What is the definition of personality? Your talents and skills The way you prefer to think and act The things that make you unique The jobs at which you will be good

Answer:

a-The equation for processor only configuration is [tex]120\times 10^6=\dfrac{I+YF}{W}\\[/tex] while that for processor and co-processor configuration is [tex]80\times10^6=\dfrac{I+F}{B}[/tex].

b-The value of B is 1.1 second.

c-The value of MFLOPS for co-processor system in configuration 2 is 80 MFLOPS.

d-The evaluation of your colleague is correct.

Explanation:

a

The MIPS rating equations are as follows

Configuration 01 (Processor only)

[tex]120\times 10^6=\dfrac{I+YF}{W}\\[/tex]

Configuration 02 (Processor + Co-processor)

[tex]80\times10^6=\dfrac{I+F}{B}[/tex]

b

From the equation, for processor and co-processor equation the value of B is calculated. For it to be calculated, the I value is calculated from the processor configuration with the following data F= 8 * 10^6 . Y= 50, W = 4 sec:

[tex]I=120\times10^6\timesW-YF\\I=(120\times10^6\times4)-(8\times10^6\times50)\\I=80\times10^6 \text{instructions}[/tex]

Using this value of I gives

[tex]B=\dfrac{I+F}{80\times10^6}\\B=\dfrac{80\times10^6+8\times10^6}{80\times10^6}\\B=\dfrac{88\times10^6}{80\times10^6}\\B=1.1\text{second}[/tex]

The value of B is 1.1 second.

c

The MFLOPS rating of configuration 2 is given as

[tex]\text{MFLOPS}=\dfrac{F}{B-\dfrac{I}{MIPS_{proc+coproc}}}\\\text{MFLOPS}=\dfrac{8\times10^6}{1.1-\dfrac{80\times10^6}{80\times10^6}}\\\text{MFLOPS}=\dfrac{8\times10^6}{1.1-1}\\\text{MFLOPS}=\dfrac{8\times10^6}{0.1}\\\text{Processor+Coprocessor MFLOPS}=80 \text{MFLOPS}[/tex]

So the value of MFLOPS for co-processor system in configuration 2 is 80 MFLOPS.

d

The value of W is 4 seconds while the value of B is 1.1 seconds. Despite being the configuration with lower MIPS, the co-processor configuration has a lower execution rate and thus the evaluation of your colleague is correct.

Answer:

The program in C++ is as follows:

#include <iostream>    

using namespace std;

int perimeter(int side1, int side2, int side3){

return side1+side2+side3;

}

struct Triangle  {

int side1;  int side2;   int side3;

};

int main(void) {

int side1, side2, side3;

cout<<"Sides of the triangle: ";

cin>>side1>>side2>>side3;

struct Triangle T;

T.side1 = side1;

T.side2 = side2;

T.side3 = side3;  

cout << "Perimeter: " << perimeter(T.side1,T.side2,T.side3) << endl;

return 0;

}

Explanation:

See attachment for complete code where comments are as explanation

Answer:

Hardware can be traced back to ancient times. False

Hardware is only found in computers. False

Instruments and weaving looms were some of the first pieces of hardware. False

Computers and hardware is the same thing. This question is a bit broad but there's many different types of hardware. From keyboards to printers to speakers.

I tried my best not exactly sure though.

Answer: E-business

Explanation:

Based on the information given, a natural extension of that phenomenon is the E-business. E-business which means electronic business is when business is done through the internet.

It should be noted that e-business processes consist of the purchase and sale of goods and services, the processing of payments, servicing customers, sharing information regarding products, managing production control, etc.

Answer:

Explanation:

Please specify which programming language this is supposed to be written in.

Without knowing that, only the last part can be answered "how many different initial speeds will you need to test this code?"

You will need to test at least 3 initial speeds: one below the lower-set-speed, one between the lower- and upper-set-speed and last one which is above the upper-set-speed.

Answer:

The function is as follows:

import random

import string

def solution(riddle):

   s = list(riddle)

   for i in range(len(riddle)):

       alpha = "".join(random.choice(string.ascii_letters) for x in range(1))

       alpha = alpha.lower()

       if s[i] == '?':

           if i > 0 and i < len(s)-1:

               if s[i+1] != alpha:

                   s[i] = alpha

               elif s[i-1] != alpha:

                   s[i] = alpha

               else:

                   i=i

           else:

               if i == 0:

                   if s[1] != alpha:

                       s[i] = alpha

                   else:

                       i = i

               else:

                   if s[i-1] != alpha:

                       s[i] = alpha

                   else:

                       i = i

   riddle = ""

   for ele in s:

       riddle+=ele

   return riddle

Explanation:

See attachment for explanation where comments are used to explain some lines

In this exercise we have to use the knowledge of the python language to write the code, so we have to:

The code is in the attached photo.

So to make it easier the code can be found at:

import random

import string

def solution(riddle):

  s = list(riddle)

  for i in range(len(riddle)):

      alpha = "".join(random.choice(string.ascii_letters) for x in range(1))

      alpha = alpha.lower()

      if s[i] == '?':

          if i > 0 and i < len(s)-1:

              if s[i+1] != alpha:

                  s[i] = alpha

              elif s[i-1] != alpha:

                  s[i] = alpha

              else:

                  i=i

          else:

              if i == 0:

                  if s[1] != alpha:

                      s[i] = alpha

                  else:

                      i = i

              else:

                  if s[i-1] != alpha:

                      s[i] = alpha

                  else:

                      i = i

  riddle = ""

  for ele in s:

      riddle+=ele

  return riddle

See more about python at brainly.com/question/26104476

Answer:

Explanation:

The following code is written in Java. It creates the interface/prototype, the function, and the main method call. The function takes in the three int parameters, adds them, and then checks if the sum equals zero, outputting the correct boolean value. Output can be seen in the picture attached below. Due to technical difficulties I had to add the code as a txt file below.

Answer:

B

Explanation:

Answer:

true

Explanation:

because its live

Answer:

A. An analog audio signal is measured at regular intervals. Each measurement is stored as a sample, which is represented at the lowest level as a sequence of bits.

Explanation:

I took the test

Answer:

format floating-point numbers in fixed-point notation

Explanation:

Required

Function of fixed manipulator

This question will be answered from the perspective of C++ programming language (however, the explanation is applicable to programming languages that uses fixed manipulators)

Fixed manipulators in C++ is used to set floating point numbers to a stated  fixed point.

Take for instance;

double pi = 3.1415926534;

cout.precision(2);

cout<< fixed << pi;

The third line of the program where the fixed manipulator is used to format pi to 2 fixed point notation.

Hence, the output will be 3.14

Answer:

science

Explanation:

Answer:

the manufacture of extremely small versions of electronic devices.

Explanation:

asks

mxskssssksskwlwslskamzmzmsmsmz

Answer:

Explanation:

The following code is written in Java, it creates the entire complex class as requested so that it works with the main method that has been provided in the question without having to change anything in the main method. Proof of output can be seen in the attached picture below

import java.util.Scanner;

class Test implements Cloneable{

   public static void main(String[] args) {

       Scanner input = new Scanner(System.in);

       System.out.print("Enter the first complex number: ");

       double a = input.nextDouble();

       double b = input.nextDouble();

       Complex c1 = new Complex(a, b);

       System.out.print("Enter the second complex number: ");

       double c = input.nextDouble();

       double d = input.nextDouble();

       Complex c2 = new Complex(c, d);

       System.out.println("(" + c1 + ")" + " + " + "(" + c2 + ")" + " = " + c1.add(c2));

       System.out.println("(" + c1 + ")" + " - " + "(" + c2 + ")" + " = " + c1.subtract(c2));

       System.out.println("(" + c1 + ")" + " * " + "(" + c2 + ")" + " = " + c1.multiply(c2));

       System.out.println("(" + c1 + ")" + " / " + "(" + c2 + ")" + " = " + c1.divide(c2));

       System.out.println("|" + c1 + "| = " + c1.abs());

       Complex c3 = c1;

       System.out.println(c1 == c3);

       System.out.println(c3.getRealPart());

       System.out.println(c3.getImaginaryPart());

   }

}

class Complex implements Cloneable {

   public interface Cloneable { }

   private double realPart;

   public double getRealPart() {

       return realPart;

   }

   public void setReal(double real) {

       this.realPart = real;

   }

   private double imaginaryPart;

   public double getImaginaryPart() {

       return imaginaryPart;

   }

   public void setImaginary(double imaginary) {

       this.imaginaryPart = imaginary;

   }

   public Complex(double a, double b) {

       realPart = a;

       imaginaryPart = b;

   }

   public Complex(double a) {

       realPart = a;

       imaginaryPart = 0;

   }

   public Complex() { }

   public Complex add(Complex comp2) {

       double real1 = this.getRealPart();

       double real2 = comp2.getRealPart();

       double imaginary1 = this.getImaginaryPart();

       double imaginary2 = comp2.getImaginaryPart();

       return new Complex(real1 + real2, imaginary1 + imaginary2);

   }

   public Complex abs() {

       double real1 = Math.abs(this.getRealPart());

       double imaginary1 = Math.abs(this.getImaginaryPart());

       return new Complex(real1, imaginary1);

   }

   public Complex subtract(Complex comp2) {

       double real1 = this.getRealPart();

       double real2 = comp2.getRealPart();

       double imaginary1 = this.getRealPart();

       double imaginary2 = comp2.getRealPart();

       return new Complex(real1 - real2, imaginary1 - imaginary2);

   }

   public Complex multiply(Complex comp2) {

       double real1 = this.getRealPart();

       double real2 = comp2.getRealPart();

       double imaginary1 = this.getRealPart();

       double imaginary2 = comp2.getRealPart();

       return new Complex(real1 * real2, imaginary1 * imaginary2);

   }

   public Complex divide(Complex comp2) {

       double real1 = this.getRealPart();

       double real2 = comp2.getRealPart();

       double imaginary1 = this.getRealPart();

       double imaginary2 = comp2.getRealPart();

       return new Complex(real1 / real2, imaginary1 / imaginary2);

   }

   public String toString() {

       String result;

       result = realPart + " + " + imaginaryPart + "i";

       return result;

   }

}

Answer:

PHP

Explanation:

The best way to answer this question is to interpret it as, which of the three is a scripting language.

Analyzing each of the languages

1. C#

C# is not a scripting language, but instead it is an object-oriented programming language. Also, c# is a compiled language and one of the features of scripting language is that, they are interpreted.

2. PHP

Basically, PHP are used for server side scripting language because it uses scripts and its programs are not for general purpose runtime environment (but instead for special runtime environments).

3. HTML

HTML is neither a programming language, nor a scripting language because its design pattern does not follow that or programming and scripting languages, and it can not perform what an actual programming and scripting language do.

Answer:

The program in Java is as follows:

import java.util.*;

import java.lang.Math;

public class Main{

public static int maxMagnitude(int num1, int num2){

    int mag = num2;

    if(Math.abs(num1) > Math.abs(num2)){

        mag = num1;

    }

    return mag;

}

public static void main(String[] args) {

 int num1, num2;

 Scanner input = new Scanner(System.in);

 System.out.print("Enter two integers: ");

 num1 = input.nextInt();

 num2 = input.nextInt();

 System.out.println(maxMagnitude(num1,num2));

}

}

Explanation:

The method begins here

public static int maxMagnitude(int num1, int num2){

This initializes the highest magnitude to num2

    int mag = num2;

If the magnitude of num1 is greater than that of num2

    if(Math.abs(num1) > Math.abs(num2)){

mag is set to num1

        mag = num1;

    }

This returns mag

    return mag;

}

The main  method begins here

public static void main(String[] args) {

This declares num1 and num2 as integer

 int num1, num2;

 Scanner input = new Scanner(System.in);

This prompts the user for two integers

 System.out.print("Enter two integers: ");

This gets input for the first integer

 num1 = input.nextInt();

This gets input for the second integer

 num2 = input.nextInt();

This calls the maxMagnitude method and prints the number with the highest magnitude

 System.out.println(maxMagnitude(num1,num2));

}

Answer: True

Explanation:

The term floating point is derived from the fact that there is no fixed number of digits before and after the decimal point; that is, the decimal point can float. There are also representations in which the number of digits before and after the decimal point is set, called fixed-pointrepresentations.

Answer:

It's true

Explanation:

Answer:

(a): The base case: if(n<1)

(b): The recursive statement: recur(n / 5)

(c): Parameter 10 returns 7

Explanation:

Given

The above code segment

Solving (a): The base case:

The base case is that, which is used to stop the recursion. i.e. when the condition of the base case is true, the function is stopped.

In the given code, the base case is:

if(n<1)

Solving (b): The recursive statement:

The recursive statement is the statement within the function which calls the function.

In the given code, the recursive statement is:

recur(n / 5)

Solving (c): A call to recur() using 10

The base case is first tested

if (n < 1); This is false because 10 > 1

So, the recursive statement is executed

recur(n/5) +2=> recur(10/5)+2 => recur(2)+2

2 is passed to the function, and it returns 2

if (n < 1); This is false because 2 > 1

So, the recursive statement is executed

recur(n/5) +2=> recur(2/5)+2 => recur(0)+2

2 is passed to the function, and it returns 2

if (n < 1); This is true because 0 < 1

This returns 3

So, the following sum is returned

Returned values = 2 + 2 + 3

Returned values = 7

Answer:

The function in Python is as follows:

def search_file(filename,mystring):

my_dict = {}

count = 0

file = open(filename)

lines = file.readlines()

for line in lines:

 count+=1

 if mystring.lower() in line.lower():

  my_dict[count] = line.rstrip('\n')

return my_dict

Explanation:

This defines the function

def search_file(filename,mystring):

This initializes an empty dictionary

my_dict = {}

This initializes the number of lines to 0

count = 0

This opens the file

file = open(filename)

This reads the lines of the file

lines = file.readlines()

This iterates through the lines

for line in lines:

This increments the number line

 count+=1

This checks if the string exists in the line

 if mystring.lower() in line.lower():

If yes, the line number and the string are added to the dictionary

  my_dict[count] = line.rstrip('\n')

This returns the dictionary

return my_dict

Answer:

Explanation:

The following code is written in Python. It is a loop that asks the user for an input. If it contains a comma then it removes whitespace, splits it into two words, and prints each word seperately, and exits the loop. If it does not contain a comma then it prompts the user for another input.

while True:

   string = input("Enter input string: ")

   if ',' in string:

       string = string.replace(" ", '')

       string_split = string.split(',')

       print("First word: " + string_split[0])

       print("Second word: " + string_split[1])

       break

Answer:

Explanation:

Answer:

Security policy is the minimum

Explanation:

I don't have that tamagotchi

But I do have 2 tamagotchi's

I think it's a cherry on your tamagotchi

Hoped this helped!

Have a wonderful day-

Answer:

Explanation:

The correct piece of code for the generic method in the question would be the following...

public static <TheType extends Number> long avgNum(TheType item1, TheType item2, TheType item3)

This declaration of the avgNum method declares this method as a Generic TheType method that is a subclass of the Number class. It also takes in generic parameters which are the same as the Generic class that was declared. Finally, outputting a long value which would be tripleSum / 3

Answer:

Explanation:

Mechanical engineers give Presentations when they work on projects and Proposals. Often, professional Presentations require you to verbally and graphically present preliminary designs to colleagues.

Hope this helped!!!

Hey the motherboard is the main circuit think about it as  a base that all other parts like the ram and video card aka graphics card connect to

Hope this helps

Answer:

x = 40

y = 46

Explanation is in the image above.

Answer:

Explanation:

The following code is written in Java, It asks the user to enter the numerator and denominator for both fraction 1 and 2. Then it prompts the user with a menu to choose the desired operation. The choice is passed into a switch statement and calls the correct function.

import java.util.Scanner;

class Brainly {

   public static void main(String[] args) {

       Scanner in = new Scanner(System.in);

       int num1, num2, den1, den2;

       System.out.println("Enter numerator for fraction 1: ");

       num1 = in.nextInt();

       System.out.println("Enter denominator for fraction 1: ");

       den1 = in.nextInt();

       System.out.println("Enter numerator for fraction 2: ");

       num2 = in.nextInt();

       System.out.println("Enter denominator for fraction 2: ");

       den2 = in.nextInt();

       System.out.println("Menu:");

       System.out.println("+ = add fractions");

       System.out.println("- = subtract fractions");

       System.out.println("/ = divide fractions");

       System.out.println("* = multiply fractions");

       String answer = in.next();

       switch (answer.charAt(0)) {

           case '+': add(num1, den1, num2, den2); break;

           case '-': subtract(num1, den1, num2, den2); break;

           case '*': multiply(num1, den1, num2, den2); break;

           case '/': divide(num1, den1, num2, den2); break;

       }

   }

   public static void add(int num1, int den1, int num2, int den2) {

       int num3 = (num1 * den2) + (num2 * den1);

       int den3 = den1 * den2;

       System.out.println("New Fraction: " + num3 + " / " + den3);

   }

   public static void subtract(int num1, int den1, int num2, int den2) {

       int num3 = (num1 * den2) - (num2 * den1);

       int den3 = den1 * den2;

       System.out.println("New Fraction: " + num3 + " / " + den3);

   }

   public static void divide(int num1, int den1, int num2, int den2) {

       int num3 = num1 * den2;

       int den3 = den1 * num2;

       System.out.println("New Fraction: " + num3 + " / " + den3);

   }

   public static void multiply(int num1, int den1, int num2, int den2) {

       int num3 = num1 * num2;

       int den3 = den1 * den2;

       System.out.println("New Fraction: " + num3 + " / " + den3);

   }

}

Answer:

hope it is helpful to you