Which statement is true about the equation 4.5z = 4.5z − 4.25 + 6.25? It has no solution. It has one solution. It has two solutions. It has infinitely many solutions.

Answer:

B) x^3-x^2-8x-2

Step-by-step explanation:

Expand the equation of g(x) to standard form

f(x) = x^3-4x+2

g(x) = x^2-4x+4

Subtract like terms in the equation and solve for the answer.

f(x) - g(x) = x^3-x^2-4x-4x+2-4

x^3-x^2-8x-2

Answer:

5

Step-by-step explanation:

5 =5 +5+5=5+5

Answer:

10

Step-by-step explanation:

Answer:

-127 is colder

Step-by-step explanation:

-54 is closer to 0 than -127 so -127 is colder

They are both negatives BUT! -127 is greater than -54 and the 0 is the begginging of frezing point

Answer:

A rational number is a number that doesn't terminate or repeat

a non rational number is a number that terminates or repeats

so she basicelly got mixed up

Hope This Helps!!!

Answer:

 1-2y+y^2

Step-by-step explanation:

(1–y)^2

(1-y) * (1-y)

FOIL

first: 1*1 =1

outer: 1*-y = -y

inner: -y *1 = -y

last: -y*-y = y^2

Add together: 1+-y-y+y^2  

Final answer1-2y+y^2

Credit:

wegnerkolmp2741o

He solved it earlier.

Answer:

  AB, CD

Step-by-step explanation:

Skew lines do not lie in the same plane, and do not intersect. One such pair is AB and CD.

__

Additional comment

Any of the lines, and any of the lines that intersect its diagonally-opposite edge will be skew lines.

For example, the opposite edge to line BC is line EG. Lines that intersect EG are ED, EF, GA, GH. All of those four lines are skew with respect to line BC.

Answer:

8x-29y Sorry if wrong!

Step-by-step explanation:

You have to distribute first and then combine like terms.

Answer:

8x-29y

Step-by-step explanation:

You have to distribute first and then combine like terms.

And that is where you get your answer.

Hope this helps.

Answer:

The expression is d(45) + 25 = c

Step-by-step explanation:

The expression is d(45) + 25 = c. Let's test it out to see if it is correct. We will test it out by substituting d and c.

Day 1:

Day 2:

Day 3:

Day 4:

Therefore, the expression is d(45) + 25 = c.

Hoped this helped.

Answer:

d=100t or d=300t depending on how much the truck travels for an hour because no image was provided i dont know

Step-by-step explanation:

Answer:

v=32

Step-by-step explanation:

23-15=8x4=32

32/4+15=23

Answer: 90%

135/150 * 100

45*2

90

Answer:

y=(5/3)x + 5

Step-by-step explanation:

Every line is in the form: y = ax+b. If some points are on this line, they satisfy this equation. So we can write:

-5 = a(-6) + b

0 = a(-3) + b

It's a system of equations. We can solve them by subtracting the second equation from the first:

-5-0 = -6a - (-3a) + b - b

That becomes:

-5 = -3a

Therefore:

a = 5/3

Now we plug this value in the second equation of the system, and find the value of b:

0 = 5/3*(-3) +b

b=5

The final line equation will be: y=(5/3)x + 5

y = [tex]\frac{5}{3}[/tex]x + 5

First, find the slope. The formula to find slope can be defined as [tex]\frac{y_2-y_1}{x_2-x_1}[/tex].

Given points (-6, -5) and (-3, 0), we can substitute those values in and find that the slope for this line will be [tex]\frac{5}{3}[/tex].

Using slope-intercept form, our equation so far is y = [tex]\frac{5}{3}[/tex]x + b. To find b, we substitute the coordinates of any point and solve. Doing so gets us a value of 5 for b.

Therefore, our final answer is y = [tex]\frac{5}{3}[/tex]x + 5.

Answer:

21

Step-by-step explanation:

1/5 x 21 = 21/5

Answer:

Step-by-step explanation:

Sam's car is 1 ft in front of the start line and its speed is 13.5 ft/s.

The distance after x seconds is:

Alice's car the speed 12 ft/s and after 3 seconds is 40 ft in front of the start line.

The distance after x seconds is:

After 15 seconds the distance from the start line is:

As we see Sam is further from the start line than Alice

The ratio of the height of the triangle to the side of the square (B) 1 : 2

The area of a triangle is (1/2)×base×height.

The area of a square is (side)².

Given, The area of a square is four times the area of a triangle.

∴ (side)² = 4{(1/2)×base×height}.

The base of the triangle and the side of the square are equal let this be 'a'.

∴ a² = 4(1/2)×a×height.

a = 2×height.

a = 2h.

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Answer:

>

Step-by-step explanation:

> means greater than and because 79 is greater than -5, the correct sign you would use will be >

79 > -5

The shape of the graph of quadratic functions is the shape of a parabola.

The steps for drawing a graph of the function f(x) = 2·(x + 4)² - 3 arranged in the correct order are;

Reasons:

The given function is; f(x) = 2·(x + 4)² - 3

The function is given in the vertex form; f(x) = a·(x - h)² + k

Therefore, the vertex, (h, k) = (-4, -3)

Step (a);

The vertex can be plotted on the graph

Step (b);

Given that the quadratic term is 2·x², the pattern that can be used for the points from the vertex is therefore, 2·x²

From the vertex (-4, -3) apply the 2·x² pattern by going to the right 1 unit and  up 2 × 1² = 2 units to get the point (-4 + 1, -3 + 2) = (-3. -1)

Step (c);

To get the next point, the 2·x² pattern is applied with x = 2, to the vertex to get; (-4 + 2, -3 + (2×2²)) = (-2, 5)

Step (d);

A third point on the graph relative to the vertex is obtained again by applying the 2·x² pattern again to the vertex with x = 3, to get;

(-4 + 3, -3 + (2 × 3²)) = (-1, 15)

Step (e);

The axis of symmetry can be drawn with a vertical line passing through the vertex, which is the line, x = -4

The line x = -4 can be drawn on the graph next

Step (f);

The points obtained relative to the vertex (-3, -1), (-2, 5), (-1, 15) can reflected about the axis of symmetry x = -4, to get;

(-3, -1) [tex]\underrightarrow {R_{(x = -4)}}[/tex] (-5, -1)

(-2, 5) [tex]\underrightarrow {R_{(x = -4)}}[/tex] (-7, 5)

(-1, 15) [tex]\underrightarrow {R_{(x = -4)}}[/tex] (-7, 15)

Step (g);

The parabola that is U shaped can be drawn from the points plotted in the steps above.

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Answer:

I think you might be able to work with this: 0.15 * x - x + x * 0.06

Step-by-step explanation:

The item's cost is X.

So he has a coupon for 15%, so the cost of the item times 0.15 = how much he's getting as a discount, for example: A toy robot costs 13.46, Jenny has a coupon for 25% off, to find out how much she paid, multiply 0.25 by 13.46 which equals about 3.37, so 13.46 - 3.37 = 10.09

So 0.15 (the coupon price) * x (the item's original price) - x (the items orignal price) + x * 0.06 (the sales tax)

Comment if you need any help T^T

Based on the definition of an isosceles triangle, the measure of angle L is: 43°

Recall:

Given that KL ≅ MK in △KLM, it means △KLM is an isosceles triangle.

If m∠M = 43°, therefore, m∠M = m∠L (equal angles directly opposite KL and MK).

This implies that: m∠L = 43°

In summary, based on the definition of an isosceles triangle, the measure of angle L is: 43°

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Answer:

22

Step-by-step explanation:

2x+x-2=2x+9

3x-2=2x+9

x-2=9

x=11

MN=2x

MN=2(11)

MN=22

Answer:

Distance (d) = 15

Step-by-step explanation:

The given requires the distance between the point of origin, (0, 0), and (-12, 9). We can use the following distance formula for this problem:

[tex]\displaystyle\mathsf{Distance(d)=\:\sqrt{(x_2-x_1)^2\:+\:(y_2-y_1)^2}}[/tex]

Let (x₁, y₁) = (0, 0)

     (x₂, y₂) = (-12, 9)

Substitute these values into the distance formula.

[tex]\displaystyle\mathsf{Distance(d)=\:\sqrt{(x_2-x_1)^2\:+\:(y_2-y_1)^2}}[/tex]

[tex]\displaystyle\mathsf{Distance(d)=\:\sqrt{(-12\:-\:0)^2\:+\:(9-0)^2}}[/tex]

Perform the required subtraction within each parenthesis:

[tex]\displaystyle\mathsf{Distance(d)=\:\sqrt{(-12)^2\:+\:(9)^2}}[/tex]

Next, take the squared values of -12 and 9 under the radical:

[tex]\displaystyle\mathsf{Distance(d)=\:\sqrt{144\:+\:81}}[/tex]

Add 144 and 81:

[tex]\displaystyle\mathsf{Distance(d)=\:\sqrt{225}}[/tex]

Distance (d) = 15

Therefore, the distance between the point of origin and (-12, 9) is 15.

Answer:

75-82=-7

Step-by-step explanation:

e

Answer:

[tex]\huge{\mathfrak{Solution}}[/tex]

[tex]\huge{\bold{ \frac{ {y}^{2} }{36} - \frac{ {x}^{2} }{121} = 1 }}[/tex]

[tex]\huge{\bold{ \frac{(y - k) {}^{2} }{ {a}^{2} } - \frac{(x - h) {}^{2} }{ {b}^{2} } = 1 \: is \: the \: standard \: equation \: with \: center \: (h ,k),semi-axis \: a \: and \: semi-conjugate \: -axis \: b.}}[/tex]

[tex]\huge\boxed{\mathfrak{We \: get,}}[/tex]

[tex](h,k) = (0,0),a = 6,b = 11[/tex]

[tex]For \: hyperbola \: assymtoms \: are \: y = + \frac{a}{b} (x - h) + k[/tex]

[tex]Therefore,y = \frac{6}{11} (x - 0) + 0,y = - \frac{6}{11} (x - 0) + 0[/tex]

[tex]\large\boxed{\bold{y = \frac{6x}{11},y = - \frac{6x}{11} . }}[/tex]

If y²/36 - x²/121 = 1, the asymptotes are y = (36/121) x and y = -(36/121) x.

To find the equations for the asymptotes of the hyperbola represented by the equation y²/36 - x²/121 = 1, we can compare it with the standard form of a hyperbola:

(y - k)² / a² - (x - h)² / b² = 1

where (h, k) represents the center of the hyperbola.

In the given equation, we have y²/36 - x²/121 = 1. To put it in standard form, we need to divide both sides by 1 (which is essentially dividing by 1 on the right side):

y²/36 - x²/121 = 1 / 1

Now, we can see that a² = 36 and b² = 121.

To find the equations of the asymptotes, we use the center (h, k) and the values of a and b. The asymptotes of a hyperbola have equations of the form:

y = k ± (a/b)(x - h)

In this case, the center (h, k) is (0, 0), a² = 36, and b² = 121:

The equations for the asymptotes are:

y = 0 ± (36/121) x

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Answer:

yes, this line will pass through the point of origin

Step-by-step explanation:

Answer:

90lbs

Step-by-step explanation:

If Tim weights 90lbs, his brother must weigh 130lbs which add to make 220lbs

Answer:

12x - 6

Step-by-step explanation:

4 + 15x - 10 -3x

(15x - 3x) + (4-10)

12x - 6