Which of the following will form the composite function G(F(x)) shown
below?
G(F(x)) = 2(x-6)2 + 5

A. F(x) = x2 + 5 and G(x) = x-6
B. F(x) = 2x + 5 and G(x) = (x-6)2
C. F(x) = x - 6 and G(x) = 2x2 + 5
O D. F(x) = (x - 6)2 and G(x) = 5

Answer:

I think A and B

Step-by-step explanation:

• A statistical question is a question that has more than one possible answer ( and can be answered by collecting data) where there will be variability in the data. for instance an example would be " How old are the students in this room?"

• However a non statical question has only one answer for instance "How old are you?"

both a and b dont have specific answers because it's not talking about a specific high school students or a specific soccer team. i would guess those are correct, but using the information from above you can also see what you think! hope this helps :)

Answer:

Para un vaso de [tex]V = 25\pi\,cm^{3}[/tex], las dimensiones del vaso son [tex]r \approx 2.321\,cm[/tex] y [tex]h \approx 4.642\,cm[/tex].

Para un vaso de [tex]V = 1000\,cm^{3}[/tex], las dimensiones del vaso son [tex]r \approx 5.419\,cm[/tex] y [tex]h \approx 10.839\,cm[/tex].

Step-by-step explanation:

El vaso se puede modelar como un cilindro recto. El enunciado pregunta por las dimensiones del vaso tal que su área superficial ([tex]A_{s}[/tex]), en centímetros cuadrados, sea mínima para el volumen dado ([tex]V[/tex]), en centímetros cúbicos. Las ecuaciones de volumen y área superficial son, respectivamente:

[tex]V = \pi\cdot r^{2}\cdot h[/tex] (1)

[tex]A_{s} = 2\pi\cdot r^{2} + 2\pi\cdot r\cdot h[/tex] (2)

De (1):

[tex]h = \frac{V}{\pi\cdot r^{2}}[/tex]

En (2):

[tex]A_{s} = 2\pi\cdot r^{2} + 2\pi\cdot \left(\frac{V}{\pi\cdot r} \right)[/tex]

[tex]A_{s} = 2\cdot \left(\pi\cdot r^{2}+V\cdot r^{-1} \right)[/tex]

Asumamos que [tex]V[/tex] es constante, la primera y segunda derivadas de la función son, respectivamente:

[tex]A'_{s} = 2\cdot (2\pi\cdot r -V\cdot r^{-2})[/tex]

[tex]A'_{s} = 4\pi\cdot r - 2\cdot V\cdot r^{-2}[/tex] (3)

[tex]A''_{s} = 4\pi + 4\cdot V \cdot r^{-3}[/tex] (4)

Si igualamos [tex]A'_{s}[/tex] a cero, entonces hallamos los siguientes puntos críticos:

[tex]4\pi\cdot r - 2\cdot V\cdot r^{-2} = 0[/tex]

[tex]4\pi\cdot r = 2\cdot V\cdot r^{-2}[/tex]

[tex]4\pi\cdot r^{3} = 2\cdot V[/tex]

[tex]r^{3} = \frac{V}{2\pi}[/tex]

[tex]r = \sqrt[3]{\frac{V}{2\pi} }[/tex] (5)

Ahora, si aplicamos este valor a (4), tenemos que:

[tex]A_{s}'' = 4\pi + \frac{4\cdot V}{\frac{V}{2\pi} }[/tex]

[tex]A''_{s} = 4\pi + 8\pi[/tex]

[tex]A_{s}'' = 12\pi[/tex] (6)

De acuerdo con este resultado, el valor crítico está asociado al área superficial mínima. Ahora, la altura se calcula a partir de (5) y (1):

[tex]h = \frac{V}{\pi\cdot \left(\frac{V}{2\pi} \right)^{2/3} }[/tex]

[tex]h = \frac{2^{2/3}\cdot \pi^{2/3}\cdot V}{\pi\cdot V^{2/3}}[/tex]

[tex]h = \frac{2^{2/3}\cdot V^{1/3}}{\pi^{1/3}}[/tex]

Si [tex]V = 25\pi\,cm^{3}[/tex], entonces las dimensiones del vaso son:

[tex]r = \sqrt[3]{\frac{25\pi\,cm^{3}}{2\pi} }[/tex]

[tex]r \approx 2.321\,cm[/tex]

[tex]h = \frac{2^{2/3}\cdot (25\pi\,cm^{3})^{1/3}}{\pi^{1/3}}[/tex]

[tex]h \approx 4.642\,cm[/tex]

Un litro equivale a 1000 centímetros cúbicos, las dimensiones del vaso son:

[tex]r = \sqrt[3]{\frac{1000\,cm^{3}}{2\pi} }[/tex]

[tex]r \approx 5.419\,cm[/tex]

[tex]h = \frac{2^{2/3}\cdot (1000\,cm^{3})^{1/3}}{\pi^{1/3}}[/tex]

[tex]h \approx 10.839\,cm[/tex]

Answer:

Option B, Shows change over time

Step-by-step explanation:

Since the slope of a line graph could be found out by the formula;

Change y / Change in x...

This represents change over time

Hope this helps!

Answer: x= 17 I hope that helps you understand it Goodbye!

Step-by-step explanation:  

7(x-2)=5(x+4) So the first step is to Distribute meaning Multiply so 7(x-2 ) that would give you -14 that where I got that from and I just did 5(x+4)= 20 and bring the x down

1. 7x-14=5x+20 So, I just do the opposite of subtracting which is adding so, I'm going to add 14 to both sides

2. 7x=5x+20+14 = 5x+34

3. 7x= 5x+34 So, I'm going to do the opposite of adding now which is subtracting meaning I'm just going to subtract 5x from both sides

4. 7x-5x=34 So then I do 7x-5x=2x

5. 2x= 34 so. I just Divide 2 from both sides x=34/2= 17

So, your answer would be x=17 and yes you got to put the variable for your answer to be right you can't just put 17 it got to be x= 17 and variable is just letters in the equation don't let it confused you but that would be your answer x=17 And can you make me Brainliest Please  

Answer:

Value of the test statistic for this problem = -3.74

Step-by-step explanation:

Here

the sample size n = 1263

and the x = 565

So, the p' -value = 565/1263 = 0.4473

As per the test statistics formula, z value will be evaluated

z = (0.4473-p)/sqrt {p(1-p)/n}

Let us say that p = 0.5

Substituting the given value in above equation, we get -

z = (0.4473-0.5)/sqrt {0.5(1-0.5)/1263}

z = -3.74

The test statistic of the question is; z = -3.74

We are given;

Sample size; n = 1263

Number of people that said yes; x = 565

Sample proportion is; p'= 565/1263 = 0.4473

Formula for the test statistic of proportion is;

z = (p' - p)/(√(p(1 - p)/n)

We will assume that population proportion p = 0.5. Thus;

z = (0.4473 - 0.5)/(√(0.5(1 - 0.5)/1263)

z = -3.74

Read more about test statistic at; https://brainly.com/question/4621112

Answer:

$11.50

Step-by-step explanation:

Answer:

tan 0 = -2.4

sin 0 = 0.42

Step-by-step explanation:

sec 0 = -13/12 => cos 0 = -12/13

cot 0 < 0 => tan 0 < 0

so, the angle is on second quadrant

=> tan 0 = -12/5 = -2.4

=> sin 0 = 5/12 = 0.42

Answer:

Solution given;

Sec θ=-[tex]\frac{13}{12}[/tex]

cotθ< 0,

It lies in second quadrant.

where sin and cosec is positive.

Now

[tex] \frac{1}{cosθ}=-\frac{13}{12}[/tex]

cosθ=[tex]\frac{12}{13}[/tex]

[tex]\frac{b}{h}[/tex]=[tex]\frac{12}{13}[/tex]

b=12

h=13

By using Pythagoras law

p=[tex] \sqrt{13²-12²}=5 [/tex]

Now

exact values of tan θ=[tex]\frac{p}{b}[/tex]=[tex]\frac{5}{12}[/tex]

since it lies in II quadrant

tan θ=-[tex]\frac{5}{12}[/tex]

and

sinθ=[tex]\frac{p}{h}[/tex]=[tex]\frac{5}{13}[/tex]

since it lies in II quadrant

sin θ=[tex]\frac{5}{13}[/tex]

Answer:

the answers are the 3 last ones

Step-by-step explanation:

hope this helped

9514 1404 393

Answer:

  (x +1)^2 +(y -3)^2 = 4

Step-by-step explanation:

The equation of a circle centered at (h, k) with radius r is ...

  (x -h)^2 +(y -k)^2 = r^2

The graphed circle is centered at (h, k) = (-1, 3), and has radius 2, so its equation is ...

  (x +1)^2 +(y -3)^2 = 4

9514 1404 393

Answer:

  7x^3 +11x^2 -5x -8

Step-by-step explanation:

Combine like terms.

  (4x^3+6x^2+2x^2-3) + (3x^3+3x^2-5x-5)

  = (4 +3)x^3 +(6 +2 +3)x^2 +(-5)x + (-3 -5)

  = 7x^3 +11x^2 -5x -8

_____

Noting that the first expression contains two x^2 terms, we wonder if you actually want the sum ...

  (4x^3+6x^2+2x-3) + (3x^3+3x^2-5x-5)

  = (4 +3)x^3 +(6 +3)x^2 +(2 -5)x +(-3 -5)

  = 7x^3 +9x^2 -3x -8

Answer:

3

Step-by-step explanation:

650/250 = 2.6 (3)can't sell half a cycle

Answer:

7. 75.36 inches

8. 21 inches

9. 13 inches

Step-by-step explanation:

7. Circumference = π × d

The diameter would be two times the radius, or 2 × 12 = 24. So, circumference would be 3.14 × 24 = 75.36 inches.

8. Circumference = π × d

If we move variables around, d = Circumference / π

So, d = 65.94 / 3.14 = 21 inches.

9. To do this, let's figure out the diameter: d = Circumference / π

d = 81.64 / 3.14 = 26. Now the diameter is two times the radius, so to get the length of the radius, we must divide the diameter in half. 26 / 2 = 13 inches.

Answer:

8

Step-by-step explanation:

X^2 -2x +5

3^2 - 2×3 + 5

9 - 6 + 5

14 - 6

8

Answer:

7/1

Step-by-step explanation:

Answer:

1 1/5

Step-by-step explanation:

Answer:

The null hypothesis is [tex]H_0: \mu = X[/tex]

The alternate hypothesis is [tex]H_1: \mu \neq X[/tex]

Step-by-step explanation:

Mean of X in 1990, test if the mean duration has changed:

At the null hypothesis, we test if the mean duration is still X, that is:

[tex]H_0: \mu = X[/tex]

At the alternate hypothesis, we test if the mean duration has the changed, that is, if it is different of X. So

[tex]H_1: \mu \neq X[/tex]

Answer:

2:56 pm

Step-by-step explanation:

end time: 7:36 pm

Borrow one hour from the hours and add it as 60 minutes to the minutes.

7:36 pm = 6:96 pm

Now subtract 2:40 from 6:96.

Subtract 2 from 7 and subtract 40 from 96.

7:36 pm - 2:40 = 6:96 pm - 2:40 = 2:56 pm

Answer: 2:56 pm

Answer:

The answer is A=2/9 yards²

Step-by-step explanation:

The formula for a rectangle  is A=B x H  

So the equation is A= 1/3 yards x 2/3 yards  

I suppose this is right.

Answer:

X4

Step-by-step explanation:

Answer:

10x

Step-by-step explanation:

10x times itself is 100x^2

Hope this helps!

Answer:

8

Step-by-step explanation:

Answer:

8

Step-by-step explanation:

1/2 = 4/8

Answer:

1. 210KM

2. 5.5 HOURS

3. 110KPH

4. 1.5HOURS

5. 336KM

6. 80KPH

7. 96KPH

8. 153.8KM

9. 40KPH

10. 45KM

Step-by-step explanation:

TIME = DISTANCE/SPEED

DISTANCE = SPEED × TIME

SPEED= DISTANCE/TIME

Answer:

divided both sides of the equation by 3

Step-by-step explanation:

Answer:

use a calculator

Step-by-step explanation:

hope this helps

Answer:

The probability is [tex]\frac{729}{100000}[/tex].

Step-by-step explanation:

probability of missing the bus = 1/10

Probability of catching the bus = 1 - 1/10 = 9 /10

So, the required probability is

[tex]\frac{9}{10}\times \frac {9}{10}\times \frac {1}{10}\times \frac {9}{10}\times \frac {1}{10}[/tex]

[tex]\frac{729}{100000}[/tex]

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Work Shown:

Apply the tangent ratio. Make sure your calculator is in degree mode.

tan(angle) = opposite/adjacent

tan(B) = CD/BC

tan(39) = x/30

30*tan(39) = x

x = 30*tan(39)

x = 24.2935209958502

x = 24.3

Answer:

gallons: 14, 21, 28, 35

time: 2, 3, 4, 5

Step-by-step explanation:

Answer:

D   540

Step-by-step explanation:

5.4 * 10²

5.4 * 100

540

Answer:

1) -⅓

2) -6

3) infinite

4) 4

Step-by-step explanation:

slope = y/x

1) -1/3 = -⅓

2) -6/1 = -6

3) 1/0 = infinite

4) 4/1 = 4

Answer:

1:

(0,-1) and (3,-2)

slope=(y2-y1)/(x2-x1)=(-2+1)/(3-0)=-⅓

2.

(0,2)&(1,-4)

d

slope=(-4-2)/(1-0)=-6

3.

(-3,-3)&(-3,-4)

slope=(-4+3)/(-3+3)=infinite

4.

(-1,2)&(2,-2)

slope=(-2-2)/(2+1)=-4/3