Ksp as:

Ksp = [Ag+]^2 = e^(1.66x10^-3)^2 = 1.09 x 10^-5

For more such questions on electrons

https://brainly.com/question/860094

#SPJ11

in which one of the following species is the central atom (the first atom in the formula) an exception to the octet rule? group of answer choices no water i2 bcl4- hydronium ion

Answers

In the given species, the central atom that is an exception to the octet rule is found in BCl4-. In this species, boron (B) is the central atom and has only 6 electrons around it, which is an exception to the octet rule that states atoms generally aim to have 8 electrons in their valence shell.

Boron, the central atom, only has six valence electrons in this compound, instead of the usual eight electrons that would fill its valence shell according to the octet rule. This is because boron is a member of group 3A of the periodic table, and as such, it has only three valence electrons available for bonding. In BCl4-, boron forms four covalent bonds with chlorine atoms, resulting in a stable compound with an incomplete octet around the boron atom. The other species mentioned (water, I2, and hydronium ion) follow the octet rule for their central atoms.

Learn more about octet rule here:

https://brainly.com/question/30779148

#SPJ11

Number of O atoms in 6.25x10^-3 mol Al(NO3)3 - Express the amount in atoms to three significant digits.

Answers

The number of O atoms in 6.25 x 10⁻³ mol Al(NO₃)₃ is 3.38 x 10²² oxygen atoms.

To find the number of O atoms in 6.25 x 10⁻³ mol Al(NO₃)₃, you need to consider the following steps:

1. Determine the number of O atoms in one formula unit of Al(NO₃)₃. There are three NO₃ groups, each containing 3 O atoms, so there are 3 x 3 = 9 O atoms in one formula unit.

2. Use Avogadro's number (6.022 x 10²³ atoms/mol) to convert moles of Al(NO₃)₃ to atoms.

Now, you can calculate the total number of O atoms:

(6.25 x 10⁻³ mol Al(NO₃)₃) x (9 O atoms/formula unit) x (6.022 x 10²³ atoms/mol)

This gives you approximately 3.38 x 10²² O atoms.

So, there are 3.38 x 10²² oxygen atoms in 6.25 x 10⁻³ mol Al(NO₃)₃, expressed to three significant digits.

Learn more about oxygen atoms: https://brainly.com/question/29695801

#SPJ11

Which pairs of molecules have the correct boiling point (bp) trend? Show & explain all work.
i.) bp of CS2 > bp of CO2
ii.) bp of O2 > bp of H2
iii.) bp of SiH4 > bp of SnH4

Answers

The correct trend for the first pair is CS₂ > CO₂ due to stronger London dispersion forces. The correct trend for the second pair is O₂ > H₂ because of more electrons and stronger London dispersion forces.

Here's the boiling point trend for each pair of molecules:
i.) bp of CS₂ > bp of CO₂
CS₂ (carbon disulfide) has a boiling point of 46.3°C, while CO₂ (carbon dioxide) has a boiling point of -78.5°C. The reason for this difference is that CS₂ has stronger London dispersion forces due to its larger molecular size and higher number of electrons compared to CO₂. CO₂ has weaker interactions because it is a linear molecule with polar bonds, but the molecule itself is nonpolar, resulting in weaker attractive forces between molecules.
ii.) bp of O₂ > bp of H₂
O₂ (oxygen) has a boiling point of -183°C, and H₂ (hydrogen) has a boiling point of -252.87°C. O₂ has a higher boiling point because it has more electrons, which results in stronger London dispersion forces compared to H₂. The small size and low electron count of H₂ lead to weaker London dispersion forces and a lower boiling point.
iii.) bp of SiH₄ > bp of SnH₄
SiH₄ (silane) has a boiling point of -111.8°C, while SnH₄ (stannane) has a boiling point of -52°C. In this case, the trend is incorrect, as SnH₄ has a higher boiling point than SiH₄. The higher boiling point of SnH₄ is due to its larger molecular size and higher number of electrons, leading to stronger London dispersion forces between its molecules compared to SiH₄.
In summary:
- The correct trend for the first pair is CS₂ > CO₂ due to stronger London dispersion forces.
- The correct trend for the second pair is O₂ > H₂ because of more electrons and stronger London dispersion forces.
- The trend for the third pair is incorrect, and the correct trend is SnH₄ > SiH₄ due to larger molecular size and stronger London dispersion forces.

Learn more about boiling point :

https://brainly.com/question/2153588

#SPJ11

solid ammonium phosphate is slowly added to 175 ml of a aluminum iodide solution until the concentration of phosphate ion is 0.0695 m. the maximum amount of aluminum ion remaining in solution is m.

Answers

The balanced chemical equation for the reaction between ammonium phosphate and aluminum iodide is: the maximum amount of aluminum ion remaining in solution is 0.139 M.

([tex]NH_{4}[/tex])[tex]3PO_{4}[/tex](aq) + 3 [tex]AlI_{3}[/tex] (aq) → 3 [tex]NH_{4}[/tex]I (aq) + [tex]AlPO_{4}[/tex] (s)

We know that solid ammonium phosphate is slowly added to 175 ml of an aluminum iodide solution, and the concentration of phosphate ion is 0.0695 M at equilibrium. This means that the equilibrium concentration of phosphate ion ([[tex]PO4^{3-}[/tex]]) is 0.0695 M.

Let's assume that x mol of [tex]Al^{3+}[/tex] ions react with the phosphate ions to form [tex]AlPO_{4}[/tex](s) and hence x mol of [tex]Al^{3+}[/tex] ions are removed from the solution. As a result, the concentration of [tex]Al^{3+}[/tex] ions at equilibrium is [[tex]Al^{3+}[/tex]] = (initial concentration of [tex]Al^{3+}[/tex]+ ions) - x.

Since 3 moles of [tex]Al^{3+}[/tex] ions react with 1 mole of [tex]PO4^{3-}[/tex] ions, we can say that the initial concentration of [tex]Al^{3+}[/tex] ions is three times the concentration of phosphate ion. Therefore, the initial concentration of [tex]Al^{3+}[/tex] ions is:

[[tex]Al^{3+}[/tex]]_initial = 3 × [[tex]PO4^{3-}[/tex]]_equilibrium = 3 × 0.0695 M = 0.2085 M

Thus, at equilibrium, we have:

[[tex]Al^{3+}[/tex]] = [[tex]Al^{3+}[/tex]]_initial - x = 0.2085 M - x

The equilibrium concentration of [tex]PO4^{3-}[/tex] ions is given as 0.0695 M. This means that x moles of [tex]Al^{3+}[/tex] ions have reacted with [tex]PO4^{3-}[/tex] ions to form [tex]AlPO_{4}[/tex](s). As a result, the maximum amount of [tex]Al^{3+}[/tex] ions remaining in solution is:

[[tex]Al^{3+}[/tex]] = 0.2085 M - x = 0.2085 M - 0.0695 M = 0.139 M

Therefore, the maximum amount of aluminum ion remaining in solution is 0.139 M.

Learn more about ammonium phosphate

https://brainly.com/question/13504694

#SPJ4

what kinds of information can be learned about molecules from the x-axis of an absorbance spectrum?

Answers

The information that can be learned about molecules from the x-axis of an absorbance spectrum is the wavelength.

The x-axis of an absorbance spectrum typically represents the wavelength of light being absorbed by the molecule. From this information, one can learn about the electronic structure of the molecule and the types of chemical bonds present. This information helps to identify the molecule's structure, electronic transitions, and possible functional groups present in the molecule.

Additionally, the position and intensity of the peaks on the x-axis can provide information about the concentration of the molecule in the sample and any chemical interactions that may be occurring. Overall, the x-axis of an absorbance spectrum can provide valuable insights into the chemical properties of the molecule being analyzed.

Learn more about absorbance spectrum here: https://brainly.com/question/28007345

#SPJ11

All hydrogen atoms have one proton. If mass number equals the number of protons plus the number of neutrons, how many neutrons does Tritium have?

Answers

Answer:

2

Explanation:

Number of neutrons = Mass number - Number of protons

= 3 - 1

= 2

Tritium has 2 neutrons.
Tritium is an extremely rare isotope of hydrogen with a mass number of 3.
Of the 3 amu that make up tritium, one is a proton, meaning the other 2 must be neutrons.

which reaction does not occur in the atp formation from the oxidation of carbon compound?

Answers

In ATP formation from the oxidation of carbon compounds, the reaction that does not occur is "reduction."

ATP is formed through oxidative phosphorylation, where carbon compounds are oxidized to release energy, which is then used to generate ATP.

During oxidative phosphorylation, the electron transport chain accepts electrons from NADH and FADH2, which are produced during glycolysis and the citric acid cycle.

Oxidative phosphorylation occurs in the mitochondria of the cell and is the final step in the process of ATP formation. During this process, the energy stored in NADH and FADH2 is used to generate a proton gradient across the inner membrane of the mitochondria. This gradient is then used to drive the production of ATP through a process known as ATP synthase.

As electrons pass through the electron transport chain, protons are pumped across the mitochondrial inner membrane, generating a proton gradient. This gradient drives the synthesis of ATP by ATP synthase.

Learn more about ATP:

https://brainly.com/question/29384539

#SPJ11

what volume of the water in milliliters contains 135 mg of pb ? (assume that the density of the solution is 1.0 g/ml .)

Answers

The volume of water in milliliters containing 135 mg of Pb (lead) with a density of 1.0 g/mL is 0.135 ml.

To calculate the volume of water in milliliters containing 135 mg of Pb, we need to use the density of the solution which is 1.0 g/ml. First, we need to convert 135 mg to grams.

135 mg = 0.135 g

Next, we can use the formula:

density = mass/volume

We know the density is 1.0 g/ml and the mass is 0.135 g, so we can rearrange the formula to solve for volume:

volume = mass/density

volume = 0.135 g ÷ 1.0 g/ml

volume = 0.135 ml

Therefore, the volume of water in milliliters containing 135 mg of pb is 0.135 ml.

Learn more about volume of water: https://brainly.com/question/17322215

#SPJ11

What products would you expect from reaction of the following alkenes with NBS? If more than one product is formed, show the structures of all.

Answers

The products would from reaction of the following alkenes with NBS (N-bromosuccinimide) typically results in the formation of allylic bromides via allylic bromination.

NBS is a selective brominating agent that allows for the replacement of a hydrogen atom at an allylic position with a bromine atom, generating products that are resonance-stabilized. If more than one product is formed, it's likely due to the presence of multiple allylic positions in the starting alkene or the possibility of forming different stereoisomers. In such cases, the major product will be the one that is more stable due to resonance or steric factors.

Structures of all the possible products can be drawn by replacing the allylic hydrogens in the starting alkene with bromine atoms and considering any stereoisomers formed. In summary, the reaction of alkenes with NBS results in allylic bromides, and if multiple products are formed, they will be due to different allylic positions or stereoisomers. The products would from reaction of the following alkenes with NBS (N-bromosuccinimide) typically results in the formation of allylic bromides via allylic bromination.

Learn more about NBS at:

https://brainly.com/question/28218391

#SPJ11

Calculate the molar solubility of AgCl in 1.0 M NH3. Ksp for AgCl is 1.8×10−10; Kf for Ag(NH3)2+ ion is 1.7×107

Answers

The molar solubility of AgCl in 1.0 M NH3 is 1.3×10^-4 M.

How to calculate the molar solubility?

To calculate the molar solubility of AgCl in 1.0 M NH3, we can use the concept of complex ion formation and the formation constant (Kf) for Ag(NH3)2+ ion.

1. Write the dissolution reaction of AgCl:
AgCl (s) ⇌ Ag+ (aq) + Cl- (aq)

2. Write the complexation reaction between Ag+ and NH3:
Ag+ (aq) + 2NH3 (aq) ⇌ Ag(NH3)2+ (aq)

3. Use the given Ksp for AgCl and Kf for Ag(NH3)2+ ion:
Ksp = 1.8 × 10^(-10)
Kf = 1.7 × 10^7

4. Calculate the equilibrium constant for the combined reaction:

Ksp = [Ag+][Cl-] = x^2

Kf = [Ag(NH3)2+]/[Ag+][NH3]^2 = 1.7×10^7

5. Let x be the molar solubility of AgCl:
AgCl (s) ⇌ Ag+ (aq) + Cl- (aq) [x][x]
Ag+ (aq) + 2NH3 (aq) ⇌ Ag(NH3)2+ (aq) [x][1.0-2x]^2

6. Apply the equilibrium constant expression:
[Ag(NH3)2+] = Kf[Ag+][NH3]^2 = 1.7×10^7 x^3

7. Substitute the concentrations and solve for x:
Ksp = x^2 = [Ag+][Cl-] = [Ag(NH3)2+][Cl-] = [Cl-][Ag+][NH3]^2

x^2 = (1.7×10^7 x^3)(1.0 M)

x = √(1.7×10^-7) = 1.3×10^-4 M

To know more about Molar Solubility:
https://brainly.com/question/15080354

#SPJ11

the solubility product for silver chloride is 1.6 x 10−10. what is the molar solubility of silver chloride in a 6.5 x 10−3 m agno3 aqueous solution at 298 k?

Answers

Silver chloride has a molar solubility of 2.5 x 10-8 M in the specified solution.

(B) 2.5 x 10-8 M is the right answer.

What is the solubility of silver chloride solution in molar terms?

Let s denote the solubility of AgCl.

The concentrations of Ag+ and Cl- ions in solution will thereafter be reduced.

The solubility product (Ksp) of AgCl is expressed as: The AgNO₃ injected will dissociate to create Ag+ and NO₃- ions.

However, because the concentration of AgNO₃ is significantly more than the solubility of AgCl, we may infer that the concentration of Ag+ ions in solution is basically equivalent to the initial concentration of AgNO₃, which is 6.5 x 10-3 M.

learn more about solubility of AgCl

https://brainly.com/question/9429637

#SPJ1

Arrange the following isoelectronic series in order of increasing atomic radius: Se2−, Sr2+, As3−, Rb+, Br−.

Answers

The isoelectronic series of Se²⁻, Sr²⁺, As³⁻, Rb⁺, and Br⁻ can be arranged in order of increasing atomic radius, starting with Se2− and ending with Br−.

Isoelectronic series is a term which refers to a group of atoms or ions which have the same electron configuration. These atoms and ions have the same number of electrons, but different numbers of protons. As such, they possess the same electron configuration, but different atomic radii.

Se²⁻, has the smallest atomic radius, due to its high nuclear charge and low electron count. Sr²⁺ has a slightly larger atomic radius than Se²⁻, owing to its lower nuclear charge and slightly higher electron count. As³⁻ has an even larger atomic radius, as its nuclear charge is lower than Sr²⁺, and its electron count is higher.

Rb⁺ has an even larger atomic radius than As³⁻, due to its lower nuclear charge and higher electron count. Finally, Br⁻ has the largest atomic radius of the series, as it has the highest electron count and the lowest nuclear charge.

Know more about isoelectronic series here

https://brainly.com/question/30808153#

#SPJ11

A sample of silver chloride has a measured solubility of 1.1x10^-5 mol/L at a certain temperature. Calculate its Ksp value. Before any reaction occurs, the system contains solid AgCl and H20. The process that occurs is the dissolving of AgCl to form the separated Ag and crions: AgCl (s) <=> Ag^+ (aq) + Cl^- (aq) where Ksp = [Ag^+] [Cl^-]. What are the initial concentrations of Ag+ and Cl- ? [Ag+]o = _____ M [Cl-]o = _____ M

Answers

The initial concentrations of Ag^+ and Cl^- ions are 0 M, as they have not yet dissociated from the solid AgCl. Therefore, [Ag^+]o = 0 M and [Cl^-]o = 0 M.

In this problem, we are given the solubility of silver chloride (AgCl) as 1.1x10^-5 mol/L. The Ksp value can be calculated using the solubility information.
Since the balanced dissolution reaction is:
AgCl (s) <=> Ag^+ (aq) + Cl^- (aq)
The solubility of AgCl is equal to the concentration of Ag^+ and Cl^- ions in the solution at equilibrium. Thus,
[Ag^+] = [Cl^-] = 1.1x10^-5 mol/L
To calculate the Ksp value, we use the formula:
Ksp = [Ag^+] [Cl^-]
Substituting the concentrations of Ag^+ and Cl^- ions:
Ksp = (1.1x10^-5) (1.1x10^-5) = 1.21x10^-10
Before any reaction occurs, the initial concentrations of Ag^+ and Cl^- ions are 0 M, as they have not yet dissociated from the solid AgCl.
Therefore, [Ag^+]o = 0 M and [Cl^-]o = 0 M.

To calculate the Ksp value of silver chloride, we need to use the formula: Ksp = [Ag^+] [Cl^-].
Since the solubility of silver chloride is given as 1.1x10^-5 mol/L, we can assume that the initial concentration of both Ag+ and Cl- ions is also 1.1x10^-5 mol/L.
Therefore, [Ag+]o = 1.1x10^-5 M and [Cl-]o = 1.1x10^-5 M.
Note that the solubility of silver chloride is affected by the temperature and the concentration of other ions present in the solution. If the concentration of Cl- ions is increased, for example, the solubility of silver chloride would decrease, and vice versa.

Learn more about ions here: brainly.com/question/1488567

#SPJ11

Consider the balanced chemical reaction shown below. 1 Ca3P2(s) + 6 H2O(l) 3 Ca(OH)2(s) + 2 PH3(g) In a certain experiment, 9.055 g of Ca3P2(s) reacts with 2.224 g of H2O(l). (A)Which is the limiting reactant? (Example: type Ca3P2 for Ca3P2(s)) (B)How many grams of Ca(OH)2(s) form? (C)How many grams of PH3(g) form? (D)How many grams of the excess reactant remains after the limiting reactant is completely consumed?

Answers

The rate limiting step is calcium phosphide, 4.86g of calcium oxide is formed, 1.49g of phosphate is formed and 2.05 g of water is unrected.

How to identify limiting agentIt follows that Calcium Phosphide is the limiting reagent since the ratio of the masses of Calcium Phosphide to those of water is lower in the balanced chemical equation than it is for the provided masses.Ans. b 122 g of calcium phosphate produces 22 g of calcium oxide. Hence, 3.981 g of calcium phosphate will produce 222 /182 3.981 = 4.86 g of calcium oxide.Ans b 122 g of calcium phosphonate yields 68 g of phosphonate; hence, 3.981 g of calcium phosphonate will yield 68 /182 3.981 = 1.49 g of phosphonate.As a result, 182 g of calcium phosphate will react with 108 g of water, resulting in a reaction of 3.981 g of calcium phosphate and 2.36 g of water.So, unreacted water = 4.412 - 2.36 = 2.05 g

For more information on limiting agent kindly visit to

https://brainly.com/question/26943650

#SPJ1

A 0.0133 mol sample of Ba(OH)2 is dissolved in water to make up 15 L of solution. What is the pH of the solution?

Answers

The pH of the Ba(OH)2 solution is approximately 11.25

To find the pH of the Ba(OH)2 solution, we first need to calculate the concentration of OH- ions and then convert it to pH.

1. Calculate the concentration of OH- ions:
Ba(OH)2 dissociates into 1 Ba²⁺ ion and 2 OH⁻ ions. Therefore, the moles of OH⁻ ions will be twice the moles of Ba(OH)2.

Moles of OH⁻ ions = 0.0133 mol × 2 = 0.0266 mol

Next, we find the concentration by dividing the moles of OH⁻ ions by the volume of the solution.

[OH⁻] = 0.0266 mol / 15 L = 0.001773 mol/L

2. Convert the concentration of OH- ions to pH:
First, we calculate the pOH value:

pOH = -log10([OH⁻]) = -log10(0.001773) ≈ 2.75

Finally, we convert pOH to pH using the relationship:

pH + pOH = 14

pH = 14 - pOH = 14 - 2.75 ≈ 11.25

The pH of the Ba(OH)2 solution is approximately 11.25.

Know more about pH here:

https://brainly.com/question/491373

#SPJ11

what aldehyde or ketone is needed to prepare each alcohol by metal hydride reduction

Answers

To prepare primary alcohols, an aldehyde is needed metal hydride reduction, while for secondary alcohols, a ketone is required.

To prepare an alcohol by metal hydride reduction, you would need an aldehyde or ketone as the starting compound. Metal hydride reagents, such as sodium borohydride (NaBH₄) or lithium aluminum hydride (LiAlH₄), are commonly used for this reduction process.

For a given alcohol, to determine the required aldehyde or ketone, you would need to consider the structural changes during the reduction. In the reduction process, the carbonyl group (C=O) in the aldehyde or ketone is reduced to an alcohol group (OH).

For primary alcohols, you will need an aldehyde. For secondary alcohols, a ketone is required. The carbon chain of the alcohol should match the carbon chain of the aldehyde or ketone.

In summary, to prepare an alcohol by metal hydride reduction, choose an aldehyde for primary alcohols and a ketone for secondary alcohols with matching carbon chains. The metal hydride reagent, like NaBH₄ or LiAlH₄, will reduce the carbonyl group to form the desired alcohol.

Know more about Aldehyde or Ketone here:

https://brainly.com/question/15859478

#SPJ11

Other Questions
3. Would the specific gravity of coffee with cream and sugar be higher or lower than the specific gravity of water? Would it be higher or lower than that of the urine of a well well-hydrated person? Why? 4. What happens to the appearance of your urine on a hot day when you drink only a minimal amount of water? 5. When taking a urine sample why do we not take the first part of the urine? 6. What can drinking only soda do to your urine? can a constant acceleration be the greatest acceleration in a graph Your patient, a 3 year old boy, is brought into your gastroenterology practice by his mother. They were referred to you by their pediatrician because he has been complaining of severe abdominal pain, especially after eating, for the past few weeks. He has an otherwise normal health history.His pediatrician ordered a fecal occult (hidden) blood test, hematocrit, and urinalysis.The fecal occult blood test is positive and the hematocrit is lower than normal for a child his age. Body temperature and urinalysis are normal.You perform a surface abdominal exam, which appears normal. But the patient complains of pain in the lower right abdominal quadrant during palpitation. You order a CT enterography procedure, which uses a contrast dye to make an X-ray of the small intestine. A CT scan shows a diverticulum. After confirmation with a technetium scan, you diagnose your patient with Meckels diverticulum.Questions1. What symptoms is your patient experiencing? What common cause of lower right abdominal pain was the pediatrician trying to rule out with the fecal test? (Hint: If he had this condition, his body temperature would have been high).2. Why would your patients hematocrit be lower than normal? How is Meckels diverticulum different from other types of diverticula?3. How did the CT enterography and the technetium scan lead to the correct diagnosis?4.What type of treatment is recommended for your patient? is question has two parts. First, answer Part A. Then, answer Part B.rt A Which three adjectives best describe the setting where Carrie's new workplace is located?friendlyhecticimpressiveOintimidatingold-fashionedOsoothing An electron is in a one-dimensional box. When the electron is in its ground state, the longest wavelength photon it can absorb is 540 nm. What is the next longest-wavelength photon it can absorb, again starting in the ground state? You are given an implementation of a function: function solution (A); which accepts as input a non-empty zero-indexed array A consisting of N integers. The function works slowly on large input data and the goal is to optimize it so as to achieve better time and/or space complexity. The optimized function should return the same result as the given implementation for every input that satisfies the assumptions. For example, given array A such that: A[0]=4A[1]=6A[2]=2A[3]=2A[4]=6A[5]=6A[6]=1 the function returns 4. Also, for given array A such that: A[0]=2A[1]=2[49999]=2A[50000]=2 in other words, A[K]=2 for each K(0K50,000), the given implementation works too slow, but the function would return 50,000 . Write an efficient algorithm for the following assumptions: - N is an integer within the range [1..100,000]; - each element of array A is an integer within the range [1..N]. The original code is: A BODY WEGIHT 6N IN AIR 5N IN WATERWHATE IS VOLUME OF BODY Consider the following function. f(x) = ln(1 + 2x), a = 3, n = 3, 2.7 ? x ? 3.3(a) Approximate f by a Taylor polynomial with degree n at the number a. T3(X) = ?(b) Use Taylor's Inequality to estimate the accuracy of the approximationf(x) ? Tn(x) when x lies in the given interval. (Round your answer to six decimal places.) |R3(x)| ? ?(c) Check your result in part (b) by graphing. |Rn(x)|. do libertarians also believe everyone should have an equal opportunity to pursuit their goals The table gives data about Northland's economy in 2018. What is the value of GDP in Northland in 2018? The value of GDP in Northland in 2018 is A. $1,371 billion B. $1,032 billion cC. $2,403 billion D. $1,526 the exchange phenomena (to resolve an ionic balance) in which a negatively charged biocarbonate ion leaving the rbc is replaced by a negatively charged chloride ion entering the rbc is called Complete the solubility product equation and the Ksp expression for silver chloride. a c Ag Agci Ag] Special Instructions: Put cation species before anion species. (s) = (aq) + (aq) Ks = The circle below is centered on the origin. The hypotenuse of the right triangle within the circle is 5 units long, has one endpoint at the center of the circle, and the other endpoint is on the circle. Enter the equation of the circle: Universal Pet House sells vinyl doghouses and treated lumber doghouses. It takes the company 5 hours to build a vinyl doghouse and 2 hours to build a treated lumber doghouse. The company dedicates 50 hours every week towards building doghouses. It takes an additional hour to paint each vinyl doghouses and an additional 2 hours to assemble each treated lumber doghouses. The company dedicates 30 hours every week towards assembling and painting doghouses.Write a system of equations that represent the production time needed to build each doghouse and the production time needed for painting and assembling each doghouse. Use x to represent the number if vinyl doghouses and y to represent the number of treated lumber doghouses A parallel plate capacitor is fully charged by a 9 Volt battery before being disconnected. If the plate area then is decreased, then the electric field between the plates of the capacitor decreases. O will increase, only if it has a dielectric inside. increases. changes in an unknown way. remains constant. O will decrease, only if it has a dielectric inside URGENT!! ILL GIVEBRAINLIEST! AND 100 POINTS 10. The diagram at right shows a circle inscribed in a square. Find the area of the shaded region if the side length of the square is 6 meters. Supplementary angles show me a short letter to a friend another town to tell him you would like to stay with him for a few weeks say everything that is necessary The hydroxide ion concentration of an aqueous solution of 0.596 M phenol (a weak acid), C6H5OH, is [OH-] = ___ M.