What is the probability that out of 125 babies born, at least 70 will be girls?
Assume that boys and girls are equally probable, and round your answer to
the nearest tenth of a percent.
O A. 70.4%
B. 10.5%
C. 51.2%
D. 99.0%

Answer:

Correct.

Step-by-step explanation:

It looks good to me.

Good job!

Answer:

b. x=4 and y= 2

...........

Answer:

The standard deviation is of 7.22 people.

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they have the mutation, or they do not. The probability of a person having the mutation is independent of any other person, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

Probability of exactly x successes on n repeated trials, with p probability.

The expected value of the binomial distribution is:

[tex]E(X) = np[/tex]

The standard deviation of the binomial distribution is:

[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]

About 7% of the population has a particular genetic mutation.

This means that [tex]p = 0.07[/tex]

800 people are randomly selected.

This means that [tex]n = 800[/tex]

Find the standard deviation for the number of people with the genetic mutation in such groups of 800.

[tex]\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{800*0.07*0.93} = 7.22[/tex]

The standard deviation is of 7.22 people.

Answer:

I got :

Step-by-step explanation:

see attached photo

Step-by-step explanation:

The angle of an equilateral triangle is 180°, and its three internal angles are equal, all being 60°.

Answer:

The exponential probability should be 33%.

Step-by-step explanation:

[tex]4 \div 12 = .33 \\ [/tex]

[tex].33 \times 100 = 33\%[/tex]

The experimental probability of rolling a multiple of 3 will be 33%.

Its basic premise is that something will almost certainly happen. The percentage of favorable events to the total number of occurrences.

A pair of dice was rolled many times and the results appear below. Based upon these results.

Outcome      2     3     4     5     6     7     8     9     10     11     12

Frequency    3    6     8     11     14   16    15    12     9      5      1

Then the experimental probability of rolling a multiple of 3 will be

Favorable events = 6 + 14 + 12 + 1 = 33

Total events = 100

Then the probability will be

P = (33 / 100) x 100

P = 0.33 x 100

P = 33%

More about the probability link is given below.

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Answer:

Parallel means that the lines never intersect. If the equation of the new line is y=ax+b , then the system

y=ax+b

y=2x+5

needs to have no solutions. Subtracting the equations gives us

(a−2)x+(b−5)=0

In order for this to ever be 0 we need either a≠2 or b=5 , so to stop this from happening, we will require both a=2 and b≠5 .

Since our line now has the form y=2x+b , and (4,5) is on the line, then the equation

5=2⋅4+b

should be true. Since this implies that b=−3 , we have that the parallel line going through (4,5) has equation

y=2x−3

What is an equation of a line that goes through point (4,-5) and is parallel to y=2x+8?

Which line is parallel to the line y = 2x -4?

What is an equation for a line parallel to y = 5 x -5 and passing through the point (4,19)?

What is an equation for the line that is parallel to y= -4x

Answer:

[tex]SA(x) = x^2 + \frac{12}{x}[/tex]

Step-by-step explanation:

Given

[tex]V = 3m^3[/tex] --- volume

[tex]x \to base\ length[/tex]

[tex]y \to height[/tex]

Required

The surface area as a function of base length

The volume (V) is calculated as:

[tex]V = Base\ Area * Height[/tex]

[tex]V = x*x*y[/tex]

[tex]V = x^2*y[/tex]

Make y the subject

[tex]y = \frac{V}{x^2}[/tex]

Substitute 3 for V

[tex]y = \frac{3}{x^2}[/tex]

The surface area of the open box is:

[tex]SA = x^2 + 2xy+2xy[/tex]

[tex]SA = x^2 + 4xy[/tex]

Substitute: [tex]y = \frac{3}{x^2}[/tex]

[tex]SA = x^2 + 4x*\frac{3}{x^2}[/tex]

[tex]SA = x^2 + 4*\frac{3}{x}[/tex]

[tex]SA = x^2 + \frac{12}{x}[/tex]

Hence, the function is:

[tex]SA(x) = x^2 + \frac{12}{x}[/tex]

Answer:

20 feet

Step-by-step explanation:

Volume = length x width x height

1200 = 10 x 6 x h

1200 = 60h

h = 1200/60

height = 20

The rectangular bin is 20 feet deep.

A cuboid is a three-dimensional shape in which all sides are rectangles. A cuboid has 6 faces, 8 vertices, and 12 edges. All the angles formed at the vertices of a cuboid are right angles. The opposite edges are parallel to each other.

For the given situation,

A rectangular bin is in the shape of a cuboid.

Volume of the rectangular bin,V = 1200 cubic feet

Length of the rectangular bin,l = 10 feet

Width of the rectangular bin,w = 6 feet

Let the height of the rectangular bin be h.

The formula of volume of cuboid is

[tex]V=lwh[/tex]

Now substitute the above values,

⇒ [tex]1200=(10)(6)h[/tex]

⇒ [tex]h=\frac{1200}{60}[/tex]

⇒ [tex]h=20[/tex]

Hence we can conclude that the rectangular bin is 20 feet deep.

Learn more about cuboid here

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Answer:

I would tell you but you do not have a picture

Answer:

16.8 [tex]m^{3}[/tex]

Step-by-step explanation:

Find your answer by using the formula of a cone (v= [tex]\frac{1}{3}[/tex]π[tex]r^{2}[/tex]h)

r= 2 (half of your diameter, which is 4)

h= 4

By inserting your radius and height, you get v= [tex]\frac{1}{3}[/tex]π([tex]2^{2}[/tex])4.

Put that into a calculator and you get 16.75516, which rounds to 16.8.

Answer:

(32 ÷4) +8

Step-by-step explanation:

More than means it comes after

quotient of 32 and 4

32÷ 4

8 more than

(32 ÷4) +8

Step-by-step explanation:

x = 180-106 = 74°

y = x/2 = 74/2 = 37°

4z+6 =106

4z = 100

z = 25°

Answer:

4. The range of the function is all

real numbers less than or equal to 9.

Answer:

Half of the trees are not fruit trees

Answer:

It means that half of the trees are fruits while the other half sprouts vegetables.

Step-by-step explanation:

100% (trees) / 2 (types of trees, in this case, fruits and vegetables) = 50% (fruit trees) : 50% (vegetable trees)

Answer:   0.8

Step-by-step explanation:

Answer:

y=-2x-10

Step-by-step explanation:

Let us start with a general slope-intercept equation, y=mx+b, where m represents the slope, b represents the y-intercept, and the y and x represents the coordinates the line passes through.

Therefore, the slope of our line

[tex]y=\frac{1}{2}x-5[/tex]

is 0.5

We also know that the perpendicular slope is simply the negative reciprocal of the current slope. We know have:

[tex]-\frac{2}{1} =\\-2[/tex]

Now, let us find the y intercept. We can plug in the x and y values using the given coordinate (–6,2).

[tex]y=-2x+b\\2=-2*(-6)+b\\2=12+b\\b=-10[/tex]

Now, we can write our equation:

[tex]y=-2x-10[/tex]

I hope this helps! Let me know if you have any questions :)

9514 1404 393

Answer:

  g(x) = |x -7|

Step-by-step explanation:

The form given for your answer has parameters 'a', 'h', and 'k'. The parameter 'a' is the vertical scale factor. Since g(x) is a translation only, that factor is 1. The parameters (h, k) identify the translation (right, up). The translation is 7 units right and 0 units up, so (h, k) = (7, 0).

Filling in these values of the parameters, your g(x) is ...

  g(x) = |x -7|

Answer:

below

Step-by-step explanation:

perimeter of a semicircle

½*2πr

=πr

=3.142*3

=9.42 ft

Answer:

A

Step-by-step explanation:   6  5  17  17

the perimeter is a semi-circle PLUS the diameter   d = 6 ft

so

      C = 2π r        semi-circle   C/2  = π r        r = d/2  = 3 ft

total perimeter is

      perimeter   =  C/2 + d

                         =  π r  + d

                         =  3π  + 6

                         =  3(3.14) + 6

                         =  15.425 ft

Answer:

x= 55

Step-by-step explanation:

Answer:

x is 55 degrees

Step-by-step explanation:

since it is a right angle set up the equation

20+x+15=90

then solve to get 55

Answer:

A) 2. Seconds

4. Minutes

B) 2. Measure the times of 24 volunteers who run a lap around the track.

3. Randomly pick 24 students to run a lap around the track and measure their times.

Step-by-step explanation:

A. The unit(s) that could be used for the unit of measurement are the units used to measure time and the correct answer according to the options given above is seconds and minutes.

B. Which of the procedures below would be the best way to find the average time?

2. Measure the times of 24 volunteers who run a lap around the track.

3. Randomly pick 24 students to run a lap around the track and measure their times.

Answer:

Sorry if this is wrong, but seeing the question I think the best answer following the question would be answer B, because for A it shows that 1 hour is 35 miles when it says 70 miles in 1 hour, not C because as the time rises so does the distance, and I checked D and it's wrong.

Step-by-step explanation:

Answer:

x = 60.6

Step-by-step explanation:

tan x = opp/adj

tan x = 3.9/2.2

x = tan^-1 3.9/2.2

x = 60.6

Answer:

1. [tex]2 \frac{2}{7} [/tex]

2. [tex]2 \frac{1}{3} [/tex]

3. [tex] \frac{5}{12} [/tex]

4. [tex]8 \frac{2}{3} [/tex]

5. [tex] \frac{2}{3} [/tex]

Step-by-step explanation:

[tex] \frac{8}{3} \div \frac{7}{6} [/tex]

[tex] \frac{8}{3} \times \frac{6}{7} [/tex]

[tex]8( \frac{2}{7} )[/tex]

[tex] \frac{8 \times 2}{7} [/tex]

[tex] \frac{16}{7} [/tex]

[tex]2 \frac{2}{7} [/tex]

[tex] \frac{20}{3} \div \frac{20}{7} [/tex]

[tex] \frac{20}{3} \times \frac{7}{20} [/tex]

[tex] \frac{1}{3} \times 7[/tex]

[tex] \frac{7}{3} [/tex]

[tex]2 \frac{1}{3} [/tex]

[tex] \frac{25}{6} \div \frac{10}{1} [/tex]

[tex] \frac{25}{6} \times \frac{1}{10} [/tex]

[tex] \frac{5}{6} \times \frac{1}{2} [/tex]

[tex] \frac{5}{6 \times 2} [/tex]

[tex] \frac{5}{12} [/tex]

[tex] \frac{13}{2} \div \frac{3}{4} [/tex]

[tex] \frac{13}{2} \times \frac{4}{3} [/tex]

[tex]13( \frac{2}{3} )[/tex]

[tex] \frac{13 \times 2}{3} [/tex]

[tex] \frac{26}{3} [/tex]

[tex]8 \frac{2}{3} [/tex]

[tex] \frac{15}{4} \div \frac{45}{8} [/tex]

[tex] \frac{15}{4} \times \frac{8}{45} [/tex]

[tex] \frac{1}{4} \times \frac{8}{3} [/tex]

[tex] \frac{2}{3} [/tex]

Answer:

bd would also equal 5 i love math

Step-by-step explanation:

Answer:

There's no diagram.

I guess You forgot to send.

I'll guess its a quadrilateral.

Draw out a little quadrilateral...eg a rectangle

Label your points.

From the labelling ... Distance BD is now the diagonal of the rectangle.

Using Pythagorean theorem to get it...

BD = √12²+5²

BD=13.

Answer:

-3/4

Step-by-step explanation:

From point (0,3), to get to point (4,0) you would need to go down 3 units, and right 4 units.

Hope this helps

9514 1404 393

Answer:

  (b)  93°

Step-by-step explanation:

Assuming the line containing YT is a diameter, the measure of angle UYT is ...

  180° -87° = 93° = m∠UYT

Answer:

505.4 in²

Step-by-step explanation:

½d2= 19×tan 35° = 19×0.7 = 13.3 in

d2 = 2×13.3 = 26.6 in

d1 = 2×19=38 in

the area of Rhombus =

½×38×26.6 = 505.4 in²

Answer:

[tex]\begin{array}{cccc}{Scores} & {f} & {LB} &{CF} & {39-41} & {6} & {39} &{6} & {36-38} & {7} & {36} &{13}& {33-35} & {9} &{33}&{22}& {30-32} & {13}&{30} &{35} & {27-29} & {22} &{27}&{57} & {24-26} & {10} &{24}&{67} & {21-23} & {9} &{21} &{76}& {18-20} & {7} &{18}&{83}& {15-17} & {8} &{15}&{91}& {12-14} & {4} &{12}&{95}& {9-11} & {2} &{9}&{97}& {6-8} & {1} &{6}& {98}&{3-5} & {1} &{3}&{99} \ \end{array}[/tex]

Step-by-step explanation:

Given

See attachment for complete question

Required

Fill in the blanks

First, we fill in the lower boundary (LB).

This is done by writing out the lower boundary of each class

So, we have:

[tex]\begin{array}{ccc}{Scores} & {f} & {LB} & {39-41} & {6} & {39} & {36-38} & {7} & {36} & {33-35} & {9} &{33}& {30-32} & {13} &{30}& {27-29} & {22} &{27}& {24-26} & {10} &{24}& {21-23} & {9} &{21}& {18-20} & {7} &{18}& {15-17} & {8} &{15}& {12-14} & {4} &{12}& {9-11} & {2} &{9}& {6-8} & {1} &{6}& {3-5} & {1} &{3} \ \end{array}[/tex]

Next, is to fill the CF column

This is done by adding the current with the previous cumulative frequency.

So, we have:

[tex]\begin{array}{cccc}{Scores} & {f} & {LB} &{CF} & {39-41} & {6} & {39} &{6} & {36-38} & {7} & {36} &{6 + 7 = 13}& {33-35} & {9} &{33}&{13+9 = 22}& {30-32} & {13}&{30} &{22+13=35} & {27-29} & {22} &{27}&{35+22=57} & {24-26} & {10} &{24}&{57+10=67} & {21-23} & {9} &{21} &{67+9=76}& {18-20} & {7} &{18}&{76+7=83}& {15-17} & {8} &{15}&{83+8=91}& {12-14} & {4} &{12}&{91+4=95}& {9-11} & {2} &{9}&{95+2=97}& {6-8} & {1} &{6}& {97+1=98}&{3-5} & {1} &{3}&{98+1=99} \ \end{array}[/tex]

Thia is the complete table of filling the values of LB(lower boundaries) and <cf (less than commulative frequency).

Answer:

B I think because i did my math

Step-by-step explanation: