What is the area of the triangle below?

On a coordinate plane, a triangle has a base of 6 units and a height of 9 units.
27 square units
45 square units
54 square units
90 square units

The purpose of knowing the angle of elevation and depression in relation to the field of surveyor, military/police, aeronautics (pilot), engineers, landscapers, and architects is discussed below

If a person stands and looks up at an object, the angle of elevation is the angle between the horizontal line of sight and the object. If a person stands and looks down at an object, the angle of depression is the angle between the horizontal line of sight and the object.

If the pilot looks straight out, that line of sight is horizontal (focused on the distant horizon). The pilot might see the airport's runway, distant buildings, or even mountains in her field of view.

If the pilot looks down at the ground, the one will see the ground crew. The angle of depression is the angle that is formed between the horizontal and the downward looking angle. It is always a downward view, an angle below the horizon.

For the ground crewmember, looking down would not be much help in communicating with the pilot in her cockpit seat. The crewmember will look up, above the horizontal line, to see the pilot. The ground crewmember's angle of vision if an angle of elevation, the angle above the horizon.

Angle of elevation or depression in a survey can be defined as the angle subtended between the line of sight passing through the scope and the horizontal axis of the instrument.

Engineers, landscapers, architects all use trigonometry in their everyday life to help them efficiently and safely create or design something new.

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The value of the function (f.h)(x) is 96x⁵ + 132x⁴ + 78x³ + 18x²

f(x) = 3x² + 4x³ + 8x⁴

g(x) = -3x + 12x² - 5x³

h(x) = 12x + 6

Therefore,

(f.h)(x) = f(x).h(x)

Hence,

f(x).h(x) = (3x² + 7x³ + 8x⁴)(12x + 6)

f(x).h(x) = 36x³ + 18x² + 84x⁴ + 42x³ + 96x⁵ + 48x⁴

(f.h)(x) = 96x⁵ + 84x⁴ + 48x⁴ +  36x³ + 42x³ + 18x²

(f.h)(x) =  96x⁵ + 132x⁴ + 78x³ + 18x²

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Answer:

a) (f + g)(x) = 8x + 2

b) (f - g)(x) = 4x - 6

Step-by-step explanation:

Given:

a) Find (f + g)(x):

a. (f + g)(x) = f(x) + g(x)

⇒ (f + g)(x) = (6x - 2) + (2x + 4)

⇒ (f + g)(x) = 6x + 2x - 2 + 4

⇒ (f + g)(x) = 8x + 2

b) Find (f - g)(x):

b. (f - g)(x) = f(x) - g(x)

⇒ (f - g)(x) = (6x - 2) - (2x + 4)

⇒ (f - g)(x) = 6x - 2x - 2 - 4

⇒ (f - g)(x) = 4x - 6

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Answer:

Step-by-step explanation:

Answer:

Step-by-step explanation:

V=14h﹣a4+2(ab)2+2(ac)2﹣b4+2(bc)2﹣c4aBase sidebBase sidecBase sidehHeight

The length of the arc is 3.5 cm

The attached image completes the question

The given parameters are:

The length of the arc is calculated as:

[tex]L = \frac{x}{360} * \pi d[/tex]

So, we have:

[tex]L = \frac{25}{360} * 3.14 * 16[/tex]

Evaluate the product

L =  3.5cm

Hence, the length of the arc is 3.5 cm

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Answer:3.5

Step-by-step explanation:

Work Shown:

tan(angle) = opposite/adjacent

tan(61) = x/9

x = 9*tan(61)

x = 16.2364298 approximately

Your calculator needs to be in degree mode. One quick way to check is to type in something like tan(45) and the result should be 1.

The temperature at midnight is 55.4  degrees Fahrenheit

The information that completes the question is "At what temperature is the building at midnight?"

The function is given as:

f(t) = -8.3cos(π/5)t + 63.7

At midnight, t = 0.

So, we have:

f(0) = -8.3cos(π/5) * 0 + 63.7

Evaluate the product

f(0) = -8.3cos(0) + 63.7

Evaluate the expression

f(0) = 55.4

Hence, the temperature at midnight is 55.4  degrees Fahrenheit

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The revenue function when the assumed values and parameters are used is F(x) = (60 + 8x)(250 - 30x)

Let the number of people be x, and the revenue function be F(x).

Using the assumed values, the revenue function is:

F(x) = (60 + 8x)(250 - 30x)

We have:

F(x) = (60 + 8x)(250 - 30x)

Expand

F(x) = 15000 - 1800x + 2000x - 240x²

Differentiate the function

F'(x) = -1800 + 2000 - 480x

Evaluate

F'(x) = 200 - 480x

Set to 0

200 - 480x = 0

This gives

480x = 200

Divide both sides by 480

x = 0.42

Substitute x = 0.42 in F(x)

F(x) = (60 + 8 * 0.42)(300 - 30* 0.42)

Evaluate

F(x) = 18210

Hence, the maximum revenue is $18210, at a rate of $0.42 per person.

We start by setting F(x) to 5000.

So, we have:

15000 - 1800x + 2000x - 240x² = 5000

Evaluate the like terms

10000 + 200x - 240x² = 0

Using a graphing tool, we have:

x = 6.89

Hence, they would reach their goal at a rate of $6.89 per ticket.

We have:

People = x

Cost per person = 20

So, the cost function is:

C(x) = 20x

Profit is calculated using:

P(x) = F(x) - C(x)

So, we have:

P(x) = 15000 - 1800x + 2000x - 240x² - 20x

Evaluate

P(x) = 15000 + 180x - 240x²

This is the point where P(x) = 0.

So, we have:

15000 + 180x - 240x²  = 0

Using a graphing tool, we have:

x = 8.29

Hence, the break even price is $8.29

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Answer:

  16.8 hours

Step-by-step explanation:

An exponential population increase can be modeled by the function ...

  p(t) = a·b^(t/p)

where 'a' is the initial value (at t=0), b is the multiplier in time period p.

__

The colony increased by a factor of b = 80/50 = 1.6 in p = 3 hours. Since we want to find the additional time to reach a population of 1119, the initial population we're working with is 80, not 50.

  p(t) = 80·1.6^(t/3)

  1119 = 80·1.6^(t/3)

__

Solving this for t, we find ...

  1119/80 = 1.6^(t/3) . . . . . . . . . . . . divide by 80

  log(1119/80) = (t/3)log(1.6) . . . . . take logarithms

  t = 3·log(1119/80)/log(1.6) . . . . . divide by the coefficient of t

  t ≈ 16.8 . . . . hours

It will take about 16.8 more hours for the population to increase from 80 to 1119.

Keys:

Step-by-step explanation:

[tex]\left(5\sqrt{3}-\sqrt{27}\right)^3\\\5\sqrt{3}-\sqrt{27}^3=\left(2\sqrt{3}\right)^3\\= 2\sqrt{3}\\\left(2\sqrt{3}\right)^3=2^3\left(\sqrt{3}\right)^3\\=2^3\left(\sqrt{3}\right)^3\\2^3=8\\=8\left(\sqrt{3}\right)^3\\=8\cdot \:3\sqrt{3}\\8\cdot \:3=24\\=24\sqrt{3}[/tex]

Answer:

It is not an integer.

Step-by-step explanation:

[tex](5\sqrt{3} -\sqrt{27} )^3\\\\=(\sqrt{3} *(5-3))^3\\\\=8*3*\sqrt{3} \\\\=24\sqrt{3} \\[/tex]

Answer:

4/5

Step-by-step explanation:

In a right triangle such as this one

 cos (angle) = adjacent leg  / hypotenuse

  cos(k) =   KL / 15

You will need to find the leg length KL using Pythagorean Theorem

 15^2 = 9^2 + (KL)^2             KL =  12

then cos k  = 12/15 = 4/5  

The scaled size of the thumbnails is 16 pixels per inch of painting

The given parameters are:

The space between adjacent images is 40 inches.

Given that there are two spaces, the remaining space is:

Remaining = 800 - 2 * 40

Remaining = 720

Given that there are three samples of image, the width of each image is:

Image = 720/3

Divide

Image = 240 pixels

The scaled size is then calculated using:

Scale = Image scale width/actual width

This gives

Scale = 240/15

Evaluate

Scale = 16

Hence, the scaled size of the thumbnails is 16 pixels per inch of painting

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Answer:

A

Step-by-step explanation:

Step-by-step explanation:

Select four types of data demographers study to make predictions.

birth rate

death rate

employment

income

marriage

migration

The properties used is [tex]\sqrt[3]{4^{5} } = (4^{5})^{\frac{1}{3} } = 4^{\frac{5}{3} }[/tex]

the correct option is (A).

power can be defined as an expression that represents repeated multiplication of the same number whereas exponent is the quantity that represents the power to which the number is raised.

Given:

[tex]4^{\frac{5}{3} } = \sqrt[3]{4^{5} }[/tex]

We can use the following property

[tex]\sqrt[3]{4^{5} } = (4^{5})^{\frac{1}{3} } = 4^{\frac{5}{3} }[/tex]

By using the property we can find the answer.

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Answer:

2677.4

Step-by-step explanation:

40161/15

          [tex]\rule{50}{1}\large\textsf{\textbf{\underline{Question:-}}}\rule{50}{1}[/tex]

       Given f(x)=-x+5, find f(-3).

    [tex]\rule{50}{1}\large\textsf{\textbf{\underline{Answer and how to solve:-}}}\rule{50}{1}[/tex]

We have the function

[tex]\longmapsto\sf{f(x)=-x+5}[/tex]

We need to find

[tex]\longmapsto\sf{f(-3)=}[/tex]

[tex]\longmapsto\sf{f(x)=-(-3)+5}[/tex]

Simplifying,

[tex]\longmapsto\sf{f(x)=3+5}[/tex]

(which is the exact same thing as 5-3)

Henceforth, We conclude that the answer is

[tex]\longmapsto\sf{f(-3)=8}[/tex]

#TogetherWeGoFar ~

[tex]\rule{300}{1}[/tex]

Hey there!

Find f(-3) :

f(-3) = 8 ✅

f(x) = -x + 5

>> Substitute -3 for x in f(x) :

f(-3) = -(-3) + 5

f(-3) = 3 + 5

f(-3) = 8

Therefore, your answer is f(-3) = 8

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Answer:

"Find g to make this statement true".

12 > 4 • g

The answer of the given expression is 1 & 2.

Thus, the answer of the given expression is 1 & 2.

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[1] n = -2

       We will convert the words given into a mathematical equation and then solve by isolating the variable. Let n be "a number"

19 decreased by four times a number is 17

19 - four times a number is 17

19 - 4 n is 17

9 - 4n = 17

-

9 - 4n = 17

- 4n = 8

n = -2

[2] x = -1, y = 3, or (-1, 3)

      I will plug the first equation into the second from the system of equations given to us because it already has an isolated variable, y.

2y - 2x = 8

2(2x + 5) - 2x = 8

4x + 10 - 2x = 8

2x = -2

x = -1

      Now, I will plug this value back into the equation and solve for y.

y = 2x + 5

y = 2(-1) + 5

y = -2 + 5

y = 3

The correct solution method of Kendall's money is 7x = 98. Divide both sides by 7. Kendall had $14

x = Kendall's money

Mateo's money = $98

= 7 × x

The equation:

7 × x = 98

7x = 98

x = 98/7

x = $14

Therefore, the correct answer is option B

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If you draw all of the diagonals from one vertex of a regular hexagon we make 5 triangles. This is further explained below.

Generally, the hexagon is simply defined as the hexagon is a polygon with six sides. to be considered a hexagon, the form must have six sides, all of which must be closed.

In conclusion, We get five triangles if we draw the diagonals of a regular hexagon starting at a single vertex.

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Answer:

3 to the fourth power, which equals 81.

Step-by-step explanation:

The area of sector EBR in the given diagram attached below is: 33.75π units².

Area = θ/360º × πr²

Given the following:

Measure of arc TE = 2(m∠TRE) = 2(15) [inscribed angle theorem]

Measure of arc TE = 30°

Arc RE = 180 - arc TE = 180 - 30 [semicircle]

Arc RE = 150°

m∠EBR = Arc RE = 150°

Area of sector EBR = m∠EBR/360 × π(BE²)

Area of sector EBR = 150/360 × π(9²)

Area of sector EBR = 33.75π units²

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Answer:

There two images below,

one is the final product and one of how it was reflected

answer this fully! i need to know what x equals

X equal minus 0.5

Answer: 11. [tex]11b-6[/tex]

12. [tex]14d^2-4d[/tex]

13. [tex]2x^2[/tex]

14. [tex]-4x+10[/tex]

15. [tex]19+x[/tex]

16. [tex]4c[/tex] (all together, the problems aren't entered correctly)

17. Nothing further can be done with these equations. Please check the expression entered.

18. [tex]2p-q[/tex] (All together, the problems aren't entered correctly)

Step-by-step explanation:

[tex]\quad \:a+\left(b+c\right)=a+b+c[/tex]

[tex]7b+\left(4b-6\right)=7b+4b-6[/tex]

[tex]=7b+4b-6[/tex]

[tex]7b+4b=11b[/tex]

[tex]=11b-6[/tex]

[tex]2d*(7d-2)=14d^2-4d[/tex]

[tex](8 * (d^2)) + ((2*3d^2) - 4d)[/tex]

[tex]2^3d^2 + (6d^2 - 4d)[/tex]

[tex]14d^2 - 4d = 2d * (7d - 2)[/tex]

[tex]((5*(x^2))+4)+((0-3x^2)-4)[/tex]

[tex](5x^2 + 4) + (-3x^2 - 4)[/tex]

[tex]=2x^2[/tex]

[tex]-4x+10-5x+5x[/tex]

[tex]-4x-5x+5x+10[/tex]

[tex]-4x-5x+5x=-4x[/tex]

[tex]=-4x+10[/tex]

[tex]8+5+6+x[/tex]

[tex]\:8+5+6=19[/tex]

[tex]=19+x[/tex]

Answer: 2a + c is the answer for #17 and #18 is 2p.

17.

3a + 8b - 5c

6a - 9b + 4c

-7a + b + 2c =

2a + c

18.

+6p - 3q + z

- 3p + 2q - z

- p +    q =

2p

Step-by-step explanation:

Answer:

The answer is 0.75

Hope this helps!