Answer:
hottest plant: vensus, close to the sun
coldest plant: Neptune, farthest from the sun
Explanation:
why does the earth get more energy from the sun than from all the other stars in the universe combined
Answer:
Explanation:
The sun is much closer than the other stars
if a 5kg ball is traveling at 20 m/s and it’s stopped in 4s, what’s the impulse on the ball?
Something has a mass of 40 kg and a velocity of 1 m/s
How much kinetic energy does it have?
Part 2: If it doubles its mass, will its KE also double?
[tex]\\ \sf\Rrightarrow K.E=\dfrac{1}{2}mv^2[/tex]
[tex]\\ \sf\Rrightarrow K.E=\dfrac{1}{2}(40)(1)^2[/tex]
[tex]\\ \sf\Rrightarrow K.E=20J[/tex]
Part 2:-m=80kg[tex]\\ \sf\Rrightarrow K.E=\dfrac{1}{2}(80)(1)^2[/tex]
[tex]\\ \sf\Rrightarrow K.E=40J[/tex]
Yeswhat are the main component of network
Answer:
A network has 5 basic components viz. clients, servers, channels, interface devices and operating systems.
Mars is 7.83x10^10m [^10 is an exponent] from planet earth. The planet Earth is 5.98x10^24kg [^24 is an exponent] while Mars has a mass of 6.42x10^23kg [^23 is an exponent]. What is the gravitational attraction between the two planets? G=6.67×10^-11 (-11 is an exponent)
Answer: 2
Explanation: Because if you add 1 to 8 you get 9 then subtract 9 by 7 then and your answer is
a 10 mh inductor is connected in series with a 10 ohm resistor, a switch and a 6 v battery. what is the time constant of the circuit
Answer:
The inductive time constant is just T = L / R
T = 10E-3 henry/ 10 ohm = 10E-2 sec = .1 sec
(.01 / 10 = .1)
what is the magnitude of the force exerted on the bottom of the bottle?
How much work can a 22 kW (22000W) car engine do in 60 s if it is 100% efficient?
The amount of work done by the car engine if it is 100% efficient is 366.67 Joules.
Given the following data:
Time = 60 secondsPower = 22,000 WattTo determine the amount of work done by the car engine if it is 100% efficient:
Mathematically, the work done by an object with respect to power and time is given by the formula:
[tex]Work\;done = \frac{Power}{time}[/tex]
Substituting the given parameters into the formula, we have;
[tex]Work\;done = \frac{22000}{60}[/tex]
Work done = 366.67 Joules.
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A student noted that the sign shown here is always associated with a wheelchair ramp at or near a staircase or entrance steps. What statement best identifies the reason why wheelchair ramps are used to move people up a staircase or steps?
The main reason why wheelchair ramps are used to move people up a staircase is because it has a high mechanical advantage which leads to a greater efficiency in moving people up the staircase.
Let the height of the staircase = hLet the length of the ramp = L
The mechanical advantage of the ramp is calculated as follows;
[tex]M.A = \frac{L}{h}[/tex]
As the length of the ramp increases, people will be move up to a greater distance up the staircase.
Thus, the main reason why wheelchair ramps are used to move people up a staircase is because it has a high mechanical advantage which leads to a greater efficiency in moving people up the staircase.
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Calcula el valor de la velocidad de las ondas sonoras en el agua sabiendo que su
densidad es 1.10 3 kg/m 3 y su módulo de comprensibilidad vale 2,16x10 9 N/m 2 ¿Cuál
es la longitud de onda de las ondas sonoras en el agua si su frecuencia es de 1000hz?
1) Inicialmente, debemos determinar la velocidad de las ondas sonoras a través del agua ([tex]v[/tex]), en metros por segundo:
[tex]v = \sqrt{\frac{K}{\rho} }[/tex] (1)
Donde:
[tex]K[/tex] - Módulo de compresibilidad, en newtons por metro cuadrado.[tex]\rho[/tex] - Densidad del agua, en kilogramos por metro cúbico.Si sabemos que [tex]\rho = 1\times 10^{3}\,\frac{kg}{m^{3}}[/tex] y [tex]K = 2,16\times 10^{9}\,\frac{N}{m^{2}}[/tex], entonces la velocidad de las ondas sonoras es:
[tex]v = \sqrt{\frac{2,16\times 10^{9}\,\frac{N}{m^{2}}}{1\times 10^{3}\,\frac{kg}{m^{3}} } }[/tex]
[tex]v\approx 1469,694\,\frac{m}{s}[/tex]
La velocidad de las ondas sonoras es aproximadamente 1469,694 metros por segundo.
2) Luego, determinamos la longitud de onda ([tex]\lambda[/tex]), en metros, mediante la siguiente fórmula:
[tex]\lambda = \frac{v}{f}[/tex] (2)
Donde [tex]f[/tex] es la frecuencia de las ondas sonoras, en hertz.
Si sabemos que [tex]v\approx 1469,694\,\frac{m}{s}[/tex] y [tex]f = 1000\,hz[/tex], entonces la longitud de onda de las ondas sonoras es:
[tex]\lambda = \frac{1469,694\,\frac{m}{s} }{1000\,hz}[/tex]
[tex]\lambda = 1,470\,m[/tex]
La longitud de onda de las ondas sonoras es 1,470 metros.
Para aprender más sobre las ondas sonoras, invitamos a ver esta pregunta verificada: https://brainly.com/question/1070238
Grass, trees, shrubs, worms, birds, and deer that live in a certain area is known as what?
Answer:they live in grass land also called forests hope the answer helps
Explanation:
will give brainlyiest what is the main need or want this wave technology meets to efficiently communicate with others to hear and see others in real time to efficiently store and share music with others to speak with and see others who are far away
Answer: To see objects surrounding more clearly
Explanation:
Marianne and her family are driving from West Virginia to California. While driving through the Rocky Mountains, they encounter a rock slide. A huge boulder, a few smaller rocks and several tree branches block the road. Her father creates a lever using a long tree branch and a small rock to help move the boulder. Look at the diagram below. Where should Marianne’s father place the small rock?
Question 6 options:
It makes no difference where he places the rock
He should place the rock (fulcrum) close to the boulder (at Point A).
He should place the rock (fulcrum) away from the boulder (at Point B).
He should place the rock (fulcrum) near the end of the branch (at Point C).
Answer:
Point A
Explanation:
Point C is way to close to where the force would need to be.
Point B is close but not as close, the reasonable answer would be point A.
Marianne’s father should place the small rock: he should place the rock (fulcrum) close to the boulder (at Point A).
What is simple lever?The simplest devices, like levers, are employed to complete tasks quickly. Leverage is the ability to increase an input force to produce a stronger output force. We are known that there are different kinds of levers depending on the force, weight, and fulcrum point. Each tool that is used to complete a task falls into one of these categories.
One of the six simple devices that Renaissance scientists identified. Leverage is the ability to increase an input force to produce a stronger output force. The mechanical advantage of the lever is determined by the ratio of output force to input force.
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A calculator of mass 0.11 kg is lowered from a bookshelf that is 1.6m above the floor to a desk that is 0.85m above the floor. What's the change in GPE?
Answer:
I think it would be 0.1496 but I'm not really sure sorry
What is the change in velocity of a 1068 kg truck that experiences an impulse of 440 N ⋅ s? Include 2 decimal places in your answer.
Answer:
try 2.4136 as an answer/ good luck
7. a heater heating up the inside of the car
Convection conduction and radiation
What will happen if the two plungers are pressed together firmly? Explain your answer.
Answer:
This air being forced out causing the air pressure inside to be much lower than that on the outside. As higher air pressure always pushes, it keeps the two plungers together.
Hope that helps. x
9- Under what circumstances would a vector have components that are equal in
magnitude?
a. if the vector is oriented at 45° from the axes.
b. if the vector is oriented at 90° from the axes.
c. if the vector is oriented at 0° from the X -axis.
d. if the vector is oriented at 0° from the y-axis.
itude of 30 units Vector B is perpendicular to vector A
Explanation:
c. if the vector is oriented at 0° from the X -axis.
A student holds an egg outside of an open window and let's go. The window is 40 meters above the ground and the egg is falling under the acceleration of gravity, which is 9.8 m/s2. There are two equations that can be used to describe its motion over time:
How far will the egg travel after 2 seconds? Be sure to use the 5 steps to solve the problem. Show which equation you used, what each variable equals, and answer the question in a complete sentence.
The distance traveled by the egg after 2 seconds is 19.6 m.
The given parameters:
Height of the window, h = 40 mThe distance traveled by the egg after 2 seconds is calculated as follows;
[tex]h = v_0_y t + \frac{1}{2} gt^2\\\\[/tex]
where;
[tex]v_0_y[/tex] is the initial vertical velocity of the egg = 0g is acceleration due to gravity = 9.8 m/s²t is the time of motion, = 2 s[tex]h = 0 \ + \ \frac{1}{2} \times 9.8 \times (2)^2\\\\h = 19.6 \ m[/tex]
Thus, the distance traveled by the egg after 2 seconds is 19.6 m.
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Before Collision:
2,000 kg 4 m/s 4,000kg 0 m/s
After collision: 2,000 kg + 4,000kg Vt = ?
I will give Brainliest to the first person. Please show work
Answer:
4/3 m/s
Explanation:
Assuming momentum is conserved, the sum of products of mass and speed before the collision is the same as after:
(2000 kg)(4 m/s) +(4000 kg)(0 m/s) = (2000 +4000 kg)(Vt)
Vt = (8000 kg·m/s)/(6000 kg) = 4/3 m/s
The speed of the combined objects after the collision is 4/3 m/s.
A wave has a frequency of 2700 Hz and λ of 6m. Calculate the speed of the wave.pls help
Answer:
16,200 m/sExplanation:
The speed of the wave given only it's frequency and wavelength can be found by using the formula
[tex]c = f \times \lambda[/tex]
where
c is the velocity of the wave in m/s
[tex] \lambda[/tex] is the wavelength in m
f is the frequency in Hz
From the question
c = 2700 × 6 = 16,200
We have the final answer as
16,200 m/sHope this helps you
Yoo what it do I don’t know the answer tho
Answer:
You should try your best to answer the question.
Which of the following rivers flows north in eastern Florida?
St. James
St. Johns
Mississippi
Hudson
St. John’s
_________
o0o0o0o0o0
what's the mass of the star rasalas?
Answer: The Rasalas's solar mass is 1.50 times that of our star, the Sun. The Sun's Mass is 1,989,100,000,000,000,000,000 billion kg.
Explanation:
Answer:
The Rasalas's solar mass is 1.50 times that of our star, the Sun. The Sun's Mass is 1,989,100,000,000,000,000,000 billion kg. which to calculate using this website is too large. To give idea of size, the Sun is 99.86% the mass of the solar system.
Explanation:
A car travels 80 km at an avarage speed of 40 km/h. It travels the remaining distance in 3h. What is its dis placement if the average speed of the car is 30 km/h.? And explain
A) 100 km
B)120 km
C)150km
D)180km
When traveling with average speed 40 km/h, the car would cover a distance of 80 km in time t such that
40 km/h = (80 km) / t ⇒ t = 2 h
so the total travel time is 2 h + 3 h = 5 h.
Average speed is defined as the total distance traveled divided by the time it took to cover that distance. So if the overall average speed was 30 km/h, then
30 km/h = (80 km + x) / (5 h) ⇒ x = 70 km
where x is the distance traveled in the last 3 h of the trip.
Then the total displacement of the car is 80 km + 70 km = 150 km.
Calculate amount of current flowing in wire if number of charge is 8 and e = 1.69 x10^-19 , t= 8millsec
The amount of current flowing in the wire is 1.69 × 10⁻¹⁶ A
From the question,
We are to calculate, the amount of current flowing in the wire.
From the formula,
[tex]I =\frac{nQ}{t}[/tex]
Where I is the current
n is the number of charge
Q is the quantity of charge
t is the time
From the given information
n = 8
Q = e = 1.69 × 10⁻¹⁹ C
t = 8 msecs = 8 × 10⁻³ sec
Putting the parameters into the formula, we get
[tex]I = \frac{8 \times 1.69 \times 10^{-19} }{8\times 10^{-3} }[/tex]
[tex]I = 1.69 \times 10^{-16} \ A[/tex]
Hence, the amount of current flowing in the wire is 1.69 × 10⁻¹⁶ A
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What is the final velocity of an object that starts from rest and travels for 5 seconds at an acceleration of 4.3 m/s2? ____________________
The final velocity of an object that starts from rest and travels for 5 seconds at an acceleration of 4.3 m/s² is 21.5m/s.
EQUATION OF MOTION:
The final velocity of a moving object can be calculated by using one of the equations of motion as follows:
V = u + at
Where;
V = final velocity (m/s)u = initial velocity (m/s)a = acceleration (m/s²)t = time (s)According to this question,
t = 5sa = 4.3m/s²u = 0 m/s (at rest)v = ?v = 0 + 4.3(5)
v = 21.5m/s.
Therefore, the final velocity of an object that starts from rest and travels for 5 seconds at an acceleration of 4.3 m/s² is 21.5m/s.
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Which impact would be more forceful, decreasing speed from 60mph to 0 mph over 2 seconds or 0.5 seconds? Explain
Maria drove 100 miles in 2 hrs. what was marias speed?
A projectile is thrown with velocity v at an angle θ with horizontal. When the projectile is at a height equal to half of the maximum height, the vertical component of the velocity of projectile is ____?
[tex]\purple{ \longrightarrow \bf{h_m = \dfrac{ {v}^{2} \: {sin}^{2} \theta }{2g} }} [/tex]
Projectile is thrown with a velocity = v Angle of projection = θVelocity of projectile at a height half of the maximum height covered be [tex] \sf{v_0}[/tex][tex]\qquad[/tex]______________________________
Then –
[tex]\qquad[/tex] [tex]\pink{ \longrightarrow \bf{ \dfrac{h_m}{2} = \dfrac{ {v_0}^{2} \: {sin}^{2} \theta }{2g} }}[/tex]
[tex]\qquad[/tex] [tex] \longrightarrow \sf{ \dfrac{ {v}^{2} \: {sin}^{2} \theta }{2g} \times \dfrac{1}{2} = \dfrac{ {v_0}^{2} \: {sin}^{2} \theta }{2g} }[/tex]
[tex]\qquad[/tex][tex]\longrightarrow \sf{ \dfrac{ {v}^{2} \: {sin}^{2} \theta }{4g} = \dfrac{ {v_0}^{2} \: {sin}^{2} \theta }{2g} }[/tex]
[tex]\qquad[/tex][tex]\longrightarrow \sf{ \dfrac{ {v}^{2} \: {sin}^{2} \theta }{2} = {v_0}^{2} \: {sin}^{2} \theta }[/tex]
[tex]\qquad[/tex][tex] \longrightarrow \sf{ \dfrac{ {v}^{2} }{2} = {v_0}^{2} }[/tex]
[tex]\qquad[/tex][tex] \longrightarrow \bf{v_0 = \sqrt{ \dfrac{ {v}^{2} }{2} } = \dfrac{v}{ \sqrt{2} } }[/tex]
Now, the vertical component of velocity of projectile at the height half of [tex] \sf{h_m}[/tex] will be –[tex]\qquad[/tex] [tex]\longrightarrow \bf{v_{(y)}=v_0 \: sin \theta }[/tex]
[tex]\qquad[/tex] [tex] \longrightarrow \bf{v_{(y)} = \dfrac{v}{ \sqrt{2} } \: sin \theta = \dfrac{v \: sin \: \theta}{ \sqrt{2} } }[/tex]
Therefore, the vertical component of velocity of projectile at this height will be–
☀️[tex]\qquad[/tex][tex] \pink {\bf{ \dfrac{v \: sin \: \theta}{ \sqrt{2} }} }[/tex]
Answer:
A projectile is thrown with velocity v at an angle θ with horizontal. When the projectile is at a height equal to half of the maximum height, the vertical component of the velocity of projectile is v sintheta / √2