Chemistry College

Which represents a balanced chemical equation?

Answers

Answer 1

i think it’s b but i could be wrong

Answer 2

Answer:

Explanation:

Reactant part has 2 Mg and 2 O, product part has 2 Mg and 2 O

Related Questions

A toy helicopter takes off and moves 2 m up and then 2 m back down. What
is the displacement of the helicopter?
A. 0 m
B. 2 m down
C. 2 m up
D. 4 m

Answers

Answer:

Explanation:

2m up - 2m down =0m

what is the pH of a 2.58 x 10^-6 M solution of an acid?

Answers

Answer:

5.59

Explanation:

The pH of a solution can be found by using the formula

[tex]pH = - log [ {H}^{+} ][/tex]

From the question we have

[tex]ph = - log(2.58 \times {10}^{ - 6} ) \\ = 5.58838[/tex]

We have the final answer as

5.59

Hope this helps you

THIS NOT MY WORK. its for my sister. HELP HER

Answers

Answer:

Your answer will be b(molten material from the outer core makes its way to the surface of earth)

Explanation:

Answer:

Explanation:

I'm pretty sure molten material comes from the inner core. I think you can search up this though, try to find where molten material comes from. Goodluck!

Which of the following density formulas have been rearranged correctly? pls help i have no idea what i’m doing

1. v = m/d

2. m = d/v

3. v = md

4. m = v/d

Answers

Answer:

v = m/d

Explanation:

To know which option is correct, we shall rearrange the the formula of density. This can be obtained as follow:

The density of a substance is defined as the mass per unit volume of the substance. Mathematically, it is expressed as:

Density (d) = mass (m) / volume (v)

d = m/v

Make m the subject

d = m/v

Cross multiply

m = dv

Next, made v the subject

d = m/v

Cross multiply

dv = m

Divide both side by d

v = m/d

SUMMARY:

From the density formula (i.e d = m/v) we obtained:

m = dv

v = m/d

Therefore, option v = m/d gives the correct answer to the question.

Determine the spec gravity of 500 mL alcohol if the density is 0.79g/ml

Answers

Answer:

S.G = 0.79.

Explanation:

Hello there!

In this case, according to the given information in the problem, it turns out possible for us to calculate the specific gravity of this alcohol by simply dividing its density, 0.79 g/mL by that of the water, 1 g/mL just as a reference for us to work with:

[tex]S.G=\frac{\rho _{alc}}{\rho _w}[/tex]

Thus, we plug in the densities to obtain:

[tex]S.G=\frac{0.79g/mL}{1g/mL}\\\\S.G=0.79[/tex]

Which is dimensionless as g/mL is cancelled out due to its presence on both top and bottom of the previous formula.

Regards!

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