what is the most likely reason for the difference between how the compass works on earth and on the moon?

Answers

Answer 1

Answer: A compass taken to Earth's moon does not point in a specific direction on the moon. The moon does not have a strong magnetic field.


Related Questions

Connor rode an inner tube down a river. For 4.6 minutes, he moved downriver at 15 meters per minute. During this time, how far did he move?

Answers

Answer:

2 miles

Explanation:

Which statement describes the magnetic field inside a bar magnet? It points from north to south. It points from south to north. It forms loops inside the magnet. There is no field within the magnet.

Answers

Inside the bar magnet, the magnetic field points from north to south. Statement A is correct.

Magnetic Field:

It is defined as a vector field or the influence of the magnet on the electric current, charges and ferromagnetic substance.

The strength of magnetic field is depends up on the numbers of magnetic field lines per unit area.

Magnetic field lines emerge from the North pole and end in the South pole of a bar magnet. Inside the magnet are also present inside the bar magnet and never intersect at any point.

Therefore, inside the bar magnet, the magnetic field points from north to south.

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Answer:b

Explanation:


The position as a function of time for two objects moving along a straight line is shown in the graph,
Which statement is true about the distances the two object have traveled at time ty?
Object 1 has traveled a greater distance.
B
Object 2 has traveled a greater distance.
Both objects have traveled the same distance
D
The total distance traveled by each object cannot be compared using the graph.

Answers

The distance traveled by object 1 is greater than the distance traveled by object 2.

The shortest distance between two points is a straight line. More distance is covered when the path of motion is curved.

The distance traveled by each object at different time is compared as follows;

[tex]at \ t_ A , \ \ \ d_1>d_2 \ \ \ (d_2 = 0)\\\\at \ t_B, \ \ d_1 > d_2 \\\\at \ t_C, \ \ \ d_2 > d_1 \\\\at \ t_D \ \ \ d_1 = d_2\\\\at \ t_f \ \ \ d_2 > d_1 \ \ \ (d_1 = 0)[/tex]

The major distinguishing distance traveled by each occurs at [tex]t_B[/tex] and [tex]t_C[/tex].

[tex]d_{(t_B)} > d_{(t_C)} \\\\d_1 > d_2[/tex]

Thus, we can conclude that the distance traveled by object 1 is greater than the distance traveled by object 2.

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A number line goes from negative 5 to positive 5. Point D is at negative 4 and point E is at positive 5. A line is drawn from point D to point E. What is the location of point F, which partitions the directed line segment from D to E into a 5:6 ratio? Negative one-eleventh One-eleventh Two-fifteenths Fifteen-halves.

Answers

The location of the point F that partitions a line segment from D to E ([tex]\overline{DE}[/tex]), that goes from negative 4 to positive 5, into a 5:6 ratio is fifteen halves (option 4).  

We need to calculate the segment of the line DE to find the location of point F.

Since point D is located at negative -4 and point E is at positive 5, we have:

[tex] \overline{DE} = E - D = 5 - (-4) = 9 [/tex]

Hence, the segment of the line DE ([tex]\overline{DE}[/tex]) is 9.

Knowing that point F partitions the line segment from D to E ([tex]\overline{DE}[/tex]) into a 5:6 ratio, its location would be:

[tex] F = \frac{5}{6}\overline{DE} = \frac{5}{6}9 = 5*\frac{3}{2} = \frac{15}{2} [/tex]  

Therefore, the location of point F is fifteen halves (option 4).

Learn more about segments here:

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I hope it helps you!

Answer:

The above answer is actually incorrect - the real answer is B. 1/11

Explanation:

I'm adding a ss below for proof

Hope this helped!

I'd really appreciate Brainliest :)

A hair dryer transforms 10,000J of energy in 4s. What is its power?

Answers

Answer:

2500 W

Explanation:

Power is the rate at which work is done and can be found by using the formula

[tex]p = \frac{w}{t} \\ [/tex]

p is power in Watts ( W)

w is the workdone in J

t is time in s

From the question

w = 10,000 J

t = 4 s

We have

[tex]p = \frac{10000}{4} = 2500 \\ [/tex]

We have the final answer as

2500 W

Hope this helps you


A tennis ball is dropped from a height of 3 m and bounces back to a height of
1 m after hitting the ground (s = 0).

Use the equation V^2=U^2 + 2as to calculate the velocity of the tennis
ball when it hits the ground.

Answers

The velocity of the tennis ball when it hits the ground is calculated as 4.43m/s. Details about velocity can be found below.

How to calculate velocity?

The velocity of a moving object can be calculated using the equation of motion as follows:

v² = u² + 2as

Where;

v = final velocityu = initial velocitya = accelerations = distance

v² = 0² + 2(9.8) (1)

v² = 19.6

v = ✓19.6

v = 4.43m/s

Therefore, the velocity of the tennis ball when it hits the ground is calculated as 4.43m/s.

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A moving coil meter has a resistance of 25 and indicate full scale deflection when a current of 4.0mA flows through it.How could this meter be converted to a millimeter having a full scale deflection for a current of 50 mA?​

Answers

GivenG=25,lg=10mA=10×10 power by 3A,v=100V
To find resistance(Rs)
Formula R

s=
lg−G
V


Calculations by formula
R

s=
(10×10
−3
−25
100


=10000−25
=9975
Ans- resistance by 9975Ω

By adding an external resistor of  287.5 Ω in series with the meter, the conversion of the moving coil meter to have a full-scale deflection for a current of 50 mA.

Current sensitivity (S) is the ratio of full-scale deflection current to full-scale deflection voltage.

S = I(fsd) / V(fsd).

S = 4.0 / 25

S = 0.16 mA/Ω

Desired current sensitivity for 50 mA (S(new)) = 50 mA / V(fsd)

(S(new)) = 50 mA / V(fsd)

(S(new)) =  50  / 0.16

(S(new)) =  312.5 Ω

Add External Resistor:

Add an external resistor (R(ext)) in series with the meter. Calculate R(ext) as the difference between R(new) and the internal resistance of the meter

(R(internal) = 25 Ω:

R(ext) = R(new) - R(internal)

R(ext) = 312.5 Ω - 25 Ω

R(ext) = 287.5 Ω

By adding an external resistor of  287.5 Ω in series with the meter, the conversion of the moving coil meter to have a full-scale deflection for a current of 50 mA. This will achieve the desired result.

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An airplane initially travels at 12 m/s when passing the "acceleration line." The airplane then
accelerates to 9 m/s2 until reaching its take off velocity of 40.0 m/s. What is the displacement of
the plane during the acceleration?

Answers

The displacement of  the plane during the acceleration is equal to 80.89 meters.

Given the following data:

Initial velocity = 12 m/sFinal velocity = 40 m/sAcceleration = 9 [tex]m/s^2[/tex]

To determine the displacement of  the plane during the acceleration, we would use the third equation of motion;

[tex]V^2 = U^2 + 2aS[/tex]

Where:

V is the final speed.U is the initial speed.a is the acceleration.S is the displacement traveled.

Substituting the given parameters into the formula, we have;

[tex]40^2 =12^2 + 2(9)S\\\\1600=144+18S\\\\18S=1600-144\\\\18S=1456\\\\S=\frac{1456}{18}[/tex]

Displacement, S = 80.89 meters.

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How fast would a(n) 75 kg man need to run in order to have the same kinetic energy as an 8.0 g bullet fired at 420 m/s ?

Answers

Mass of the bullet (m1) = 8g = 0.008 KgVelocity of the bullet (v1) = 420 m/sWe know, kinetic energy = [tex] \frac{1}{2}m {v}^{2} [/tex]Therefore, the kinetic energy of the bullet

[tex] = \frac{1}{2} \times 0.008 \times 420J \\ = 1.68J[/tex]

So, the kinetic energy of the bullet is 1.68 J. It is said that the man's kinetic energy should be same as that of the bullet.Mass of the man (m2) = 75 KgLet the velocity of the man be v2.Therefore,

[tex]1.68J = \frac{1}{2} \times 75 \: kg \times v2 \\ = > v2 = \frac{1.68 \times 2}{75} m {s}^{ - 1} \\ = 0.0448 \: m \: {s}^{ - 1} [/tex]

Answer:

0.0448 m/s

Hope you could get an idea from here.

Doubt clarification - use comment section.

A number line goes from 0 to 30. Closed circles are at 6 and 25. A line is drawn from point 6 to point 25. Ari is swimming a 25-meter race. After swimming 6 meters, she catches up to Amanda in a ratio of 7:3 from the 6-meter mark. At what meter mark does Ari catch up to Amanda? Round to the nearest tenth, if necessary. Ari catches up to Amanda at meters.

Answers

The position on the meter mark where Ari catches up with Amanda is 19.3 m.

The given parameters:

Range of the number line, = 0 to 30Position of the closed circles, = 6 and 25The ratio between the initial position and final position of Ari = 7:3

The distance between 6 m mark and 25 m mark is calculated as follows;

[tex]d = 25 \ m - \ 6 \ m\\\\\d = 19 \ m[/tex]

The distance traveled by Ari before catching up with Amanda is calculated as follows;

total ratio = 7 + 3 = 10

[tex]distance = \frac{7}{10} \times 19 \ m\\\\distance = 13.3 \ m[/tex]

The position of Ari from the 6 m mark is calculated as follows;

[tex]position = 6 \ m \ + \ 13.3 \ m\\\\position = 19.3 \ m[/tex]

Thus, the position on the meter mark where Ari catches up with Amanda is 19.3 m.

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Answer:

The above answer is correct! The answer is 19.3 meters :)

Explanation:

adding a ss for proof!

hope this helps :D

Calculate the resistance of a 1km length, 1mm diameter wire made from:

a) constantan (\rho = 4.9 × 10-7 Ωm)
b) copper (\rho = 1.7 × 10-8 Ωm)

c) State which material is better suited for being used to make resistors, and justify your answer.
d) With 1 amp of current flowing through each of the wires how much energy is converted to heat?
e) What potential difference would be needed to force a current of 1 amp through that length of each type of wire?

Answers

From the values of resistivity, the resistance of copper wire is 22 Ω.

Let us recall that;

R = ρl/A

ρ = resistivity

l = length of the wire

A = cross sectional area of the wire

For constantan;

R = 4.9 × 10^-7  × 1 × 10^3/[3.14 × ((1 × 10^-3)/2)^2]

R = 620 Ω

For copper;

R =  1.7 × 10-8 × 1 × 10^3/[3.14 × ((1 × 10^-3)/2)^2]

R = 22 Ω

The material that is best suitable to make resistors is constantan wire.

For constantan, the energy converted to heat is;

I^2 R = (1)^2 ×  620 Ω = 620 W

For copper, the energy converted to heat is;

I^2R = (1)^2 × 22 Ω = 22Ω

The potential difference of constantan = IR = 1 ×  620 Ω =   620 V

The potential difference of copper =  = IR = 1 ×  22Ω  = 22 V

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how did you identify the layer that belonged next to the cambrian layer?

Answers

Answer:

Morphology and phylogenetics revealed by fossils. Perhaps the strongest evidence to support the Cambrian evolutionary explosion of animal forms is the first clear appearance, in the Early Cambrian, of skeletal fossils representing members of many marine bilaterian animal phyla

Name a device or gadget that converts
a) Heat energy to mechanical energy b) heat energy to light energy
c)electrical energy to sound energy

Answers

Answer:

a heat engine converts heat to mechanical energy.

electric generator

Given an unknown metal using C= {Q/(M T)} with energy added of 8,000. J, in which the temperature goes from 24.0 C to 28.0 C at a mass of 46.0 g, find its specific heat capacity?​

Answers

Answer:

47.48 J/g/K or 4.74 × 10⁴J/Kg/K

Explanation:

C(specific heat capacity)= Q(quantity of heat)/M(mass) × ∆T(change in temperature, Kelvin)

Q= 8000J

M= 46g or 46 ×10^-3Kg

T1= 24°C = 297K

T2 = 28°C = 301K

∆T = 301-297

= 4K

C= 8000/46 × 4

= 47.48 J/g/K or 4.74 × 10⁴J/Kg/K

which is the following is a modern method used to pressure food

1. sprey drying

2.salting

3. smoking

4. Honey​

Answers

Answer:

1. Spray Drying

Explanation:

it is the most modern

Suppose you take a piece of hard wax from an unlit candle. After you roll the wax between your fingers for a while, it becomes soft. What state of matter is the softer wax? Is it possible for the wax to change without changing its state?

Answers

Answer:

An amorphous solid does not have a definite melting point; instead, it melts gradually over a range of temperatures, because the bonds do not break all at once. This means an amorphous solid will melt into a soft, malleable state (think candle wax or molten glass) before turning completely into a liquid.

Explanation:

Hope this helps

May I get braineist pls?

Please help me answer this! ANSWER IN SCENTENCE FORMAT!!! :
Two factors that affect climate patterns on Earth are the tilt of Earth on its axis and the topography of Earth. Describe how these two factors affect the climate patterns of Earth.

Answers

The answer is
You need to look at the top of the axis
You need to look

Answer:

If you are saying How much does the tilt of the Earth affect the climate

This varies between a tilt of 22.1 and 24.5 degrees over a period of about 41,000 years. This trend not only affects the average temperature of the earth, but also how prominent the seasons are. Procession is a wobble in the earth's axis.

In an inelastic collision:

I. only momentum is conserved

II. only kinetic energy is conserved

III. momentum and kinetic energy are both conserved.

IV. neither momentum nor kinetic energy are conserved.

Answers

Hi there!

I. Only momentum is conserved.

An inelastic collision means that there is a LOSS in the KINETIC ENERGY of the system.

However, momentum is ALWAYS conserved for every type of collision unless there is an external force acting on the system.

I think it’s I.
Hope this will help.

Hi sweeties.. I want 5 solving questions about (Fluid Pressure and Temperature) and (Archimedes' Principle) may u help me?!​

Answers

Answer:

1) A 1L bottle, with a height of 30cm, full of water is emptied. The bottle is filled with oil (density = 920 kg/m^3). Calculate the change in pressure of the bottom of the first bottle. If you decide to put potatoes (assume its density is  1,8 kg/m^3), each one of a volume V = 10 cm^3, will they float?

2) The fusion temperature of the Nitrogen is -210°C and its boiling temperature is 77K. Calculate the difference between the fusion temperature and the boiling temperature.

can somebody explain it to me please?​

Answers

Range be R and height be h

[tex]\boxed{\sf R=\dfrac{u^2sin2\theta}{g}}[/tex]

[tex]\boxed{\sf h=\dfrac{u^2sin^2\theta}{2g}}[/tex]

u=initial velocity

theta is angle of projection.

g=acceleration due to gravity

ATQ

[tex]\\ \sf\longmapsto R=2h[/tex]

[tex]\\ \sf\longmapsto \dfrac{u^2sin2\theta}{g}=\dfrac{2u^2sin^2\theta}{2g}[/tex]

Cancelling required ones

[tex]\\ \sf\longmapsto sin^2\theta=sin2\theta[/tex]

sin2O=2sinOcosO

[tex]\\ \sf\longmapsto sin^2\theta=2sin\theta cos\theta [/tex]

[tex]\\ \sf\longmapsto \dfrac{sin^2\theta}{sin\theta cos\theta=2[/tex]

[tex]\\ \sf\longmapsto \dfrac{sin\theta}{cos\theta}=2[/tex]

[tex]\\ \sf\longmapsto tan\theta=2[/tex]

[tex]\\ \sf\longmapsto \theta=tan^{-1}(2)[/tex]

[tex]\\ \sf\longmapsto \theta=63.4°[/tex]

Done

Option B is correct

Can someone please help me with number 10

Answers

Answer:

A

Explanation:

increase

Answer:

B???

Explanation:

The rate of it going up is lower than L

It might be D too.

Your father bought you a pair of shoes. When you wore the shoes you realized there was a problem. The shoes were too long. Why might such prblm arise and how can it be mitigated?
Please answer it soon as possible ​

Answers

Answer: This problem may arise when your father never bought a shoe before. A male is bad at buying accesories and guessing the size, so the mother should have bought a pair of shoes. Or it can also be that your father has a short term memory or that he never knew the size of your feets. The feet might also have irregular growth for which it grows more than the normal size but such cases are rare to be seen.

You can prevent this by going with your father and selecting the shoe of your size. Or you can simply send your mother to buy it for you instead. Or another perfect choice could be is that you just dont ever send your father to buy anything for you or just never buy a pair of shoes. Wear the shoes that you always did or buy it yourself since your the one who is supposed to know the size of your feets. Another possible solution could be that you can make use of the money by gifitng them to someone close to you.

how many asteroids do scientists believe exist in the solar system?

Answers

Answer:

Astronomers think there are between 1.1 and 1.9 million asteroids in the solar system.

Explanation:

Paint is an example of which of these?

compound

heterogeneous mixture

homogeneous mixture

none of the above

Answers

Answer:

Homogenous Mixture

Explanation:

The composition in paint is uniform so every part of it looks the same throughout the paint.

What is the low end of the range of surface temperature for blue white stars

Answers

B 10,000 - 30,000 K Blue-white stars

A 7,500 - 10,000 K White stars

F 6,000 - 7,500 K Yellow-white stars

G 5,000 - 6,000 K Yellow stars (like the Sun)

The lowest temperature stars are red while the hottest stars are blue. Astronomers are able to measure the temperatures of the surfaces of stars by comparing their spectra to the spectrum of a black body.

how is one kg mass defined in SI system​

Answers

Answer:

It is originally defined as the mass of one liter (10-3 cubic meter) of pure water.

The kilogram, symbol kg, is the SI unit of mass. It is defined by taking the fixed numerical value of the Planck constant h to be 6.626 070 15 × 10-34 when expressed in the unit J s, which is equal to kg m2 s -1 , where the meter and the second are defined in terms of c and ∆νCs.

Scientists suggest that the universe is still expanding. Which statement supports the claim made by the scientists?
The universe is 13.7 billion years old.
The galaxies in the universe are composed of dark matter.
The universe originated from a hot, dense point.
The galaxies in the universe are moving away from Earth at high speeds.

Answers

Answer:

The galaxies in the universe are moving away from Earth at high speeds.

Explanation:

Light years.

A block of mass 1.0 kg rests on a trolley of mass 4.0 kg. The coefficient of dynamic friction between the block and the trolley is 0.30. A horizontal force f = 5.0 n acts on the block. The block slides over the trolley. What is the acceleration of the trolley?

Answers

Answer:

the acceleration of the trolley is the acceleration of the trolley is 0.75 m/s^-2

Explanation:

friction force between the block and the trolley

= 1×0.3×9.8

= 2.94 N

(F = ma)

the acceleration of the trolley

= friction force/mass

= 2.94/4

= 0.735 m/s^-2

= 0.75 m/s^-2

The acceleration of the trolley will be 0.75 m/s².Acceleration is the ratio of the force to the mass.

What is the friction force?

It is a type of opposition force acting on the surface of the body that tries to oppose the motion of the body. its unit is Newton (N).

Mathematically it is defined as the product of the coefficient of friction and normal reaction.

The friction force between the block and the trolley is found as;

[tex]\rm F_f = \mu N \\\\ \rm F_f = \mu \times mg \\\\ \rm F_f = 0.30 \times 1 \timess 9.81 \\\\ \rm F_f= 2.94 \ N[/tex]

Mechanical force is equal to the product of the mass and the acceleration which is equal to the frictional force;

[tex]\rm F_f =F=ma \\\\ \rm a = \frac{F}{m} \\\\ \rm a = \frac{2.94}{4} \\\\ a=0.735 \ ms^{-2}[/tex]

Hence the acceleration of the trolley will be 0.75 m/s².Acceleration is the ratio of the force to the mass.

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2. Think about an activity you may have learned that involves muscle memory. Consider when you first learned the activity, how easy or difficult it was the first time, and if you can do it now without thinking. What happened in your brain during practices that resulted in muscle memory for you?

Answers

Answer:

Muscle memory is found in many everyday activities that become automatic and improve with practice, such as riding bicycles, driving motor vehicles, playing ball sports, typing on keyboards, entering PINs, playing musical instruments, poker, martial arts, and dancing.

Explanation:

when a rigid body rotates about a fixed axis, all the points in the body have the same

Answers

Hi there!

[tex]\large\boxed{\text{Angular acceleration.}}[/tex]

For a rigid body rotating about a fixed axis, its angular characteristics ⇒ angular acceleration and velocity are constant throughout.

However, its LINEAR velocities/accelerations differ because of the following relationships:

v = ωr

a = αr

Thus, a point closer to the axis of rotation has a smaller linear velocity or acceleration compared to a point along the edge.

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