Answer:
12(x+5)=
12x+60=
12x÷12 & 60÷12
x=5
In January 2008, the temperature in parts of Minnesota fell from 46 (Fahrenheit) to -14(Fahrenheit) over a 24-hour period. What was the average temperature change per hour?
Answer:
the answer is -0.4.
Step-by-step explanation:
brainliest if right maybe?
7ax−7bx−2ay+2by
Factor by grouping
Answer:
(7x−2y)(a−b)
Step-by-step explanation:
To tell the truth I am just guessing from what I know I AM ONLY 13 DON"T EXPAECT TOO MUCH FROM ME!
A study examined the effectiveness of an ear-molding technique used to correct ear deformities in newborns without the need for surgery. A plastic mold was placed around the deformed ear shortly after birth for about two weeks. The study reports that 152 of 158 procedures were successful. We would like to estimate with 95% confidence the true proportion of successful ear-molding procedures among all newborns needing ear-deformity correction. We can use
Answer:
The 95% confidence interval for the true proportion of successful ear-molding procedures among all newborns needing ear-deformity correction is (0.932, 0.992).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.
[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In which
z is the zscore that has a pvalue of [tex]1 - \frac{\alpha}{2}[/tex].
The study reports that 152 of 158 procedures were successful.
This means that [tex]n = 158, \pi = \frac{152}{158} = 0.962[/tex]
95% confidence level
So [tex]\alpha = 0.05[/tex], z is the value of Z that has a pvalue of [tex]1 - \frac{0.05}{2} = 0.975[/tex], so [tex]Z = 1.96[/tex].
The lower limit of this interval is:
[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.962 - 1.96\sqrt{\frac{0.962*0.038}{150}} = 0.932[/tex]
The upper limit of this interval is:
[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.962 + 1.96\sqrt{\frac{0.962*0.038}{150}} = 0.992[/tex]
The 95% confidence interval for the true proportion of successful ear-molding procedures among all newborns needing ear-deformity correction is (0.932, 0.992).
The 95% confidence interval of the true proportion of successful ear-molding procedures among all newborns needing ear-deformity correction is; CI = (0.9322, 0.9918)
We want to find confidence interval and the formula is;
CI = p^ ± z√(p^(1 - p^)/n)
We are told that the study reports that 152 of 158 procedures were successful. Thus;
n = 158
p^ = 152/158
p^ = 0.962
Now, we want to find the confidence interval at a 95% confidence level.
The critical z value for 95% confidence level is;
z = 1.96
Thus;
CI = 0.962 ± 1.96√(0.962(1 - 0.962)/158)
CI = 0.962 ± 0.0298
CI = (0.962 - 0.0298), (0.962 + 0.0298)
CI = (0.9322, 0.9918)
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Question 1 (10 points)
A jar lid has a diameter of 32
millimeters. What is the
circumference of the lid to the
nearest tenth?
Blank 1:
Step-by-step explanation:
C=2πR=πD=3.14*32=100.5 mm
There are 2 hikers, one of them wanders off the trail. How many hikers are left?
PLZ HELP!!!!!
Given N , what is mABC
#4 please help! One question seen in pic
Answer:
B. (x - 2)(x + 2)
Step-by-step explanation:
The answer is b. If you have (x + a)(x - a), the variables will cancel each other out. For example, if we take the answer (x - 2)(x + 2) and factor it out, we get:
x² - 2x + 2x - 4
Then it becomes just:
x² - 4 because the x to the power of one has been canceled. This proves his theory wrong.
Answer:
B
Step-by-step explanation:
I think I think I think I think
Pls help me if u can
Answer:
523.33 cm³
Step-by-step explanation:
Formula of volume of sphere
[tex] = \frac{4}{3} \pi {r}^{3} [/tex]
The volume of the sphere
[tex] = \frac{4}{3} \times 3.14 \times {5}^{3} [/tex]
[tex] = \frac{1570}{3} [/tex]
[tex] = 523.3333333...[/tex]
= 523.33 cm³ (rounded to the nearest hundredth)
Which side lengths form a right triangle?
Answer:
Answer:[tex] \huge\mathfrak\pink{S} \huge\mathfrak\purple{o} \huge\mathfrak\blue{l} \huge\mathfrak\red{u} \huge\mathfrak\green{t} \huge\mathfrak\pink{i}\huge\mathfrak\purple{o}\huge\mathfrak\red{n}\huge\mathfrak\orange{➔}\ [/tex] Pythagoras law:h²=p²+b²
needed to apply
4²+√8²=24²
24≠576
not a right angled triangle
again
5²+√5²=5²
50≠25
side are not a right angled triangle
again
4²+7.5²=(8.5)²
72.25=72.25
side are a right angled triangle
What is the length of the third side of a right triangle if it is known that the two of the sides have lengths 9 and 12. How many solutions does this problem have
Answer:
34 the answer
Step-by-step explanation:
Point A is located at -7 on a number line, and point B is located at 3 on the number line. Point C is the same distance away from point A as point B is from point A, but in the opposite direction. Which is the location of point C on the number line?
options:
-17
-10
-4
-3
Answer:
Dang someone come help him
Step-by-step explanation:
please help me i need to reconcile but it is hard, thank you
Answer:
Step-by-step explanation:
Add the first two columns - third column. See if it equals last column.
Number one is correct, number 2 is off by $1.00,etc
let me know if you are still confused
The length of a rectangle is 4y inches. The with of a rectangle is (y+2) Find the perimeter of the rectangle in terms of y
Answer:
10y+4
Step-by-step explanation:
perimeter=2(l+b)
2(4y+(y+2))
2(4y+y+2)
2(5y+2)
10y+4
Suppose you have 62 feet of fencing to go around a rectangular flower garden. You want
the length to be 9 feet longer than the width, w. What are the dimensions of the flower garden?
Define your variables, write an equation, and solve. (Hint: Draw a rectangle and label all the sides).
What's the width of the rectangle?
And what's the length?
Answer:
Answer is 9 feet = 9 fe 2t
w= 9fe 2t
Step-by-step explanation:
Anyone know this.......
Answer:
a) The basic rate of pay is 6 sterling pounds per hour.
b) The higher rate of pay is 10 sterling pounds per hour.
Step-by-step explanation:
Both segments of the curve are first order polynomials, which means that each have constant slopes.
a) The basic rate of pay is the value of the slope ([tex]r[/tex]), in sterling pounds per hour, of the line for the first 20 hours worked, that is:
[tex]r = \frac{\Delta y}{\Delta x}[/tex] (1)
Where:
[tex]\Delta x[/tex] - Change in hours worked, in hours.
[tex]\Delta y[/tex] - Change in pay, in sterling pounds.
If we know that [tex]\Delta x = 20\,h[/tex] and [tex]\Delta y = \pounds\, 120[/tex], then the basic rate is:
[tex]r = \frac{\Delta y}{\Delta x}[/tex]
[tex]r = \frac{\pounds\,120}{20\,h}[/tex]
[tex]r = 6\,\frac{\pounds}{h}[/tex]
The basic rate of pay is 6 sterling pounds per hour.
b) By using (1), we calculate the higher rate of pay below. If we know that [tex]\Delta x = 10\,h[/tex] and [tex]\Delta y = \pounds \,100[/tex], then the higher rate is:
[tex]r = \frac{\Delta y}{\Delta x}[/tex]
[tex]r = \frac{\pounds\,100}{10\,h}[/tex]
[tex]r = 10\,\frac{\pounds}{h}[/tex]
The higher rate of pay is 10 sterling pounds per hour.
Help please thank you !!
Answer:
AC and AE
Step-by-step explanation:
Those are the only secants in the image shown.
An inspector for a military agency desires a variables sampling plan for use with an AQL of 1.5%, assuming that lots are of size 7,000. If the standard deviation of the lot or process is unknown, derive a sampling plan using Procedure 1 from MIL STD 414.
Answer:
use inspection level 4 ( IV ) to perform a normal inspection or tightened inspection to derive a sampling plan procedure from MIL STD 414
Step-by-step explanation:
Having an AQL of 1.55
assuming lots size of 7000
Std = unknown
To derive a sampling plan
use inspection level 4 ( IV ) where the sample size is denoted as M ( i.e. sample size n = 14) which will reciprocate an acceptable quality level of 1.5%. on a normal inspection the value of K will be = 1.4 but if we employ a tightened inspection the value of K will become 1.54 in value
note that : both the normal and tightened inspection can be performed using the same table
Fill in the missing number 87, 84, 81 —, —-
Answer:
87 , 84, 81, 78, 75
Step-by-step explanation:
it goes down each time by threes
What is the average rate of change from x = −4 to x = 1?
Answer:
What is the average rate of change from x = −4 to x = 1? x= -4 x + 5
What is the median of the data set?
History Test Scores
50 8
65 6 8 9
70 3 5 8
80 6 7 7 7
9 0 1 3 5 6 8 99
50 = 50 points
50
0 87
49
86.5
86
Helppp!!
Answer:
86
Step-by-step explanation:
Median : the middle value of a set of data arranged in numerical order.
To solve: Place number in order from least to greatest then began crossing one off at the beginning of the data set and one at the end. (like your playing the game one for you , and one for me) The median will be the last number left without a match in the middle.
Answer:
The answer is 86 beacause
Step-by-step explanation:
I did the lesson so its correct if you think its wrong then i dont care at all or if u think i stole answer i really dont care
On a standardized exam, the scores are normally distributed with a mean of 200 and
a standard deviation of 50. Find the Z-score of a person who scored 140 on the exam.
Answer:
First, compute the z-score:
z = (x-μ)/σ = (650-500)/100 = 150/100 = 1.5
Now look up the percentile for z = 1.5 on a z-score table (http://www.z-table.com/). The percentile, p(z=1.5), is the percent of people who scored 650 or less. The percent who scored more than 650 is 1-p(z=1.5). Multiply that by the 1200 students to get the number who scored more than 650. Round to the nearest whole number (because you can't have a fraction of a person).
For the given data the value of the z score will be 1.5
What is the standard deviation?It is referred to as a measure of data dispersal since it provides information on how widely the data is dispersed.
[tex]\rm \sigma = \sqrt{\dfrac{ \sum (x_i-X)}{n}[/tex]
σ stands for the standard deviation
x is the value from the data set
X is the data set mean
n is the number of observations
It is given that, On a standardized exam, the scores are normally distributed with a mean of 200 and a standard deviation of 50.
The Z-score of a person who scored 140 on the exam is as,
z = (x-μ)/σ
z = (650-500)/100
z = 150/100
z = 1.5
Thus, the value of the z score will be 1.5
Learn more about the standard deviation here:
brainly.com/question/12402189
#SPJ2
(8 – 10i) – (-16 + 2i)
Answer:
8-10i - -16+2i= 236
Step-by-step explanation:
I am brainliest
Answer:
-16
Step-by-step explanation:
(8-10i) - (-16+2i)
2i - (-14i)
-16
In the Eqaulity -8 ≤ -5. Which number appears farther left on a number line and why?
A -8 appears farther left because -8 is smaller -5
B -5 appears farther left because -5 is larger than -8
C -8 appears farther left because -8 is larger than -5
D -5 appears farther left because -5 is smaller than -8
How many distinguishable permutations are there for the word SCIENCE?
Answer:
Step-by-step explanation:
= 7*6*5*4*3*2*1 = 5040.
Step-by-step explanation:
Step-by-step explanation:
= 7*6*5*4*3*2*1 = 5040.
Triangle UVW has a perimeter of 11.5 units. Solve for y.
Answer:
y = 3.2 units
Step-by-step explanation:
Find the missing angle measure x. Use the fact that all interior angle measures in a triangle add up to 180 degrees.
55 + 50 + x = 180105 + x = 180x = 75We can use the Law of Cosines to determine the missing side length y.
a² = b² + c² - 2bc · cos(A)Let's set UW (y) as a, WV as b, and UV as c. Therefore, ∠V must be A, ∠U must be B, and ∠W must be C.
Use the Law of Cosines to solve for a (side length y).
a² = b² + c² - 2bc · cos(A) a² = (4)² + (3.5)² - 2(4)(3.5) · cos(50) a² = 28.25 - 28cos(50) a² = 28.25 - 17.99805307 a² = 10.25194693 a = 3.20186616366Side length y is equal to 3.2 units.
The smaller cube measures 10 cm on each edge. What is the surface area?
Answer:
10 cm cubed or 10^3cm
Step-by-step explanation:
Answer:
600
Step-by-step explanation:
6 sides x 10 x 10 = 600
this is the surface area
Find the surface area of the prism.
2 in.
2 in.
6 in.
Answer:
56 m^2
Explanation: L=2, H=2, W=2, d = 6.63324958 m, TSA = 56 m^2, LSA = 48 m^2, TSA = 4 m^2, BSA = 4 m^2, V = 24 m^3
Rewrite by completing the square f(x) = x2 - 6x +43
Answer:
f(x) = (x - 3)^2 + 34
Step-by-step explanation:
what is 873 divided by 35?!!
873 divided by 35= 24 33/35
The lengths of a professor's classes has a continuous uniform distribution between 50.0 min and 52.0 min. If one such class is randomly selected, find the probability that the class length is between 50.4 and 51.4 min.
P(50.4 < X < 51.4) =
Answer:
=0.70
Step-by-step explanation:
p(x < 51.4) = (51.4-50.0)/(52.0-50.0)
p(x < 51.4) =1.4/2
=0.70