What is the slope of a line perpendicular to the line whose equation is
2x – 2y = 36. Fully reduce your answer.
Answer:
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attempt 1 out of 2

Answer:

y=80-8x

Step-by-step explanation:

Bc the 80 is what it started at and the x represents the hour

(In y=mx+b form)

Answer:

it will be on platform 9 3/4

Step-by-step explanation:

Answer:

Never

Step-by-step explanation:

Their slope is the same so they will go down the same distance every time, and since the first one touches the y-intercept at 1 and the other one touches the y-intercept at -2, it is completely impossible for them to ever intersect

Answer:

what are the measurements of the semi circle

Step-by-step explanation:

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[tex]y = {x}^{2} - x - 20[/tex]

[tex]y = (x - 5)(x + 4)[/tex]

To find the zeroes , Just need to put 0 instead of y .

[tex]0 = (x - 5)(x + 4)[/tex]

[tex](x - 5)(x + 4) = 0[/tex]

_________________________________

Hint :

[tex]a \times b = 0[/tex]

[tex]a = 0 \: \: \: or \: \: \: b = 0[/tex]

_________________________________

[tex]x - 5 = 0[/tex]

Add sides 5

[tex]x - 5 + 5 = 0 + 5[/tex]

[tex]x = 5[/tex]

Or

[tex]x + 4 = 0[/tex]

Subtract sides 4

[tex]x + 4 - 4 = 0 - 4[/tex]

[tex]x = - 4[/tex]

Thus the zeroes are :

( - 4 , 0 ) and ( 5 , 0 ) .

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Answer:

How you find the area of a triangle is by, multiplying  two of the sides together  then multiplying that by 1/2 or .5 . To find the perimeter of the triangle add all the three sides together!

Step-by-step explanation:

Answer:

45 ways

Step-by-step explanation:

Combination method is appropriate for this question since it deals with arrangement.

i.e [tex]^{n}C_{r}[/tex] = [tex]\frac{n!}{(n - r)!r!}[/tex]

Since 8 records are to be selected from 10 available records. Then, the number of ways for the arrangement of the records can be determined as;

Let n = 10 and r = 8

[tex]^{10}C_{8} }[/tex] = [tex]\frac{10!}{(10 - 8)!8!}[/tex]

       = [tex]\frac{10!}{2!8!}[/tex]

       = [tex]\frac{10*9*8*7*6*5*4*3*2!}{2!8*7*6*5*4*3*2!}[/tex]

       = [tex]\frac{10*9}{2}[/tex]

       = 45

Therefore, the number of ways by which the records can be arranged is 45.

Answer:

3 medium and 2 large pizzas.

Step-by-step explanation:

70= 2.5+(12.50x+15y)

70-2.5=67.5

Possibilities

67.5=12.5(1)+15(4) FALSE(72.5)

67.5=12.5(4)+15(1) FALSE (65)

67.5=12.5(2)+15(3)FALSE(52.5)

67.5=12.5(3)+15(2)

TRUE (67.5)

Answer:

x - 5y = - 10

Step-by-step explanation:

y = mx + b (b is y-intercept)

m = [tex]\frac{y_{2} -y_{1} }{x_{2} -x_{1} }[/tex]

~~~~~~~~~~~~

x + 4y = 8 ⇔ y = [tex]-\frac{1}{4}[/tex] x + 2 ⇒ y-intercept is 2 and coordinates of y-intercept are (0, 2)

(5, 3)

m = [tex]\frac{3-2}{5-0}[/tex] = [tex]\frac{1}{5}[/tex]

y = [tex]\frac{1}{5}[/tex] x + 2 (slope-intercept form)

x - 5y = - 10 (standard form)

Answer:

55

Step-by-step explanation:

FCA equals 180 degrees so you subtract 180 from 125 and get 55 degrees.

Answer:

55

Step-by-step explanation:

Just subtract 180 and 125

You said that m∠DCF = 125° right?

And the m∠DCF and m∠DCA are linear pair because they have angles that share a side, so supplementary angles = 180

m∠DCF + m∠DCA = 180

replace (since m∠DCF = 125):

125 + m∠DCA = 180

-125                           -125

m∠DCA = 180 - 125

m∠DCA = 55

Answer:

It dosent say at this rate so all you need is this

Minutes/ questions which your answer is

75/30

Answer:

168

Step-by-step explanation:

photos are enlarged by a certain factor, divide the new width by the old width and youll get the factor (12).

You can then multiply the original height by 12 to get the answer

12 X 14 =168

Answer:

D: 168.

Step-by-step explanation:

Divide the new width by the old width to find the scale factor of 12. Then multiply 12 by the old length of 14 to get 168 the new length.

Answer:

The rate of solution change is 2/3 teaspoons per minute

Step-by-step explanation:

Here, we want to calculate rate

From what we have in the question,

68 teaspoons of solution dropped out entirely within 102 minutes

So the rate is takes to drop out per minute will be:

68/102 = 2/3 teaspoon per minute

Answer:

10

Step-by-step explanation:

The factors of 50 are: 1, 2, 5, 10, 25, 50

The factors of 80 are: 1, 2, 4, 5, 8, 10, 16, 20, 40, 80

The factors of 260 are: 1, 2, 4, 5, 10, 13, 20, 26, 52, 65, 130, 260

In all of these numbers, we can see that 10 is common throughout and 10 is also the greatest factor all these numbers share.

Hope this helps you :)

Answer:

144

Step-by-step explanation:

It should be. I don't really know if there are answer choices or not.

Answer:

Each equal part is called one-fourth or a quarter of the whole sheet. Thus, any whole can be divided into four equal parts and each part is one-fourth or a quarter of the whole. It is expressed as 1/4 and read as one over four or one upon four.

Step-by-step explanation:

Answer:

d)Divide both sides of the equation by 5.

Step-by-step explanation:

Marshall is writing an equivalent equation to solve for x. What should be his next step?

5x+4y=8

5x+4y-4y=8-4y

5x=8-4y

a)Add 5x to both sides of the equation.

b)Subtract 5x from both sides of the equation.

c)Multiply both sides of the equation by 5.

d)Divide both sides of the equation by 5.

5x + 4y = 8

Subtract 4y from both sides

5x + 4y - 4y = 8 - 4y

5x = 8- 4y

Divide both sides by 5

5x / 5 = (8 - 4y) / 5

x = (8 - 4y) / 5

Marshall's next step should be to divide both sides of the equation by 5

Answer: D)Divide both sides of the equation by 5.

Step-by-step explanation:

got it right edge 2021

Answer:

7000degrees/sec

Step-by-step explanation:

The question is not properly structured. Here is the correct question.

A pitcher's arm rotates at a speed of 7 degrees per millisecond (degrees/ms) . At what speed does the pitcher's arm rotate in degrees/s?

Before we proceed, you must know that we will be applying the following conversion;

1 milliseconds = 10⁻³secs

Given

Speed of pitcher's arm in degree per milliseconds = 7deg/ms

Required

We are to express in degree/sec

Using the conversion formula above;

[tex]7deg/ms = \dfrac{7^0}{1millisecs} \\\\converting \ to \ deg/s\\7deg/ms = \dfrac{7^0}{1millisecs} \times \dfrac{1}{10^{-3}s}\\7deg/ms = \dfrac{7^0}{10^{-3}s}\\[/tex]

[tex]7deg/ms = 7^0 \times 1/0.001s\\7deg/ms = 7^0 \times 1000/s\\7deg/ms = 7000^0/sec\\[/tex]

Hence the value in degree/sec is 7000degrees/sec

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[tex]3 {x}^{2} + 9 {x}^{2} - 9x + 9 = [/tex]

[tex](3 + 9) {x}^{2} - 9x + 9 = [/tex]

[tex]12 {x}^{2} - 9x + 9 = [/tex]

[tex]3(4 {x}^{2} - 3x + 3) [/tex]

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Answer:

y= (-1/2)x+(5/2)

Step-by-step explanation:

equation point slope

(y-y1)=m(x-x1)

y-3 = -1/2(x+1) add -3 to both sides and distribute

y=( -x/2) +(-1/2)+3 rewrite 3 as 6/2

y=(-1/2)x +(-1+6/2) solve

y= (-1/2)x+(5/2)

Answer:

31/40

Step-by-step explanation:

Given that:

Fraction of the trail walked intulally = 9/10

Fraction of the trail walked back = 1/8 before stopping to rest

His current distance from the beginning :

Distance walked initially - distance walked back

9/10 - 1/8

The L. C. M of 10 and 8 = 80

Hence,

9/10 - 1/8

= (72 - 10) / 80

= 62 / 80

= 31 / 40

Hence, his rest point or position is 31/40 from the beginning of the trail

Answer:

Step-by-step explanation:

The last step should be: using distributive property by taking out of parentheses the common factor √5

4√5 + 9√5 = √5(4 + 9) = 13√5

The error is made at the last step

it should be 13√5 instead of 13√10.

Answer:

I don't know if I'm doing this 100% correctly but I would put:

four plus nine's total multiplied by 3

Answer: 8 hours

Step-by-step explanation: You would first multiply 2 hours by 4 mph, and get 8 miles. You would then subtract 8 miles from 26 miles, and have 18 miles left. You would now divide 18 miles by 3, as he is now traveling 3 miles per hour and needs to travel 18 miles. You would get 6 hours. You would now add 6 hours by the 2 hours initially traveled at 4 mph, and get 8 hours.

Answer: A) 175%

B) 260%

C) 171.43%

Step-by-step explanation:

Answer:

1.4/3

2.13/5

3.12/7

Step-by-step explanation:

Answer:

yes

Step-by-step explanation:

The function f(x) = x/4 represents a proportional relationship.

Proportional relationships are relationships between two variables where their ratios are equivalent.  A straight line represents a proportional relationship. Mathematically -

y = mx + b

(y - b)/x = m       [m is constant]

or

y = mx

m = y/x               [m is constant]

Given is the following function -

y = x/4

We have -

f(x) = x/4

Now, we know a straight line represents a proportional relationship. The general form of equation representing the proportional relationship is -

y = mx

where -  [m] is constant

y = x/4

y = (1/4)x

On comparing, we get -

m = 1/4

Hence, the function f(x) = x/4 represents a proportional relationship.

Therefore, the function f(x) = x/4 represents a proportional relationship.

To solve more questions on proportional relationship, visit the link below-

brainly.com/question/19306970

#SPJ2

Answer:

7. 2b and b are like terms, [tex]b^{6}[/tex] and 3[tex]b^{6}[/tex] are like terms

8. 6 and 7 are like terms, 2n and [tex]\frac{n}{4}[/tex] are like terms

9. m and 2m are like terms, 3³ and 2 are like terms

10. 6³ and 6² are like terms, y³ and 5y³ are like terms

Step-by-step explanation:

Let us solve from No. 7 to No. 10

#7

∵ The terms are 2b, [tex]b^{6}[/tex], b, [tex]x^{4}[/tex], 3[tex]b^{6}[/tex], 2x²

∵ 2b and b have the same variable and the same power

∴ 2b and b are like terms

∵ [tex]b^{6}[/tex] and 3[tex]b^{6}[/tex] have same variable b and same power 6

∴ [tex]b^{6}[/tex] and 3[tex]b^{6}[/tex] are like terms

#8

∵ The terms are 6, 2n, 3n², 6m², [tex]\frac{n}{4}[/tex], 7

∵ 6 and 7 are numerical rational terms

∴ 6 and 7 are like terms

∵ 2n and [tex]\frac{n}{4}[/tex] have the same variable and the same power

∴ 2n and [tex]\frac{n}{4}[/tex] are like terms

#9

∵ The terms are 10k², m, 3³, [tex]\frac{p}{6}[/tex], 2m, 2

∵ m and 3m have the same variable and the same power

∴ m and 2m are like terms

∵ 3³ and 2 are numerical rational terms

∴ 3³ and 2 are like terms

#10

∵ The terms are 6³, y³, 3y², 6², y, 5y³

∵ 6³ and 6² are numerical rational terms

∴ 6³ and 6² are like terms

∵ y³ and 5y³ have the same variable and the same power

∴ y³ and 5y³ are like terms