What is the length of NP?

Answer:

15^2+x^2=22^2

225+x^2=484

x^2=259

x=16.09 feet

Step-by-step explanation: 15^2+x^2=22^2

225+x^2=484

x^2=259

x=16.09 feet

Answer:80

Step-by-step explanation: I am not 100% sure this is right but what i did was 75 - 15 =60, 60/75 in percentage is 80%

Answer:

The answers are B, D, and E

Step-by-step explanation:

Answer:

I think B, D, E! Sorry if it's wrong!

Step-by-step explanation:

Only ones that fits the plot!

Answer:

21.46

Step-by-step explanation:

Start with the square

[tex]A = a^{2} \\100 = a^{2}\\10 = a[/tex]

Each side of the square is 10

This also means the diameter of the circle is 10, with a radius of 5

[tex]A = \pi r^{2} \\A = \pi 5^{2} \\A = 78.54[/tex]

Now substract the area of the circle from the square

x = 100 - 78.54

Answer:

w=-1+[tex]\sqrt{2}[/tex], w=-1-[tex]\sqrt{2}[/tex]

Step-by-step explanation:

Answer:

88 in

Step-by-step explanation:

we have to find the circumference of the circle which is ;

C = pie d

= 22/7 x 28

= 88 in

Answer:

Percentage

Step-by-step explanation:

Answer:

-48

Step-by-step explanation:

4(-4)(3)

-16(3)

-48

Answer:

4(-4) (3)

Step-by-step explanation:

put that in your calccalculator:)

Step-by-step explanation:

hope it helps you see the attachment for further information

Answer:

4

Step-by-step explanation: 16/4=4

reflection, then translation

Answer:

-1.2

Step-by-step explanation:

Solution :

Avrami relationship

[tex]$1-y=exp(-kt^n)$[/tex]

[tex]$\ln(1-y)=-kt^n$[/tex]

[tex]$-\ln(1-y)=kt^n$[/tex]

[tex]$\ln\left[\ln\left(\frac{1}{1-y}\right)\right]=\ln k + n \ln t$[/tex]

The fraction transformed is 0.2 at 12.6 s,

[tex]$\ln\left[\ln\left(\frac{1}{1-0.2}\right)\right]=\ln k + n \ln (12.6)$[/tex]

[tex]$-1.5 = \ln k + 2.533 n$[/tex]  .........(i)

The fraction transformed is 0.7 at 25.7 s,

[tex]$\ln\left[\ln\left(\frac{1}{1-0.7}\right)\right]=\ln k + n \ln (25.7)$[/tex]

[tex]$0.5 = \ln k + 3.24 n$[/tex]   ..............(ii)

Subtract (ii) from (i),

-2 = -0.71 n

n = 2.81

Therefore, from (i),

[tex]$-1.5 = \ln k + 2.533 (2.81)$[/tex]

k = 0.000181

Now if the fraction transformed is 0.92, then

[tex]$kt^n=-\ln (1-y)$[/tex]

[tex]$t=\left[\frac{-\ln (1-y)}{k}\right]^{\frac{1}{n}}$[/tex]

[tex]$t=\left[\frac{-\ln (1-0.92)}{0.000181}\right]^{\frac{1}{2.81}}$[/tex]

t = 29.8528 s

Answer:

the answer is one hundred and eight 108

Step-by-step explanation:

108 bro trust me

Answer:

DE

Step-by-step explanation:

You can tell by the markings. Since there are two vertical markings it concludes that those sides are the same length.

Answer:

m<W = 103°

Step-by-step explanation:

First, find the value of x

m<W + m<Y = 180° (opposite angles in a cyclic quadrilateral are supplementary)

11x - 29 + 6x + 5 = 180 (substitution)

Add like terms

17x - 24 = 180

Add 24 to both sides

17x = 180 + 24

17x = 204

Divide both sides by 17

17x/17 = 204/17

x = 12

Find m<W:

m<W = 11x - 29

Plug in the value of x

m<W = 11(12) - 29 = 132 - 29

m<W = 103°

Answer:

The answer is "0.00842".

Step-by-step explanation:

Due to these cards, a conventional 52-card set is dealt one at a time.

While the first two cards are spades, then it would be expected that we could find the next three cards tents, too.

Let A draw 2 spade cards out of 52 cards. Let B become the occasion to draw 3 spade cards the remaining 50 end cards [tex](A \cap B)[/tex] was its case where a 52 card spade is chosen [tex](2+3)=5[/tex].

The number of plots drawn first from 13 regular 52-cerd decks equals number of,[tex]n(A)=\binom{13}{2}[/tex]  probability of event [tex]A, PA =\frac{\binom{13}{2}}{\binom{52}{2}}[/tex]

Furthermore, the multitude of possibilities we can pull from of the remaining 11 spades of the previous 3 cards is 50-card decks standard, [tex]n (B) = \binom{11}{3}[/tex]  then, the probability of event, [tex]B, P(B)=\frac{\binom{11}{3}}{\binom{50}{3}}[/tex]

The chances of five cards being drawn (three spades and two spades),

[tex]P(B \cap A)=\frac{\binom{13}{5}}{\binom{52}{5}}[/tex]

Then there is the chance that the next three cards will be picked if the first two are both pads, [tex]P(\frac{B}{A})[/tex]

[tex]\to P(\frac{B}{A}) \\\\ =\frac{P(B\cap A )}{P(A)}\\\\=\frac{\frac{\frac{13}{5}}{\frac{52}{2}}}{\frac{\frac{13}{2}}{\frac{52}{2}}}\\\\= 0.00842[/tex]

Answer:

c

Step-by-step explanation:

a and b start with negative numbers meaning it couldnt be the greatest, then d shoes a negative number second so that cant be it

Answer:

12x - 6y + 2

Step-by-step explanation:

Answer:

q = 3m

Step-by-step explanation:

We know that segment HF is half of IJ, therefore we can say;

IJ / 2 = HF or q

6 / 2 = HF or q

3 = HF or q

Hope this helps!

Answer:

Step-by-step explanation:

11.5 is greater than -12.5

Answer: -12.5 is greater

-

Step-by-step explanation:

Answer:

Corrie = 5 ft.  2 in.

Jennifer = 4 ft.  6 in.

Step-by-step explanation:

If you convert Jason's height to inches then it would be 57 in.

4 x 12 = 48 in.     48 + 9 = 57 in.

To find Corrie's height you just have to add 5 inches to Jason's height.

57 + 5 = 62 in.

And to find Jennifer's height you just subtract 8 inches from Corrie's height.

62 - 8 =  54 in.

Now all you need to do is convert Corrie and Jennifer's height into feet. You have to divide Corrie and Jennifer's height by 12 inches. And if there are leftover or remaining numbers once you divide, they are just inches that you add on after the feet.

Jennifer's height =  54 / 12 = 4 feet and 6 inches are left over.

Corrie's height = 62 / 12 = 5 feet and 2 inches are left over.

(x – 3)² – 10 = 15

↓

[tex] {x}^{2} - 6x + 9 - 10 = 15[/tex]

[tex] {x}^{2} - 6x - 1 = 15[/tex]

[tex] {x}^{2} - 6x - 15 = 0[/tex]

[tex] {x}^{2} + 2x - 8x - 1 - 15 = 0[/tex]

[tex] {x}^{2} + 2x - 8x - 16 = 0[/tex]

[tex]x \times (x + 2) - 8x - 16 = 0[/tex]

[tex]x \times (x + 2) - 8(x + 2) = 0[/tex]

[tex](x + 2) \times (x - 8) = 0[/tex]

[tex]x + 2 = 0[/tex]

[tex]x - 8 = 0[/tex]

so,

[tex]x1 = - 2[/tex]

[tex]x2 = 8[/tex]

Answer: 1,599,960

Step-by-step explanation:

Since the population of crawfish in a section of the Louisiana bayou increased from 900,000 to 1.2 million between 2010 and 2011. The percentage increase in population will be:

= (1.2 million - 900000) / 900000 × 100

= 300000/900000 × 100

= 33.33%

Since the population increases by the same percentage between 2011 and 2012, then the population in 2012 will be:

= (100% + 33.33%) × 1.2 million

= 133.33% × 1.2 million

= 1.3333 × 1.2 million

= 1,599,960

The population in 2012 is 1,599,960

Answer:

A. 0.75

B. Elsa can expect to gain 0.75 dollars

Step-by-step explanation:

We have six outcomes

Using the table in the attachment, the expected value was calculated.

Expected value = 0.166667+0.3333+0.5-0.083333-0.083333-0.083333

= 0.75

B. From the answer in part A , we can conclude that Elsa can expect to gain money. She can expect to win 0.75 dollars per roll.

Answer:

Reason : by ASA , x = 36

Step-by-step explanation:

∠ABC = ∠EBD      (vertically opposite angle)

BC = BD = 54        (same length)

∠BAC = ∠BDE       (alternate interior angles)

By ASA , ΔABC ≅ ΔDBE

[tex]54 \times x = 36 \times 54\\\\x = 36[/tex]

Answer:

Solution given:

1.

L.h.s.

cscx+cotx

[tex] \frac{1}{cosx}+\frac{cosx}{sinx}[/tex]

[tex]\frac{1+cosx}{sinx}[/tex]

multiplying and dividing by (1-cosx)

[tex]\frac{(1+cosx)(1-cosx)}{sinx(1-cosx)}[/tex]

[tex]\frac{1-cos²x}{sinx(1-cosx)}[/tex]

we have

1-cos²x=sin²x

[tex]\frac{sin²x}{sinx(1-cosx)}[/tex]

[tex]\frac{sinx}{1-cosx}[/tex]

=R.h.s.

proved.

2.

l.h.s

[tex]\frac{tan y}{1-cot y}+\frac{cot y}{1-tany}[/tex]

[tex]\frac{\frac{sin y}{cos y}}{1-\frac{cos x}{siny}}+\frac{\frac{cos y}{sin y}}{1-\frac{siny}{cos y}}[/tex]

[tex]\frac{\frac{sin y}{cos y}}{\frac{siny -cos y}{siny}}+\frac{\frac{cos y}{sin y}}{\frac{cos y-siny}{cos y}}[/tex]

[tex]\frac{sin²y}{cos y(siny-cosy)}+\frac{cos ² y}{sin y(cos y-siny)}[/tex]

[tex]\frac{sin²y}{cos y(siny-cosy)}- \frac{cos ² y}{sin y(-cos y+siny)}[/tex]

[tex] \frac{sin³y -cos³y}{sinycosy(siny -cosy)}[/tex]

[tex] \frac{(sin y- cos y)(sin²y+sinycosy+cos²y)}{sinycosy(siny -cosy)}[/tex]

[tex] \frac{sin²y+cos²y +siny cosy}{sinxcosy}[/tex]

[tex] \frac{1+sinxcosy}{sinycosy}[/tex]

[tex]\frac{1}{sinycosy}+1[/tex]

1+cscysecy

R.h.s.

proved.