When developing an algorithm to solve a problem, which of these steps can help you design the solution for the problem?
Answers
Answer:
3 is the answer please mark me brainlist
Explanation:
ok
Related Questions
Q. Describe the T.V. as an ICT tool.
Answers
Answer:
TV or modern televisions are also a type of ICT tool because we get a wide amount of information about mass communication through the various news channels on the TV. TV is now also the most popular as well as a cheap medium of mass communication.
Complete main() to read dates from input, one date per line. Each date's format must be as follows: March 1, 1990. Any date not following that format is incorrect and should be ignored. Use the substring() method to parse the string and extract the date. The input ends with -1 on a line alone. Output each correct date as: 3/1/1990. Ex: If the input is:
Answers
Answer:
Explanation:
The following code was written in Java it creates a switch statement for all the month values in order to turn them from Strings into integer values. Then it reads every line of input places them into an array of dates if they are the correct input format, and loops through the array changing every date into the correct output format.Ouput can be seen in the attached picture below.
import java.util.ArrayList;
import java.util.Scanner;
class Brainly {
public static int intForMonth(String monthString) {
int monthValue;
switch (monthString) {
case "January": monthValue = 1;
break;
case "February": monthValue = 2;
break;
case "March": monthValue = 3;
break;
case "April": monthValue = 4;
break;
case "May": monthValue = 5;
break;
case "June": monthValue = 6;
break;
case "July": monthValue = 7;
break;
case "August": monthValue = 8;
break;
case "September": monthValue = 9;
break;
case "October": monthValue = 10;
break;
case "November": monthValue = 11;
break;
case "December": monthValue = 12;
break;
default: monthValue = 00;
}
return monthValue;
}
public static void main(String[] args) {
Scanner scnr = new Scanner(System.in);
ArrayList<String> dates = new ArrayList<>();
String date;
String month;
String day;
String year;
int i = 0;
while (true) {
date = scnr.nextLine();
if (date.equals("-1")) {
break;
}
dates.add(date);
}
for (i = 0; i < dates.size(); i++) {
try {
month = dates.get(i).substring(0, dates.get(i).indexOf(" "));
day = dates.get(i).substring(dates.get(i).indexOf(" ") + 1, dates.get(i).indexOf(","));
year = dates.get(i).substring(dates.get(i).indexOf(",") + 2, dates.get(i).length());
System.out.println(intForMonth(month) + "/" + day + "/" + year);
} catch (Exception e) {}
}
}
}
Write the MIPS assembly code to find the area of a given shape. Your program must take a floating-point value and shape (Circle - 1, Triangle - 2, Square - 3) as input and return the circumference/perimeter and area of the shape. Assume the floating-point value units are meters and the triangle is an equilateral triangle. [Note: you can search for the expression to calculate the area and circumference/perimeter of these shapes]
Answers
Answer:
Explanation:
.data
msg1: .asciiz "Enter the floating point value = "
msg2: .asciiz "\nEnter the shape (Circle - 1, Triangle - 2, Square - 3) = "
msg3: .asciiz "\nThe perimeter of the triangle with side = "
msg4: .asciiz " meters is "
msg5: .asciiz " meters.\n"
msg6: .asciiz "\nThe area of the triangle with side = "
msg7: .asciiz " square meters.\n"
msg8: .asciiz "\nThe circumference of the circle with radius = "
msg9: .asciiz "\nThe area of the circle with radius = "
msg10: .asciiz "\nThe perimeter of the square with side = "
msg11: .asciiz "\nThe area of the square with side = "
pi: .float 3.1415816
eq_tr_area: .float 0.43305186
two: .float 2
three: .float 3
four: .float 4
.text
li $v0,4 # system call code for printing string = 4
la $a0,msg1 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
li $v0,6 # system call code for reading floating point number
syscall # call operating system to perform read operation
li $v0,4 # system call code for printing string = 4
la $a0,msg2 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
li $v0,5 # system call code for reading integer
syscall # call operating system to perform read operation
move $t0,$v0
IF:
bne $t0,1,ELSE_IF #if not 1 then goto elseif
li $v0,4 # system call code for printing string = 4
la $a0,msg8 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
li $v0, 2 # system call code for printing float = 2
mov.s $f12,$f0 #move the single precision f2 in f12
syscall # call operating system to perform print operation
li $v0,4 # system call code for printing string = 4
la $a0,msg4 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
l.s $f1,pi
l.s $f3,two
mul.s $f3,$f3,$f1 #calculate 2*pi*radius
mul.s $f3,$f3,$f0
li $v0, 2 # system call code for printing float = 2
mov.s $f12,$f3 #move the single precision f2 in f12
syscall # call operating system to perform print operation
li $v0,4 # system call code for printing string = 4
la $a0,msg5 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
li $v0,4 # system call code for printing string = 4
la $a0,msg9 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
li $v0, 2 # system call code for printing float = 2
mov.s $f12,$f0 #move the single precision f2 in f12
syscall # call operating system to perform print operation
li $v0,4 # system call code for printing string = 4
la $a0,msg4 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
mul.s $f2,$f0,$f0 #calculate radius *radius
mul.s $f2,$f2,$f1 #calculate pi *r^2
li $v0, 2 # system call code for printing float = 2
mov.s $f12,$f2 #move the single precision f2 in f12
syscall # call operating system to perform print operation
li $v0,4 # system call code for printing string = 4
la $a0,msg7 # load address of string to be printed into $a0
syscall
ELSE_IF:
bne $t0,2,ELSE #if not 2 then check else
li $v0,4 # system call code for printing string = 4
la $a0,msg3 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
li $v0, 2 # system call code for printing float = 2
mov.s $f12,$f0 #move the single precision f2 in f12
syscall # call operating system to perform print operation
li $v0,4 # system call code for printing string = 4
la $a0,msg4 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
l.s $f3,three
mul.s $f3,$f3,$f0 #calculate 3*side
li $v0, 2 # system call code for printing float = 2
mov.s $f12,$f3 #move the single precision f2 in f12
syscall # call operating system to perform print operation
li $v0,4
la $a0,msg5
syscall
li $v0,4
la $a0,msg6
syscall
li $v0, 2
mov.s $f12,$f0
syscall
li $v0,4
la $a0,msg4
syscall
l.s $f3,eq_tr_area
mul.s $f2,$f0,$f0
mul.s $f2,$f2,$f3
li $v0, 2
mov.s $f12,$f2
syscall
li $v0,4
la $a0,msg7
syscall
ELSE:
bne $t0,3,END
li $v0,4
la $a0,msg10
syscall
li $v0, 2
mov.s $f12,$f0
syscall
li $v0,4
la $a0,msg4
syscall
l.s $f3,four
mul.s $f3,$f3,$f0
li $v0, 2
mov.s $f12,$f3
syscall
li $v0,4
la $a0,msg5
syscall
li $v0,4
la $a0,msg11
syscall
li $v0, 2
mov.s $f12,$f0
syscall
li $v0,4
la $a0,msg4
syscall
mul.s $f2,$f0,$f0
li $v0, 2
mov.s $f12,$f2
syscall
li $v0,4
la $a0,msg7
syscall
END:
li $v0,10
syscall
Code is as follows:
.data
msg1: .asciiz "Enter the floating point value = "
msg2: .asciiz "\nEnter the shape (Circle - 1, Triangle - 2, Square - 3) = "
msg3: .asciiz "\nThe perimeter of the triangle with side = "
msg4: .asciiz " meters is "
msg5: .asciiz " meters.\n"
msg6: .asciiz "\nThe area of the triangle with side = "
msg7: .asciiz " square meters.\n"
msg8: .asciiz "\nThe circumference of the circle with radius = "
msg9: .asciiz "\nThe area of the circle with radius = "
msg10: .asciiz "\nThe perimeter of the square with side = "
msg11: .asciiz "\nThe area of the square with side = "
pi: .float 3.1415816
eq_tr_area: .float 0.43305186
two: .float 2
three: .float 3
four: .float 4
.text
li $v0,4 # system call code for printing string = 4
la $a0,msg1 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
li $v0,6 # system call code for reading floating point number syscall # call operating system to perform read operation
li $v0,4 # system call code for printing string = 4 la $a0,msg2 # load address of string to be printed into $a0 syscall # call operating system to perform print operation
li $v0,5 # system call code for reading integer syscall # call operating system to perform read operation move $t0,$v0
IF:
bne $t0,1,ELSE_IF #if not 1 then goto elseif
li $v0,4 # system call code for printing string = 4
la $a0,msg8 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
li $v0, 2 # system call code for printing float = 2 mov.s $f12,$f0 #move the single precision f2 in f12 syscall # call operating system to perform print operation
li $v0,4 # system call code for printing string = 4 la $a0,msg4 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
l.s $f1,pi l.s $f3,two
mul.s $f3,$f3,$f1 #calculate 2*pi*radius
mul.s $f3,$f3,$f0
li $v0, 2 # system call code for printing float = 2
mov.s $f12,$f3 #move the single precision f2 in f12
syscall # call operating system to perform print operation
li $v0,4 # system call code for printing string = 4
la $a0,msg5 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
li $v0,4 # system call code for printing string = 4
la $a0,msg9 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
li $v0, 2 # system call code for printing float = 2
mov.s $f12,$f0 #move the single precision f2 in f12
syscall # call operating system to perform print operation
li $v0,4 # system call code for printing string = 4
la $a0,msg4 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
mul.s $f2,$f0,$f0 #calculate radius *radius
mul.s $f2,$f2,$f1 #calculate pi *r^2
li $v0, 2 # system call code for printing float = 2
mov.s $f12,$f2 #move the single precision f2 in f12
syscall # call operating system to perform print operation
li $v0,4 # system call code for printing string = 4
la $a0,msg7 # load address of string to be printed into $a0
syscall
ELSE_IF:
bne $t0,2,ELSE #if not 2 then check else
li $v0,4 # system call code for printing string = 4 la $a0,msg3 # load address of string to be printed into $a0 syscall # call operating system to perform print operation
li $v0, 2 # system call code for printing float = 2
mov.s $f12,$f0 #move the single precision f2 in f12
syscall # call operating system to perform print operation
li $v0,4 # system call code for printing string = 4
la $a0,msg4 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
l.s $f3,three
mul.s $f3,$f3,$f0 #calculate 3*side
li $v0, 2 # system call code for printing float = 2
mov.s $f12,$f3 #move the single precision f2 in f12
syscall
bne $t0,3,END #if not 3 then end
li $v0,4 # system call code for printing string = 4
la $a0,msg10 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
li $v0, 2 # system call code for printing float = 2
mov.s $f12,$f0 #move the single precision f0 in f12
syscall # call operating system to perform print operation
li $v0,4 # system call code for printing string = 4
la $a0,msg4 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
l.s $f3,four # multilply by 4
mul.s $f3,$f3,$f0 #calculate 4*side
li $v0, 2 # system call code for printing float = 2
mov.s $f12,$f3 #move the single precision f3 in f12
syscall # call operating system to perform print operation
END:
li $v0,10 # system call code for printing exit (end of program)
syscall # call operating system to perform print operation
Learn More:https://brainly.com/question/10169933
QUESTION TWO
(50 MARKS)
2.1 Using multi-dimensional arrays, create an array that will store 10 items of stock (can be any item
e.g. cars,) with brand name, Number of stock in Store and Quantity Sold
(25)
NB: Use the While loop to display array elements
E.g.:
Brand name
Number of stock in Store
Quantity Sold
HP
15
28
DELL
14
16
Your output must be in tabular form as above.
Answers
The question is a programming exercise that involves the use of Multi-Dimensional Arrays. See below for the definition of a Multi-Dimensional Array.
What is a Multi-Dimensional Array?A Multi-Dimensional Array is an array that has over one level and at least two dimensions. You could also state that it is an array that contains a matrix of rows and columns.
How do we create the array indicated in the question?The array or output table may be created using the following lines of code:
<!DOCTYPE html>
<html>
<head>
<title>Multi-Dimensional Arrays</title>
<meta http-equiv="Content-Type" content = "text/html; charset=UTF-8"
</head>
<body>
<?php
$cars = array
(
array("Volvo", 22, 18),
array("BMW", 15, 13),
array("Kia", 5, 2),
array("Land Rover", 17, 15),
array("Toyota", 16, 18),
array("Volkswagen", 20, 10),
array("Audi", 19, 10),
array("Mercedes Benz", 50, 5),
array("Mazda", 11, 12),
array("Ford", 14, 13),
);
echo "<table border =\"1\" style='border-collapse: collapse'>";
echo '<tr><th>Brand name</th><th>Number of Stock in Store</th><th>Quantity Sold</th></tr>';
foreach($cars as $cars)
{
echo '<tr>';
foreach($cars as $key)
{
echo '<td>'.$key.'</td>';
}
echo '</tr>';
}
echo "</table>";
?>
</body>
</html>
See the attached for the result of the code when executed.
Learn more about Multi-Dimensional Arrays at:
https://brainly.com/question/14285075
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How does an introduction in a set of instructions help an audience of laypeople?
A. It defines unfamiliar terms that are used in the instructions.
B. It provides background information about the instructions.
C. It warns about potential hazards in the instructions.
D. It shows a list of supplies needed to complete the instructions.
E. It cautions against causing damage while carrying out the instructions.
Answers
Answer:
B. It provides background information about the instructions.
Explanation:
It says introduction in a set of audience. A introduction creates a background.
Why do Apple phones die quickly
Answers
Answer:
anything
Explanation:
A lot of things can cause your battery to drain quickly. If you have your screen brightness turned up, for example, or if you're out of range of Wi-Fi or cellular, your battery might drain quicker than normal. It might even die fast if your battery health has deteriorated over time.
The given SQL creates a song table and inserts three songs.
Write three UPDATE statements to make the following changes:
Change the title from 'One' to 'With Or Without You'.
Change the artist from 'The Righteous Brothers' to 'Aritha Franklin'.
Change the release years of all songs after 1990 to 2021.
Run your solution and verify the songs in the result table reflect the changes above.
CREATE TABLE song (
song_id INT,
title VARCHAR(60),
artist VARCHAR(60),
release_year INT,
PRIMARY KEY (song_id)
);
INSERT INTO song VALUES
(100, 'Blinding Lights', 'The Weeknd', 2019),
(200, 'One', 'U2', 1991),
(300, 'You\'ve Lost That Lovin\' Feeling', 'The Righteous Brothers', 1964),
(400, 'Johnny B. Goode', 'Chuck Berry', 1958);
-- Write your UPDATE statements here:
SELECT *
FROM song;
Answers
Answer:
UPDATE song SET title = 'With Or Without You' WHERE song_ID = 200UPDATE song SET artist = 'Aritha Franklin' WHERE song_ID = 300UPDATE song SET release_year = 2021 WHERE release_year > 1990Explanation:
Given
The above table definition
Required
Statement to update the table
The syntax of an update statement is:
UPDATE table-name SET column-name = 'value' WHERE column-name = 'value'
Using the above syntax, the right statements is as follows:
UPDATE song SET title = 'With Or Without You' WHERE song_ID = 200The above sets the title to 'With Or Without You' where song id is 200
UPDATE song SET artist = 'Aritha Franklin' WHERE song_ID = 300
The above sets the artist to 'Aritha' where song id is 300
UPDATE song SET release_year = 2021 WHERE release_year > 1990The above sets the release year to '2021' for all release year greater than 1990
Can you debug the following code using the given test code?public class SavingAccount{ // interest rate for all accounts private static double annualInterestRate = 0; private final double savingsBalance; // balance for currrent account // constructor, creates a new account with the specified balance public void SavingAccount( double savingsBalance ) { savingsBalance = savingsBalance; } // end constructor // get monthly interest public void calculateMonthlyInterest() { savingsBalance += savingsBalance * ( annualInterestRate / 12.0 ); } // end method calculateMonthlyInterest // modify interest rate public static void modifyInterestRate( double newRate ) { annualInterestRate = ( newRate >= 0 && newRate <= 1.0 ) ? newRate : 0.04; } // end method modifyInterestRate // get string representation of SavingAccount public String toString() { return String.format( "$%.2f", savingsBalance ); } // end method toSavingAccountString} // end class SavingAccount Using this test codepublic class SavingAccountTest{ public static void main(String[] args) { SavingAccount s1 = new SavingAccount(400); SavingAccount s2 = new SavingAccount(1000); SavingAccount.modifyInterestRate(0.05); System.out.printf("SavingAccount 1 is: %s\nSavingAccount 2 is: %s\n", s1, s2); s1.calculateMonthlyInterest(); s2.calculateMonthlyInterest(); System.out.printf("\nSavingAccount 1 after the interest is: %s\nSavingAccount 2 after the interest is: %s\n", s1, s2); SavingAccount.modifyInterestRate(.025); s1.calculateMonthlyInterest(); s2.calculateMonthlyInterest(); System.out.printf("\nSavingAccount 1 after the new interest is: %s\nSavingAccount 2 after the new interest is: %s\n", s1, s2); }}
Answers
Answer:
Explanation:
The reason the code was not working was due to a couple of errors. First, the SavingAccount class needed to be public so that it can be accessed within the same file. Secondly, the savingsBalance variable was set to final and therefore could not be modified, the final keyword needed to be removed. Lastly, the constructor for the SavingAccount class was incorrect. Constructors do not use the keyword void and instance class variables need to be referenced using the this keyword.
class SavingAccount{
// interest rate for all accounts
private static double annualInterestRate = 0;
private double savingsBalance;
public SavingAccount(double savingsBalance) {
this.savingsBalance = savingsBalance;
}
public void calculateMonthlyInterest() {
savingsBalance += savingsBalance * ( annualInterestRate / 12.0 );
}// end method calculateMonthlyInterest
// modify interest rate
public static void modifyInterestRate( double newRate ) {
annualInterestRate = ( newRate >= 0 && newRate <= 1.0 ) ? newRate : 0.04;
} // end method modifyInterestRate
// get string representation of SavingAccount
public String toString() { return String.format( "$%.2f", savingsBalance );
} // end method toSavingAccountString
}// end class SavingAccount
// Using this test codepublic
//
class SavingAccountTest{
public static void main(String[] args) {
SavingAccount s1 = new SavingAccount(400);
SavingAccount s2 = new SavingAccount(1000);
SavingAccount.modifyInterestRate(0.05);
System.out.printf("SavingAccount 1 is: %s\nSavingAccount 2 is: %s", s1, s2);
s1.calculateMonthlyInterest(); s2.calculateMonthlyInterest();
System.out.printf("\nSavingAccount 1 after the interest is: %s\nSavingAccount 2 after the interest is: %s", s1, s2);
SavingAccount.modifyInterestRate(.025);
s1.calculateMonthlyInterest();
s2.calculateMonthlyInterest();
System.out.printf("\nSavingAccount 1 after the new interest is: %s\nSavingAccount 2 after the new interest is: %s", s1, s2); }}
In class we created an opaque object for a type called MY_VECTOR that had an internal structure called My_vector consisting of an integer size, an integer capacity, and an integer pointer data that held the address of the first element of a dynamic array of integers. Write a function called copyVECTOR that receives an opaque object (of type MY_VECTOR) and returns the address of an exact copy of the passed opaque object upon success and NULL otherwise.
Answers
Does anybody have the full answer sheet for Cisco Packet Tracer 11.10.1 (Design and implement a vlsm addressing scheme)? Will give brainliest!
Answers
Answer:
Red font color or Gray highlights indicate text that appears ... In this lab, you will design a VLSM addressing scheme given a network ... You have been asked to design, implement, and test addressing ...
Explanation:
Write a program to generate a square wave with 80% duty cycle on bit P2.7 Microprocessor.
Answers
Answer:
assuming its assembly (otherwise just delete this ans)
Explanation:
MOV TMOD , #01 ;
MOV TLO, #00 ;
MOV THO, #DCH
CPL P1.5
ACALL DELAY
SJMP HERE
;generate delay using Timer 0
DELAY:
SETB TR0
AGAIN:
JNB TF0 ,AGAIN
CLR TR0
CLR TF0
RET
We can cluster in one dimension as well as in many dimensions. In this problem, we are going to cluster numbers on the real line. The particular numbers (data points) are 1, 4, 9, 16, 25, 36, 49, 64, 81, and 100, i.e., the squares of 1 through 10. We shall use a k-means algorithm, with two clusters. You can verify easily that no matter which two points we choose as the initial centroids, some prefix of the sequence of squares will go into the cluster of the smaller and the remaining suffix goes into the other cluster. As a result, there are only nine different clusterings that can be achieved, ranging from {1}{4,9,...,100} through {1,4,...,81} {100}. We then go through a reclustering phase, where the centroids of the two clusters are recalculated and all points are reassigned to the nearer of the two new centroids. For each of the nine possible clusterings, calculate how many points are reclassified during the reclustering phase. Identify in the list below the pair of initial centroids that results in exactly one point being reclassified.
a) 36 and 64
b) 36 and 100
c) 4 and 16
d) 4 and 81
Answers
A is the answer because I’m good
The list of the pair of initial centroids that results in exactly one point being reclassified is 36 and 64. The correct option is a.
What is the real line?A real axis, or a line with a set scale so that each real number corresponds to a distinct point on the line, is the most popular definition of "real line." The complex plane is a two-dimensional extension of the real line.
A cluster is a collection or grouping of items in a certain place. Mathematicians define a cluster as data accumulating around a single value, specifically a number. On a table or graph, a cluster can be seen visually where the data points are grouped together.
The numbers are 4, 9, 16, 25, 36, 49, 64, 81, and 100. In the real line, it will be 36 and 64.
Therefore, the correct option is a. 36 and 64.
To learn more about real line, refer to the link:
https://brainly.com/question/19571357
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please help me ASAP!
Answers
Answer:
loser
Explanation:
what is an input device
Answers
Complete the Rectangle class. It has a rectangle's length and width as class variables and contains methods to compute its area and perimeter. If either parameter is negative, the method should calculate based on its absolute value. Then, you'll take user inputs to create an instance of Rectangle. For example, if you provide the input -13 7 You should receive the output Perimeter = 40.0 Area = 91.0 Note: It is NOT necessary to use the math module to calculate absolute value, though you may if you want. 298800.1775650.qx3zqy7 LAB ACTIVITY 28.4.1: Final Exam 2021 - Problem 4 of 6 0/10 main.py Load default template... 1 class Rectangle: _init__(self, length, width): # your code here 4 5 def area (self): 6 # your code here 7 8 def perimeter (self): 9 # your code here 10 11 if _name__ == '__main__': 12 1 = float(input) 13 w = float(input) 14 r = Rectangle(1, w) 15 print("Perimeter =', r.perimeter()) 16 print('Area =', r.area(), end='')|
Answers
Answer:
The complete program is as follows:
class Rectangle:
def __init__(self, length, width):
self.width = abs(width)
self.length = abs(length)
def area(self):
area = self.length * self.width
return area
def perimeter (self):
perimeter = 2 * (self.length + self.width)
return perimeter
if __name__ == '__main__':
l = float(input(": "))
w = float(input(": "))
r = Rectangle(l, w)
print('Perimeter =', r.perimeter())
print('Area =', r.area(), end='')
Explanation:
This defines the class:
class Rectangle:
This gets the parameters from maiin
def __init__(self, length, width):
This sets the width
self.width = abs(width)
This sets the length
self.length = abs(length)
The area function begins here
def area(self):
Calculate the area
area = self.length * self.width
Return the calculated area back to main
return area
The perimeter function begins here
def perimeter (self):
Calculate the perimeter
perimeter = 2 * (self.length + self.width)
Return the calculated perimeter back to main
return perimeter
The main begins here
if __name__ == '__main__':
This gets input for length
l = float(input(": "))
This gets input for width
w = float(input(": "))
This passes the inputs to the class
r = Rectangle(l, w)
This prints the returned value for perimeter
print('Perimeter =', r.perimeter())
This prints the returned value for area
print('Area =', r.area(), end='')
What is up with the bots? They are so annoying.
Answers
Answer:
very very very annoying
Answer:
yeah
Explanation:
Using a text editor, create a file that contains a list of at least 15 six-digit account numbers. Read in each account number and display whether it is valid. An account number is valid only if the last digit is equal to the remainder when the sum of the first five digits is divided by 10. For example, the number 223355 is valid because the sum of the first five digits is 15, the remainder when 15 is divided by 10 is 5, and the last digit is 5. Write only valid account numbers to an output file, each on its own line. Save the application as ValidateCheckDigits.java.
Answers
Answer:
Explanation:
The following code is written in Java. It reads every input and checks to see if it is valid. If it is it writes it to the output file.
import java.io.File;
import java.io.FileNotFoundException;
import java.io.FileWriter;
import java.io.IOException;
import java.util.Scanner;
class Brainly {
public static void main(String[] args) {
try {
File myObj = new File("C:/Users/Gabriel2/AppData/Roaming/JetBrains/IdeaIC2020.2/scratches/input.txt");
Scanner myReader = new Scanner(myObj);
FileWriter myWriter = new FileWriter("C:/Users/Gabriel2/AppData/Roaming/JetBrains/IdeaIC2020.2/scratches/output.txt");
while (myReader.hasNextLine()) {
String data = myReader.nextLine();
int sum = 0;
for (int x = 0; x < 5; x++ ) {
sum += data.charAt(x);
}
int remainder = (sum % 10);
System.out.println(remainder);
System.out.println(data.charAt(5));
if (remainder == Integer.parseInt(String.valueOf(data.charAt(5)))) {
System.out.println("entered");
try {
myWriter.write(data + "\n");
System.out.println("Successfully wrote to the file.");
} catch (IOException e) {
System.out.println("An error occurred.");
e.printStackTrace();
}
}
sum = 0;
}
myWriter.close();
myReader.close();
} catch (FileNotFoundException e) {
System.out.println("An error occurred.");
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
}
}
convert 10101010 into decimal number system
Answers
Answer:
170 hope this helps you with
Explanation:
"128 + 0 + 32 + 0 + 8 + 0 + 2 + 0 = 170. So, 170 is the decimal equivalent of the number 10101010."
Describing How to Insert a Subdatasheet
Use the drop-down menus to complete the steps for inserting a subdatasheet.
1. Open a table in Design view.
2. Click the
v tab, and in the Records group, click
3. In the drop-down menu, select Subdatasheet.
4. In the Insert Subdatasheet dialog box, select the table you want and click
5. If there is no relationship between the tables, you can
one.
Ve
Answers
Answer:
1. Home
2. More
4. Ok
5. Create
Explanation:
Answer:
1. insert
2. smartart
3. OK
4. close
Explanation:
Understanding Inner Joins
Which records would be returned in a query based on an inner join between a table named Customers and a table
named Orders? Check all that apply.
orphaned orders
orphaned customers
O customers who placed orders
customers who did not place orders
orders that are attached to customers
orders that are not attached to customers
Answers
Answer: customers who placed orders, orders that are attached to customers or C E
Explanation: on edg
The records that would returned in a query based on an inner join between a table named Customers and a table named Orders includes:
customers who placed ordersorders that are attached to customersWhat is a query?In a database, this refers to the request for information stored within a database management system that maintains data.
Hence, the "customers who placed orders" and "orders that are attached to customers" will be returned in a query based on an inner join between a table named Customers and a table named Orders
Therefore, the Option C & E is correct.
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Create a game that rolls two dies (number from 1 to 6 on the side) sequentially for 10 times (use loop). If at least once out of 10 times the sum of two random numbers is equal to 10, you win, else you loose. You will need to get your own method getRandom(int n) that generates a random number, see below (you can modify it as needed), a loop, and IF statement in the loop that checks if a sum of two random numbers is 10 or not.
Please start your program as follows, similar to what we did in class:
import java.util.Random;
public class UseRandom{
//your method getRandom() is here below, n is a range for a random number from 0 to n
public int getRandom(int n)
{
Random r=new Random();
int rand=r.nextInt(n);
return rand;
}
//code continues here, don't forget your main() method inside the class, and making your own object in main() using "new" keyword.
Answers
Answer:
Explanation:
The following code is written in Java and loops through 10 times. Each time generating 2 random dice rolls. If the sum is 10 it breaks the loop and outputs a "You Win" statement. Otherwise, it outputs "You Lose"
import java.util.Random;
class Brainly {
public static void main(String[] args) {
UseRandom useRandom = new UseRandom();
boolean youWin = false;
for (int x = 0; x<10; x++) {
int num1 = useRandom.getRandom(6);
int num2 = useRandom.getRandom(6);
if ((num1 + num2) == 10) {
System.out.println("Number 1: " + num1);
System.out.println("Number 2: " + num2);
System.out.println("You Win");
youWin = true;
break;
}
}
if (youWin == false) {
System.out.println("You Lose");
}
}
}
class UseRandom{
public int getRandom(int n)
{
Random r=new Random();
int rand=r.nextInt(n);
return rand;
}}
What do you consider to be the next big thing in "Small Systems" (technology, hardware, software, etc.) and why?
Answers
Explanation:
The answer is rom or read only storage devices
What is the problem with paying only your minimum credit card balance each month?
A. It lowers your credit score
B. You have to pay interest
C. The bank will cancel your credit card
D. All of the above
Answers
Answer:b
Explanation:
Answer: The answer is B.
Explanation: While yes it is important to make at least the minimum payment, its not ideal to carry a balance from month to month (You'll rack up interest charges). And risk falling into debt. Therefore, the answer is B.
Hope this helps!
3.This exercise considers the implementation of search algorithms in Prolog. Suppose that successor(X,Y) is true when state Y is a successor of state X; and that goal(X) is true when X is a goal state. Write a definition for solve(X,P), which means that P is a path (list of states) beginning with X, ending in a goal state, and consisting of a sequence of legal steps as defined by {\tt successor}. You will find that depth-first search is the easiest way to do this. How easy would it be to add heuristic search control
Answers
Answer:
c
Explanation:
How can technical writers help readers focus on important information in a set of instructions?
Technical writers can bring a reader's attention to important details in a set of instructions by ___.
1. adding an explanation and caution
2. using a highlighting technique
3. repeating the information
4. adding graphics to the introduction
Answers
Answer:
2. using a highlighting technique
Explanation:
highlighting is for to draw attention
Which of the following statements should be avoided when developing a mission statement?
The how-to statements.
Describe the “who, what, and where” of the organization.
Be brief, but comprehensive.
Choose wording that is simple.
Answers
Answer: The how-to statements
Explanation:
The mission statement is simply a short summary of the purpose of a company. It is the guideline on how a company will operate. The mission statement states the reason for the existence of a company, products sold or service rendered and the company's goals.
The mission statement should be brief but comprehensive, consist of simple words and describe the “who, what, and where” of the organization.
Therefore, the incorrect option based on the explanation above is "The how-to statements". This shouldn't be part of the mission statement.
Write a function, stringify_digit that takes a single digit (integer) and returns the corre-sponding digit as a string. For example, stringify_digit(9) returns "9" and stringify_digit(0)returns "0". You may assume that only the digits 0 to 9 will be passed in as argumentsto your function. You may not use the str() function for this function.
Answers
Answer:
The function in Python is as follows:
def stringify_digit(digit):
dig = "%s" % digit
return dig
Explanation:
This defines the function
def stringify_digit(digit):
This converts the input parameter to string
dig = "%s" % digit
This returns the string equivalent of the input parameter
return dig
Describing How to Create a Self-Join Query
Use the drop-down menus to complete the steps for creating a self-join query.
1. Click the
tab.
2. In the Queries group, click Query Design.
3. In the Show Table dialog box, add
4. Click and drag a field from one copy of the table and drop it on the other table.
5. Add the fields to the query.
6. Click
to see the results.
е
Answers
Answer:1. Click the ✔ Create tab.
2. In the Queries group, click Query Design.
3. In the Show Table dialog box, add ✔ the same table twice
.
4. Click and drag a field from one copy of the table and drop it on the other table.
5. Add the fields to the query.
6. Click ✔ Run
to see the results.
Explanation:on edg
Describing How to Create a Self-Join Query Use the drop-down menus to complete the steps for creating a self-join query is by 1. Click the tick in the tab to design a Self-Join Query.
Why can we use self be a part of?A self-be a part of is a be a part of that may be used to sign up for a desk with itself. Hence, it's miles a unary relation. In a self-be, a part of, every row of the desk is joined with itself and all of the different rows of the equal desk.
The Query and View Designer assigns an alias to the second one example via way of means of including a sequential wide variety to the desk name. In addition, the Query and View Designer creates a be a part of line among the 2 occurrences of the desk or desk-valued item withinside the Diagram pane.
Read more about the Queries :
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Write a program that prompts the user to enter a series of numbers between 0 and 10 asintegers. The user will enter all numbers on a single line, and scores will be separatedby spaces. You cannot assume the user will supply valid integers, nor can you assumethat they will enter positive numbers, so make sure that you validate your data. You donot need to re-prompt the user once they have entered a single line of data. Once youhave collected this data you should compute the following: • The largest value • Thesmallest value • The range of values • The mode (the value that occurs the most often) •A histogram that visualizes the frequency of each number Here’s a sample running of theprogram.
Answers
Answer:
The program in Python is as follows:
import collections
from collections import Counter
from itertools import groupby
import statistics
str_input = input("Enter a series of numbers separated by space: ")
num_input = str_input.split(" ")
numList = []
for num in num_input:
if(num.lstrip('-').isdigit()):
if num[0] == "-" or int(num)>10:
print(num," is out of bound - rejecting")
else:
print(num," is valid - accepting")
numList.append(int(num))
else:
print(num," is not a number")
print("Largest number: ",max(numList))
print("Smallest number: ",min(numList))
print("Range: ",(max(numList) - min(numList)))
print("Mode: ",end = " ")
freqs = groupby(Counter(numList).most_common(), lambda x:x[1])
print([val for val,count in next(freqs)[1]])
count_freq = {}
count_freq = collections.Counter(numList)
for item in count_freq:
print(item, end = " ")
lent= int(count_freq[item])
for i in range(lent):
print("#",end=" ")
print()
Explanation:
See attachment for program source file where comments are used as explanation. (Lines that begin with # are comments)
The frequency polygon is printed using #'s to represent the frequency of each list element
Python The Sieve of Eratosthnes Prgram
A prime integer is any integer greater than 1 that is evenly divisible only by itself and 1. The Sieve of Eratosthenes is a method of finding prime numbers. It operates as follows:
Create a list with all elements initialized to 1 (true). List elements with prime indexes will remain 1. All other elements will eventually be set to zero.
Starting with list element 2, every time a list element is found whose value is 1, loop through the remainder of the list and set to zero every element whose index is a multiple of the index for the element with value 1. For list index 2, all elements beyond 2 in the list that are multiples of 2 will be set to zero (indexes 4, 6, 8, 10, etc.); for list index 3, all elements beyond 3 in the list that are multiples of 3 will be set to zero (indexes 6, 9, 12, 15, etc.); and so on.
When this process is complete, the list elements that are still set to 1 indicate that the index is a prime number. These indexes can then be printed. Write a program that uses a list of 1000 elements to determine and print the prime numbers between 2 and 999. Ignore element 0 of the list. The prime numbers must be printed out 10 numbers per line.
Sample Executions:
Prime numbers between 2 and 999 as determined by the Sieve of Eratosthenes.
2 357 11 13 17 19 23 29
31 37 41 43 47 53 59 61 67 71
73 79 83 89 97 101 103 107 109 113
127 131 137 139 149 151 157 163 167 173
179 181 191 193 197 199 211 223 227 229
233 239 241 251 257 263 269 271 277 281
283 293 307 311 313 317 331 337 347 349
353 359 367 373 379 383 389 397 401 409
419 421 431 433 439 443 449 457 461 463
467 479 487 491 499 503 509 521 523 541
547 557 563 569 571 577 587 593 599 601
607 613 617 619 631 641 643 647 653 659
661 673 677 683 691 701 709 719 727 733
739 743 751 757 761 769 773 787 797 809
811 821 823 827 829 839 853 857 859 863
877 881 883 887 907 911 919 929 937 941
947 953 967 971 977 983 991 997
Answers
Answer:
try this
Explanation:
def SieveOfEratosthenes(n):
prime = [True for i in range(n+1)]
p = 2
while (p * p <= n):
if (prime[p] == True):
for i in range(p * p, n+1, p):
prime[i] = False
p +=1
c=0
for p in range(2, n):
if prime[p]:
print(p," ",end=" ")
c=c+1
if(c==10):
print("")
c=0
n= 1000
print("prime number between 2 to 999 as determined by seive of eratostenee ")
SieveOfEratosthenes(n)