Answer:
8.22 g/dm³
Explanation:
Applying,
PV = nRT............... Equation 1
Where P = pressure of krypton, V = Volume of krypton, n = number of moles, R = molar gas constant, T = Temperature
But,
number of mole (n) = mass(m)/molar mass(m')
n = m/m'.............. Equation 2
Substitute equation 2 into equation 1
PV = mRT/m'
P = (m/V)(RT)/m'................ Equation 3
Also,
Density (D) = Mass(m)/Volume(V)
D = m/V.............. Equation 4
Substitute equation 4 into equation 3
P = DRT/m'
D = Pm'/RT.................... Equation 5
From the question,
Given: P = 3.00 atm, T = 100°C = (273+100) = 373 K, m' = 83.8 g/mol
Constant: R = 0.082atm.dm³.K⁻¹.mol⁻¹
Substitute these values into equation 5
D = (3×83.8)/(0.082×373)
D = 251.4/30.586
D = 8.22 g/dm³
The density of krypton gas is 8.22 g/dm³
What is density?Density of any substance is its mass per unit volume.
By ideal gas law
PV = nRT
Where p = pressure is 3.00 atm,
t = temperature is 100 °C = 273 + 100 = 373 K
Molar mass = 83.8 g/mol
R = constant is 0.082 atm.
[tex]\rm Number\;of \;moles= \dfrac{mass}{molar\;mass}[/tex]
Substituting the equation in 1
P = (m/V)(RT)/m'
Now, density = m/V
Then,
[tex]\rm D = \dfrac{Pm'}{RT}[/tex]
[tex]\rm D = \dfrac{3\times 83.8}{0.082\times373} = 8.22 g/dm^3\\[/tex]
Thus, the density is 8.22 g/dm3.
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What are the 2 common uses for Copper?
• Create a stoichiometry problem. It can be a problem using moles, grams, enthalpy, solutions, or acids and bases. Make
sure there is an equation to balance
Answer:
All I can give you is The steps for it.
Explanation:
Almost all stoichiometric problems can be solved in just four simple steps:
: Balance the equation. Convert units of a given substance to moles.
Using the mole ratio, calculate the moles of substance yielded by the reaction.
Convert moles of wanted substance to desired units.
Is this an example of physical or chemical weathering?
chemical
physical
Answer:
Physical
Explanation:
because the erosion of the canyon did not change any of the chemical attributes of the rock it only changed the appearance. it may have changed the color which is an example of chemical properties but in this case, it is physical. But in other cases, you would refer to this type of weathering as mechanical weathering.
Answer:
it physical
Explanation:
because it moving
CAN ANYONE HELP FIGURE OUT THESE QUESTIONS FOR ME PLEASE
Explanation:
1.180g
2.saturated solution
3.25
4.6
5.367
what is the name of the chemical used for bleach in sugar industries?
Answer:
Sulfur Dioxide
Explanation:
Sulfur dioxide is the chemical that, when released by factories using fossil fuels, combines with the atmosphere and can produce acid raid.
What does Avagardo's Law state?
Answer:
Avogadro's law, a statement that under the same conditions of temperature and pressure, equal volumes of different gases contain an equal number of molecules.
Answer:
6.02 x 10^23 moles of any substance is one mole.
Explanation:
Who are the scientists that contributed in arranging of the periodic table?
If 164.8 g of iodine monobromide is combined with 62.4 g of ammonia, determine the amount of excess reactant that remains after the reaction is completed and the percentage yield of nitrogen triiodide if 96.4 is produced?
Answer:
[tex]m_{NH_3}^{leftover}=57.88g[/tex]
[tex]Y= 92.0\%[/tex]
Explanation:
Hello there!
In this case, according to the following chemical reaction between iodine monobromide and ammonia:
[tex]3IBr+NH_3\rightarrow NI_3+3HBr[/tex]
It turns out firstly necessary to identify the limiting reactant, by considering the proper molar masses and the 3:1 and 1:1 mole ratios of iodine monobromide to nitrogen triiodide and ammonia to nitrogen triiodide respectively:
[tex]n_{NI_3}^{by\ IBr}=164.8gIBr*\frac{1molIBr}{206.81gIBr}*\frac{1molNI_3}{3molIBr} =0.266molNI_3\\\\n_{NI_3}^{by\ NH_3}=62.4gNH_3*\frac{1molNH_3}{17.03gNH_3}*\frac{1molNI_3}{1molNH_3} =3.66molNI_3[/tex]
Thus, we conclude that the limiting reactant is IBr as is yields the fewest moles of nitrogen triiodide product. Next, we can calculate the reacted grams of ammonia as the excess reactant:
[tex]m_{NH_3}^{reacted}=0.266molNI_3*\frac{1molNH_3}{1molNI_3}*\frac{17.03gNH_3}{1molNH_3}=4.52gNH_3[/tex]
And therefore the leftover of ammonia is:
[tex]m_{NH_3}^{leftover}=62.4g-4.52g=57.88g[/tex]
Next, the percent yield is calculated by firstly calculating the theoretical yield of nitrogen triiodide as follows:
[tex]m_{NI_3}^{theoretical}=0.266molNI_3*\frac{394.72gNI_3}{1molNI_3} =104.8gNI_3[/tex]
And finally the percent yield by dividing the given actual yield of 96.4 g by the previously computed theoretical yield:
[tex]Y=\frac{96.4g}{104.8g}*100\%\\\\Y= 92.0\%[/tex]
Best regards!
Forensic biologist Manning is looking at a cell sample under the microscope. The cell she sees is oval, with a long tail or flagellum. Immediately, she knows that this is a ________ cell.
red blood
skin
sperm
plant
Answer:
Sperm Cell
Explanation:
A.6.10
B.90
C.6.00
6.20
Answer:
6.1
Explanation:
Because if you get to the large mark it would be 5 but since its not at 5, it would be 6.1 as you can see in my drawing. It aligns perfectly with 6.1.
A sample of gas as a volume of 425 mL at 25°C at and 760 tour what volume with this gas sample have at STP
Answer:
[tex]\Rightarrow V_2 = 389mL[/tex]
Explanation:
To solve this question, we could use Charles' law since both the number of mole and pressure are constant
At STP pressure P = 760 tor and Temperature = 273K
V1 =425mL, T1 =298K and T2 =273K
and [tex]\frac{V_1}{T_1} =\frac{V_2}{T_2}[/tex]
[tex]\Rightarrow V_2 =T_2\times\frac{V_1}{T_1}[/tex]
[tex]\Rightarrow V_2 =273\times\frac{425}{298}[/tex]
Therefore, [tex]\Rightarrow V_2 = 389mL[/tex]
States of Matter Escape Room
Matter is defined as anything that has
A. Phase changes and mass
B. Atoms and density
C. Color and weight
D. Volume and mass
Answer:
A
Explanation:
matter has mass and undergoes a phase change
If the density of mercury is 13.6 g/mL, what is the mass of 25.4 cm3 of
mercury?
Answer:
345.44 g or 0.34544 kg
Explanation:
Applying
D = m/V...................... Equation 1
Where D = Density of mercury, m = mass of mercury, V = Volume of mercury.
make m the subject of the equation
m = D×V................. Equation 2
From the question,
Given: D = 13.6 g/mL = 13.6 g/cm³, V = 25.4 cm³
Substitute these values into equation 2
m = 13.6×25.4
m = 345.44 g
m = 0.34544 kg
Hence the mass of mercury is 345.44 g or 0.34544 kg
Speed is the rate of change of position expressed as _____ traveled per unit of time. A. direction B. meter C. displacement D. distance... Help!!!
Answer:
Distance
Explanation:
14. As the moles of salt added are increased, what
happens to the melting point of the water?
Salt increases the boiling point and decreases the melting point of water. That means if you add salt before heating some water on the stove, it will take longer to boil. Also, if you add salt to ice, it will melt faster.
What is the melting point?
Melting point is the temperature at which a given solid material changes from a solid state to a liquid, or melts.
Salt makes water boil at a higher temperature - water sticks to the salt ions, so they can't get out of the liquid as easily.
Salt makes water freeze at a lower temperature - it's probably harder for the water molecules to get organized into a solid-state with all the salt ions messing up its structure.
Hence, as the moles of salt are added melting point of the water increases.
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Please help due tonight!!! NO LINKS PLEASE they will be flagged.
When 57,816 J of heat are transferred to a 240-g of an unknown metal, its temperature increases from 32⁰C to 164⁰ C. Identify the metal.
If there is a link and you can't answer please put it in the comments I really need help!!!
Answer:
Carbon fiber if I'm correct
calculate the molar mass for BaSO4
Answer:
233.38 g/mol
Explanation:
you find the molar mass of each element and then add them up.
while many microorganisms are harmful there are some that perform an important function. what is one example of suck a microorganisms
Answer:
Yeast
that helps in fermentation
Look at the picture to answer
Answer:
True; Water is stored in reservoirs.
A sample of gas is inside of a rigid container with fixed volume of 350mL. The initial pressure of the system is 366kPa, and the initial temperature is 88 degrees Celsius. How would the pressure of the system change if the temperature was increased to 110 degrees Celsius?
Answer:
457.5kPa
Explanation:
Given data
V1=V2=350mL (fixed volume )
P1=366kPa
T1= 88 degrees Celsius
P2=??
T2= 110 degrees Celsius
For the general gas equation
P1V1/T1= P2V2/T2
V1=V2
P1/T1= P2/T2
Substitute
366/88= P2/110
Cross multiply we have
P2*88=366*110
P2*88= 40260
P2= 40260/88
P2= 457.5 kPa
Hence the pressure will change to 457.5kPa
one example of potential energy.
Answer:
a raised weight
water that is behind the dam
a car that is parked at the top of a hill
a you before it released
a ripe fruit before It falls
____ occurs when the vapor pressure of a liquid is equal to the external atmospheric pressure.
A. Sublimation
B. Compression
C. Boiling
D. Freezing
Answer:
Boiling
Explanation:
c.boiling
choice number 3
What keeps mountains from being even taller than they
already are?
Answer:
Three main processes control mountain height: lateral support of mountains from tectonic forces, which stops mountains from collapsing under their own weight or pushes them up against gravity; climate-controlled erosion; and isostasy, which keeps mountains afloat on the hot and soft mantle material.
Explanation:
What is the function of the system shown in the diagram?
O A. removal of wastes
OB. absorption of nutrients into the bloodstream
O C. carrying oxygenated blood and nutrients to cells
O D. transmitting and receiving messages
Answer:
the answer is carrying oxygenated blood and nutrients to cells
The balanced equation for the combustion of ethene is given below. If 97.7 g of oxygen is used, how much
heat energy will be produced?
C2H4+ 3O2 → 2CO2 + 2H2O + 1390 kJ
Answer:
c
Explanation:
The reaction a(g)⇌b(g) has an equilibrium constant of 5.8 and under certain conditions has q = 336. part a what can you conclude about the sign of δg∘rxn and δgrxn for this reaction under these conditions?
Answer:
The answer is "As [tex]Q=336[/tex], at high-temperature [tex]\Delta G_{rxn}>0[/tex] and When[tex]K>1,[/tex][tex]\Delta G^{\circ}_{rxn}>0[/tex]."
Explanation:
The equation for the reaction is:
[tex]A(g) \leftrightharpoons B(g)[/tex]
[tex]K=5.8\\\\Q=336[/tex]
At equilibrium,
[tex]\Delta G^{\circ}_{rxn}>0[/tex][tex]=-RT \ln \ K[/tex]
When k=5.8(>1), the value of [tex]\ln k[/tex] would be positive
So, [tex]\Delta G^{\circ}_{rxn}[/tex] is negative (< 0)
So if K > l, [tex]\Delta G^{\circ}_{rxn}<0[/tex]
If the reaction is not in equilibrium so the equation is :
[tex]\Delta G_{rxn}>0[/tex]=[tex]\Delta G^{\circ}_{rxn}[/tex][tex]+RT \ln Q[/tex]
Substituting the expression:
[tex]\Delta G_{rxn}>0[/tex][tex]= (-RT \ln K) + RT \ln Q[/tex]
[tex]= RT(\ln Q- \ln K)\\= RT(\ln (336)-\ln (5.8))\\= RT(4.06)[/tex]
It is the positive value for all temperatures.
So, As Q = 336, at the high temperature [tex]\Delta G_{rxn}>0[/tex].
Neptune is 30 AU (astronomical units) from the sun. How long, in light minutes, would it take for light from the sun to reach Neptune?
Answer:
250 light minutes takes
Explanation:
1 astonomical unit is equal to 1.50x10¹¹m
The light travels at the speed of 3.0x10⁸m/s. That means in 1 second, travels 3.0x10⁸m. To solve this question we must find the distance of neptune to the sun in meters. In this way we can find the seconds (And minutes) that need the light to travel from the sun to neptune:
Distance from Sun to neptune:
30AU * (1.50x10¹¹m / 1AU) = 4.5x10¹²m
Time transcurred:
4.5x10¹²m * (1s / 3.0x10⁸m) = 15000s
15000s * (1min / 60s) =
250 light minutes takesin which of these compounds are there twice as many oxygen atoms as hydrogen atoms?
Answer:
G - H2SO4
Explanation:
two hydrogen atoms and 4 oxygen atoms
How do you write the formula for the combination of 2 chemicals?
example: al3+, br1-, and o2- combined would be what?
Explanation:
[tex]Al(Br)O _{3} \\ name \: = > \: aluminiummonobromo(iii)oxide[/tex]
1: Scrieţi şi egalaţi ecuaţiile reacţiilor chimice de schimb prezentate mai jos: a) carbonat de sodiu + clorură de calciu = b) carbonat de potasiu + azotat de calciu = c) sulfat de sodiu + clorură de bariu = d) clorură de aluminiu + hidroxid de sodiu = e) sulfat de magneziu + clorură de bariu = 2: Determinaţi compoziţia procentuală a substanţei sulfat de aluminiu; calculaţi numărul de ioni Al 3+ existenţi în 3,5 Kmoli sulfat de aluminiu. 3: Acidul fluorhidric nu se poate păstra în vase de sticlă (SiO 2 ),deoarece reacţionează cu acesta: 2 SiO 2 + 4HF = SiF 4 + 2H 2 O Ştiind că sticla are un conţinut de 75,3% SiO 2, calculaţi numărul de moli, respectiv numărul de molecule de HF ce reacţionează cu 500 g sticlă. 4: Determinaţi masa de Al, respectiv de K din 500g alaun KAl(SO 4 ) 2 x 12H 2 O 5: Calculaţi cantitatea de azotat de calciu care reacţionează cu 500g soluţie carbonat de potasiu de puritate 80%. 6: Calculaţi masa de H 3 PO 4 care conţine 1,05 x 10 20 atomi oxigen.
Answer:
AMBANTOT MO MALIGO KANA