a. Using backwards finite difference approximations for both partial derivatives, we get:
∂Q/∂x ≈ (Q(i,j) - Q(i-1,j))/a
∂Q/∂y ≈ (Q(i,j) - Q(i,j-1))/a
Therefore,
∂Q/∂x + ∂Q/∂y ≈ (Q(i,j) - Q(i-1,j))/a + (Q(i,j) - Q(i,j-1))/a
≈ Q(i,j)/a - [Q(i-1,j) + Q(i,j-1)]/a
b. Using backwards finite difference approximations for both partial derivatives twice, we get:
∂^2Q/∂x^2 ≈ (Q(i,j) - 2Q(i-1,j) + Q(i-2,j))/a^2
∂^2Q/∂y^2 ≈ (Q(i,j) - 2Q(i,j-1) + Q(i,j-2))/a^2
Therefore,
∂^2Q/∂x^2 + ∂^2Q/∂y^2 ≈ (Q(i,j) - 2Q(i-1,j) + Q(i-2,j))/a^2 + (Q(i,j) - 2Q(i,j-1) + Q(i,j-2))/a^2
≈ 2Q(i,j)/a^2 - [Q(i-1,j) + Q(i-2,j) + Q(i,j-1) + Q(i,j-2)]/a^2
c. Using backwards finite difference approximations for both partial derivatives thrice, we get:
∂^3Q/∂x^3 ≈ (Q(i,j) - 3Q(i-1,j) + 3Q(i-2,j) - Q(i-3,j))/a^3
∂^3Q/∂y^3 ≈ (Q(i,j) - 3Q(i,j-1) + 3Q(i,j-2) - Q(i,j-3))/a^3
Therefore,
∂^3Q/∂x^3 + ∂^3Q/∂y^3 ≈ (Q(i,j) - 3Q(i-1,j) + 3Q(i-2,j) - Q(i-3,j))/a^3 + (Q(i,j) - 3Q(i,j-1) + 3Q(i,j-2) - Q(i,j-3))/a^3
≈ 3Q(i,j)/a^3 - [Q(i-1,j) + Q(i-2,j) + Q(i-3,j) + Q(i,j-1) + Q(i,j-2) + Q(i,j-3)]/a^3
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3/10 of ________ g = 25% of 120g
Answer: Let's use "x" to represent the unknown quantity in grams:
We have:
3/10 x = 25% of 120g
Converting 25% to a fraction:
3/10 x = 25/100 * 120g
Simplifying 25/100:
3/10 x = 0.25 * 120g
Multiplying 0.25 by 120g:
3/10 x = 30g
To solve for "x", we can multiply both sides by the reciprocal of 3/10:
x = (10/3) * 30g
Simplifying:
x = 100g
Therefore, 3/10 of 100g is equal to 25% of 120g.
Step-by-step explanation:
Answer:
3/10 of 100g = 25% of 120g
Step-by-step explanation:
Let us assume that,
→ Missing quantity = x
Now we have to,
→ Find the required value of x.
Forming the equation,
→ 3/10 of x = 25% of 120
Then the value of x will be,
→ 3/10 of x = 25% of 120
→ (3/10) × x = (25/100) × 120
→ 3x/10 = 25 × 1.2
→ 3x/10 = 30
→ 3x = 30 × 10
→ 3x = 300
→ x = 300/3
→ [ x = 100 ]
Hence, the value of x is 100.
A twice-differentiable function f is defined for all real numbers x. The derivative of the function f and its second derivative have the properties and various values of x, as indicated in the table.
Part A: Find all values of x at which f has a relative extrema on the interval [0, 9]. Determine whether f has a relative maximum or a relative minimum at each of these values. Justify your answer.
Part B: Determine where the graph of f is concave up and where it is concave down. Support your answer.
Part C: Find any points of inflection of f. Show the analysis that leads to your answer.
Part A :f has relative maxima at x = 1 and x = 3, and a relative minimum at x = 8, on the interval [0, 9].
Part B: the graph of f is concave up on the intervals (−∞, 1) and (8, ∞) and is concave down on the interval (1, 8).
Part C: x = 1 and x = 8 these are the points of inflection of f.
How to find relative extrema?To find relative extrema, we want to find the basic places of the capability and afterward decide if they are greatest or least by really looking at the indication of the subsequent subordinate.
The point is a relative minimum when the second derivative is positive, and it is a relative maximum when the second derivative is negative. To determine the nature of the critical point, we must employ alternative strategies if the second derivative is zero.
Part A:
The values of x at which f'(x) is zero or undefined are the critical points of f. From the table, we see that f'(x) = 0 at x = 1 and x = 8, and f'(x) is unclear at x = 3.
At each critical point, we must now examine the sign of the second derivative to determine whether it is a maximum or a minimum.
Negative f''(1) = -2 is the case when x = 1. As a result, the relative maximum is the critical point at x = 1.
Because f''(3) is not defined, the second derivative test cannot be used to determine the nature of the critical point at x = 3. However, as the table demonstrates, f shifts from increasing to decreasing at x = 3, indicating that x = 3 is the relative maximum.
We have a positive value of f'(8) = 2 when x = 8. As a result, the relative minimum at x = 8 is the critical point.
Therefore, f has relative maxima at x = 1 and x = 3, and a relative minimum at x = 8, on the interval [0, 9].
Part B:
To determine where the graph of f is concave up and where it is concave down, we need to find the intervals where f''(x) > 0 and where f''(x) < 0, respectively.
From the table, we see that f''(x) > 0 for x < 1 and for x > 8, and f''(x) < 0 for 1 < x < 8. Therefore, the graph of f is concave up on the intervals (−∞, 1) and (8, ∞) and is concave down on the interval (1, 8).
Part C:
We must determine the values of x at the points on the graph where the concavity changes in order to locate any points of inflection of f. From part B, we see that the concavity changes at x = 1 and x = 8. Accordingly, these are the marks of expression of f.
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Evaluate tα/2 for a confidence level of 99% and a sample size of 17.
Group of answer choices
2.567
2.583
2.898
2.921
To evaluate tα/2 for a confidence level of 99% and a sample size of 17, we need to find the t-value associated with a given confidence level and degrees of freedom (df). The correct answer: 2.921
In this case, the degrees of freedom (df) can be calculated as: df = sample size - 1 => df = 17 - 1 => df = 16
Now, we need to find the t-value for a confidence level of 99%, which means α = 0.01 (1 - 0.99). Since we are looking for tα/2, we need to find the t-value associated with α/2 = 0.005 in the t-distribution table.
Looking up the t-distribution table for 16 degrees of freedom and α/2 = 0.005, we find the t-value to be approximately 2.921.
So, the tα/2 for a confidence level of 99% and a sample size of 17 is 2.921.
The correct answer: 2.921
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The rate at which people arrive at a theater box office is modeled by the function B, where B(t) is measured in people per minute and t is measured in minutes. The graph of B for 0 Sts 20 is shown in the figure above. Which of the following is closest to the number of people that arrive at the box office during the time interval Osts 202 (A) 188 (B) 150 (C) 38 (D) 15
Based on this estimation method, the closest answer choice to the number of people that arrive at the box office during the time interval Osts 202 is (B) 150
What is definite integral?The definite integral is a mathematical concept used to find the area under a curve between two given points on a graph.
What is Estimation Method?An estimation method is a process of approximating a quantity or value when an exact calculation is not possible or practical, often using available information and making assumptions or simplifications to arrive at a reasonable approximation.
According to the given information:
Unfortunately, the graph mentioned in the question is not provided. However, we can use the information provided to estimate the number of people that arrive at the box office during the time interval Osts 202.
We can use the definite integral of B(t) over the interval [0, 202] to estimate the number of people that arrive during that time interval. This is given by:
∫[0,202] B(t) dt
Since we don't have the graph of B(t), we cannot calculate the definite integral exactly. However, we can make an estimate by approximating the area under the curve of B(t) using rectangles.
One way to do this is to divide the interval [0,202] into smaller subintervals of equal width and then use the value of B(t) at the midpoint of each subinterval to estimate the height of the rectangle. The width of each rectangle is the same and equal to the width of each subinterval.
Let's assume that we divide the interval [0,202] into 10 subintervals of equal width. Then, the width of each subinterval is:
Δt = (202 - 0) / 10 = 20.2
We can then estimate the height of each rectangle using the value of B(t) at the midpoint of each subinterval. Let's call the midpoint of the ith subinterval ti:
ti = (i - 0.5)Δt
Then, the height of the rectangle for the ith subinterval is:B(ti)
We can then estimate the area under the curve of B(t) over each subinterval by multiplying the height of the rectangle by its width. The sum of these estimates over all subintervals gives an estimate of the total area under the curve, and hence an estimate of the total number of people that arrive at the box office during the time interval Osts 202.
The estimate of the total number of people is given by:
∑[i=1,10] B(ti)Δt
We can use a calculator to compute this sum. Since we don't have the graph of B(t), we cannot calculate the sum exactly. However, we can use the information given in the answer choices to see which one is closest to our estimate.
Based on this estimation method, the closest answer choice to the number of people that arrive at the box office during the time interval Osts 202 is (B) 150
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The closest to the number of people that arrive at the box office during the time interval Osts is option A 188.
What is area under the curve?Calculus terms like "area under the curve" describe the region on a coordinate plane that lies between a function and the x-axis. Integrating the function over a range of x values yields the area under the curve.
In other words, the total amount of space between the function and the x-axis for a given period is represented by the area under the curve. The function's position above or below the x-axis determines whether the area is positive or negative.
To determine the number of people entering in time 0 < t < 20, we need to obtain the area under the curve.
The curve can be divided into two triangles and one rectangle thus:
Area of Rectangle = Length * Breadth = 15 * 5 = 75
Area of Blue Triangle = 1/2 * Base * height = 1/2 * 15 * 10 = 75
Area of Green Triangle = 1/2 * Base * height = 1/2 * 5 * 15 = 75/2
The total area is thus,
75 + 75 + 75/2 = 187.5 = 188
Hence. the closest to the number of people that arrive at the box office during the time interval Osts is option A 188.
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The complete question is:
find the taylor series centered at =−1. ()=73−2 identify the correct expansion. 7∑=0[infinity]35−1( 1) −7∑=0[infinity]35 1( 1) ∑=0[infinity]3−75 1( 1) ∑=0[infinity]37 1(−2)
The Taylor series for f(x) = e^(7x) centered at c = -1 is e^(-7) - 7e^(-7)(x+1) + 49e^(-7)(x+1)^2/2! - 343e^(-7)(x+1)^3/3! + 2401e^(-7)(x+1)^4/4! - ...
The Taylor series for a function f(x) centered at c is given by
f(x) = f(c) + f'(c)(x-c)/1! + f''(c)(x-c)^2/2! + f'''(c)(x-c)^3/3! + ...
To find the Taylor series for f(x) = e^(7x) centered at c = -1, we will need to calculate the derivatives of f(x) at c = -1.
f(x) = e^(7x)
f'(x) = 7e^(7x)
f''(x) = 49e^(7x)
f'''(x) = 343e^(7x)
f''''(x) = 2401e^(7x)
...
Evaluating these derivatives at c = -1, we get
f(-1) = e^(-7)
f'(-1) = -7e^(-7)
f''(-1) = 49e^(-7)
f'''(-1) = -343e^(-7)
f''''(-1) = 2401e^(-7)
...
Substituting these values into the Taylor series formula, we get:
e^(7x) = e^(-7) - 7e^(-7)(x+1) + 49e^(-7)(x+1)^2/2! - 343e^(-7)(x+1)^3/3! + 2401e^(-7)(x+1)^4/4! - ...
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The given question is incomplete, the complete question is:
Find the Taylor series centered at c= -1, f(x) = e^(7x)
solve the initial-value problem 2y′′−7y′ 3y=0,y(0)=5,y′(0)=10.
The characteristic equation is [tex]$2r^2-7r+3=0$[/tex], which can be factored as [tex]$(2r-1)(r-3)=0$[/tex]. Hence, the roots are [tex]$r_1=\frac{1}{2}$[/tex] and[tex]$r_2=3$[/tex], and the general solution is given by
[tex]$$y(x)=c_1 e^{r_1 x}+c_2 e^{r_2 x}=c_1 e^{\frac{1}{2} x}+c_2 e^{3 x} .$$[/tex]
Taking the first derivative of [tex]\mathrm{y}(\mathrm{x})[/tex], we have [tex]$y^{\prime}(x)=\frac{1}{2} c_1 e^{\frac{1}{2} x}+3 c_2 e^{3 x}$[/tex].
Taking the second derivative of[tex]\mathrm{y}(\mathrm{x})[/tex], we have [tex]$y^{\prime \prime}(x)=\frac{1}{4} c_1 e^{\frac{1}{2} x}+9 c_2 e^{3 x}$[/tex].
Substituting these expressions into the differential equation [tex]2 y^{\prime \prime}-7 y^{\prime}+3 y=0[/tex], we obtain [tex]$\left(\frac{1}{2} c_1 e^{\frac{1}{2} x}+27 c_2 e^{3 x}\right)-7\left(\frac{1}{2} c_1 e^{\frac{1}{2} x}+3 c_2 e^{3 x}\right)+3\left(c_1 e^{\frac{1}{2} x}+c_2 e^{3 x}\right)=0$[/tex], which simplifies to[tex]$-\frac{1}{2} c_1 e^{\frac{1}{2} x}-3 c_2 e^{3 x}=0$[/tex].
We can solve for[tex]c_2[/tex] in terms of [tex]c_{1}[/tex] by dividing both sides by [tex]-3 \mathrm{e}^{\wedge}\{3 \mathrm{x}\} : c_2=[/tex] [tex]$-\frac{1}{6} c_1 e^{-\frac{7}{2} x}$[/tex]
Using the initial conditions [tex]\mathrm{y}(0)=5[/tex] and [tex]y^{\prime}(0)=10[/tex], we have [tex]$c_1+c_2=5, \quad \frac{1}{2} c_1+$[/tex] [tex]$3 c_2=10$[/tex]
Substituting the expression for [tex]C_2[/tex] in terms of [tex]c_1[/tex], we obtain [tex]$c_1-\frac{1}{6} c_1=$[/tex] 5
Solving for [tex]c_1[/tex] and [tex]c_2[/tex], we get [tex]$c_1=-\frac{36}{11}, \quad c_2=\frac{61}{66}$[/tex].
Therefore, the solution to the initial-value problem is [tex]$y(x)=-\frac{36}{11} e^{\frac{1}{2} x}+\frac{61}{66} e^{3 x}$[/tex].
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a) Work out the size of angle x.
b) Give reasons for your answer.
I need help on the reasoning please
Answer:80
Step-by-step explanation:
first, we can find out angle dbf which is 80 as angles on a straight line sum to 180, then we can enforce the alternate angles concept
Hi, so I got this question wrong, the answers I got for blank 1 was [-pi/2,pi/2]
and for blank 2 [0, pi] is this not correct? And if it's not what should I put instead?
To find the restricted range for the inverse function of sine, we represent y as follows: (y = sin⁻¹x) is [-π/2, π/2].
To find the restricted range for the inverse function of cosine, we would have; (y = cos⁻¹x) is [0, π]
What is the restricted range?The restricted range refers to the ability to specify a function criterion such that the population data would meet that criterion. For the above problem, we are to get the inverse functions of sine and cosine by restricting the range.
This can be obtained as follows:
[-π/2, π/2] for the function sine and
[0, π] for the function cosine.
Thus, the restricted ranges are [-π/2, π/2] and [0, π] respectively.
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The sample space for tossing a coin 4 times is {HHHH, HHHT, HHTH, HHTT, HTHH, HTHT, HTTH, HTTT, THHH, THHT, THTH, THTT, TTHH, TTHT, TTTH, TTTT}.
Determine P(3 tails).
8.5%
25%
31.25%
63.75%
The probability of getting exactly 3 tails when tossing a coin 4 times is 25%.
Determining the value of P(3 tails).From the question, we have the following parameters that can be used in our computation:
{HHHH, HHHT, HHTH, HHTT, HTHH, HTHT, HTTH, HTTT, THHH, THHT, THTH, THTT, TTHH, TTHT, TTTH, TTTT}.
There are 16 equally likely outcomes in the sample space.
Out of these, there are 4 outcomes that have exactly 3 tails: TTTH, TTHT, THTT, and HTTT.
Therefore, P(3 tails) = 4/16 = 1/4 = 0.25.
So, the probability of getting exactly 3 tails when tossing a coin 4 times is 0.25 or 25%.
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find the rate of change of total revenue, cost, and profit with respect to time. assume that r(x) and c(x) are in dollars. r(x)=45x−0.5x^2, c(x)=2x + 15, when x=25 and dx/dt=20 units per day The rate of change of total revenue is $ ____
per day. The rate of change of total cost is $_____per day. The rate of change of total profit is $____ per day.
Rate of change of total revenue is $22500 per day.
Rate of change of total cost is $800 per day.
Rate of change of total profit is $31250 per day.
Describe indetaill method to calculate total revenue, total cost and total profit?The total revenue is given by TR(x) = x * R(x), where R(x) is the revenue function. Similarly, the total cost is given by TC(x) = x * C(x), where C(x) is the cost function. The total profit is given by TP(x) = TR(x) - TC(x).
Given, R(x) = 45x - 0.5x² and C(x) = 2x + 15, we have:
TR(x) = x * (45x - 0.5x²) = 45x² - 0.5x^3
TC(x) = x * (2x + 15) = 2x² + 15x
TP(x) = TR(x) - TC(x) = 45x² - 0.5x³ - 2x² - 15x = -0.5x³ + 43x² - 15x
To find the rate of change of total revenue, we differentiate TR(x) with respect to time t:
d(TR)/dt = d/dt(x * (45x - 0.5x²)) = (45x - 0.5x²) * dx/dt
Substituting x = 25 and dx/dt = 20, we get:
d(TR)/dt = (45(25) - 0.5(25)²) * 20 = 22500
Therefore, the rate of change of total revenue is $22500 per day.
Similarly, to find the rate of change of total cost, we differentiate TC(x) with respect to time t:
d(TC)/dt = d/dt(x * (2x + 15)) = (2x + 15) * dx/dt
Substituting x = 25 and dx/dt = 20, we get:
d(TC)/dt = (2(25) + 15) * 20 = 800
Therefore, the rate of change of total cost is $800 per day.
To find the rate of change of total profit, we differentiate TP(x) with respect to time t:
d(TP)/dt = d/dt(-0.5x³ + 43x² - 15x) = (-1.5x² + 86x - 15) * dx/dt
Substituting x = 25 and dx/dt = 20, we get:
d(TP)/dt = (-1.5(25)² + 86(25) - 15) * 20 = 31250
Therefore, the rate of change of total profit is $31250 per day.
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let the random variables x and y have a joint pdf which is uniform over the triangle with vertices at (0,0) , (0,1) , and (1,0).
The joint PDF which is uniform over the triangle with vertices is:
f(x,y) = 2, 0 ≤ x ≤ 1, 0 ≤ y ≤ 1-x.
How to find x and y have a joint pdf which is uniform over the triangle with vertices?Since the joint PDF is uniform over the triangle with vertices at (0,0), (0,1), and (1,0), the joint PDF can be expressed as:
f(x,y) = c, 0 ≤ x ≤ 1, 0 ≤ y ≤ 1-x,
where c is a constant that ensures that the total probability over the entire region is equal to 1. To find c, we can integrate the joint PDF over the entire region:
[tex]\int \int f(x,y)dydx = \int ^1_0 \int _0^{(1-x)} c dydx[/tex]
[tex]= \int ^1_0 cx - cx^2/2 dx[/tex]
= c/2
Since the total probability over the entire region must be equal to 1, we have:
∫∫f(x,y)dydx = 1
Thus, we have:
c/2 = 1
c = 2
Therefore, the joint PDF is:
f(x,y) = 2, 0 ≤ x ≤ 1, 0 ≤ y ≤ 1-x.
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you are dealt two cards successively (without replacement) from a shuffled deck of 52 playing cards. find the probability that both cards are jacks. 0.154 0.005 0.033 0.006
The probability of drawing two jacks in a row from a deck of 52 cards without replacement is equal to option(B) 0.005.
Total number of cards in a deck = 52
Number of Jack in deck of cards = 4
Probability of getting a jack on the first draw is
= 4/52
Now, there are only 3 jacks remaining in a deck of 51 cards.
This implies,
Probability of drawing another jack on the second draw given that the first card was a jack
= 3/51
Probability of drawing two jacks in a row,
Multiply the probability of drawing
= (a jack on first draw by another jack on second draw given first card was a jack)
⇒ P(two jacks)
= (4/52) × (3/51)
= 1/13 × 1/17
= 1/221
= 0.00452489
= 0.005 (rounded to three decimal places).
Therefore, the probability of drawing two jacks in a row is equal to option(B) 0.005.
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The probability of drawing two jacks in a row from a deck of 52 cards without replacement is equal to option(B) 0.005.
Total number of cards in a deck = 52
Number of Jack in deck of cards = 4
Probability of getting a jack on the first draw is
= 4/52
Now, there are only 3 jacks remaining in a deck of 51 cards.
This implies,
Probability of drawing another jack on the second draw given that the first card was a jack
= 3/51
Probability of drawing two jacks in a row,
Multiply the probability of drawing
= (a jack on first draw by another jack on second draw given first card was a jack)
⇒ P(two jacks)
= (4/52) × (3/51)
= 1/13 × 1/17
= 1/221
= 0.00452489
= 0.005 (rounded to three decimal places).
Therefore, the probability of drawing two jacks in a row is equal to option(B) 0.005.
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Venus Flycatcher Company sells exotic plants and is trying to decide which of two hybrid plants to introduce into their product line. Demand Probabilities 4 3 3Hybrid/Demand Hybrid 1 Hybrid 2Low Medium high-10,000 10.000 30.000-15,000 10.000 35.000a. If Venus wants to maximize expected profits, which Hybrid should be introduced? b. What is the most that Venus would pay for a highly reliable demand forecast?
To determine which hybrid plant to introduce, we need to calculate the expected profits for each option. The profits for each option depend on the demand for the plant and the cost of producing it. Let's assume that the cost of producing each hybrid plant is the same and equal to $5,000.
a) Expected profits for Hybrid 1:
If demand is low: profit = (10,000 - 5,000) = $5,000
If demand is medium: profit = (10,000 - 5,000) = $5,000
If demand is high: profit = (30,000 - 5,000) = $25,000
Expected profit for Hybrid 1 = (4/10)*5,000 + (3/10)*5,000 + (3/10)*25,000 = $13,000
Expected profits for Hybrid 2:
If demand is low: profit = (15,000 - 5,000) = $10,000
If demand is medium: profit = (10,000 - 5,000) = $5,000
If demand is high: profit = (35,000 - 5,000) = $30,000
Expected profit for Hybrid 2 = (4/10)*10,000 + (3/10)*5,000 + (3/10)*30,000 = $16,500
Therefore, if Venus wants to maximize expected profits, they should introduce Hybrid 2.
b) To determine the most that Venus would pay for a highly reliable demand forecast, we need to calculate the expected value of perfect information (EVPI). The EVPI is the difference between the expected profits with perfect information and the expected profits under uncertainty.
With perfect information, Venus would know exactly which hybrid plant to introduce based on the demand. The expected profits with perfect information would be:
If demand is low: profit = (15,000 - 5,000) = $10,000
If demand is medium: profit = (10,000 - 5,000) = $5,000
If demand is high: profit = (35,000 - 5,000) = $30,000
Expected profit with perfect information = (4/10)*10,000 + (3/10)*5,000 + (3/10)*30,000 = $16,500
The expected profits under uncertainty for Hybrid 2 (the preferred option) are $16,500. Therefore, the EVPI is:
EVPI = Expected profit with perfect information - Expected profit under uncertainty = $16,500 - $16,500 = $0
This means that Venus should not be willing to pay anything for a highly reliable demand forecast since it would not increase their expected profits.
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which one is the correct answer?
Answer: B
Step-by-step explanation: 21+12= 33.
45 - 33 = 12.
red came 21 times, which is too much. blue came 12 times, which is exactly the same as green.
hope this helps, please make me the brainliest answer
Answer:
D
Step-by-step explanation:
write the set of points from −6 to 0 but excluding −5 and 0 as a union of intervals:
The union symbol (∪) means that we are combining all three intervals into a single set.
The set of points from -6 to 0 but excluding -5 and 0 can be expressed as a union of intervals as follows:
(-6, -5) U (-5, 0) U (0, 6)
This means that the set includes all real numbers from -6 to 6, except for -5 and 0, which are excluded. The parentheses indicate that the endpoints (-6, -5, 0, and 6) are not included in the set. The union symbol (∪) means that we are combining all three intervals into a single set.
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how many lattice paths exist from ( 0 , 0 ) (0,0) to ( 17 , 15 ) (17,15) that pass through ( 7 , 5 ) (7,5)?
There are 7,210,800 lattice paths from (0,0) to (17,15) through (7,5) calculated using the principle of inclusion-exclusion.
To begin with, we number the number of cross-section ways from (0,0) to (17,15) without any limitations. To do this, we have to take add up to 17 steps to the proper and 15 steps up, for a add up to 32 steps.
We will speak to each step by an R or U (for right or up), and so the issue decreases to checking the number of stages of 17 R's and 15 U's. This will be calculated as:
(32 select 15) = 8,008,015
Next, we check the number of grid ways from (0,0) to (7,5) and from (7,5) to (17,15). To tally the number of ways from (0,0) to (7,5), we have to take add up to 7 steps to the proper and 5 steps up, to add up to 12 steps.
The number of such ways is (12 select 5) = 792. To check the number of ways from (7,5) to (17,15), we have to take add up to 10 steps to the proper and 10 steps up, to add up to 20 steps.
The number of such ways is (20 select 10) = 184,756.
In any case, we have double-counted the ways that pass through (7,5).
To adjust for this, subtract the number of paths from (0,0) to (7.5) that pass through (7.5) and the number of paths from (7.5) to (17.15 ) that also pass through (7.5).
To tally the number of ways from (0,0) to (7,5) that pass through (7,5), we got to take a add up to of 6 steps to the correct and 4 steps up, for a add up to 10 steps.
The number of such paths is (10 select 4) = 210. To count the number of ways from (7,5) to (17,15) that pass through (7,5), we have to take add up to 3 steps to the right and 5 steps up, to add up to 8 steps.
The number of such ways is (8 select 3) = 56.
Subsequently, the number of grid ways from (0,0) to (17,15) that pass through (7,5) is:
(32 select 15) - (12 select 5)(20 select 10) + (10 select 4)(8 select 3) = 7,210,800
So there are 7,210,800 grid paths from (0,0) to (17,15) through (7,5).
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Please sort all trees on 8 vertices into homeomorphism classes 2. Show that the graph G (defined later) is not planar in two ways: (1) Use Kuratowski's Theorem, and (2) use the Euler identity n-e+f=2 Define G = (VE) as follows. Let V = (2-sets of[5]], with vertices x and y adjacent if and only if x ny=0.
G is non-planar as embedded in 3-dimensional space and it is not possible for a planar graph to have more than 2 faces that are not unbounded.
How to find planer or non-planner?There are 5 homeomorphism classes of trees on 8 vertices:
The star graph, which has one central vertex with degree 7 and 7 leaves with degree 1.The tree with maximum degree 3, which has 4 vertices of degree 3 and 4 leaves of degree 1.The tree with maximum degree 4, which has 2 vertices of degree 4, 2 vertices of degree 3, and 4 leaves of degree 1.The tree with maximum degree 5, which has 1 vertex of degree 5, 3 vertices of degree 4, and 4 leaves of degree 1.The tree with maximum degree 6, which has 1 vertex of degree 6, 1 vertex of degree 5, 2 vertices of degree 4, and 4 leaves of degree 1.Now, let's consider the graph G defined as follows:
V = {all 2-sets of [5]}
E = {(x,y) | x and y are adjacent iff x ∩ y = ∅}
To show that G is not planar, we will use Kuratowski's Theorem and the Euler identity.
(1) Kuratowski's Theorem:
A graph is non-planar if and only if it contains a subgraph that is a subdivision of K5 (the complete graph on 5 vertices) or K3,3 (the complete bipartite graph on 6 vertices with 3 vertices in each partition).
To show that G is non-planar using Kuratowski's Theorem, we need to find a subgraph of G that is a subdivision of K5 or K3,3. We can do this by considering the vertices of G as the sets {1,2}, {1,3}, {1,4}, {1,5}, {2,3}, {2,4}, {2,5}, {3,4}, {3,5}, and {4,5}. Now, we can construct a subgraph of G that is a subdivision of K5 as follows:
Start with the vertex {1,2}.Add the vertices {1,3}, {1,4}, {1,5}, and {2,3} and connect them to {1,2}.Add the vertices {2,4}, {2,5}, and {3,4} and connect them to {2,3}.Add the vertex {3,5} and connect it to {1,4} and {2,5}.The resulting subgraph is a subdivision of K5, which means that G is non-planar.
(2) Euler identity:
In a planar graph, the number of vertices (n), edges (e), and faces (f) satisfy the identity n - e + f = 2.
To show that G is non-planar using the Euler identity, we need to find a contradiction in the identity. We can do this by counting the number of vertices, edges, and faces in G. G has 10 vertices and each vertex is adjacent to 8 other vertices, so there are a total of 40 edges in G. We can then use Euler's identity to calculate the number of faces:
[tex]n - e + f = 2\\10 - 40 + f = 2\\f = 32[/tex]
This means that G has 32 faces. However, this is a contradiction since G is a planar graph embedded in 3-dimensional space and it is not possible for a planar graph to have more than 2 faces that are not unbounded. Therefore, G is non-planar.
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Evaluate the line integral integral ∫C(3x−y)ds, where C is the quarter-circle x2+y2=9 from (0, 3) to (3, 0).
We can parameterize the quarter-circle C by using the parameter t to represent the angle that the line connecting the point (3, 0) and the point on the circle makes with the x-axis. So, the line integral ∫C(3x−y)ds = 9.
To evaluate the line integral ∫C(3x−y)ds, where C is the quarter-circle x^2 + y^2 = 9 from (0, 3) to (3, 0), we need to parameterize the curve and compute the integral.
1. Parameterize the curve: For the quarter-circle, we can use polar coordinates. Since x = r*cos(θ) and y = r*sin(θ), we have:
x = 3*cos(θ)
y = 3*sin(θ)
where θ goes from 0 to π/2 for the given quarter-circle.
2. Compute the derivatives:
dx/dθ = -3*sin(θ)
dy/dθ = 3*cos(θ)
3. Find the magnitude of the tangent vector:
|d/dθ| = sqrt((dx/dθ)^2 + (dy/dθ)^2) = sqrt(9*(sin^2(θ) + cos^2(θ))) = 3
4. Substitute the parameterization into the integrand:
(3x - y) = 3(3*cos(θ) - 3*sin(θ))
5. Evaluate the line integral:
∫C(3x−y)ds = ∫₀^(π/2) (3*(3*cos(θ) - 3*sin(θ)))*3 dθ = 9 ∫₀^(π/2) (cos(θ) - sin(θ)) dθ
Now, we can integrate with respect to θ:
= 9 [sin(θ) + cos(θ)]₀^(π/2) = 9 [(sin(π/2) + cos(π/2)) - (sin(0) + cos(0))] = 9 * (1 - 1 + 1) = 9.
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The surface area of a cone is 250 square centimeters. The height of the cone is double the length of its radius. What is the height of the cone to the nearest centimeter?
The height of the cone to the nearest centimeter is, 10 centimeters.
Therefore, option A is the correct answer.
Given that,
the surface area of a cone is 250 square centimeters. The height of the cone is double the length of its radius.
We need to find what is the height of the cone to the nearest centimeter.
If the radius of the base of the cone is "r" and the slant height of the cone is "l",
And, the surface area of a cone is given as total surface area,
SA = πr(r + l) square units
Now, let the radius of a cone be x.
Then the height of the cone is 2x.
Slant height=√x²+4x²
=√5x
So, the surface area of cone=πx(x+2.24x)
⇒250=3.14 × 3.24x²
⇒x²=24.57
⇒x=4.95≈5 centimeter
So, height=2x=10 centimeter
Hence, The height of the cone to the nearest centimeter is 10 centimeters.
Therefore, option A is the correct answer.
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The amount of time spent by North American adults watching television per day is normally distributed with a mean of 6 hours and a standard deviation of 1.5 hours.
a. What is the probability that a randomly selected North American adult watches television for more than 7 hours per day?
b. What is the probability that the average time watching television by a random sample of five North American adults is more than 7 hours?
c. What is the probability that, in a random sample of five North American adults, all watch television for more than 7 hours per day?
a,b. We are given that the amount of time spent by North American adults watching television per day follows a normal distribution with mean μ = 6 hours and standard deviation σ = 1.5 hours.
c. Therefore, the probability that all five North American adults in the sample watch television for more than 7 hours per day is approximately 0.00001.
a. We need to find P(X > 7), where X is the random variable representing the amount of time spent watching TV. Using the standard normal distribution, we can standardize X as follows:
Z = (X - μ) / σ = (7 - 6) / 1.5 = 0.67
b. Using a standard normal table or calculator, we can find P(Z > 0.67) ≈ 0.2514. Therefore, the probability that a randomly selected North American adult watches television for more than 7 hours per day is approximately 0.2514.
c. We need to find:[tex]P(X_1 > 7 AND X_2 > 7 AND X_3 > 7 AND X_4 > 7 AND X_5 > 7)[/tex],
where [tex]X_1, X_2, X_3, X_4, & X_5[/tex] are the random variables representing the amount of time spent watching TV by each individual in the sample. Since the TV-watching times are independent and identically distributed, we have:
[tex]P(X_1 > 7 AND X_2 > 7 AND X_3 > 7 AND X_4 > 7 AND X_5 > 7) = P(X > 7)^5[/tex]
Using the value of P(X > 7) from part (a), we get:
[tex]P(X_1 > 7 AND X_2 > 7 AND X_3 > 7 AND X_4 > 7 AND X_5 > 7)[/tex] ≈ 0.2514^5 ≈ 0.00001
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plsss answer correctly my grade depends on it
Answer: 4 km
Step-by-step explanation:
You use the Pythagorean theorem: [tex]a^{2} +b^{2} =c^{2}[/tex]
So 2^2 + 3^2 = c^2
C=[tex]\sqrt{13}[/tex] or 3.60555
Then you round to the nearest km to get 4
Find the center of mass of the given system of point masses lying on the x-axis. m1 = 0.1, m2 = 0.3, m3 = 0.4, m4 = 0.2 X1 = 1, X2 = 2, X3 = 3, x4 = 4
The center of mass of the given system of point masses lying on the x-axis is (2.6, 0).
To find the center of mass, we need to use the formula:
xcm = (m1x1 + m2x2 + m3x3 + m4x4) / (m1 + m2 + m3 + m4)
Plugging in the values, we get:
xcm = (0.1 * 1 + 0.3 * 2 + 0.4 * 3 + 0.2 * 4) / (0.1 + 0.3 + 0.4 + 0.2) = 2.6
So the x-coordinate of the center of mass is 2.6.
Since all the masses are lying on the x-axis, the y-coordinate of the center of mass will be 0.
Therefore, the center of mass of the given system of point masses lying on the x-axis is (2.6, 0).
The center of mass is the point at which the entire mass of a system can be considered to be concentrated. It is the point at which a force can be applied to the system to cause it to move as a whole, without causing any rotation. To find the center of mass of a system of point masses, we use the formula that takes into account the masses and their positions. In this case, all the masses are lying on the x-axis, so we only need to consider the x-coordinates. By adding up the products of the masses and their respective x-coordinates, and dividing by the total mass, we can find the x-coordinate of the center of mass. The y-coordinate will be 0 since all the masses are on the x-axis.
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The center of mass of the given system of point masses lying on the x-axis is (2.6, 0).
To find the center of mass, we need to use the formula:
xcm = (m1x1 + m2x2 + m3x3 + m4x4) / (m1 + m2 + m3 + m4)
Plugging in the values, we get:
xcm = (0.1 * 1 + 0.3 * 2 + 0.4 * 3 + 0.2 * 4) / (0.1 + 0.3 + 0.4 + 0.2) = 2.6
So the x-coordinate of the center of mass is 2.6.
Since all the masses are lying on the x-axis, the y-coordinate of the center of mass will be 0.
Therefore, the center of mass of the given system of point masses lying on the x-axis is (2.6, 0).
The center of mass is the point at which the entire mass of a system can be considered to be concentrated. It is the point at which a force can be applied to the system to cause it to move as a whole, without causing any rotation. To find the center of mass of a system of point masses, we use the formula that takes into account the masses and their positions. In this case, all the masses are lying on the x-axis, so we only need to consider the x-coordinates. By adding up the products of the masses and their respective x-coordinates, and dividing by the total mass, we can find the x-coordinate of the center of mass. The y-coordinate will be 0 since all the masses are on the x-axis.
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In each of Problems 13 through 16, find the inverse Laplace transform of the given function. 13. F(s)=(s−2)43! 14. F(s)=s2+s−2e−2s 15. F(s)=s2−2s+22(s−1)e−2s 16. F(s)=se−s+e−2s−e−3s−e−4s
The inverse Laplace transform of the given function f(t) are (1/6)t^3 - 1/30, t^2 + t - 3e^(-2t), t(e^t - te^t) + 2u(t-2)e^(t-2), (1/4)*[1 - e^(t-2) - 2e^(t-3) + 3e^(t-4)]*u(t-4) and e^(-t) + e^(-2t) - e^(-3t) - e^(-4t).
Using the formula for the inverse Laplace transform of a constant multiple of a function, we can see that
L⁻¹[(s-2)/(4!)] = L⁻¹[s/(4!)] - 2L⁻¹[1/(4!)]
= 1/3! * t^3 - 2/4!
= (1/6)t^3 - 1/30
So, the inverse Laplace transform of F(s) = (s-2)/(4!) is (1/6)t^3 - 1/30.
To find the inverse Laplace transform of F(s) = s^2 + s - 2e^(-2s), we can first use partial fractions to write
F(s) = (s+2)(s-1) - 3/(s+2)
Then, we can use the formulas for the inverse Laplace transform of the terms on the right-hand side
L⁻¹[(s+2)(s-1)] = L⁻¹[s^2 + s] = t^2 + t
L⁻¹[3/(s+2)] = 3e^(-2t)
So, by linearity of the inverse Laplace transform, we have
L⁻¹[F(s)] = L⁻¹[(s+2)(s-1)] - L⁻¹[3/(s+2)] = t^2 + t - 3e^(-2t)
Therefore, the inverse Laplace transform of F(s) is t^2 + t - 3e^(-2t).
We can start by factoring the numerator of F(s)
F(s) = (s-1)(s-1)e^(-2s) + 2e^(-2s)
Then, we can use the formulas for the inverse Laplace transform of the terms on the right-hand side
L⁻¹[(s-1)(s-1)e^(-2s)] = L⁻¹[(s-1)^2/s] = t(e^t - te^t)
L⁻¹[2e^(-2s)] = 2L⁻¹[e^(-2s)] = 2u(t-2)
where u(t) is the unit step function.
So, by linearity of the inverse Laplace transform, we have
L⁻¹[F(s)] = L⁻¹[(s-1)(s-1)e^(-2s)] + L⁻¹[2e^(-2s)/(s-1)]
= t(e^t - te^t) + 2u(t-2)e^(t-2)
Therefore, the inverse Laplace transform of F(s) is t(e^t - te^t) + 2u(t-2)e^(t-2).
To find the inverse Laplace transform of F(s) = s*e^(-s) + e^(-2s) - e^(-3s) - e^(-4s), we can use partial fraction decomposition and standard Laplace transforms.
First, let's rewrite F(s) as a sum of four terms
F(s) = s*e^(-s) + e^(-2s) - e^(-3s) - e^(-4s)
= s/(s+1) + 1/(s+2) - 1/(s+3) - 1/(s+4)
Next, we can find the inverse Laplace transform of each term using the Laplace transform table
L^-1{s/(s+1)} = e^(-t)
L^-1{1/(s+2)} = e^(-2t)
L^-1{-1/(s+3)} = -e^(-3t)
L^-1{-1/(s+4)} = -e^(-4t)
Therefore, the inverse Laplace transform of F(s) is
L^-1{F(s)} = e^(-t) + e^(-2t) - e^(-3t) - e^(-4t)
So the inverse Laplace transform of F(s) is a sum of exponential functions, each with a negative exponent.
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The inverse Laplace transform of the given function f(t) are (1/6)t^3 - 1/30, t^2 + t - 3e^(-2t), t(e^t - te^t) + 2u(t-2)e^(t-2), (1/4)*[1 - e^(t-2) - 2e^(t-3) + 3e^(t-4)]*u(t-4) and e^(-t) + e^(-2t) - e^(-3t) - e^(-4t).
Using the formula for the inverse Laplace transform of a constant multiple of a function, we can see that
L⁻¹[(s-2)/(4!)] = L⁻¹[s/(4!)] - 2L⁻¹[1/(4!)]
= 1/3! * t^3 - 2/4!
= (1/6)t^3 - 1/30
So, the inverse Laplace transform of F(s) = (s-2)/(4!) is (1/6)t^3 - 1/30.
To find the inverse Laplace transform of F(s) = s^2 + s - 2e^(-2s), we can first use partial fractions to write
F(s) = (s+2)(s-1) - 3/(s+2)
Then, we can use the formulas for the inverse Laplace transform of the terms on the right-hand side
L⁻¹[(s+2)(s-1)] = L⁻¹[s^2 + s] = t^2 + t
L⁻¹[3/(s+2)] = 3e^(-2t)
So, by linearity of the inverse Laplace transform, we have
L⁻¹[F(s)] = L⁻¹[(s+2)(s-1)] - L⁻¹[3/(s+2)] = t^2 + t - 3e^(-2t)
Therefore, the inverse Laplace transform of F(s) is t^2 + t - 3e^(-2t).
We can start by factoring the numerator of F(s)
F(s) = (s-1)(s-1)e^(-2s) + 2e^(-2s)
Then, we can use the formulas for the inverse Laplace transform of the terms on the right-hand side
L⁻¹[(s-1)(s-1)e^(-2s)] = L⁻¹[(s-1)^2/s] = t(e^t - te^t)
L⁻¹[2e^(-2s)] = 2L⁻¹[e^(-2s)] = 2u(t-2)
where u(t) is the unit step function.
So, by linearity of the inverse Laplace transform, we have
L⁻¹[F(s)] = L⁻¹[(s-1)(s-1)e^(-2s)] + L⁻¹[2e^(-2s)/(s-1)]
= t(e^t - te^t) + 2u(t-2)e^(t-2)
Therefore, the inverse Laplace transform of F(s) is t(e^t - te^t) + 2u(t-2)e^(t-2).
To find the inverse Laplace transform of F(s) = s*e^(-s) + e^(-2s) - e^(-3s) - e^(-4s), we can use partial fraction decomposition and standard Laplace transforms.
First, let's rewrite F(s) as a sum of four terms
F(s) = s*e^(-s) + e^(-2s) - e^(-3s) - e^(-4s)
= s/(s+1) + 1/(s+2) - 1/(s+3) - 1/(s+4)
Next, we can find the inverse Laplace transform of each term using the Laplace transform table
L^-1{s/(s+1)} = e^(-t)
L^-1{1/(s+2)} = e^(-2t)
L^-1{-1/(s+3)} = -e^(-3t)
L^-1{-1/(s+4)} = -e^(-4t)
Therefore, the inverse Laplace transform of F(s) is
L^-1{F(s)} = e^(-t) + e^(-2t) - e^(-3t) - e^(-4t)
So the inverse Laplace transform of F(s) is a sum of exponential functions, each with a negative exponent.
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Find the median class size
The median class size, would be 40–50.
How to find the median class size ?First, find the total frequency to be :
= 4 + 12 + 24 + 36 + 20+ 16 + 8 + 5
= 125
The median would be located at :
= (125 + 1 ) / 2
= 63 rd position
Cumulative frequency
10–20 4
20–30 16
30–40 40
This means that the median class would be 40–50 as this interval has a cumulative frequency of 76 which means the 63 rd number is there.
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The rest of the question is :
Find Median:- Class interval : 10–20 20–30 30–40 40–50 50–60 60–70 70–80 Frequency: 4 12 24 36 20 16 8 5
let (,)f(x,y) be a 2c^2 function which has a local maximum at (0,0)(0,0) . then the hessian matrix of f at (0,0)(0,0) is necessarily negative definite. True or False
We cannot conclude that the Hessian matrix of f at (0,0) is necessarily negative definite.
False.
The Hessian matrix of a function f(x,y) at a critical point (a,b) is the matrix of second-order partial derivatives evaluated at (a,b). In this case, the Hessian matrix of f at (0,0) is:
H = [f_xx(0,0) f_xy(0,0)]
[f_xy(0,0) f_yy(0,0)]
Since f has a local maximum at (0,0), we know that f_x(0,0) = f_y(0,0) = 0, and that the leading term of f in the Taylor expansion around (0,0) is negative (because it's a local maximum). However, this information alone is not enough to determine the sign of the Hessian matrix.
For example, consider the function f(x,y) = -x^4 - y^4. This function has a local maximum at (0,0), and its Hessian matrix at (0,0) is:
H = [-12 0]
[ 0 -12]
This matrix is negative definite (i.e., it has negative eigenvalues), but there are also examples where the Hessian matrix is positive definite or indefinite. Therefore, we cannot conclude that the Hessian matrix of f at (0,0) is necessarily negative definite.
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41) Triangle CAT has vertices
C(-9,9), A(-3,3), and T(-6,0). If ABUG has vertices B(-3,3), U(-1, 1), and
G(-2,0). Is ACAT similar to ABUG? If so, what transformation maps ACAT onto ABUG?
A. No, dilation centered at the origin with scale factor of 3.
B. No, dilation centered at the origin with scale factor of
C. Yes, dilation centered at the origin with scale factor of 3.
D. Yes, dilation centered at the origin with scale factor of
Answer: Yes, dilation centered at the origin with scale factor of 3.
Step-by-step explanation:
Two figures are similar if they have the same shape, but possibly different sizes. In order to check whether two triangles are similar, we need to check whether their corresponding angles are congruent and whether their corresponding side lengths are proportional.
We can see that triangle ACAT and triangle ABUG have corresponding angles that are congruent, and their corresponding side lengths are proportional with a ratio of 3 (i.e., AC = 3AB, AT = 3AU, and CT = 3UG). Therefore, triangle ACAT is similar to triangle ABUG.
To map triangle ACAT onto triangle ABUG, we need a transformation that scales each point by a factor of 3 about the origin (since the dilation is centered at the origin). Therefore, the correct answer is option (C).
Answer: yes
Step-by-step explanation THE Answer the length of the median
is 11.4 units.
Step 1. Given Information.
Given triangle CAT has vertices
,
and
. M is the midpoint of
.
The length of the median
is to be determined.
Step 2. Explanation.
The midpoint of two points
is given by
.
Plugging the values in the equation to find the point M:
The distance between two points
is given by
.
Plugging the given values in the equation to find the distance between C and M:
Step 3. Conclusion.
Hence, the length of the median
is 11.4 units.
which of the following are necessary when proving that the opposite angles of a parallelogram are congruent. Check all answers that apply
The theorems that are necessary when proving that the opposite angles of a parallelogram are congruent are;
B. Angle Addition Postulate.
D. Corresponding parts of congruent triangles are congruent.
How do you know that opposite angles of a parallelogram are congruent?The pairs of alternate internal angles are congruent when two parallel lines are intersected by a transversal, such as a line that crosses through both lines.
When two sides of a parallelogram are parallel, the angles created by the transversal that cuts through them are alternate internal angles.
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Missing parts;
Which of the following are necessary when proving that the opposite angles of a parallelogram are congruent?
Check all that apply.
A. Corresponding parts of similar triangles are similar.
B. Angle Addition Postulate.
C. Segment Addition Postulate.
D. Corresponding parts of congruent triangles are congruent.
1/1×2+1/2×3+...+1/n(n+1)
by examining the values of this expression for small values of n.
b.Prove the formula you conjectured in part (a)
The expression 1/1×2 + 1/2×3 + ... + 1/n(n+1) can be written as Σ(k=1 to n) 1/k(k+1). After examining the values of this expression for small values of n, we can conjecture that the formula for this expression is 1 - 1/(n+1).
To prove this formula, we can use mathematical induction.
We need to prove that 1/1×2 + 1/2×3 + ... + 1/n(n+1) = 1 - 1/(n+1) for all positive integers n.
First, we can show that the formula is true for n = 1:
1/1×2 = 1 - 1/2
Next, we assume that the formula is true for some positive integer k, and we want to prove that it is also true for k+1.
Assuming the formula is true for k, we have:
1/1×2 + 1/2×3 + ... + 1/k(k+1) = 1 - 1/(k+1)
Adding (k+1)/(k+1)(k+2) to both sides, we get:
1/1×2 + 1/2×3 + ... + 1/k(k+1) + (k+1)/(k+1)(k+2) = 1 - 1/(k+1) + (k+1)/(k+1)(k+2)
Simplifying the right side, we get:
1/1×2 + 1/2×3 + ... + 1/k(k+1) + (k+1)/(k+1)(k+2) = 1 - 1/(k+2)
Therefore, the formula is true for k+1 as well.
By mathematical induction, the formula is true for all positive integers n.
Thus, we have proved that 1/1×2 + 1/2×3 + ... + 1/n(n+1) = 1 - 1/(n+1) for all positive integers n.
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Evaluate the iterated integral.
π/2
0
y/7
0
4/y sin y dz dx dy
0
To evaluate this iterated integral, we first need to integrate with respect to z from 0 to sin(y). This will give us an expression involving sin(y). Next, we integrate this expression with respect to x from 0 to y/7. Finally, we integrate the resulting expression with respect to y from 0 to π/2.
The integration steps involve some trigonometric substitutions and u-substitutions, which make the process quite lengthy. However, by carefully following the steps and simplifying the expressions, we can arrive at the final answer. In summary, the iterated integral evaluates a complicated expression involving sine and cosine functions, which can be obtained through a long explanation involving multiple integration steps. Overall, the process involves calculating the integral with respect to z, then x, and finally y, and simplifying the resulting expressions at each step.
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To evaluate this iterated integral, we first need to integrate with respect to z from 0 to sin(y). This will give us an expression involving sin(y). Next, we integrate this expression with respect to x from 0 to y/7. Finally, we integrate the resulting expression with respect to y from 0 to π/2.
The integration steps involve some trigonometric substitutions and u-substitutions, which make the process quite lengthy. However, by carefully following the steps and simplifying the expressions, we can arrive at the final answer. In summary, the iterated integral evaluates a complicated expression involving sine and cosine functions, which can be obtained through a long explanation involving multiple integration steps. Overall, the process involves calculating the integral with respect to z, then x, and finally y, and simplifying the resulting expressions at each step.
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03. Determine side length BC. Round your
answer to the nearest tenth.
A
√11 cm
17°
C
B
4
The length of the side of the triangle BC is 0. 97 cm
How to determine the valueIt is important to note that their are different trigonometric identities. These identities are;
sinetangentcotangentcosecantsecantcosineFrom the information given, we have that;
cos θ = adjacent/hypotenuse
sin θ = opposite/hypotenuse
tan θ = opposite/adjacent
Then, we have;
sin 17 = BC/√11
cross multiply the values, we have;
BC = sin 17 (√11)
BC = 0. 97 cm
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