What is a fixed annual sum of money paid at regular intervals to an employee for their work?

9514 1404 393

Answer:

  a) no

  b) yes

Step-by-step explanation:

a) You cannot draw the graph around x=0 without lifting your pencil. The function is not continuous at x=0.

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b) You can draw the graph around x=1 without lifting your pencil. The function is continuous at x=1.

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Additional comment

In technical terms, the limit from the left at x=0 is 2; the limit from the right is 3. These are different, so the function is not continuous there.

On the other hand, the left and right limits at x=1 are the same (both 2), and are equal to the value of the function at that point (f(1)=2). Hence, the function is continuous at x=1.

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Work Shown:

f(x) = |x+1|

f(-5) = |-5+1| .... x is replaced with -5

f(-5) = |-4|

f(-5) = 4

Answer:

4

Step-by-step explanation:

Answer:

y-intercept: -5

Slope: 4

Equation: y = 4x - 5

Step-by-step explanation:

✔️The y-intercept is the value of y when x = 0. From the table of values, it shows that when x = 0, y = -5. Therefore:

y-intercept (b) = -5

✔️using two pairs from the table, (1, -1) and (2, 3):

[tex] Slope (m) = \frac{y_2 - y_1}{x_2 - x_1} = \frac{3 -(-1)}{2 - 1} = \frac{4}{1} = 4 [/tex]

Slope = 4

✔️To write an equation for the function, substitute m = 4, and b = -5 into y = mx + b.

Thus:

y = 4x +(-5)

y = 4x - 5

Answer: You need to divide the numbers.

Step-by-step explanation:

Answer:

The answer is X=3

Step-by-step explanation:

2/5x=6/5

x=6/5*5/2=3

So your answer is 3

Hope this helps

also can I plz have brainliest :)

Answer:

556

Step-by-step explanation:

formula

L = a + (n - 1)*d

Givens

n = 70

a = 4

d = 8

Solution

t = 4 + (70 - 1)*8

t = 4 + 69*8

t = 4 + 552

t = 556

Answer:

[tex]\frac{31}{50}-\frac{4i}{25}[/tex]

Step-by-step explanation:

Answer: Bottom Left

Step-by-step explanation:

Answer:

bottom left

Step-by-step explanation:

cuz it makes sense

Answer:

I would say, 2.5

Step-by-step explanation:

Because the calculator said 2.67

Answer:

x=30

Step-by-step explanation:

Let's solve your equation step-by-step.

35=1.5x−10

Step 1: Flip the equation.

1.5x−10=35

Step 2: Add 10 to both sides.

1.5x−10+10=35+10

1.5x=45

Step 3: Divide both sides by 1.5.

1.5x÷1.5=45÷1.5

x=30

Answer:

500

Step-by-step explanation:

you welcome!! can  have brainliest?

Answer:

500

Step-by-step explanation:

Answer:

brainlest?

Step-by-step explanation:

......

Answer: I looked it up and got a couple of answers of spatial reasoning. Don’t know if that helps but yeah thats what I got lol

Step-by-step explanation:

Answer:

As the x=-2 does not satisfy the inequality.

Therefore, the solution is False!

Step-by-step explanation:

Given the expression

[tex]x-10x+1<\:20+\:5x\:[/tex]

substituting the value x = -2

[tex]\left(-2\right)-10\left(-2\right)+1<20+5\left(-2\right)[/tex]

[tex]-2+20+1 < 20-10[/tex]

[tex]19 < 10[/tex]

As the x=-2 does not satisfy the inequality.

Therefore, the solution is False!

Answer:

e. 79/30     f.   18.2

Step-by-step explanation:

Answer:

I can’t see the picture!

Step-by-step explanation:

Answer:

28%

Step-by-step explanation:

hope this helps, have a good day

Answer:

-6x=64

Step-by-step explanation:

Answer:

64 -- 6 = x

( x equals 58 btw )

<3 Enjoy,

    Dea

Answer:

The measure of the largest angle is 72º.

Step-by-step explanation:

We will first solve for x. We know that the sum of the interior angles of a triangle is 180º, so 15x + 21x + 24x is equal to 180º. This means that 60x = 180º, so x = 3º. The largest angle is 24x, which is 72º.

Answer:

Table (4)

Step-by-step explanation:

If data in the given tables show the proportional relation then they will follow the rule,

y = kx

k = [tex]\frac{y}{x}[/tex]

where 'k' = proportionality constant

From table (1),

k = [tex]\frac{2}{1}[/tex] = 2

k = [tex]\frac{3}{2}=1.5[/tex]

But 2 ≠ 1.5

So the data in the table (1) is not proportional.

Table (2)

k = [tex]\frac{0}{2}=0[/tex]

k = [tex]\frac{2}{4}=0.5[/tex]

Therefore, data in the table is not proportional.

Table (3)

k = [tex]\frac{1}{0}[/tex] = Not defined

k = [tex]\frac{3}{2}=1.5[/tex]

Data is not proportional.

Table (4)

k = [tex]\frac{y}{x}=\frac{-6}{-2}[/tex]

  = 3

k = [tex]\frac{3}{1}=3[/tex]

3 = 3

Therefore, data given in table (4) represents the proportional relationship.

Answer:

I think that it is

C

Please let me know if it is not correct!!!!

Answer:

A would most likly be the answer

Step-by-step explanation:

because in the equation sinse A =  -5 1/4 which is whe he was at the end hopefully you understand

Answer:

200

Step-by-step explanation:

Find 60 kilos then just follow the line up till you reach the blue line  

Answer:

[tex]\frac{8}{14} = \frac{14}{x+2}[/tex]  (since they're similar, set them up as a proportion to find x)

14*14 = 8(x+2) (cross multiply, solve the left side, and distribute the right side)

196 = 8x +16 (subtract 16 from both sides)

180 = 8x (divide both sides by 8)

x= 22.5 (is your answer, or C)

Step-by-step explanation:

Answer:

Step-by-step explanation:

AC ≅ AD ; BC≅ BD                      Given

AB ≅ AB                                        Reflexive property of congruence

ΔACB ≅ ΔADB                              Side Side Side Postulate

Answer:

d(c(3))=30I5

Step-by-step explanation:

C(3)=5×9+3 +7=55

d(c(3))= ( 55)^2-10= 3O 15

Answer and Step-by-step explanation:

Starting from

[tex]f(x)=\dfrac14(x+1)^{\frac83}-4(x+1)^{\frac23}[/tex]

take the first derivative using the power and chain rules:

[tex]f'(x)=\dfrac83\cdot\dfrac14(x+1)^{\frac83-1}-\dfrac23\cdot4(x+1)^{\frac23-1}[/tex]

[tex]f'(x)=\dfrac23(x+1)^{\frac53}-\dfrac83(x+1)^{-\frac13}[/tex]

Now take the second derivative:

[tex]f''(x)=\dfrac53\cdot\dfrac23(x+1)^{\frac53-1}-\left(-\dfrac13\right)\cdot\dfrac83(x+1)^{-\frac13-1}[/tex]

[tex]f''(x)=\boxed{\dfrac{10}9(x+1)^{\frac23}+\dfrac89(x+1)^{-\frac43}}[/tex]

Optionally, you can condense the second derivative a bit by factoring out [tex]\frac89(x+1)^{-\frac43}[/tex], which gives

[tex]f''(x)=\dfrac89 (x+1)^{-\frac43} \left(80(x+1)^{\frac63}+1\right)[/tex]

[tex]f''(x)=\dfrac89 (x+1)^{-\frac43} \left(80(x+1)^2+1\right)[/tex]

[tex]f''(x)=\dfrac89 (x+1)^{-\frac43} \left(80x^2+160x+81\right)[/tex]