x + (-13) = -5
x - 13 = -5
x = -5 + 13
x = 8
Can someone please help me with these 2 problems
Answer:
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Answer:
I believe the first one is 250
the second one I haven't got a clue
A roof has a cross section that is a right triangle. The diagram shows the approximate dimensions of this cross section. Find the height h of the roof. Round your answer to the nearest tenth.
Answer:
5
Step-by-step explanation:
Area of right angle Triangle:
6.5 * 9 * 1/2 = 29.25
2nd way to find area:
1/2 * base * height
Since we have area and base:
1/2 * 11.1 * h = 29.25
= 5.27m
= 5m (nearest tenth)
The height h of the roof to the nearest tenth is 5.3 m
Right angle triangle:Right angle triangle has one of its angles as 90 degrees. The triangles are likewise similar and can be used to find the height h of the roof.
Therefore,
11.1 / 6.5 = 9 / hcross multiply
11.1 h = 9 × 6.5
11.1 h = 58.5
divide both sides by 11.1
11.1 h / 11.1 = 58.5 / 11.1
h = 5.27027027027
h = 5.3 m
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I will give brainiest to the person who answers this
Find the length of arc AB. Use 3.14 for 7.
Round to the nearest tenth.
h 7.9 cm
B
66 49
D
[? ]cm
Answer:
12.4
Step-by-step explanation:
[tex]AL= 2r\pi (\frac{angle}{360} )[/tex]
[tex]AL= 2(7.9)(\pi )(\frac{90}{360})\\[/tex]
y∝1√x
If
y=7 when x=64
find,
x when y=8
Answer:
uhm im really sorry about this but i really need points i would help but id get it wrong im bad aat math
Step-by-step explanation:
what is the value of p in 24 = 2p
Declan's goal is to score 90% on the upcoming science test. If there are 50 questions on the test, how many does he need to answer correctly?
Answer:
45
Step-by-step explanation:
find the area under the standard normal curve to the right of z=−2.28 z = − 2.28 .
1.1.
A quadratic pattern has a second term equal to 1, a third term equal to -6 and a fifth term equal to
- 14.
1.1.1. Calculate the second difference of this quadratic pattern.
(5)
The second difference of this quadratic pattern is 2.
The first term of this quadratic pattern is 10.
Quadratic patternA sequence of numbers has a quadratic pattern when its sequence of second differences is constant. Therefore,
let the first and fourth term be a and b.
Therefore,
first difference:
1 - a; - 6 - 1 = -7; b + 6; -14 - b;
Second difference:
The second difference is constant . Therefore,
-7 - (1 - a) = -8 + a; b + 6 + 7 = b + 13; -14 - b - b - 6 = -2b - 20;
Therefore,
b + 13 = -8 + a
b - a = -21
Then,
-2b - 20 = b + 13
-3b = 33
b = 33 / -3
b = - 11
Therefore,
- 11 - a = - 21
-a = -21 + 11
-a = -10
a = 10
Hence, the second difference = b + 13 = -11 + 13 = 2
First term = a
Therefore,
a = 10
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(15x-7)-(23x-2)
use foil
Answer:
=15x-7-23+2
=-8x-7+2
=-8x-5
Step-by-step explanation:
Which of the following relations is a function?
OA. (-8,0), (-2,5), (-8, -3), (1,9)
OB. (-8, 2), (-2,3), (1, 7), (7,2)
OC. (-2,-2).(-8,-5), (1,8), (1, 2)
OD. (7,-10), (-8, 7), (7,6), (-8, 12)
A snack is 5 parts peanuts and 2 parts raisins. How many pounds of peanuts should be mixed with one-half pound raisins
Which set of sides will make a triangle? 1 cm, 3 cm, Icm 10 cm, 5 cm, 9 cm 5 cm, 2 cm, 3 cm 10 cm, 3 cm, 4 cm
Answer:
5cm, 9cm, 10cm
Step-by-step explanation:
What number is 73 1/4th of
Step-by-step explanation:
70x4=280
12x4=48
48+280=328
k+12=23
plsssss help
if tan theta =3, find the value of tan theta + tan (theta+pi) + tan (theta +2pi)
Answer:
[tex]tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9[/tex]
Step-by-step explanation:
Given
[tex]tan\theta = 3[/tex]
Required
Find
[tex]tan\theta + tan(\theta + \pi) + tan(\theta+2\pi)[/tex]
Calculate [tex]tan(\theta + \pi) \ and\ tan(\theta+2\pi)[/tex]
Using tan rule
[tex]tan(\theta + \pi) = \frac{tan\theta + tan\pi}{1 - tan\theta tan\pi}[/tex]
So:
[tex]tan(\theta + \pi) = \frac{tan\theta + 0}{1 - tan\theta *0}[/tex]
[tex]tan(\theta + \pi) = \frac{tan\theta}{1 }[/tex]
[tex]tan(\theta + \pi) = \tan\theta[/tex]
[tex]tan(\theta+2\pi)[/tex]
[tex]tan(\theta + 2\pi) = \frac{tan\theta + tan2\pi}{1 - tan\theta tan2\pi}[/tex]
[tex]tan(\theta + 2\pi) = \frac{tan\theta + 0}{1 - tan\theta *0}[/tex]
[tex]tan(\theta + 2\pi) = \tan\theta[/tex]'
'So:
[tex]tan\theta + tan(\theta + \pi) + tan(\theta+2\pi)[/tex] [tex]= tan\theta +tan\theta +tan\theta[/tex]
[tex]tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 3+3+3[/tex]
[tex]tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9[/tex]
find the difference between 1, 407 and 699
Answer:708
Step-by-step explanation:
Suppose the probability that it will rain tomorrow is 0.59. What is the probability that it will not rain tomorrow?
Answer:
0.41
Step-by-step explanation:
All probability equals 1. So if the probability that something will happen is x, then the probability that it will not happen is 1-x
A manufacturing company produces 3 different products A, B, and C. Three types of components, i.e., X, Y, and Z, are used in the production of these products. One unit of product A requires 2 units of X, 2 units of Y, and 2 units of Z. One unit of product B requires 1 unit of X, 3 units of Y, and 2 units of Z. One unit of product C requires 1 unit of X, 2 units of Y, and 3 units of Z.Currently, the company has no existing inventory of the components. The company can purchase X at the price of $20 per unit but no more than 300 units due to the supplier's limited capacity constraint. The company can purchase Y at the price of $30 per unit without any upper limit. The company can purchase Z at the full price of $25 per unit for the first 100 units but the per unit price drops to $20 for the remaining units if any i.e., the purchase quantity in excess of 100 units). The market prices of the three products are $200 for A, $240 for B and $220 for C. The company knows that the demand for products A, B, and Care equal to 100, 80, and 90 units, respectively. Therefore, the company should not produce more than the demand for each product. However, the company incurs a per unit penalty of $40 for any unsatisfied demand. The company needs to decide the component płarchase plan and the production mix decisions to maximize its profits subject to all the business constraints described above. Formulate the company's problem as an optimization problem, i.e., providing the mathematical expressions for the decision variables, the objective function, and the constraints.
Answer:
Step-by-step explanation:
Using the Excel Formula:
Decision Variable Constraint Constraint
A 65 65 100
B 80 80 80
C 90 90 90
14100 300 300
= (150 *B3)+(80*B4) +(65*B5)-(100-B3+80-B4+90-B5)*90
Now, we have:
Suppose A, B, C represent the number of units for production A, B, C which is being manufactured
A B C Unit price
Need of X 2 1 1 $20
Need of Y 2 3 2 $30
Need of Z 2 2 3 $25
Price of
manufac - $200 $240 $220
turing
Now, for manufacturing one unit of A, we require 2 units of X, 2 units of Y, 2 units of Z are required.
Thus, the cost or unit of manufacturing of A is:
$20 (2) + $30(2) + $25(2)
$(40 + 60 + 50)
= $150
Also, the market price of A = $200
So, profit = $200 - $150 = $50/ unit of A
Again;
For manufacturing one unit of B, we require 1 unit of X, 3 units of Y, and 2 units of Z are needed and they are purchased at $20, $30, and 425 each.
So, total cost of manufacturing a unit of B is:
= $20(1) + $30(3) + $25(2)
= $(20 + 90+50)
= $160
And the market price of B = $240
Thus, profit = $240- $160
profit = $80
For manufacturing one unit of C, we have to use 1 unit of X, 2 unit of Y, 3 units of Z are required:
SO, the total cost of manufacturing a unit of C is:
= $20 (1) + $30(2) + $25(3)
= $20 + $60 + $25
= $155
This, the profit = $220 - $155 = $65
However; In manufacturing A units of product A, B unit of product B & C units of product C.
Profit --> 50A + 80B + 65C
This should be provided there is no penalty for under supply of there is under supply penalty for A, B, C is $40
The current demand is:
100 - A
80 - B
90 - C respectively
So, the total penalty
[tex]{(100 - A) + (80 - B) +(90 - C) } + \$40[/tex]
This should be subtracted from profit.
So, we have to maximize the profit
[tex]Z = 50A + 80B + 65C = {(100 -A) + (80 - B) + (90 - C)};[/tex]
Subject to constraints;
we have the total units of X purchased can only be less than or equal to 300 due to supplies capacity
Then;
[tex]2A + B +C \le 300[/tex] due to 2A, B, C units of X are used in manufacturing A, B, C units of products A, B, C respectively.
Next; demand for A, B, C will not exceed 100, 80, 90 units.
Hence;
[tex]A \le 100[/tex]
[tex]B \le 80[/tex]
[tex]C \le 90[/tex]
and [tex]A, B, C \ge 0[/tex] because they are positive quantities
The objective is:
[tex]\mathbf{Z = 50A + 80B + 65 C - (100 - A + 80 - B + 90 - C) * 40}[/tex]
A, B, C [tex]\to[/tex] Decision Varaibles;
Constraint are:
[tex]A \le 100 \\ \\ B \le 100 \\ \\ C \le 90 \\ \\2A + B + C \le 300 \\ \\ A,B,C \ge 0[/tex]
help with math please will give 5 stars and brainlyist
write 11.3826 to the nearest thousand
Answer:
11.383
Step-by-step explanation:
the third place is the thousandths.
By rounding 11.3826 to the nearest thousand, we get 11.383.
What is the method of rounding a number?The number you are rounding is followed by 5, 6, 7, 8, or 9, round the number up.
Example: 0.2358 rounded to the nearest thousand is 0.236.
If the number you are rounding is followed by 0, 1, 2, 3, or 4, round the number down.
Example: 0.7231 rounded to the nearest thousand is 0.723.
Given number is 11.3826.
Rounding to nearest thousand, we get:
11.3826 ⇒ 11.383.
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#SPJ2
Please help me on this answer I am 1 week behind
lisa spent $21 on diapers. if they cost $7 package, how many packages did she buy
Answer:
3 packages
Step-by-step explanation:
first we need to make this into a equation that we can solve!
x = 21/7
if we use our times tables then we know that
7 * 3
= 21
so knowing what we know, lets go back to the question/ equation!
21/7
= 3
( if you wanted, that could also be a way to double check you answer :)
hope this helped you and if you have any more questions then please ask me! :)
What is the sum?
8+(-12)
-20
-4
4
20
Answer:
-4
Step-by-step explanation:
Suppose that the distribution of IQ's of North Catalina State University's students can be approximated by a normal model with mean 130 and standard deviation 8 points. Also suppose that the distribution of IQ's of Chapel Mountain University's students can be approximated by a normal model with mean 120 and standard deviation 10 points.
Required:
What is the probability that the mean IQ of the 3 North Catalina students is at least 5 points higher than the mean IQ of the 3 Chapel Mountain students?
Answer:
0.7517 = 75.17% probability that the mean IQ of the 3 North Catalina students is at least 5 points higher than the mean IQ of the 3 Chapel Mountain students
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Subtraction of normal variables:
When we subtract normal variables, the mean is the subtraction of the means, while the standard deviation is the square root of the sum of the variances.
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
North Catalina:
Population has mean 130 and standard deviation 8 points. Sample of 3. This means that:
[tex]\mu_{N} = 130, s_{N} = \frac{8}{\sqrt{3}} = 4.6188[/tex]
Chapel Mountain:
Population has mean 120 and standard deviation 10 points. Sample of 3. This means that:
[tex]\mu_{C} = 120, s_{C} = \frac{10}{\sqrt{3}} = 5.7735[/tex]
What is the probability that the mean IQ of the 3 North Catalina students is at least 5 points higher than the mean IQ of the 3 Chapel Mountain students?
We want that: [tex]N - C > 5[/tex]
Distribution N - C:
The mean is:
[tex]\mu = \mu_N - \mu_C = 130 - 120 = 10[/tex]
The standard deviation is:
[tex]s = \sqrt{s_N^2+s_C^2} = \sqrt{4.6188^2+5.7735^2} = 7.3937[/tex]
This probability is 1 subtracted by the pvalue of Z when X = 5. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{5 - 10}{7.3937}[/tex]
[tex]Z = -0.68[/tex]
[tex]Z = -0.68[/tex] has a pvalue of 0.2483
1 - 0.2483 = 0.7517
0.7517 = 75.17% probability that the mean IQ of the 3 North Catalina students is at least 5 points higher than the mean IQ of the 3 Chapel Mountain students
For the function f(x) = 5x + 4
Find f(6)
Answer:
f(6) =34
Step-by-step explanation:
f(x) = 5x + 4
Let x= 6
f(6) = 5*6 +4
= 30 +4
= 34
If I save 500$ per month, for 12 years how much money will I have ?
Answer:
I think its 72,000
Step-by-step explanation:
there's 144 months in 12 years and i just multiplied it by 500
URGENT I NEED HELP FIRST PERSON WHO ANSWERS I'LL GIVE BRAINLYEST
A cylindrical vase has a diameter of 6 inches. At the bottom of the vase, there are 9 marbles, each of diameter 3 inches. The vase is filled with water up to a height of 12 inches.
Which of the following could be used to calculate the volume of water in the vase?
π(3in)2(12in) − 1.5(four over threeπ(9in)3)
π(12in)2(3in) − 1.5(four over threeπ(9in)3)
π(3in)2(12in) − 9(four over threeπ(1.5in)3)
π(12in)2(3in) − 9(four over threeπ(1.5in)3)
Answer:
C. π(3in)2(12in) − 9(four over threeπ(1.5in)3)Step-by-step explanation:
Volume of water is the difference of volume of vase at 12 in height and the total volume of marbles.
Volume of cylinder up to water level:
Vs = πr²h = π(6/2)²(12) = π×(3 in)²×(12 in)Volume of marbles:
Vm = 9(4/3πr³) = 9×(4/3×π(3/2)³) = 9×(4/3×π×(1.5 in)³)Volume of water:
Vw = Vs - Vm = π×(3 in)²×(12 in) - 9×(4/3×π×(1.5 in)³)Correct choice is C
Answer:
C. π(3in)2(12in) − 9(four over threeπ(1.5in)3)
Step-by-step explanation:
Volume of water is the difference of volume of vase at 12 in height and the total volume of marbles.
Volume of cylinder up to water level:
Vs = πr²h = π(6/2)²(12) = π×(3 in)²×(12 in)
Volume of marbles:
Vm = 9(4/3πr³) = 9×(4/3×π(3/2)³) = 9×(4/3×π×(1.5 in)³)
Volume of water:
Vw = Vs - Vm = π×(3 in)²×(12 in) - 9×(4/3×π×(1.5 in)³)
Correct choice is C
PLS HELP ME!!! i’ll give you a brainliest answer :)
Answer:
B is the correct answer
The graph shows different types of books in a class library.
Books In Our Library
Number of Books
ou to use
45
40
35
30
25
10
Animal
History Science Sports Weather
Type of Books
How many more animal books are there than history and sports books?
O A 15
Ов. 25
O c. 35
D. 45
E. 50
Answer:
Step-by-step explanation:
Its c
The perimeter of a rectangular painting is 340cm. If the width of the painting is 74cm, what is its length?
Answer:
96
Step-by-step explanation:
Answer:
96 cm
Step-by-step explanation:
Length + Width + Length + Width = Perimeter
Length + 74 cm + Length + 74 cm = 340 cm
74 + 74 = 148
340 - 148 = 192
192 ÷ 2
96
Check:
74cm + 96cm + 74cm + 96cm = 340 cm