Vanadium has an atomic mass of 50.9415 amu. It has two common isotopes. One isotope has a mass of 50.9440 amu and a relative abundance of 99.75 %.
What is the abundance of the other isotope?
What is the mass of the other isotope?

Answers

Answer 1

Answer:

Average atomic mass of the  vanadium = 50.9415 amu

Isotope (I) of vanadium' s abundance = 99.75 %= 0.9975

Atomic mass of Isotope (I) of vanadium ,m= 50.9440 amu

Isotope (II) of vanadium' s abundance =(100%- 99.75 %) = 0.25 % = 0.0025

Atomic mass of Isotope (II) of vanadium ,m' = ?

Average atomic mass of vanadium =

m × abundance of isotope(I) + m' × abundance of isotope (II)

50.9415 amu =50.9440 amu× 0.9975 + m' × 0.0025

m'= 49.944 amu

Explanation:

Answer 2

The abundance of the other isotope is 0.25% and the mass of the other isotope is 49.944 amu.

What is the natural abundance of elements?

Natural abundance can be described as the abundance of isotopes of a chemical element naturally found on a planet. The relative atomic mass of these isotopes is the atomic weight of the element in the modern periodic table.

The abundance of an isotope can vary from planet to planet but remains relatively constant in time. The natural abundance of an isotope can be affected by the probability of its creation in nucleosynthesis and by the production of a given isotope as a daughter of the natural radioactive isotope.

Given, the average atomic mass of Vanadium = 50.9415 amu

The mass of one isotope = 50.9440 amu, relative abundance =99.75 %.

The relative abundance of the other isotope = 100 - 99.75 = 0.25 %

50.9415  = 50.9440 × 0.9975 + 0.0025 × M

Mass of other isotope = 49.944 amu

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Answers

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...............................

Multiple people cannot use one brainly account at the same time on a computer.

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Answers

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correct on  a p e x

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