A man is sitting on a chair with wheels. He grabs a 2.1 kg book from the desk and throws
the book at a speed of 7.2 m/s. His chair moves backward. The man has a mass of 70 kg and
the chair has a mass of 9.2 kg. What is the speed of the man and the chair after the book is
thrown?
The speed of the man and the chair after the book is thrown is 0.2 m/s.
The given parameters:
mass of the book, m₁ = 2.1 kgspeed of the book, u₁ = 7.2 m/smass of the man, M = 70 kgmass of the book, m = 9.2 kgThe total mass of the man and the book is calculated as follows;
m₂ = 70 kg + 9.2 kg
m₂ = 79.2 kg
The speed of the man and the chair after the book is thrown is determined by applying the principle of conservation of linear momentum;
[tex]m_1 u_1 = m_2u_2\\\\u_2 = \frac{m_1u_1}{m_2} \\\\u_2 = \frac{2.1 \times 7.2}{79.2} \\\\u_2 = 0.2 \ m/s[/tex]
Thus, the speed of the man and the chair after the book is thrown is 0.2 m/s.
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See the person on the right side of the front car. Six reference points could be used to show that the person is in / is NOT in motion. They are:
**a person standing on the ground **the car **the seat
**another person on the ride **the track **the sun
[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]
1. According to person standing on ground ~
The person is in motion2. According to The car ~
The person is not in motion3. According to the Seat ~
The person is not in motion4. According to another person on ride ~
The person is not in motion5. According to the track ~
The person is in motion6. According to the Sun ~
The person is in motionI hope that's what you were looking for, goodluck for your assignment ~
How are earthquakes at continental plate boundaries different from earthquakes at mid-ocean ridges?
Differences between earthquakes at continental plate boundaries and earthquakes at mid-ocean ridges discussed in the answer.
What is earthquakes at continental plate boundaries and earthquakes at mid-ocean ridges?When plates travel in the same direction and collide, this happens. The thinner, denser, and more flexible oceanic plate dips beneath the thicker, more rigid continental plate when a continental plate meets an oceanic plate. It's known as subduction.
Deep ocean trenches, like the one that runs down South America's west coast, are created by subduction. The continent's undercut rocks start to melt. On occasion, a chain of volcanoes forms as the molten rock rises to the surface and passes through the continent. Nearly 80% of earthquakes happen along convergent borders, when plates are being forced together.
Shallow earthquakes, often less than 30 km deep, occur in small bands adjacent to plate borders along mid-ocean ridges and transform edges. There are earthquakes in subduction zones at various depths, some of which are more than 700 km deep. Because they occur everywhere throughout the subducting slab that stretches beneath the opposing plate, earthquake bands are wider along subduction zones. Wide areas of distributed earthquakes may be associated with collision zones between continents, such as those between the Eurasian plate and the plates to the south of the African, Arabian, and Indian tectonic arcs.
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Two forces are applied to a 50-kg box. One is 60.0
N to the south and the other is 80.0 N to the east.
These are the only forces acting on the box. The
magnitude of the acceleration of the box is:
1. 20m/s^2
2. 1.5 m/s^2
3. 5.2 m/s^2
4. 0.50m/s^2
5. 10m/s^2
The magnitude of the acceleration of the box is 2 m/s².
The given parameters;
mass of the box, m = 50 kgfirst force, F₁ = 60 N southsecond force, F₂ = 80 eastThe resultant of the two given forces is calculated as follows;
[tex]F= \sqrt{F_1 ^2 + F_2 ^2} \\\\F = \sqrt{60^2 + 80^2} \\\\F = 100 \ N[/tex]
The magnitude of the acceleration of the box is calculated as follows;
[tex]F = ma\\\\a = \frac{F}{m} \\\\a = \frac{100}{50} \\\\a = 2 \ m/s^2[/tex]
Thus, the magnitude of the acceleration of the box is 2 m/s².
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Find the displacement in the time interval 3 seconds to 4 seconds
A. 1m
B.3m
C.7m
D.9m
Answer:
B. 3m
Explanation:
Took the quiz.
Hope this helps!!
How do atoms join together?
Answer:
Atoms can be joined together by chemical bonds.
Explanation:
When atoms form bonds, they can achieve a stable electron arrangement. To achieve a stable electron arrangement atoms can lose, gain or share electrons. There are many different types of bonds that hold atoms together.
Answer:
Atoms come together to form molecules because of their electrons. Electrons can join (or bond) atoms together in two main ways. When two atoms share electrons between them, they are locked together (bonded) by that sharing. These are called covalent bonds.
Explanation:
PLEASE ANSWER NEED HELP!!!!!!!! PLEASE THE CORRECT ANSWER!!!!!!
Medicine in Western cultures has not focused on the energy in the body as much as cultures in Asia have.
A.
True
B.
False
PLEASE NO LINKS
Answer:
A
Explanation:
This is true because culture in Asia focus more on energy that is why we see kung fu and taekwondo etc.
Answer:
A
Explanation:
Got it right.
Which of the following is NOT a part of Earth’s atmosphere?
1. mesosphere
2. troposphere
3. asthenosphere
4. stratosphere
Answer:
3
Explanation:
It is part of the Earth's mantle
Answer:
it is the astenospere number 3
what is the formula for calculating potentiometer
When did the objects that we now see as asteroids and comets form in the solar system?.
Answer:
After solid particles condensed from the gas but before the planets finished forming
A ball is projected at an immovable wall with a speed vi and bounces back the wall in such a manner that it only has 1/3 of its original linear momentum. a) Determine what fraction of the kinetic energy is lost in the collision.
The fraction of the kinetic energy of the ball lost during the collision is [tex]\frac{1}{3}[/tex].
The given parameters;
initial speed of the ball, = vifinal momentum of the ball, Pf = ¹/₃PiThe initial and final momentum of the ball is calculated as;
[tex]P_i = m_ivi[/tex]
[tex]P_f = m_fv_f = \frac{1}{3} m_iv_i[/tex]
The initial and final kinetic energy of the ball is calculated as;
[tex]K.E_i = \frac{1}{2} m_iv_i^2 = \frac{1}{2} P_iv_i\\\\K.E_f = \frac{1}{2} m_fv_f^2= \frac{1}{2} (\frac{1}{3} P_iv_i)= \frac{1}{6} P_iv_i[/tex]
The change in the kinetic energy is calculated as;
[tex]\Delta K.E = K.E_f - K.E_i \\\\\Delta K.E = \frac{1}{6} P_iv_i - \frac{1}{2} P_iv_i = \frac{1}{3} P_iv_i[/tex]
Thus, the fraction of the kinetic energy of the ball lost during the collision is [tex]\frac{1}{3}[/tex].
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A force of 6.0 N acts on a 4.0 Kg object for 10.0s. What is the object's change in momentum?
Answer:
60 Ns
Explanation:
change in momentum = Fxt
6*10
60 Ns
A force of 6.0 N acts on a 4.0 Kg object for 10.0 s. The object's change in momentum is 60 kg-m/sec.
What is force?A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
change in momentum = force . time
change in momentum = 6 . 10 = 60
A force of 6.0 N acts on a 4.0 Kg object for 10.0 s. The object's change in momentum is 60 kg-m/sec.
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an astronomer looking out into space will observe that
Answer:
The farther out a galaxy is from Earth, the faster it is moving away.
Explanation:
What is occurring in the umbra?
A. a total solar eclipse
B. a total lunar eclipse
C. a partial lunar eclipse
D. a partial solar eclipse
Answer:
A. a total solar eclipse
Explanation:
During a solar eclipse,the moon comes between the sun and Earth, casting its shadow over the Earth
a gas increases in pressure from 2.00 atm to 6.00 atm at a constant volume of 1.00 m3 and then expands at constant pressure to a volume of 3.00 m3 before returning to its initial state as shown in the figure below. how much work is done in one cycle?
The work done on the given gas in one cycle is -405.3 kJ.
The given parameters;
initial pressure of the gas, P₁ = 2 atmfinal pressure of the gas, P₂ = 6 atminitial volume of the gas, V₁ = 1 m³final volume of the gas, V₂ = 3 m³Convert the pressure to Pascal (N/m²);
1 atm = 101325
The work done in one cycle is the area of the triangle and it is calculated as follows
[tex]Area = \frac{1}{2} \times base \times height\\\\Area = \frac{1}{2} \times (3 \ m^3\ -\ 1 \ m^3)\times (6 \ atm \ - \ 2 \ atm)\\\\Area = 4 \ atm -m^3\\\\Area = 4 \ atm -m^3 \ \times \frac{101325 \ Pa}{1 \ atm} \\\\Area = 405,300 \ m^3.Pa\\\\Area = 405,300 \ m^3. (N/m^2)\\\\Area = 405,300 \ Nm\\\\Area = 405,300 \ J\\\\Area = 405.3 \ kJ[/tex]
the net work done on the gas = - 405.3 kJ
Thus, the work done on the given gas in one cycle is -405.3 kJ.
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what kind of frog species is this
Answer: i think its a bullfrog forgive me if im wrong i dont exactly know
Explanation:
Answer:
that is an African bullfrog
What water pressure must a pump that is located on the first floor supply to have water on the thirteenth of a building with a pressure of 35 lb/in2 Assume that the distance between each floors is 10ft.
The water pressure on the first floor must be 455 PSI in order to push the water to the 13th floor at the given pressure.
The given parameters;
Pressure on the 13 th floor, P₁ = 35 PSIDistance between each floor, d = 10 ftThe vertical pressure of the water is calculated as follows;
[tex]P = \rho gh\\\\\frac{P}{h} = \rho g\\\\\frac{P}{h} = k\\\\\frac{P_1}{h_1} = \frac{P_2}{h_2} \\\\[/tex]
The vertical height of the first floor from the 13th floor = 130 ft
The vertical height of the 13 ft floor = 10 ft
[tex]P_1 = \frac{P_2 h_1}{h_2} \\\\P_1 = \frac{35 \times 130}{10} \\\\P_1 = 455 \ PSI[/tex]
Thus, the water pressure on the first floor must be 455 PSI in order to push the water to the 13th floor at the given pressure.
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Which of the following processes generated heat during earths formation that is still a source of heat in earths interior
Answer:
There are three main sources of heat in the deep earth: (1) heat from when the planet formed and accreted, which has not yet been lost; (2) frictional heating, caused by denser core material sinking to the center of the planet; and (3) heat from the decay of radioactive elementsDéterminer la charge de noyau d’atome d’oxygène en coulomb C
Answer:
determine a large mam I have no idea
This should be pretty easy i think.
Describe the components within the system involved in the collision between pilot and landing zone.
Answer:
its a sure for not but i think its a 192583
People who drink coffee are more likely to develop cancer
Answer:
The answer is False
What is gibbs free energy.
Answer:
It’s a
Explanation:
How to find angular velocity of an object traveling at a constant speed.
I only know the formula which is ω = 2πf
An object is at rest. There are several forces acting on the object, but the net force is zero. If all the
forces acting on the object were to suddenly double in size, would the object start moving? Why or why not?
Answer:
no
Explanation:
because the heaver an object the harder it is to move s the force will not be able to move it
A bus slams on its breaks and goes from 30km/hr to 15km/hr in 4 seconds. What is its acceleration?
Answer:
− 2.08
Explanation:
Why are people so rude???
Answer:
It could be low self-esteem
Explanation:
There probably insecure have problems and issues of their own could be that were abused growing up and weren’t treated right who knows.
Interpreting Graphics
11. Look at the model of an atom below. Does the
model represent a metal atom or a nonmetal
atom? Explain your answer.
ng
By looking at the model shown in the problem one can clearly say that this model represents the metal because there are a total of 12 electrons revolving around the nucleus which clearly represents the Magnesium metal.
What are metalloids?The elements of the periodic tables that behave as metals, as well as the nonmetal in some chemical or physical aspects, are known as metalloids. Some examples of metalloids are Boron, silicon, germanium, arsenic, antimony, tellurium, etc.
As given in the problem, there is a graphical representation of the model of an atom,
One can see that the model in the problem accurately depicts the metal by looking at the total of 12 electrons circulating around the nucleus, which is a clear representation of the magnesium metal.
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1
A pencil weighing 1N is sitting on a desk.
Write down all the forces on the desk.
a.
b.
Draw a free body diagram of the desk.
c.
Add up the forces in the x-direction (horizontal) and the y-direction (vertical)
The force diagram on the desk consists of normal reaction and weight of the pencil.
The net force on the desk in vertical direction is 1 N.
The net force on the desk in horizontal direction is 0.
The given parameters;
weight of the pencil, W = 1 NThe force diagram of the desk is sketched as follows;
↑ N
⊕
↓ W
Where;
N is the normal reaction on the deskW is the weight of the ballThe net force on the desk in vertical direction = 1 N
The net force on the desk in horizontal direction = 0
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what metaphor most closely describes the nature of space-time?
a. chemistry formula
b.fabric
c. sine wave
d. moebius strip
Answer:
b.fabric
Explanation:
Nowadays, when people talk about space-time, they often describe it as resembling a sheet of rubber. This, too, comes from Einstein, who realized as he developed his theory of general relativity that the force of gravity was due to curves in the fabric of space-time.
Answer:
B. fabric
Explanation:
A 34. 8 n object is in free fall. What is the magnitude of the net force which acts on the object? answer in units of n.
Answer:
-34.8n
Explanation:
when object in free fall, only force is the Force by weight,
which is 34.8 and direction is down.