Answer:
C. Visible light
Explanation:
Visible light is responsible for the colors of objects.
Hope it will help :)❤
How do we weigh planets? Explain your thinking
Train cars are coupled together by being bumped into one another. Suppose two loaded train cars are moving toward one another, the first having a mass of 138000 kg and a velocity of 0.288 m/s, and the second having a mass of 123000 kg and a velocity of -0.131 m/s. (The minus indicates direction of motion.) What is their final velocity
Answer:
their final velocity is 0.091 m/s
Explanation:
Given;
mass of the first train, m₁ = 138,000 kg
mass of the second train, m₂ = 123,000 kg
initial velocity of the first train, u₁ = 0.288 m/s
initial velocity of the seocnd train, u₂ = -0.131 m/s (opposite direction to the first)
Let their common final velocity after been coupled = v
Apply the principle of conservation of linear momentum;
m₁u₁ + m₂u₂ = v(m₁ + m₂)
(138,000 x 0.288) + (-0.131 x 123,000) = v(138,000 + 123,000)
39,744 - 16,113 = v(261,000)
23,631 = v(261,000)
v = 23,631 / 261,000
v = 0.091 m/s
Therefore, their final velocity is 0.091 m/s
2. In any energy transformation, energy is _____. A created B conserved C destroyed
Answer:
B energy can't be created or destroyed
A circuit has a voltage of 10 V and a current of 5 A. What must the resistance be?
0.5 ohms
50 ohms
2 ohms
15 ohms
Answer:
R=V/I
R= 2
Explanation:
R = 10V/5A
R = 2ohms
help pleeeeeeeease???
Answer:
30 miles
Explanation:
Calculate the electric force between two point charges of -54.0 μC and +36.0 μC when they are 2.00 cm apart.
**note -- the metric prefix "micro" = μ = x10 - 6 **
Is this attractive or repulsive?
Can someone help me please? Thank you!!!!
Answer:
43740 N and attractive force
Explanation:
Given that,
Charge 1, q₁ = -54.0 μC
Charge 2, q₂ = +36.0 μC
The distance between charges, r = 2 cm = 0.02 m
We need to find the force between charges. The formula for the force between charges is given by :
[tex]F=k\dfrac{q_1q_2}{r^2}[/tex]
Put all the values,
[tex]F=9\times 10^9\times \dfrac{54\times 10^{-6}\times 36\times 10^{-6}}{(0.02)^2}\\\\F=43740\ N[/tex]
As the charges are opposite, the force between them is attractive. Hence, the required force is 43740 N.
Two identical spheres a and b carry charges of +0.6 coulomb and -0.2 coulomb, respectively. If these spheres touch, the resulting charge on the first sphere will be...
A) + 0.8 C
B) + 0.2 C
C) - 0.3 C
D) + 0.4 C
A 330.-ohm resistor is connected to a 5.00-volt battery. What is the current through the resistor?
Answer:
From Ohms Law
V=IR
V=5volts
R=33.0hms
I=V/R
I= 5/330
=0.0152A
The current flowing through the cross-section of the resistor is 0.0152A.
Given the data in the question;
Resistance; [tex]R = 330ohm[/tex]Voltage; [tex]V = 5.00V[/tex]Current; [tex]I = \ ?[/tex]Ohm's lawOhm's law states that "the current flowing through the cross-section of a conductor is directly proportional to the voltage across it".
It is expressed as;
[tex]V = IR[/tex]
Where V is voltage, I is current and R is the Resistance.
To determine the current flowing through the resistor, we substitute our given values into the expression above.
[tex]V = IR\\\\I = \frac{V}{R}\\ \\I = \frac{5.00V}{330\ Ohm} \\\\I = 0.0152A[/tex]
Therefore, the current flowing through the cross-section of the resistor is 0.0152A.
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I will give more points
for this thank you I u helped
me
Answer:
weight = mass×gravity
15×9.8147Nstay safe healthy and happy.Help fast please physics
Answer:
10
Explanation:
An alpha particle (charge 2e) is sent at high speed toward an atomic nucleus. The electric force acting on the alpha particle is 79.8 N when it is 2.29 x 10(-14) m away from the nucleus. What is the charge on the atomic nucleus? (e = 1.60 x 10(-19) C, Kc = 9 x 10(9) N•m(2)/c(2)
Answer:
1.45×10⁻¹⁶ C
Explanation:
Applying,
F = kqq'/r²................ Equation 1
Where F = force acting on the alpha particle, k = coulomb's constant, q = charge on the alpha particle, q' = charge on the atomic nucleus, r = distance of seperation between the alpha particle and the atomic nucleus.
make q' the subject of the equation
q' = Fr²/(kq)................. Equation 2
From the question,
Given: F = 79.8 N, r = 2.29×10⁻¹⁴ m, q = 2e = (2×1.6×10⁻¹⁹) = 3.2×10⁻¹⁹ C, k = 9×10⁹ Nm²/C²
Substitute these values into equation 2
q' = [79.8×(2.29×10⁻¹⁴)²]/(3.2×10⁻¹⁹×9×10⁹)
q' = (4.18×10⁻²⁶)/(2.88×10⁻¹⁰)
q' = 1.45×10⁻¹⁶ C
pls send the answer..pls...
Answer:
The fall in temperature of the liquid is 8.6 +/- 0.1 ⁰C
Explanation:
Given;
initial temperature of the liquid, t₁ = 76.3 +/- 0.4⁰C
final temperature of the liquid, t₂ = 67.7 +/- 0.3⁰C
The change in temperature of the liquid is calculated as;
Δt = t₂ - t₁
Δt = (67.7 - 76.3) +/- (0.3 - 0.4)
Δt = (-8.6) +/- (-0.1)
Δt = 8.6 +/- 0.1 ⁰C
Therefore, the fall in temperature of the liquid is 8.6 +/- 0.1 ⁰C
the magnetic field at a certain point next to a wire carrying 10.0 A of current is 4.20x10^-5 T. what is the field at that point when the current is 20 A
Answer:
B=8.40x10^-5 T
Explanation:
To find the magnetic field at the new current, first you need to find the distance. To do so, alter the original equation from finding the field to finding the distance.
r (distance) = 4 pi x 10^-7 / 2 pi multiplied by 10.0 / 4.20 x 10^-5
which equals 0.04762
Next, just plug the numbers back into the original equation, taking into account the requested changes.
which equals 8.40x10^-5
Also it was right on Acellus ;)
Hope this helps :)
How would you calculate the number of moles of oxygen you had?
Answer:
Explanation:
1 mole of gas contains 6.02x10^23 molecules. That is the Avogadro's number. To find the number of moles, you divide the number of molecules by the Avogadro's number.
The correct answer is C.
Answer:
Explanation:
ans is C. divided by Avogadro no.
what is a Pulley why is it used
Answer:
A simple pulley is a wheel with a rope that allows you to pull one end and have it lift whatever is on the other end. A modern, common example of this is a crane, often used in construction.
Explanation:
The switch in a circuit breaker opens when which of the following in the circuit becomes too high?
A) current
B) resistance
C) static charge
D) total charge
Answer:
b) resistance
Explanation:
since resistance is responsible for heating, if it increases the circuit breaker opens breaking the flow of current to the circuit and thus preventing short circuits.
In what way may the turning effect of a force be increased?
By decreasing the perpendicular distance between the force and the pivot point
By lubricating the fulcrum with oil or grease.
By increasing the perpendicular distance between the force and the pivot point.
By reducing the applied force
Answer:
By increasing the perpendicular distance between the force and the pivot point
Explanation:
Due to the formula [tex]force * distance[/tex],
An increase in distance would cause the turning force to increase
Feel free to mark it as brainliest :D
Read the following lines from The Call of the Wild .
He was surprised at the eagerness which animated the whole team and which was communicated to him; but still more surprising was the change wrought in Dave and Sol-leks. They were new dogs, utterly transformed by the harness… The toil of the traces seemed the supreme expression of their being, and all that they lived for and the only thing in which they took delight.
Cite the quotation that best supports Buck's observation that the other dogs actually enjoy the harness.
"He was surprised at the eagerness which animated the whole team and which was communicated to him..."
"...but still more surprising was the change wrought in Dave and Sol-leks. They were new dogs, utterly transformed by the harness…"
"...still more surprising was the change wrought in Dave and Sol-leks."
"The toil of the traces seemed the supreme expression of their being, and all that they lived for and the only thing in which they took delight."
hey I read it do you use there a pacific question you want me to answer or something?
Answer:
I also recently read Call of the Wild for school and it was a great book.
Explanation:
ik its a lot but can u help
tysm for the person who helped me
Answer:
It's option 1: they have the same density.
Kiran runs along a straight road of length 150 m. After
reaching at end of the road he runs back to his initial
position along the same straight path. If he takes a total
time of 1 minute for completing his running, find the
average speed and average velocity of Kiran.
Answer:
Explanation:
Speed and velocity are not the same thing, as I'm sure you have determined while in physics. To find the average speed, we add the total distance run by Kiran and divide that total number of meters by the number of seconds it took to do this (just because I am going to state the speed and velocity in terms of m/s as opposed to m/min). To find the average velocity, we add the displacements together and divide by the total time. First the average speed:
[tex]s=\frac{150+150}{60}=\frac{300}{60}=5\frac{m}{s}[/tex]
Velocity has direction. If Kiran runs to the end of the road (which we will call positive) and then runs back to the start (that direction will be negative), then his displacement fits into the velocity equation as
[tex]v=\frac{150+(-150)}{60}=0[/tex] That means, even though he ran a lot and I'm sure he was very tired, his average velocity for the trip was 0 m/s. When velocity is 0, remember that that means that the total displacement was 0.
which of the following is a vector physical quantity
a. speed
b. energy
c. mass
d. displacement
Answer:
D. displacement
Explanation:
Vector quantities have both magnitude and direction.
Scalar quantities have only magnitude.
29. A boy lifts a book with the weight of 30.0 N from the floor to the top of a table, a vertical distance of 2.0. meters. Compute the increase in the potential energy of the weight.
Remember to include your data, equation, and work when solving this problem.
Answer:
60J
Explanation:
Since the book's weight is 30N and weight = mass * gravity (around 10m/s²):
30 = X * 10 ===> X = 3.
Using the potential energy formula we have Gravity * Height * Mass:
10 * 2 * 3 = 60J
which of these is a mechanical wave
1)Light .
2)Sound .
3)Gamma ray .
4)Electromagnetic .
Explanation:
Mechanical Sound Waves - A sound wave moves through air by displacing air particles in a chain reaction. ... Sound energy, or energy associated with the vibrations created by a vibrating source, requires a medium to travel, which makes sound energy a mechanical wave.(≚ᄌ≚)ℒℴѵℯ❤
18 kilogram Mass Blokus addressed a level surface if the coefficient of static friction between the Block in the surface is 0.6 what is horizontal force is required to take gravity 10m/s2
Question: 18 kilogram Mass Block rest on level surface if the coefficient of static friction between the Block and the surface is 0.6 what horizontal force is required to just move the blcok ( take gravity as 10m/s2 )
Answer:
108 N
Explanation:
From the question,
Applying
F' = mgμ................ Equation 1
Where F' = Frictional force = horizontal force required to just move the block, m = mass of the block, g = acceleration due to gravity, μ = coefficient of static friction.
From the question,
Given: m = 18 kg, μ = 0.6, g = 10 m/s²
Substitute these values into equation 1
F' = 18×0.6×10
F' = 108 N
which is the term for the study of weather and climate?
Answer:
Meteorology
Explanation:
That is indeed the study of weather and climate.
2. Stars normally convert hydrogen into helium through nuclear fusion. That requires incredibly hot temperatures and high pressure. At the moment, the temperature of empty space is nowhere near warm enough to fuse any elements together. What type of temperature and pressure conditions needed to be present in the early universe in order to create the first hydrogen atoms
Answer:
About 4,000 K and 10⁻¹⁷ atm
Explanation:
The Big Bang theory states that the Big Bang which is the origin of the universe was about 13.75 billion years ago, and the temperature a few seconds later was 10³²K
The first element began forming at about 3 minutes after the Big Bang with a temperature of 10⁹ K, the nuclei of simple elements
The nuclei of hydrogen and helium began combine with electrons at a temperature of 3,000 K to 4,000 K to form the first neutral atoms. The pressure of the universe at that stage was 10⁻¹⁷ atmospheres
If g were 15 instead of 9.81, what would your quads look like?
Answer:
Quads will have more energy
Explanation:
If the acceleration due to gravity increases from 9.81 to 15, then the velocity will increase as the rate of changing velocity i.e acceleration has increased from 9.81 to 15 m/s^2
With increase of velocity, the energy and force will also increase. Hence, the squad will require/have higher energy.
Numa máquina térmica uma parte da energia térmica fornecida ao sistema(Q1) é transformada em trabalho mecânico (τ) e o restante (Q2) é dissipado, perdido para o ambiente.
sendo:
τ: trabalho realizado (J) [Joule]
Q1: energia fornecida (J)
Q2: energia dissipada (J)
temos: τ = Q1 - Q2
O rendimento (η) é a razão do trabalho realizado pela energia fornecida:
η= τ/Q1
Exercícior resolvido:
Uma máquina térmica cíclica recebe 5000 J de calor de uma fonte quente e realiza trabalho de 3500 J. Calcule o rendimento dessa máquina térmica.
solução:
τ=3500 J
Q1=5000J
η= τ/Q1
η= 3500/5000
η= 0,7 ou seja 70%
Energia dissipada será:
τ = Q1 - Q2
Q2 = Q1- τ
Q2=5000-3500
Q2= 1500 J
Exercicio: Qual seria o rendimento se a máquina do exercicio anterior realizasse 4000J de trabalho com a mesma quantidade de calor fornecida ? Quanta energia seria dissipada agora?
obs: Entregar foto da resolução ou o cálculo passo a passo na mensagem
Bill is farsighted and has a near point located 125 cm from his eyes. Anne is also farsighted, but her near point is 75.0 cm from her eyes. Both have glasses that correct their vision to a normal near point (25.0 cm from the eyes), and both wear the glasses 2.0 cm from the eyes. Relative to the eyes, what is the closest object that can be seen clearly (a) by Anne when she wears Bill's glasses and (b) by Bill when he wears Anne's glasses
Answer:
a) The closest object Anne can see, while wearing Bill's glasses is at approximately 22.39 cm relative to her eyes
b) The closest object Bill can see while wearing Anne's glasses is at approximately 26.38 cm relative to his eyes
Explanation:
The point where Bill has a near point = 125 cm
The point where Anne has a near point = 75.0 cm
Their vision are both corrected to the normal near point = 25.0 cm
The distance of their glasses from the eye, d = 2.0 cm
The lens formula is presented as follows;
[tex]\dfrac{1}{f} =\dfrac{1}{d_0} +\dfrac{1}{d_i}[/tex]
The required distance of the of the object from Bill's glass, [tex]d_{oB}[/tex] = 25 cm - 2.0 cm = 23.0 cm
The distance of the of the image from Bill's glass, [tex]d_{iB}[/tex] = -(125 cm - 2.0 cm) = -123 cm
Therefore, for Bill, we have;
[tex]\dfrac{1}{f_B} =\dfrac{1}{d_{0B}} +\dfrac{1}{d_{iB}}[/tex]
Plugging in the values gives;
[tex]\dfrac{1}{f_B} =\dfrac{1}{23} -\dfrac{1}{123} = \dfrac{100}{2,829}[/tex]
Therefore;
[tex]f_B[/tex] = 2,829/100 cm = 28.29 cm
The required distance of the of the object from Anne's glass, [tex]d_{oA}[/tex] = 25 cm - 2.0 cm = 23.0 cm
The distance of the of the image from Anne's glass, [tex]d_{iA}[/tex] = -(75 cm - 2 cm) = -73 cm
The focal length for Anne is therefore;
[tex]\dfrac{1}{f_A} =\dfrac{1}{d_{0A}} +\dfrac{1}{d_{iA}}[/tex]
Plugging in the values gives;
[tex]\dfrac{1}{f_A} =\dfrac{1}{23} -\dfrac{1}{73} = \dfrac{50}{1,679}[/tex]
Therefore, we have;
[tex]f_A[/tex] = 1,679/50 cm = 33.58 cm
a) When Anne wears Bill's lasses, we have;
[tex]\dfrac{1}{f_B} =\dfrac{1}{d_{0A}} +\dfrac{1}{d_{iA}}[/tex]
Therefore, we get;
[tex]\dfrac{1}{28.29} =\dfrac{1}{d_{0A}} -\dfrac{1}{73}[/tex]
[tex]\dfrac{1}{d_{0A}} = \dfrac{1}{28.29} + \dfrac{1}{73} = \dfrac{10,129}{206,517}[/tex]
[tex]d_{0A}[/tex] ≈ 20.39 cm
The distance of the closest object Anne can see, from her eye, [tex]d_{oe}[/tex] = [tex]d_{0A}[/tex] + d
∴ [tex]d_{oe}[/tex] ≈ 20.39 cm + 2.0 cm = 22.39 cm
The distance of the closest object Anne can see, from her eye, [tex]d_{oe}[/tex] ≈ 22.39 cm
b) The closest object that can be seen when Bill wears Anne's glasses, we have;
[tex]\dfrac{1}{f_A} =\dfrac{1}{d_{0B}} +\dfrac{1}{d_{iB}}[/tex]
Therefore;
[tex]\dfrac{1}{33.58} =\dfrac{1}{d_{0B}} -\dfrac{1}{123}[/tex]
[tex]\dfrac{1}{d_{0B}} = \dfrac{1}{33.58} +\dfrac{1}{123} = \dfrac{7,829}{206,517}[/tex]
∴ [tex]d_{oB}[/tex] ≈ 26.38 cm
The closest object Bill can see while wearing Anne's glasses, [tex]d_{oB}[/tex] ≈ 26.38 cm.
What types of changes occur during the erosion and deposition of sediments in a river?
Answer:
Slow-moving rivers generate extensive floodplains and meanders through erosion and deposition. Stream and river deposition can result in the formation of alluvial fans and deltas. Natural levees may be formed by floodwaters. Caves and sinkholes can arise as a result of groundwater erosion and deposition.
Explanation:
s
The erosion and deposition of sediments in a river creates broad floodplains and meanders.
What is Erosion and Deposition?Deposition occurs when sediment, a combination of soil and rock produced by weathering, is eroded and transported to a new area.
Deposition is the act of depositing silt that has been transported by the wind, water, sea, or ice.
Earthen materials are worn away during erosion, a geological process in which they are moved by wind or water.
The removal of soil, rock, or dissolved material from one area on the Earth's crust and subsequent transport to another region for deposition are known as erosional processes. Erosion differs from weathering, which is a static process.
Given data ,
Let the erosion and deposition of sediments be deposited in a river
Now , Pebbles, sand, mud, and salts that have been dissolved in water can all be used to convey sediment. Afterwards, salts may be left behind by organic action.
Now , floodplain is caused when erosion happens
And , A floodplain is a broad, level or nearly level area of land where the stream flows.
Meandering streams that wander from side to side broaden the plain by eroding it during the formation of the plain. Flooding can occur when stream flows overflow from their channel due to very excessive rainfall or quick snow-melt.
Hence , floodplain and meandering occurs due to erosion and deposition
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