What is the percent composition of Ca(C2H3O2)2?
Select one:
a. 25.3% Ca, 30.4% C, 3.8% H, 40.5% O
b. 40.4% Ca, 24.2% C, 3.1% H, 32.3% O
c. 6.67% Ca, 26.67% C, 40.0% H, 26.67% O
d. 12.5% Ca, 25% C, 37.5% H, 25% O

Answers

Answer 1

Answer:

a

Explanation:

relative formula mass of Ca(C2H3O2)2=158

% for Ca=25.3

% for C=30.4

% for H=3.8

% for O=40.5

Answer 2

Answer:

Choice a. The compound [tex]\rm Ca(C_2 H_3 O_2)_2[/tex] contains approximately [tex]25.3\%\; \rm Ca[/tex], by mass, approximately [tex]30.4\%\; \rm C[/tex] by mass, approximately [tex]3.8\%\; \rm H[/tex] by mass, and approximately [tex]40.5\%\; \rm O[/tex] by mass.

Explanation:

Look up the relative atomic mass of these elements on a modern periodic table:

[tex]\rm Ca[/tex]: [tex]40.078[/tex].[tex]\rm C[/tex]: [tex]12.011[/tex].[tex]\rm H[/tex]: [tex]1.008[/tex].[tex]\rm O[/tex]: [tex]15.999[/tex].

The relative atomic mass of an element gives the numerical value of the mass (in grams) of one mole of the atoms of this element. For example, the relative atomic mass of hydrogen is [tex]1.008[/tex]. Therefore, the mass of one mole of hydrogen atoms would be (approximately) [tex]1.008\; \rm g[/tex].

One mole of [tex]\rm Ca(C_2 H_3 O_2)_2[/tex] formula units include:

[tex]1\; \rm mol[/tex] of [tex]\rm Ca[/tex] atoms, and[tex]2\; \rm mol[/tex] of [tex]\rm (C_2H_3O_2)^{-}[/tex] ions.

Inside each mole of [tex]\rm (C_2H_3O_2)^{-}[/tex] ions, there are:

[tex]2\; \rm mol[/tex] of [tex]\rm C[/tex] atoms,[tex]3\; \rm mol[/tex] of [tex]\rm H[/tex] atoms, and[tex]2\; \rm mol[/tex] of [tex]\rm O[/tex] atoms.

Therefore, that [tex]2\; \rm mol[/tex] of [tex]\rm (C_2H_3O_2)^{-}[/tex] ions in one mole of [tex]\rm Ca(C_2 H_3 O_2)_2[/tex] formula units would include:

[tex]2\; \rm mol \times 2 = 4\; \rm mol[/tex] of [tex]\rm C[/tex] atoms,[tex]3\; \rm mol \times 2 = 6\; \rm mol[/tex] of [tex]\rm H[/tex] atoms, and[tex]2\; \rm mol \times 2 = 4\; \rm mol[/tex] of [tex]\rm O[/tex] atoms.

In summary, each mole of [tex]\rm Ca(C_2 H_3 O_2)_2[/tex] formula units would contain:

[tex]1\; \rm mol[/tex] of [tex]\rm Ca[/tex] atoms,[tex]4\; \rm mol[/tex] of [tex]\rm C[/tex] atoms,[tex]6\; \rm mol[/tex] of [tex]\rm H[/tex] atoms, and[tex]4\; \rm mol[/tex] of [tex]\rm O[/tex] atoms.

Calculate the mass of these atoms using their relative atomic mass data.

For example, the mass of one mole of [tex]\rm H[/tex] atoms is (approximately) [tex]1.008\; \rm g[/tex] because the relative atomic mass of hydrogen is [tex]1.008[/tex]. Therefore, the mass of that [tex]6\; \rm mol[/tex] of hydrogen atoms would be approximately:

[tex]6\; \rm mol \times 1.008\; \rm g \cdot mol^{-1} = 6.048\; \rm g[/tex].

Similarly, calculate the mass of the other three elements in one mole of [tex]\rm Ca(C_2 H_3 O_2)_2[/tex] formula units:

[tex]40.078\; \rm g[/tex] of [tex]\rm Ca[/tex].[tex]48.044\; \rm g[/tex] of [tex]\rm C[/tex].[tex]6.048\; \rm g[/tex] of [tex]\rm H[/tex].[tex]63.996\; \rm g[/tex] of [tex]\rm O[/tex].

The sum of these masses is [tex]158.166\; \rm g[/tex].

In other words, the mass of one mole of [tex]\rm Ca(C_2 H_3 O_2)_2[/tex] formula units is (approximately) [tex]158.166\; \rm g[/tex]. Approximately [tex]40.078\; \rm g[/tex] of that is [tex]\rm Ca[/tex]. Therefore, the percentage of [tex]\rm Ca\![/tex] by mass in [tex]\rm Ca(C_2 H_3 O_2)_2\![/tex] would be approximately:

[tex]\begin{aligned}&100\%\times \frac{40.078\; \rm g}{158.166\; \rm g} \quad \genfrac{}{}{0pt}{}{\leftarrow\text{mass of $\mathrm{Ca}$ in $\mathrm{Ca(C_2 H_3 O_2)_2}$}}{\leftarrow\text{mass of $\mathrm{Ca(C_2 H_3 O_2)_2}$}}\\ & \approx 25.3\% \end{aligned}[/tex].

In other words, [tex]\rm Ca[/tex] accounts for approximately [tex]25.3\%[/tex] of the mass of [tex]\rm Ca(C_2 H_3 O_2)_2\![/tex].

In a similar way, calculate the percentage of the other three elements by mass.

[tex]\rm C[/tex]: approximately [tex]30.4\%[/tex].[tex]\rm H[/tex]: approximately [tex]3.8\%[/tex].[tex]\rm O[/tex]: approximately [tex]40.5\%[/tex].


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Answers

Answer:

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Explanation:

C. red blood cell → heart tissue → circulatory system

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Answers

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Answer:

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Explanation:

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Answers

Answer:

Crisscross method is simply writing the charges crossly near each element. Since oxidation number of Mg (metal) is +2 and oxygen (nonmetal) is -2, if we cross them and write next to each; we get Mg2O2 .

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Answers

Answer:

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Answers

Answer:

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Answers

Answer:

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ex. 3.0 x 10^12 kg^2 then the force factor would be 3.

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Which covalent bond is the most polar?
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Answers

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Answers

Answer:

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Answers

Answer:

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Explanation:

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Answers

Answer:

The First layer is the troposphere. The troposphere is what we live in. It creates weather for us. Second layer is the Stratosphere. You will find the ozone layer in it. The ozone layer helps protect us from ultraviolet radiation (UV) from the sun. In fact, the ozone layer absorbs most of the UV radiation the sun sends to us. Life as we know it wouldn't be possible without this layer of protection. Third layer is Mesosphere. The Mesosphere is very important for earth's protection. The mesosphere burns up most meteors and asteroids before they are able to reach the earth's surface. Fourth layer is Thermosphere. The Thermosphere absorbs the sun radiation making it very hot.

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Answer:

Explanation:

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Need help fast!!!!!!!!!!!

Answers

I think it’s the second one!! Hope this helps! BRANLIEST plzzzz

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A. one
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C. three
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Answers

There are none

Further explanation

Given

a molecule of calcium sulfide

two valence electron of Calcium(Ca)

six valence electrons of Sulfur(S)

Required

number of lone pairs of electrons

Solution

Lewis structure shows the form of bonds that occur in the valence electrons of an element or compound

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Answers

Answer:

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Answers

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......

Explanation:

How many moles in 435 liters of Krypton gas at STP?

Answers

Answer:

19.4 mol Kr

General Formulas and Concepts:

Chemistry

Stoichiometry

Using Dimensional Analysis

Gas Laws

STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right Explanation:

Step 1: Define

435 L Kr at STP

Step 2: Identify Conversions

[STP]   22.4 L = 1 mol

Step 3: Convert

[tex]435 \ L \ Kr(\frac{1 \ mol \ Kr}{22.4 \ L \ Kr} )[/tex] = 19.4196 mol Kr

Step 4: Check

We are given 3 sig figs. Follow sig fig rules and round.

19.4196 mol Kr ≈ 19.4 mol Kr

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Answers

A) Neither carbon nor oxygen has satisfied the octet rule

To begin with...

The bond between carbon and oxygen is suppose to have 3 bonds in between

Second:

The lone pairs are not drawn. Since carbon monoxide has 3 bonds in between it should have a lone pair (2 dots) left over on each atom.

Reminder: in order to satisfy the octet rule EACH atom must have 8 electrons. Carbon has 4 valence shell electrons and oxygen has 6. In order to satisfy this rule, there should be 3 bonds in between which makes a total of 6 for each atom plus the lone pairs that make up the 8.

I hope that’s not too confusing, if you still have any questions please let me know in the comments (:

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Answers

Answer:

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An object is located 360 millimeters from a converging lens. The image formed is 150 millimeters high, at a distance of 90 millimeters from the lens. What’s the height of the object?

Answers

The height of the object : 600 mm

Further explanation

Given

d object=360 mm(object distance)

d image=90 mm(image distance)

Required

h object

Solution

focal length = f :

[tex]\tt \dfrac{1}{f}=\dfrac{1}{d_o}+\dfrac{1}{d_i}\\\\\dfrac{1}{f}=\dfrac{1}{360}+\dfrac{1}{90}\rightarrow f=72~mm[/tex]

The magnification :

[tex]\tt M=\dfrac{d_i}{d_o}=\dfrac{90}{360}=0.25[/tex]

[tex]\tt M=\dfrac{h_i}{h_o}\\\\0.25=\dfrac{150}{h_o}\rightarrow h_o=600~mm[/tex]

calculate the molar mass of cacl2

Answers

Answer:

[tex]\boxed {\boxed {\sf 110.98 \ g/mol}}[/tex]

Explanation:

The molar mass is the mass of a substance in grams per mole.

To find it, add the mass of each element in the compound. These masses can be found on the Periodic Table.

The compound given is:

[tex]CaCl_2[/tex]

The compound has 1 Ca (calcium) and 2 Cl (chlorine).

 

Mass of Calcium

The molar mass of calcium is 40.08 g/mol There is only one atom of Calcium in CaCl₂, so the number above is what we will use.

Mass of Chlorine

The molar mass of chlorine is 35.45 g/mol There are two atoms of chlorine in CaCl₂, therefore we need to multiply the molar mass by 2. 35.45 * 2= 70.9 g/mol

Molar Mass of CaCl₂

Now, to find the molar mass, add the molar mass of 1 calcium and 2 chlorine. 40.08 g/mol + 70.9 g/mol =110.98 g/mol

The molar mass of CaCl₂ is 110.98 grams per mole.

Which waves carries the most energy?


HURRY PLZZ!!!!

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Answers

Answer: D Because it is moving at a fast pace

Explanation:

The higher the amplitude the more energy a wave has. So A should be your answer

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1. Identify one reason why all plants need energy.
A. to produce new cells and structures
* B. to absorb sunlight
C. to absorb oxygen
D. to release carbon dioxide
Try Again

Answers

A. to produce new cells and structures
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which is equal to a tempature of 20 c. 20 F. 68F. 36F. 32F

Answers

Answer:

68F

Explanation:

What is an acid in Science​

Answers

An acid is a substance that donates hydrogen ions. Because of this, when an acid is dissolved in water, the balance between hydrogen ions and hydroxide ions is shifted. Now there are more hydrogen ions than hydroxide ions in the solution.

Answer :An acid is any hydrogen containing substance

Explanation: i hope it helps i got a little help from a friend

There is a mixture of three gases. We know the total pressure is 2.50 atmosphere and the pressure of the oxygen and the nitrogen in the mixture are 0.52 atmosphere and 0.84 atmosphere. The jar containing the gases has a volume of 25.0 liters and is at a temperature of 32 degrees Celsius. What are the pressure and the number of moles of carbon dioxide in the container?

Answers

Answer:

1.14 atm and 1.139 mol

Explanation:

The total pressure of the container is equal to the sum of the partial pressure of the three gasses:

P = Poxygen + Pnitrogen + Pcarbon dioxide2.50 atm = 0.52 + 0.84 + Pcarbon dioxide

Now we solve for the pressure of carbon dioxide:

Pcarbon dioxide = 1.14 atm

To calculate the number of CO₂ moles we use PV=nRT:

P = 1.14 atmV = 25.0 Ln = ?R = 0.082 atm·L·mol⁻¹·K⁻¹T = 32 °C ⇒ 32 + 273.16 = 305.16 K

1.14 atm * 25.0 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 305.16 K

n = 1.139 mol
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