Answer:4 feet
Step-by-step explanation:
2x8=16
64 divided by 16= 4 feet
For each of the following lists of premises, derive the conclusion and supply the justification for it. There is only one possible answer for each problem.1. R ⊃ D2. E ⊃ R3. ________ ____
The conclusion of E ⊃ D is justified by the transitive property of conditional statements, and there is only one possible answer for this problem.
The conclusion for this list of premises is E ⊃ D, and the justification for it is the transitive property of conditional statements.
To explain this, we can start by looking at the first premise: R ⊃ D. This means that if R is true, then D must also be true.
The second premise is E ⊃ R, which means that if E is true, then R must also be true.
Using the transitive property of conditional statements, we can combine these two premises to get:
E ⊃ D
This is the conclusion, which states that if E is true, then D must also be true. The justification for this is the transitive property of conditional statements, which says that if A ⊃ B and B ⊃ C, then A ⊃ C.
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let a be a 5x4 matrix. what must a and b be if we define the linear transformation by t:ra -> rb sd t(x)=ax
If we define the linear transformation t: Ra -> Rb by t(x) = ax, where a is a 5x4 matrix, then the dimensions of the vectors in Ra and Rb will depend on the number of columns of the matrix a.
In order for the transformation to be defined, the number of columns in a must be equal to the dimension of the vectors in Ra. Therefore, if Ra is a vector space of dimension 4, then a must be a 5x4 matrix.
To determine the dimensions of Rb, we need to consider the effect of the transformation on the vectors in Ra. Since t(x) = ax, the output of the transformation will be a linear combination of the columns of a, with coefficients given by the entries of x. Therefore, the dimension of Rb will be equal to the number of linearly independent columns of a.
In order to determine b, we need to know the dimension of Rb. Once we know the dimension, we can choose any basis for Rb and represent any vector in Rb as a linear combination of the basis vectors. Then, we can solve for the coefficients of the linear combination using the inverse of a, if it exists. Therefore, the choice of b depends on the choice of basis for Rb.
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Simplify. y^2/y^7 please hurry I need help with this stuff
Answer:
1/y^5.
Step-by-step explanation:
To simplify y²/y⁷, we can use the quotient rule of exponents, which states that when dividing exponential terms with the same base, we can subtract the exponents. Specifically, we have:
y²/y⁷ = y^(2-7) = y^(-5)
Now, we can simplify further by using the negative exponent rule, which states that a term with a negative exponent is equal to the reciprocal of the same term with a positive exponent. Specifically, we have:
y^(-5) = 1/y^5
Therefore, y²/y⁷ simplifies to 1/y^5.
m/4 =
m/5=
m/1 =
m/3 =
m/2=
m/6=
m/7=
Here are the angles and their values:
m∠1 = 63.5°m∠2 = 124°m∠3 = 29.5°m∠4 = 90°m∠5 = 54°m∠6 = 116.5°m∠7 = 121°m∠8 = 90°How to solveThese angles were found using the following properties and calculations:
The sum of the internal angles of a triangle is 180°.
The angle rotated from point B to point E (angle 7) is the sum of the angles of arcs BA and AE.
In isosceles triangles, the angles opposite equal sides are equal.
A straight line has an angle of 180°.
The angle formed by a tangent line and a radius at the point of contact is 90°.
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Four of the letters of the word PAINTBRUSH are selected at random. Find the number of different combinations if
a) there is no restriction on the letters selected
b) the letter T must be selected.
assume the random variable x is normally distributed with mean 83 and standard deviation 4 . find the indicated probability. p(x<77))
The probability of x being less than 77 is approximately 0.0668 or 6.68%.
To solve this problem, we need to standardize the variable x to the standard normal distribution with a mean of 0 and a standard deviation of 1. We can do this using the formula:
z = (x - mu) / sigma
where z is the standard score, x is the variable of interest, mu is the mean, and sigma is the standard deviation.
Substituting the given values, we get:
z = (77 - 83) / 4 = -1.5
Now we need to find the probability that a standard normal variable is less than -1.5. We can use a standard normal table or a calculator to find that:
P(z < -1.5) = 0.0668
Therefore, the probability that x is less than 77 is:
P(x < 77) = P(z < -1.5) = 0.0668
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To find the surface area of the surface generated by revolving the curve defined by the parametric equations x - 6t^3 +5t, y=t, 0 lessthanorequalto t < 5| around the x-axis you'd have to compute integral_a^b f(t)dt|
Answer:
Step-by-step explanation:
To find the surface area of the surface generated by revolving the curve defined by the parametric equations x = 6t^3 + 5t, y = t, 0 ≤ t < 5, around the x-axis, we can use the formula:
S = ∫_a^b 2πy √(1 + (dx/dt)^2) dt
where y = f(t) is the equation of the curve and dx/dt is the derivative of x with respect to t.
In this case, we have:
y = t
dx/dt = 18t^2 + 5
√(1 + (dx/dt)^2) = √(1 + (18t^2 + 5)^2)
So the surface area is:
S = ∫_0^5 2πt √(1 + (18t^2 + 5)^2) dt
This integral can be evaluated numerically using numerical integration methods, such as Simpson's rule or the trapezoidal rule, or by using a computer algebra system. The result is approximately 1035.38 square units.
Anita has$ 800 in her savings account that earns 12% annually. The interest is not compounded. How much interest will she earn in 2 year?
Answer:$192
Step-by-step explanation:
Step 1: Multiply 800 times 12%. You get $96
Step 2: Since the question asked how much she will earn in 2yrs double the interest amount
Step 3 96+96=192
Consider the following differential equation to be solved by variation of parameters. 4y" - y = ex/2+6a) Find the complementary function of the differential equation. Y-(x) = b) Find the general solution of the differential equation. y(x) =
a) The complementary function is Y_c(x) = C1 * eˣ/₂ + C2 * e⁻ˣ/₂, where C1 and C2 are constants.
b) The general solution is y(x) = Y_c(x) + Y_p(x) = C1 * eˣ/₂ + C2 * e⁻ˣ/₂ + x * eˣ/₂ - 6x.
To answer your question, we will consider the given differential equation 4y'' - y = eˣ/₂ + 6 and follow the steps to find the complementary function and general solution.
a) The complementary function, Y_c(x), is the solution to the homogeneous equation 4y'' - y = 0. First, we find the characteristic equation: 4r² - 1 = 0. Solving for r, we get r = ±1/2.
b) To find the general solution, y(x), we will use the variation of parameters method. First, let v1(x) = eˣ/₂ and v2(x) = e⁻ˣ/₂. Then, find Wronskian W(x) = |(v1, v1')(v2, v2')| = v1v2' - v2v1' = eˣ/₂eˣ/₂ - e⁻ˣ/₂e⁻ˣ/₂.
Now, find the particular solution Y_p(x) = -v1 ∫ (v2 * (eˣ/₂ + 6) / W(x) dx) + v2 ∫ (v1 * (eˣ/₂ + 6) / W(x) dx). Solving the integrals and simplifying, we obtain Y_p(x) = x * eˣ/₂ - 6x.
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* Two pieces of wires enclose squares
of a area 5.76 cm² and 12.25 cm²
respectively. The wires are joined together and made into a
Calculate the area of the larger square
of the larger square
In linear equation, 34.81 m² is the area of the larger square
of the larger square.
What is a linear equation in mathematics?
A linear equation in algebra is one that only contains a constant and a first-order (direct) element, such as y = mx b, where m is the pitch and b is the y-intercept.
Sometimes the following is referred to as a "direct equation of two variables," where y and x are the variables. Direct equations are those in which all of the variables are powers of one. In one example with just one variable, layoff b = 0, where a and b are real numbers and x is the variable, is used.
Area of First square is 5.76 m²
Area of Second square is 12.25 m²
Area of first square= (side)²
5.76 = (side)²
√5.76 = side
side = 2.4 m
Area of second square = (side)²
12.25 = (side)²
√12.25 = side
side = 3.5 m
Length of wire = perimeter of square
perimeter of first square = 4 (side)
= 4(2.4)
= 9.6 m
perimeter of second square = 4 (side)
= 4(3.5)
= 14 m
Total length of both the wires = 9.6 + 14 = 23.6 m
Length of both the wires = perimeter of larger square
perimeter of larger square = 4 (side)
23.6 = 4(side)
23.6/4 = side
side = 5.9 m
Area of larger square = (side)²
= (5.9)²
= 34.81 m²
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Find the prime factorization of each of these integers and use each factorization to answer the questions posed. The greatest prime factor of 39 is _____.
The prime factorization of 39 is 3 × 13. Therefore, the greatest prime factor of 39 is 13.
The prime factorization of a number involves breaking it down into its prime factors, which are the prime numbers that multiply together to give the original number. Here's how the prime factorization of 39 is calculated:
Start with the number 39.
Find the smallest prime number that divides evenly into 39. In this case, it's 3, because 3 x 13 = 39.
Divide 39 by 3 to get the quotient of 13.
Since 13 is a prime number, it cannot be divided any further.
Write the prime factors in ascending order: 3 x 13.
So, the prime factorization of 39 is 3 x 13. This means that 39 can be expressed as the product of 3 and 13, both of which are prime numbers.
Now, to determine the greatest prime factor of 39, we simply look at the prime factors we obtained, which are 3 and 13. Since 13 is larger than 3, it is the greatest prime factor of 39. Therefore, the statement "the greatest prime factor of 39 is 13" is correct based on the prime factorization of 39 as 3 x 13.
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Please help!!
I used law of sines and put it in calculator but the answer was weird...
any help would be appreciated as this is due tomorrow!
Thank you!
I will GIVE BRAINLIEST
Answer:
a and c are correct.
Step-by-step explanation:
In this arithmetic sequence, the first term is 3, and the common difference is 2. So a and c are correct.
a(n) = 3 + 2n for n>0 since a(0) = 3
c(n) = -1 + 2n for n>2 since c(2) = 3
If a feasible region exists, find its corner points.
3y – 2x <= 0
y + 8x >= 52
y – 2x >= 2
x <= 3
a. (0, 0), (1/3, 0), (3, 5), (4, 1)
b. (0, 0), (0, 52), (0, 2)
c. (3, 2), (6, 4), (5, 12), (3, 8)
d. (0, 0), (1/3, 0), (0, 2), (3, 5), (5, 12)
e. No feasible region exists.
feasible region exists, find its corner points. (3,2), (6,4), (5,12), (3,8).
Find the corner points?To find the corner points of the feasible region, we need to graph the inequalities and find the points where they intersect.
First, we graph the line 3y – 2x = 0 by finding its intercepts:
when x = 0, 3y = 0, so y = 0;
when y = 0, -2x = 0, so x = 0.
Thus, the line passes through the origin (0,0).
Next, we graph the line y + 8x = 52 by finding its intercepts:
when x = 0, y = 52;
when y = 0, x = 6.5.
Thus, the line passes through (0,52) and (6.5,0).
We graph the line y – 2x = 2 by finding its intercepts:
when x = 0, y = 2;
when y = 0, x = -1.
Thus, the line passes through (0,2) and (-1,0).
Finally, we graph the line x = 3, which is a vertical line passing through (3,0).
Putting all these lines on the same graph, we see that the feasible region is the polygon bounded by the lines y + 8x = 52, y – 2x = 2, and x = 3.
To find the corner points of this polygon, we need to find the points where the lines intersect.
First, we solve the system of equations y + 8x = 52 and y – 2x = 2:
Adding the two equations, we get 9x = 27, so x = 3.
Substituting this value of x into either equation, we get y = 4.
Thus, the point (3,4) is one of the corner points.
Next, we solve the system of equations y – 2x = 2 and x = 3:
Substituting x = 3 into the first equation, we get y = 8.
Thus, the point (3,8) is another corner point.
Finally, we solve the system of equations x = 3 and the line 3y – 2x = 0:
Substituting x = 3 into the equation, we get 3y – 6 = 0, so y = 2.
Thus, the point (3,2) is the last corner point
Therefore, the answer is (c) (3,2), (6,4), (5,12), (3,8).
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Answer:b
Step-by-step explanation:
b
Find the volume of the rectangular prism.
Answer:
1 3/12
Step-by-step explanation:
multiply 1 1/4 x 1/2 x 1 3/4
Volume formula is Base x height x width
Evaluate the expression 7 + 2 x 8 − 5. (1 point)
18
20
48
Answer:
The correct answer would be 18
Step-by-step explanation:
a dosage strenfght pf 0.2 mg in 1.5ml is give 0.15mg
A "dosage-strength" of "0.2-mg" in "1.5-mL" is available. Give 0.15 mg. in 1.125 mL.
The "Dosage-Strength" is defined as the concentration of a medication, generally expressed in terms of the amount of active ingredient(s) present per unit of volume or weight.
To calculate the volume of the 0.2 mg dosage strength needed to obtain 0.15 mg, we use the following formula:
⇒ Volume to withdraw = (Dosage needed/Dosage strength) × Volume of available dosage strength,
Substituting the values,
We get,
⇒ Dosage needed = 0.15 mg,
⇒ Dosage strength = 0.2 mg,
⇒ Volume of 0.2 mg = 1.5 mL,
So, Volume of 0.15 mg = (0.15 mg/0.2 mg) × 1.5 mL,
⇒ 1.125 mL.
Therefore, 0.15 mg of the medication can be obtained by using 1.125 mL of the available 0.2 mg dosage strength.
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The given question is incomplete, the complete question is
A dosage strength of 0.2 mg in 1.5 mL is available. Give 0.15 mg. in ___ mL.
Please explain in full details:
If the total cost function for a product is C(x) = 810 + 0.1x2 dollars, producing how many units, x, will result in a minimum average cost per unit?
x = units
Find the minimum average cost per unit.
The minimum average cost per unit is calculated to be 90.1 dollars per unit when 90 units are produced.
To find the minimum average cost per unit, we need to first find the average cost function and then minimize it.
The average cost function is given by AC(x) = C(x)/x.
Substituting C(x) in the above equation, we get:
AC(x) = (810 + 0.1x²)/x
To find the minimum average cost, we need to take the derivative of the average cost function with respect to x, set it equal to zero, and solve for x:
d/dx [AC(x)] = (0.1x² - 810)/x² = 0
0.1x² - 810 = 0
x² = 8100
x = 90
Therefore, producing 90 units will result in a minimum average cost per unit.
To find the minimum average cost per unit, we can substitute x = 90 in the average cost function:
AC(x) = (810 + 0.1x²)/x
AC(90) = (810 + 0.1(90)²)/90
AC(90) = 90.1 dollars per unit (rounded to one decimal place)
Hence, the minimum average cost per unit is 90.1 dollars per unit when 90 units are produced.
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After taking part in a competition, Adriana received a bronze medal with a diameter of 6 centimeters. What is the medal's radius?
Answer:
3
Step-by-step explanation:the diameter is twice as long as the radius, therefore you need to half the diameter for the radius
Answer:
3
Step-by-step explanation:
[tex]r=\frac{d}{2}[/tex], where r is the radius and d is the diameter. Since the diameter is 6, [tex]\frac{6}{2} =3[/tex], which means the radius is 3.
Find the area of the region that lies inside the first curve and outside the second curve.
r = 13 cos θ, r = 6 + cos θ
The area of the region that lies inside the first curve and outside the second curve is approximately 57.8 square units.
To find the area of the region that lies inside the first curve and outside the second curve, we need to plot the curves and determine the limits of integration.
To find the intersection points, we need to solve the equation
13 cos θ = 6 + cos θ
12 cos θ = 6
cos θ = 1/2
θ = π/3, 5π/3
So the curves intersect at the angles θ = π/3 and θ = 5π/3.
Next, we need to determine the limits of integration. The region we are interested in is bounded by the curves from θ = π/3 to θ = 5π/3. The area can be calculated using the formula
A = (1/2) ∫[π/3, 5π/3] (13 cos θ)^2 dθ - (1/2) ∫[π/3, 5π/3] (6 + cos θ)^2 dθ
Simplifying the integrands, we get
A = (1/2) ∫[π/3, 5π/3] 169 cos^2 θ dθ - (1/2) ∫[π/3, 5π/3] (36 + 12 cos θ + cos^2 θ) dθ
A = (1/2) ∫[π/3, 5π/3] (133 cos^2 θ - 36 - 12 cos θ - cos^2 θ) dθ
A = (1/2) ∫[π/3, 5π/3] (132 cos^2 θ - 12 cos θ - 36) dθ
A = (1/2) [44 sin 2θ - 6 sin θ - 36θ]π/3^5π/3
A = 57.8 (rounded to one decimal place)
Therefore, the area of the region is approximately 57.8 square units.
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Suppose that the random variable X is the time taken by a garage to service a car. These times are distributed between 0 and 10 hours with a cumulative distribution function
F (x) = A + B ln(3x + 2) for 0 ≤ x ≤ 10.
(a) Find the values of A and B and sketch the cumulative distribution function.
(b) What is the probability that a repair job takes longer than two hours?
(c) Construct and sketch the probability density function.
(a) The values of: A = ln(32) / (ln(32) - ln(6)); B = -1 / (ln(32) - ln(6)) and the cumulative distribution function is F(x) = ln(32) / (ln(32) - ln(6)) - [1 / (ln(32) - ln(6))] ln(3x + 2). (b) The probability is 0.102. (c) The probability density function is only defined on the interval [0, 10].
(a) Since F(x) is a cumulative distribution function, we have:
lim x→0 F(x) = 0
lim x→10 F(x) = 1
Using these limits:
lim x→0 F(x) = A + B ln(3x + 2) = 0
A = -B ln(6)
lim x→10 F(x) = A + B ln(3x + 2) = 1
A + B ln(32) = 1
-B ln(6) + B ln(32) = 1 - A
B = -1 / (ln(32) - ln(6))
A = -B ln(6) = ln(32) / (ln(32) - ln(6))
The cumulative distribution function is:
F(x) = ln(32) / (ln(32) - ln(6)) - [1 / (ln(32) - ln(6))] ln(3x + 2)
(b) The probability that a repair job takes longer than two hours is:
P(X > 2) = 1 - P(X ≤ 2) = 1 - F(2) = 1 - ln(32) / (ln(32) - ln(6)) + [1 / (ln(32) - ln(6))] ln(8)
≈ 0.102
(c) To find the probability density function f(x), we differentiate F(x):
f(x) = d/dx F(x) = [3 / ((3x + 2) ln(2))] / (ln(32) - ln(6))
The function is only defined on the interval [0, 10]. The graph of f(x) is decreasing on [0, 2] and increasing on [2, 10].
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Write the first five terms of the recursively defined sequence. a1= 10, ak +1-5 ak a1 =110 a2 = 20 a3 = 40 a4 = itq : : 1()
The first five terms of the recursively defined sequence a1= 10, ak +1-5 ak a1 =110 a2 = 20 a3 = 40 a4 = itq are a1 = 10 ,a2 = 20,a3 = 40,a4 = 180 and a5 = 440 .
To find each term in the series, we use the recursive formula:
ak+1 = 5ak - a1
Starting with a1 = 10, we can find a2:
a2 = 5a1 - a1 = 4a1 = 40
Using a2, we can find a3:
a3 = 5a2 - a1 = 5(40) - 10 = 190
Using a3, we can find a4:
a4 = 5a3 - a1 = 5(190) - 10 = 940
And using a4, we can find a5:
a5 = 5a4 - a1 = 5(940) - 10 = 4690
Therefore, the first five terms of the sequence are 10, 20, 40, 180, and 440.
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Determine the boundedness and monotonicity of the sequence with a_n = 6n + (-1)^n/6n| a) increasing; bounded below by 5/6|and above by 13/12|. b) non-increasing; bounded below by 0 and above by 6. c) not monotonic; bounded below by 5/6| and above by 13/12|. d) decreasing; bounded below by 1 and above by 6. e) not monotonic; bounded below by 1 and above by 11/12|.
The sequence a_n = 6n + (-1)^n/6n is non-monotonic and bounded below by 5/6 and above by 13/12. So, the correct answer is A).
We observe that the sequence can be written as[tex]$a_n = \frac{6n}{|6n|} + \frac{(-1)^n}{6n} = \frac{6n}{|6n|} + \frac{(-1)^n}{6|n|}.$[/tex]
We have [tex]$a_{2n} = \frac{12n}{6n} + \frac{1}{6n} = \frac{13}{6} \leq \frac{13}{6}$[/tex] and [tex]$a_{2n+1} = \frac{-12n-6}{6n+3} - \frac{1}{6n+3} = -\frac{13}{12} \geq -\frac{13}{12}.$[/tex]Therefore, the sequence is increasing and bounded below by 5/6 and above by 13/12.
We have[tex]$a_{2n} = \frac{12n}{6n} + \frac{1}{6n} = \frac{13}{6} \geq \frac{0}{1}$[/tex]and
[tex]$a_{2n+1} = \frac{-12n-6}{6n+3} - \frac{1}{6n+3} = -\frac{13}{12} \geq -\frac{13}{12}.$[/tex] Therefore, the sequence is non-increasing and bounded below by 0 and above by 6.
From above part, we see that the sequence is not monotonic.
We have [tex]$a_{2n} = \frac{12n}{6n} + \frac{1}{6n} = \frac{13}{6} \geq 1$[/tex] and[tex]$a_{2n+1} = \frac{-12n-6}{6n+3} - \frac{1}{6n+3} = -\frac{13}{12} \leq \frac{13}{12}.$[/tex] Therefore, the sequence is decreasing and bounded below by 1 and above by 6.
We have [tex]$a_{2n} = \frac{12n}{6n} + \frac{1}{6n} = \frac{13}{6} \geq 1$[/tex] and [tex]$a_{2n+1} = \frac{-12n-6}{6n+3} - \frac{1}{6n+3} = -\frac{13}{12} \geq \frac{-11}{12}.$[/tex]Therefore, the sequence is not monotonic and bounded below by 1 and above by 11/12.
Therefore, the answer is a_n = 6n + (-1)^n/6n| is increasing; bounded below by 5/6 and above by 13/12. So, the correct option is A).
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verify that the intermediate value theorem applies to the indicated interval and find the value of c guaranteed by the theorem. f(x) = x2 3x 2, [0, 5], f(c) = 20
Answer:
Step-by-step explanation:
To apply the intermediate value theorem, we need to show that the function f(x) = x^2 + 3x + 2 is continuous on the closed interval [0, 5].
Since f(x) is a polynomial function, it is continuous on the entire real line. Therefore, it is also continuous on the closed interval [0, 5].
To find the value of c guaranteed by the theorem, we need to find two values a and b in [0, 5] such that f(a) < 20 < f(b).
We have:
f(0) = 2
f(5) = 60
Since f(x) is an increasing function on [0, 5], we can conclude that for any value of x between 0 and 5, f(x) will lie between f(0) and f(5).
Therefore, there exists a value c in [0, 5] such that f(c) = 20.
We have verified that the intermediate value theorem applies to the given function on the interval [0, 5] and the value of c guaranteed by the theorem is a solution of f(c) = 20.
Find the length of the third side. If necessary, write in simplest radical form.
[tex]\begin{array}{llll} \textit{using the pythagorean theorem} \\\\ a^2+o^2=c^2\implies a=\sqrt{c^2 - o^2} \end{array} \qquad \begin{cases} c=\stackrel{hypotenuse}{10}\\ a=\stackrel{adjacent}{x}\\ o=\stackrel{opposite}{5} \end{cases} \\\\\\ x=\sqrt{ 10^2 - 5^2}\implies x=\sqrt{ 100 - 25 } \implies x=\sqrt{ 75 }\implies x=5\sqrt{3}[/tex]
Put the numbers in each category to which they belong.
1) a rational number is -2/5
2) -14/9 is a rational number
3) 567 is a prime number, a whole number
4) -20/5 is a rational number, an integer
What is a rational number, a whole number, and a prime number?Rational numbers are any numbers that can be expressed as p/q, where p and q are integers and q is not equal to zero. Whole Numbers- Whole numbers are integers ranging from 0 to infinity. Prime numbers are those that have only 1 and themselves as factors.
A rational number is -2/5. It is a fraction with a numerator of -2 and a denominator of 5.
-14/9 is a rational number. It is a fraction with a numerator of -14 and a denominator of 9.
567 is a prime number. It is a whole number as well as an integer. It cannot be stated as a fraction with a denominator other than one, hence it is not a rational number.
-20/5 is a sensible number. It is the same as -4, which is an integer. It is also an even number. Because it is negative, it is not a natural number.
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usign he sepreaion of variavbles echinuqe solve the following differetiablw equation with initial conditions: dy/dx=e^(2x 3y) and y(0)=1 (Hint: Use a property of exponentials to rewrite the differential equation so it can be separated.) The solution is:
The solution to the differential equation dy/dx = e^(2x 3y) with initial condition y(0) = 1 is: y = (1/3) ln|e⁶ˣ - 1| - (1/6)e³
To solve the differential equation dy/dx = e^(2x 3y) using separation of variables, we first need to rewrite it in a separable form. Using the property of exponentials that e^(a+b) = eᵃ × eᵇ, we can rewrite the equation as:
1/y dy = e^(2x) dx × e^(3y)
Now we can separate the variables by integrating both sides:
∫(1/y) dy = ∫(e^(2x) dx × e^(3y))
ln|y| = (1/2)e^(2x) × e^(3y) + C
where C is the constant of integration.
Applying the initial condition y(0) = 1, we can solve for C:
ln|1| = (1/2)e^(2×0) × e^(3*1) + C
0 = (1/2) × e³ + C
C = -1/2 × e³
Substituting C back into the equation, we get:
ln|y| = (1/2)e^(2x) × e^(3y) - 1/2 × e³
Simplifying and solving for y, we get:
y = (1/3) ln|e⁶ˣ - 1| - (1/6)e³
Therefore, the solution to the differential equation dy/dx = e^(2x 3y) with initial condition y(0) = 1 is:
y = (1/3) ln|e⁶ˣ - 1| - (1/6)e³
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Find the volume of the solid enclosed by the parabolic cylinder y = x^2 and the planes z = 3 + y and z = 4y by subtracting two volumes. Volume = integral_a^b integral_c^d dx dx - integral_a^b integral_c^d dy dx where a = b = c = d = Find the volume. Volume =
To find the volume enclosed by the parabolic cylinder and the given planes, we need to subtract the volume under the parabolic cylinder between the two planes from the volume under the upper plane between the same limits.
First, let's find the limits of integration. Since we have symmetry around the z-axis, we can integrate over a quarter of the parabolic cylinder and then multiply by 4 to get the total volume. Since the parabolic cylinder is given by y = x^2, we have:
0 ≤ x ≤ sqrt(y)
0 ≤ y ≤ 4y - (3 + y) (since the upper plane is z = 4y and the lower plane is z = 3 + y)
Simplifying the second inequality, we get:
0 ≤ y ≤ 1
So the limits of integration are:
0 ≤ x ≤ 1
0 ≤ y ≤ x^2
Using the formula for the volume of a solid of revolution, we can express the volume under the parabolic cylinder between the two planes as:
V1 = pi ∫^1_0 (3 + x^2)^2 - x^4 dx
Simplifying the integrand, we get:
V1 = pi ∫^1_0 (9 + 6x^2 + x^4) - x^4 dx
V1 = pi ∫^1_0 (9 + 5x^2) dx
V1 = pi [9x + (5/3)x^3]∣_0^1
V1 = (32/3)pi
Similarly, we can express the volume under the upper plane between the same limits as:
V2 = pi ∫^1_0 (4y)^2 dy
V2 = pi ∫^1_0 16y^2 dy
V2 = (16/3)pi
So the volume enclosed by the parabolic cylinder and the given planes is:
V = 4V2 - 4V1
V = 4[(16/3)pi] - 4[(32/3)pi]
V = -16pi
Therefore, the volume of the solid enclosed by the parabolic cylinder and the given planes is -16pi. Note that the negative sign indicates that the solid is oriented in the opposite direction of the positive z-axis.
180 learners for every 5 teachers how do you simplify this
Answer:
If there's 5 teachers then for that amount of teachers there are 180 learners.
Step-by-step explanation:
If you have a number, example 20 you have to know how many times 5 goes in 20 (4 times). Now you have to do: 4 times 180
PLEASE HELP 30 POINTS SOLVE FOR MISSING SIDE SHOW WORK PLS
Answer:
Step-by-step explanation:
The third side of the triangle may be found using Pythagoras theorem.
Pythagoras theorem is for right angle triangles-
c^2 = a^2 + b^2
‘c’ = the side opposite the triangle’s 90 degree angle. This is called the hypotenuse.
‘a’ and ‘b’ = a and b are just the two remaining sides of the triangle that is NOT the hypotenuse. It does not matter which side you pick out of the two for ‘a’ and which side you pick for ‘b’
The side we are trying to find is the hypotenuse, which is ‘c’
Let’s say that
a= 9m
b= 12m
Substituting that into the
c^2 = a^2 + b^2 formula,
c^2 = 9^2 + 12^2
= 81+ 144
= 225
( square root both sides of the equation so we get just the value of ‘c’)
c= 15m
Therefore the missing side (the right angle triangle’s hypotenuse) is 15m.
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