What is the specific heat of silicon if the temperature of a 4.11 g sample of silicon
is increased by 3.8 °C when 11.1 J of heat is added?

Answers

Answer 1

Answer:

The right solution is "0.7107 J/g°C".

Explanation:

The given values are:

Mass,

m = 4.11 g

Temperature,

ΔT = 3.8°C

Heat,

Q = 11.1 J

The specific heat of silicon will be:

⇒  [tex]C=\frac{Q}{m \Delta T}[/tex]

On substituting the values, we get

⇒      [tex]=\frac{11.1}{4.11\times 3.8}[/tex]

⇒      [tex]=\frac{11.1}{15.618}[/tex]

⇒      [tex]=0.7107 \ J/g^{\circ}C[/tex]


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◕‿↼ Hey There!

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Neon in a piston is compressed to a volume of 14L its original volume was 22 L at 11.2 atm find the new pressure in atm

Answers

I love chem!!! Hopefully I got it right for u I got


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Answers

Answer :D: evaporation

Explanation: cus i am smart

sorry if i am wrong heh

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Answer:

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Answers

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Answers

Answer:

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Explanation:

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To solve this question we must convert the mass of Cr2O3 to grams and then, compute the value in the equation:

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Answers

Answer:

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Explanation:

Conforme indicado no parágrafo -

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Answers

Answer:

Increasing the temperature of a system will increase the rate of a reaction. More particles are moving faster, and have more energy, increasing the overall rate of reaction.

Explanation:

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Answers

Answer:

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Answers

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Answers

Answer:

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Answers

Answer:

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Answers

Answer:

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For I,xe

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Answer:

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You can download[tex]^{}[/tex] the answer here

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Answers

Answer:

6.46g of PbCl2 are produced

Explanation:

The PbCl2 will not react, is a product of the reaction. The question must be say how many grams of PbCl2 will be produced

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Pb(NO3)2(aq)+2KCI(aq) → PbCl2(s)+2KNO2 (aq)

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Moles PbCl2:

0.04646 moles KCl * (1mol PbCl2 / 2mol KCl) =

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hi so can help me with something

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Answers

Answer:

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Explanation:

take your notes man

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