Computers And Technology High School

Which of the following string primitives will copy a BYTE from the memory location pointed to by ESI to the memory location pointed to by EDI?

STOSB
MOVSB
CMPSB
LODSB
SCASB

Answers

Answer 1

The string primitive that will copy a BYTE from the memory location pointed to by ESI to the memory location pointed to by EDI is: MOVSB

What is The MOVS instruction?

The code snippet responsible for copying a byte from the memory location indicated by ESI to the memory location indicated by EDI belongs to the string primitive.

To move a byte, word, or doubleword from one memory location (ESI) to another (EDI), the MOVS command is utilized. The MOVS instruction is employed in this scenario to transfer a byte (specified by the 'B' suffix) from ESI to EDI.

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Related Questions

what is dynamic information? the person responsible for creating the original website content the person responsible for updating and maintaining website content includes fixed data incapable of change in the event of a user action includes data that change based on user action

Answers

Dynamic information refers to data that changes based on user action. It includes information that changes as a result of an event initiated by the user or an outside program.In website design, dynamic information refers to website content that changes based on the user's activity or preferences.

Dynamic content includes information that can be personalized or customized to the user's preferences. It can be seen in e-commerce sites where the user is presented with personalized product recommendations based on their browsing history, or social media sites where users see posts and advertisements based on their interests and activity on the platform.The person responsible for updating and maintaining website content is the one who creates dynamic content. They may use content management systems (CMS) or programming languages such as JavaScript to ensure that the website content is dynamic and responsive to user behavior.On the other hand, fixed data incapable of change in the event of user action refers to static content.

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A "Trojan Horse" is a hijacked computer that can be remote-controlled by the attacker to respond to the attacker's commands.

a. True
b. False

Answers

The given statement: "A "Trojan Horse" is a hijacked computer that can be remote-controlled by the attacker to respond to the attacker's commands." is true because A Trojan horse is a type of malware that is installed on a computer without the user's knowledge and that allows an attacker to take control of that computer from a remote location, typically for malicious purposes.

The term comes from the story of the Trojan horse in Greek mythology, where the Greeks used a large wooden horse to gain access to the city of Troy and then emerged from it to attack the city from within. In the same way, a Trojan horse malware is disguised as a harmless program or file but contains malicious code that can harm a computer system or network

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heapsort has heapified an array to: 77 61 49 18 14 27 12 and is about to start the second for what is the array after the first iteration of the second for loop?

Answers

Heap Sort: After an array has been heapified, the first element will always be the largest element, so it is always swapped with the last element and sorted out.

After sorting, the array is re-heaped to ensure that the second-largest element is placed in the first element location of the heap and the second-largest element in the second element location of the heap. This process is repeated until the entire array is sorted.Therefore, for the given array which is 77 61 49 18 14 27 12, the array after the first iteration of the second for loop can be calculated as follows;

Since the first element is the largest element in the heap, it will be swapped with the last element and will be sorted out. The array after sorting out the largest element will be 12 61 49 18 14 27 77.The next step is to re-heap the remaining elements 12 61 49 18 14 27. After re-heapifying the remaining elements, the first two elements will be in order. The second iteration of the second for loop will begin after re-heapifying. The array after the first iteration of the second for loop will be 14 61 49 18 12 27 77.Hence, the answer is 14 61 49 18 12 27 77.

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