Answer:
equal to 1
Explanation:
When any ray of light falls or strikes on a surface, the ray is reflected back and the angle of reflection is equal to angle of the incidence, where both the angles are always measured from the path of light that is normal to surface of the point at which the ray of light strikes the surface. This is called as the laws of reflection of light.
And therefore, the ratio of the angle of incidence to the angle of reflection is always equal to 1.
AP Physics Question
An amusement park ride consists of a large vertical wheel of radius that rotates counterclockwise on a horizontal
axis through its center, as shown above. The cars on the wheel move at a constant speed . Points and
represent the position of a car at the highest and lowest point of the ride, respectively. A person of weight sits
upright on a seat in one of the cars. As the seat passes point , the seat exerts a normal force with magnitude
on the person. While passing point , the person releases a small rock of mass , which falls to the ground
without hitting anything.
2. Which of the following best describes the passenger’s linear and angular velocity while passing point ?
A
Linear Velocity Angular Velocity
Constant Changing
B
Linear Velocity Angular Velocity
Constant Constant
C
Linear Velocity Angular Velocity
Changing Changing
D
Linear Velocity Angular Velocity
Changing Constant
The linear velocity is changing and the angular velocity is Constant best describes the passenger’s linear and angular velocity while passing a point.
What is the definition of Angular velocity?The rate of change of angular displacement is defined as angular speed, and it is stated as follows:
ω = θ t
Where,
θ is the angle of rotation,
t is the time
ω is the angular velocity
The linear velocity is given as the product of angular velocity and radius.
v=ωr
In the circular motion, the linear velocity is changing. Because the radius is changing.While the angular velocity is constant.Because it is an independent quantity.
Hence the Linear velocity is changing and the angular velocity is Constant best describing the passenger’s linear and angular velocity while passing a point.
To learn more about the angular velocity refer to the link;
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A sample of a low-density gas is initially at room temperature and has pressure p. The gas is warmed at constant volume until the pressure is 2p. Compared to the initial Celsius temperature of the gas, the final Celsius temperature is
Answer:
Compared to the initial Celsius temperature of the gas, the final Celsius temperature is greater by a factor of more than 2.
Explanation:
Gay-Lussac's law states that the pressure of a fixed volume of a gas is directly proportional to its temperature. In other words, if the temperature increases, the pressure will increase and if the temperature decreases, the pressure will decrease.
In summary, Gay-Lussac's law is a law that says that when the amount of gas and volume are kept constant, the quotient that exists between the pressure and the temperature will always have the same value:
[tex]\frac{P}{T}=k[/tex]
Being an initial state 1 and a final state 2, it is true:
[tex]\frac{P1}{T1} =\frac{P2}{T2}[/tex]
In this case:
P1= pT1= tP2= 2pT2= ?Replacing:
[tex]\frac{p}{t} =\frac{2p}{T2}[/tex]
Solving:
[tex]T2=2p*\frac{t}{p}[/tex]
T2= 2*t
Compared to the initial Celsius temperature of the gas, the final Celsius temperature is greater by a factor of more than 2.
does anybody know what i can put for these 3 questions?
Where inside an atom are protons and neutrons located?
Answer:
They are located in the core
Explanation:
Answer:
Inside the nucleus.
Explanation:
There are three subatomic particles. Protons have a charge of 1+, a mass of 1amu, and are found in the nucleus. Neutrons do not have a charge, have a mass of 1amu, and are found in the nucleus. Electrons have a charge of 1-, have negligible mass, and can be found orbiting the nucleus in the electron cloud.
Two charges of 5 x 10-6 C are a certain distance apart. These two positive charges experience 3.6 N of repelling electrical force between them. How far apart are these charges?
Answer:
r = 0.2499 m
Explanation:
Use Coulomb's Law: [tex]F_{e} = kq_{1}q_{2} / r^{2}[/tex] where Fe is the electric force, q1 and q2 are the 2 charges respectively, k is a constant (8.99*10^9 N • m^2 / C^2) and r is the distance.
[tex]3.6 N = (8.99*10^{9})(5*10^{-6})(5*10^{-6}) / r^{2}[/tex]
r = 0.2499 m
The distance that should be apart from these charges should be considered when the r = 0.2499 m.
Calculation of the distance apart:Since
Two charges of 5 x 10-6 C are a certain distance apart. These two positive charges experience 3.6 N of repelling electrical force between them
So
here we use Columb law
Electric force = k * two charges * two charges)r^2
3.6 N = (8.99*10^9) * ( 5 * 10^-6) * (5*10^-6)r^2
r = 0.2499 m.
Hence, The distance that should be apart from these charges should be considered when the r = 0.2499 m.
Learn more about force here: https://brainly.com/question/15866225
What are sport skills sometimes referred to as?
a skill-related fitness
b. performance skills
c. health-related fitness
d. physical fitness
If a net force acting on a moving object causes its speed to increase, what
happens to the object's momentum?
A. It stays the same.
B. It increases.
C. It changed directions.
D. It decreases.
Answer:
It increases.
Explanation:
If a force acts in the same direction as the object's motion, then the force speeds the object up. Either way, a force will change the velocity of an object. And if the velocity of the object is changed, then the momentum of the object is changed.
Part D The surface area of a material is a factor that affects heat conductivity. Does heat flow faster through a large surface area or through a small surface area? Why? (Hint: Think about the number of particles available to bump into one another)
Answer:
That guy is right i got a 100 as my score :)
Explanation:
How many lobes are in the lungs
Answer:
There are 5 lobes in the lungs.
Explanation:
The right lung consists of three lobes: the RUL, the RML, and the RLL. While the left lung consists of two lobes: the LUL, and the LLL.
what is SI unit of speed
Answer:
m/s
Explanation:
The SI unit of speed is the metre per second, but the most common unit of speed in everyday usage is the kilometre per hour or, in the US and the UK, miles per hour.
m/s
which is also written as
ms-¹
The above mentioned symbols are said as 'meter per second'
hope it helps!
How much energy (in kWh) can you get from a 72 cell solar panel in one year?
Please hurry
Starting from rest, this airliner accelerates at 2.4m/s2 for 32 seconds before leaving the ground. Calculate its velocity at liftoff.
Answer:
The velocity will be "76.8 m/s".
Explanation:
The given values are:
Acceleration,
a = 2.4 m/s²
Time,
t = 32 seconds
By equation of motion,
⇒ [tex]v=u+at[/tex]
On substituting the values, we get
⇒ [tex]=0+2.4\times 32[/tex]
⇒ [tex]=0+76.8[/tex]
⇒ [tex]=76.8 \ m/s[/tex]
What is the nergy of a wave that has a
frequency of 6.32 x 10^20 Hz?
here you go thank bob not me he will be very thankful
This girl named Emma she my crush what do I say to her.
Answer:
you gotta shoot your shot.
Explanation:
look for the signs. ask her out before someone else does. you got this dawg
please help me
A football player kicks a football and exerts a force on the football of 0.4 kg (m/s²). The football’s acceleration is 0.92 m/s². What is the mass of the football?
Answer:
0.368 Newtons
Explanation:
Answer:
i think it's 0.88
Explanation:
What is the velocity of a bus that travels 250 km in 2 hrs?
Answer:
125
Explanation:
you divide km/hrs to find your velocity.
V=km/hr
V= 250km/2hr
V=125
hope this helps !:)
An oscillator is made with a rubber band and a block of wood
as shown in the diagram. What happens to the oscillator if we
make the block of wood heavier?
Answer:
Explanation:
a. The frequency increases.
b. The period increases.
c. The frequency stays the same.
d. The period stays the same
AP Physics Question 3
A planet has two moons, Moon and Moon , that orbit at different distances from the planet’s center, as shown.
Astronomers collect data regarding the planet, the two moons, and their obits. The astronomers are able to estimate
the planet’s radius and mass.
3. The masses of the two moons are determined to be for Moon and for Moon . It is observed that
the distance between Moon and the planet is two times that of the distance between Moon and the
planet. How does force exerted from the planet on Moon compare to the force exerted from the planet on
Moon ?
The gravitational force exerted from the planet on Moon is two times larger than the gravitational force
exerted from the planet on Moon .
B
The gravitational force exerted from the planet on Moon is eight times larger than the gravitational force
exerted from the planet on Moon .
C
The gravitational force exerted from the planet on Moon is two times smaller than the gravitational force
exerted from the planet on Moon .
D
The gravitational force exerted from the planet on Moon is eight times smaller than the gravitational force
exerted from the planet on Moon .
Gravitational force increases as the mass increases and decreases as the distance between the bodies is increased.
The correct option is; The gravitational force exerted from the planet on Moon A is eight times larger than the gravitational force exerted from the planet on Moon B.Reasons:
The given parameters are;
The moons of the planet = Moon A and Moon B
Mass of Moon A = 2·M
Mass of moon B = M
The distance between Moon B and the planet = 2 × The distance between Moon A and the planet
Required:
Comparison (compare) of the force exerted from the planet on Moon A and Moon B.
Solution:
The force, F, exerted from the planet is the gravitational force which is given by Newton's Law of Gravitation as follows;
[tex]\displaystyle F = \mathbf{G \cdot \frac{M_{planet} \times M}{R^2}}[/tex]Where;
G = Universal gravitational constant
[tex]M_{planet}[/tex] = Mass of the planet
M = Mass of the Moon
R = The distance from the planet to the Moon
For Moon A, we have;
Mass = 2·M
Distance = R
Which gives;
[tex]\displaystyle F_A = G \cdot \frac{M_{planet} \times 2\cdot M}{R^2} = 2\cdotG \cdot \frac{M_{planet} \times M}{R^2} = \mathbf{2 \cdot F}[/tex]
With Moon B, we have;
Mass = M
Distance = 2·R
Therefore;
[tex]\displaystyle F_B = G \cdot \frac{M_{planet} \times M}{(2 \cdot R)^2} = G \cdot \frac{M_{planet} \times M}{4 \cdot R^2} = \frac{1}{4} \cdot G \cdot \frac{M_{planet} \times M}{R^2} = \mathbf{\frac{1}{4} \cdot F}[/tex]
Which gives;
[tex]\displaystyle \frac{F_A}{F_B} = \frac{2 \cdot F}{\frac{1}{4} \cdot F } =2 \times \frac{4}{1} = \mathbf{8}[/tex]
[tex]\displaystyle \frac{F_A}{F_B} = 8[/tex]
[tex]F_A = \mathbf{8 \times F_B}[/tex]
The force from the planet on Moon A, [tex]F_A[/tex], is 8 times the force from the planet on Moon B.
Therefore, whereby option B is;
The gravitational force exerted from the planet on Moon A is eight times larger than the gravitational force exerted from the planet on Moon B.The correct option is option B
Learn more about Newton's Law of gravitation here:
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A hockey puck slides across the ice with an initial velocity of 7.3 m/s .It has a decleration of 1.1 m/s and is traveling towards the goal 5.0 m away .How much time does the goalie have to stop the puck?
Answer:
t = 6.63 s
Explanation:
Given that,
Initial velocity of the puck, u = 7.3 m/s
Deacceleration of the puck, a = -1.1 m/s²
Distance traveled, d = 5 m
We need to find the time the goalie have to stop the puck. Using equation of motion.
v = u +at
v = 0 (stops)
So,
[tex]u=-at\\\\t=\dfrac{u}{-a}\\\\t=\dfrac{7.3}{-(-1.1)}\\\\t=6.63\ s[/tex]
So, the required time is 6.63 seconds.
Which three parts of the graph’s curve represent the solid, liquid, and gaseous state of water? Explain your reasoning.
B,C,D maybe
Explanation:
plz dont get mad
A car slams into a wall with a force of 5000 N. What is the force of the wall on the car? 5000 N -5000 N 49000 N 510 N It cannot be determined with the information provided.
Answer:
-5000 N
Explanation:
Newtons third law of motion states that action and reaction are equal and opposite. This means that to every action, there is an equal opposite reaction.
Hence when a body A exerts a force FA on another body B, the body B also exerts a force FB on A which is equal in magnitude to FA but opposite in direction. FB is the reaction force due to FA.
Hence, when a car hits a wall with a force of 5000N, the reaction of the wall on the car is -5000N
Metals allow electrons to flow through and complete the circuit. Therefore they are called?
Answer:
the answer would be conductors
What is the mass of an asteroid with a speed of 200 m/s and a momentum of 2,000 kg m/s?
A. 2200 kg
B. 10 kg
C. 400,000 kg
D. 1,800 kg
Answer:
jhnnmhunn vgu fhbiy f
Explanation:
hjbgyvfvubhjgvg
Answer:10 kg
Explanation: momentum p = mv and m = p/v
Mass m = 2000 kgm/ s / 200 m/s
Rank the ten objects from loudest to softest.
In red shift, the wavelengths of light become?
Answer:
Explanation:god is good because the god is what it stays
god is good because the god is what it staysgod is good because the god is what it staysgod is good because the god is what it stays
.
A .63 kg ball is moving at 4.3m/s. What is the momentum of the ball?
Answer:
Given Mas (m) =63kg
velocity (v) =4.3m/s
momentum (p) =?
p=mv
63kgx4.3m/s
270.9kg.m/s
the momentum =270.9kg.m /s
If a ball of mass 0.63 kilograms is moving at 4.3 meters/seconds, then the momentum of the ball would be 2.709-kilogram meters/second.
What is momentum?It can be defined as the product of the mass and the speed of the particle, it represents the combined effect of mass and the speed of any particle.
Momentum = mass of the object × velocity of the object
As given in the problem we have to calculate the momentum of the ball if it has a mass of 0.63 kilograms and moving with a speed of 4.3 meters/seconds,
The momentum of the ball = 0.63× 4.3
=2.709 kilogram meters/second
Thus, the momentum of the ball comes out to be 2.709-kilogram meters/second.
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#SPJ2
Carbon dioxide can be represented by the chemical formula
es
A)
C₂0
B)
CO2
C)
Ca,
D)
CaOz
pls help fast !!!
Answer:
Your answer is B co2
Explanation:
Answer: CO2
Explanation:
Carbon dioxide is consisted of one carbon molecule and 2 oxygen molecules, therefore CO2
If a 7 kg bowling ball is lifted 2 m into the air and dropped, what speed will it strike the ground? (
Answer:
6.32m/s
Explanation:
note:Now these calculations are based in the fact that acc. due to gravity is 10m/s²
okay so I'm thinking you think the speed of a body depends on the mass of the body also,umh... well it doesn't at all!
when two bodies of different masses fall from the same height,they fall at the same time( this is just to say)
now enough of the talking let solve....
so the ball was dropped .ie from rest to the ground through a distance of 2m,
the formula for calculating the distance if a body moving in a straight line is given by:
S=ut + ½at² where u is initial velocity, a is acceleration ( of the body or due to gravity, but since its falling freely under the influence of gravity its " we use the acceleration due to gravity ,which is 10m/s²) and t is the time taken to cover the distance.
from our question the ball was dropped from rest thus its u is 0 therefore we use this equation to find the time it took to touch ground (S=½at²)
solving ....
we get t to be 0.632s
to find the speed we substitute t in the equation below:
V=u+at ,but since u=0
V=at =10•0.632=6.32m/s
therefore the speed the body uses to strike the ground is 6.32m/s
please help me
A football, that has a mass of 0.43 kg, is kicked across a field at an acceleration of 0.92 m/s². What is the force used on the football?
Answer:
0.3956
Explanation:
Newton's 2nd law of motion says that Force = Mass*Acceleration (f=ma) so to find the force used on the football you multiply it's mass by its acceleration.
0.43*0.92 = 0.3956.
0.4 if you round
A 230 kg motorcycle zooms away from a red light with a force of
13,800 Newtons. What is the acceleration of the motorcycle in m/s??
Answer:343
Explanation: