Answer:
[tex] \orange{ \bold{\frac{dy}{dx} =\frac{ 5{x}^{2} + 3 }{3\sqrt[3]{(1 + {x}^{2})^{2} } }}}[/tex]
Step-by-step explanation:
[tex]y = x \sqrt[3]{1 + {x}^{2} } \\ assuming \: log \: both \: sides \\log y = log(x \sqrt[3]{1 + {x}^{2} } ) \\ \therefore log y = logx + log(\sqrt[3]{1 + {x}^{2} } ) \\ \therefore log y = logx + \frac{1}{3} log({1 + {x}^{2} } ) \\ differentiating \: both \: sides \: w.r.t.x \\ \frac{1}{y} \frac{dy}{dx} = \frac{1}{x} + \frac{1}{3} . \frac{1}{(1 + {x}^{2}) } (0 + 2x) \\ \frac{1}{y} \frac{dy}{dx} = \frac{1}{x} + \frac{2x}{3(1 + {x}^{2}) }\\ \frac{1}{y} \frac{dy}{dx} =\frac{3(1 + {x}^{2}) + 2 {x}^{2} }{3x(1 + {x}^{2}) }\\ \frac{1}{y} \frac{dy}{dx} =\frac{3 + 3{x}^{2} + 2 {x}^{2} }{3x(1 + {x}^{2}) }\\ \frac{1}{y} \frac{dy}{dx} =\frac{3 + 5{x}^{2} }{3x(1 + {x}^{2}) }\\ \frac{dy}{dx} =\frac{y(3 + 5{x}^{2} )}{3x(1 + {x}^{2}) } \\ \\ \frac{dy}{dx} =\frac{x \sqrt[3]{1 + {x}^{2} } (3 + 5{x}^{2} )}{3x(1 + {x}^{2}) }\\ \\ \frac{dy}{dx} =\frac{(3 + 5{x}^{2} )\sqrt[3]{1 + {x}^{2} } }{3(1 + {x}^{2}) }\\ \\ \purple{ \bold{\frac{dy}{dx} =\frac{ 5{x}^{2} + 3 }{3\sqrt[3]{(1 + {x}^{2})^{2} } }}}[/tex]
Kate leans a ladder against her house to get to the roof. The house is 25 feet tall and The ladder is 15 feet away from the side of the house. What is the angle that the latter makes with the ground?
Answer:
this is the correct answer
please mark brainliest
A coffee distributor needs to mix a(n) Mexican Shade Grown coffee blend that normally sells for $8.10 per pound with a Tanzanian coffee blend that normally sells for $14.10 per pound to create 100 pounds of a coffee that can sell for $10.26 per pound. How many pounds of each kind of coffee should they mix?
Answer:
64 pounds of the $8.10 Mexican Shade Grown
36 pounds of the $14.10 Tanzanian
Step-by-step explanation:
8.1x + 14.1(100 - x) = 10.26(100)
Distribute
8.1x + 1410 - 14.1x = 1026
Combine like terms
1410 - 6x = 1026
Subtract 1410 from both sides
-6x = -384
Divide both sides by -6
x = 64 pounds of the $8.10
100 - x = 36 pounds of the $14.10
Let g(x) be the transformation of f(x)= 3x - 5 when it is translated 6 units up followed by a horizontal stretch by a factor of 3/2.
g(x) = Blank 1X +Blank 2
Answer:
g(x) = 2x + 1
Step-by-step explanation:
f(x)= 3x - 5 when it is translated 6 units up
Translating a function a units is adding a to the function. So
[tex]3x - 5 + 6 = 3x + 1[/tex]
Horizontal stretch by a factor of 3/2.
This means that [tex]g(x) = f(\frac{2x}{3})[/tex], that is. So
[tex]g(x) = 3(\frac{2x}{3}) + 1 = 2x + 1[/tex]
Then
g(x) = 2x + 1
The lifetime of a certain brand of battery is known to have a standard deviation of 9 hours. Suppose that a random sample of 90 such batteries has a mean lifetime of 38.9 hours. Based on this sample, find a 90% confidence interval for the true mean lifetime of all batteries of this brand.
Answer:
lower limit : 36.44
upper limit : 39.56
Step-by-step explanation:
Given :
s = 9
n = 90
x = 38.9
Alpha, α = 0.10
∴ [tex]$z_{\alpha/2}=z_{0.05} = 1.645$[/tex]
The confidence interval is :
[tex]$=x \pm\left(z_{\alpha /2} \times \frac{s}{\sqrt{n}}\right)$[/tex]
[tex]$=38.9 \pm\left(1.645 \times \frac{9}{\sqrt{90}}\right)$[/tex]
[tex]$=38.9 \pm 1.56$[/tex]
[tex]$=(36.44, 39.56)$[/tex]
Therefore,
lower limit : 36.44
upper limit : 39.56
PLEASE HELP I WILL GIVE BRAINLIEST TO THE FIRST PERSON THAT ANSWER PLEASE
Answer:
[tex]a) x = k \times \frac{1}{y^2} \ , \ where \ k \ is \ a \ constant\\\\b) x = 3, \ when\ y\ =\ 10\\\\c) y = 10, \ when \ x = 3[/tex]
Step-by-step explanation:
a)
[tex]x \ \alpha \ \frac{1}{y^2}\\\\x = k \times \frac{1}{y^2}\\\\[/tex] [tex][ \ where \ k \ is \ a \ constant \ ][/tex]
Find k.
Given x = 12, y = 5,
[tex]12 = k \times \frac{1}{5^2}\\\\k = 12 \times 25 = 300[/tex]
b)
Find x.
Given y = 10
We have k = 300
[tex]x = k \times \frac{1}{y^2}\\x = 300 \times \frac{1}{10^2} \\\\x= \frac{300}{100} = 3[/tex]
c)
Find y
Given x = 3
We have k = 300
[tex]x = k \times \frac{1}{y^2}\\\\3 = 300 \times \frac{1}{y^2}\\\\\frac{1}{y^2} = \frac{3}{300}\\\\\frac{1}{y^2} = \frac{1}{100}\\\\y^2 = 100\\\\y = \sqrt{100} = 10[/tex]
2x - y - 4 = 0
3x + y - 9 = 0
What is the solution set of the given system?
Answer:
[tex](\frac{13}{5};\frac{6}{5}).[/tex]
Step-by-step explanation:
[tex]1)\left \{ {{5x=13} \atop {y=2x-4}} \right. \ 2)\left \{ {{x=\frac{13}{5} } \atop {y=\frac{6}{5} }} \right.[/tex]
short explanation: 1) to add the 1st equation to the 2d; 2) to calculate the value of 'x', then to substitute x=13/5 into the 2d equation and calculate the value of 'y'.
double a number equals 18 help pls
Answer:
9 is the answer
Answer:
2n=18
Step-by-step explanation:
Double means multiply by 2. A number can be represented by n.
So the equation is
2n=18
BONUS:
2n=18
/2 /2
n=9
---
hope it helps
what are the multiples of 5 between 61 and 69
Answer:
I think it is 65 because we can divide it by 5
Answer:
i think there is only one multiple which is 65
i am a number beetween 20 and 30 who is divisible by 2 4 and 7. I am an even number as well who am I?
Answer:
28
Step-by-step explanation:
28/2=14
28/4=7
28/7=4
28 is an even number
Step-by-step explanation:
28 is the answer
28 is a number between 20 and 30
and divisible by
28/2=14
28/4=7
28/7=4
Use your graph to find estimates of the solutions to the equation x^2-x-6=-2
Answer:
-2 and 3
Step-by-step explanation:
From the graph, the solution is the points where the curve cuts the x axis. From the graph, you can see that the equation cuts the x axis at two points that is at x=-2 and 3.
Hence the solutions to the equation is -2 and 3
Mrs Gren baked a cake on her son's birthday and divided it into 12 pieces.
Serah
ate 1/3 of the cake and her son ate 1/4 of the cake.
2. How many pieces of the cake did Serah eat?
- How many pieces of the cake did her son eat?
What fraction of the cake was eaten?
What fraction of the cake was left?
Answer:
2
Step-by-step explanation:
it has 2 in the equation
If v=-1, x=-2
and y= 3, find the value of:
3v + 2x
Answer:
-7
Step-by-step explanation:
3 v + 2 x
Where, v = -1 and x = -23 ( - 1) + 2 ( -2)
-3 - 4
-7
The maximum load that a cylindrical column with a circular cross section can hold varies directly as the fourth power of the diameter and inversely as the square of the height. A 9 meter column 2 meters in a diameter will support 64 metric tons. How many metric tons can be supported by a column 13 meters high and 5 meters in diameter? Round to the nearest whole metric ton
Answer:
2396
Step-by-step explanation:
Let the diameter = d
Let the height = h
Formula
Metric Tons = k * d^4 / h^2
Solution
Metric Tons = 64
d = 2
h = 9
k = ?
(You can't do the second part by not using a ratio unless you put k in and solve for it)
64 = 2^4 k / 9^2
64 = 8 *k / 81
64 * 81 / 8 = k
5184 / 8 = k
k = 648
Solve for the second example
Metric Tons = d^4 * k / h^2
Metric Tons = ?
d = 5
h = 13
k = 648
Metric Tons = 5^4 * 648 / 13^2
Metric Tons = 625 * 648 / 169
Metric Tons = 2396 rounded.
hi can someone help me w this
Answer:
336 ft³ or 336 cubic feet
Step-by-step explanation:
Volume = Area triangle * height
Area triangle = 1/2(8 x 14)
Area triangle = 1/2(112) = 56 ft²
56 ft² * 6 ft = 336 ft³
If my answer is incorrect, pls correct me!
If you like my answer and explanation, mark me as brainliest!
-Chetan K
Jun 07, 9:22:26 AM
+
Write a sine function that has an
amplitude of 2, a midline of 3 and a period of 3/2.
Answer:
[tex]\displaystyle y = 2sin\:1\frac{1}{3}\pi{x} + 3[/tex]
Step-by-step explanation:
[tex]\displaystyle \boxed{y = 2cos\:(1\frac{1}{3}\pi{x} - \frac{\pi}{2}) + 3} \\ \\ y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 3 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{\frac{3}{8}} \hookrightarrow \frac{\frac{\pi}{2}}{1\frac{1}{3}\pi} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{1\frac{1}{2}} \hookrightarrow \frac{2}{1\frac{1}{3}\pi}\pi \\ Amplitude \hookrightarrow 2[/tex]
OR
[tex]\displaystyle y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 3 \\ Horisontal\:[Phase]\:Shift \hookrightarrow 0 \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{1\frac{1}{2}} \hookrightarrow \frac{2}{1\frac{1}{3}\pi}\pi \\ Amplitude \hookrightarrow 2[/tex]
You will need the above information to help you interpret the graph. First off, keep in mind that although the exercise told you to write the sine equation based on the speculations it gave you, if you plan on writing your equation as a function of cosine, then there WILL be a horisontal shift, meaning that a C-term will be involved. As you can see, the photograph on the right displays the trigonometric graph of [tex]\displaystyle y = 2cos\:1\frac{1}{3}\pi{x} + 3,[/tex]in which you need to replase "sine" with "cosine", then figure out the appropriate C-term that will make the graph horisontally shift and map onto the sine graph [photograph on the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the cosine graph [photograph on the right] is shifted [tex]\displaystyle \frac{3}{8}\:unit[/tex]to the left, which means that in order to match the sine graph [photograph on the left], we need to shift the graph FORWARD [tex]\displaystyle \frac{3}{8}\:unit,[/tex]which means the C-term will be positive, and by perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{\frac{3}{8}} = \frac{\frac{\pi}{2}}{1\frac{1}{3}\pi}.[/tex]So, the cosine graph of the sine graph, accourding to the horisontal shift, is [tex]\displaystyle y = 2cos\:(1\frac{1}{3}\pi{x} - \frac{\pi}{2}) + 3.[/tex]Now, with all that being said, in this case, sinse you ONLY have the exercise to wourk with, take a look at the above information next to [tex]\displaystyle Wavelength\:[Period].[/tex]It displays the formula on how to define each wavelength of the graph. You just need to remember that the B-term has [tex]\displaystyle \pi[/tex]in it as well, meaning both of them strike each other out, leaving you with just a fraction. Now, the amplitude is obvious to figure out because it is the A-term, so this is self-explanatory. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = 3,[/tex]in which each crest is extended three units beyond the midline, hence, your amplitude. So, no matter what the vertical shift is, that will ALWAYS be the equation of the midline, and if viewed from a graph, no matter how far it shifts vertically, the midline will ALWAYS follow.
I am delighted to assist you at any time.
Will pick brainliest. How would I do this?
Undefined
Order of matrix Q is 4 by 3
whereas order of R is 4by 4
In order to add two matrices , they should be of same order.
Answer:
DOES NOT EXIST.
Step-by-step explanation:
The sum of two matrices exists only if the matrices are of the same order.
Here Q is 3x3 and R is 4x4, so they do not have the same order, hence the sum DOES NOT EXIST.
The path earth follows around the sun is earth's ___
A translação é o movimento que a Terra realiza em torno do Sol, sendo que ela demora 365 dias, 5 horas e 48 minutos para completá-lo. Esse movimento é o responsável direto pela existência das estações do ano. Como o eixo de inclinação do nosso planeta é de 23º27', há períodos em que os dias são maiores que as noites (solstícios de verão), períodos em que as noites são maiores que os dias (solstícios de inverno) e períodos em que eles possuem a mesma duração (equinócios de primavera e outono).
please help me i’m begging!!
i need to match them
An angle of depression is measured from the horizon downwards and an angle of elevation is measured from the horizon upwards.
When solving for the sides or angles of a right triangle you can use trigonometry. The sine of an angle is found by the ratio of the opposite side and the hypotenuse. The cosine of an angle is found by the ratio of the adjacent side and the hypotenuse. The tangent of an angle is found by the ratio of the opposite side and the adjacent side.
The opposite side is always the leg opposite the angle that you are using. The adjacent side is the leg that forms one of the sides of the angle you are talking about and the hypotenuse is always across from the right angle.
If you know two lengths you can find the third leg length by using the Pythagorean Theorem.
Cory has received the following grades this term: 75, 87, 90, 88, 79. If he wishes to earn an 85 average, what must he score on his final test?
Answer:
A 91.
Step-by-step explanation:
[tex]\frac{75+87+90+88+79+x}{6}=85\\\\\frac{419+x}{6}=85\\\\(\frac{419+x}{6})6=85*6\\\\419 + x = 510\\\\419-419+x=510-419\\\\\boxed{x = 91}[/tex]
HELP ME WITH THIS PLSSS!!!
A circle has been divided into three equal angles. is each angle acute obtuse or right?
Answer:
obtuse
Step-by-step explanation:
A circle is 360 degrees
Divide by 3
360/3 =120
This is greater than 90 and less than 180 so it is obtuse
Make use of the given interpretation for the median to assign probabilities to the simple events and find P(A), P(B), and P(C).
Answer: Hello your question is incomplete below is the missing part of the question
The Bureau of the Census reports that the median family income for all families in the United States during the year 2003 was $43,318. That is, half of all American families had incomes exceeding this amount, and half had incomes equal to or below this amount. Suppose that four families are surveyed and that each one reveals whether its income exceeded $43,318 in 2003.
answer :
P(A) = 11 / 16
P(B) = 3/8
and P(C) = 1/4
Step-by-step explanation:
Making use of the given interpretation for the median we can assign probabilities to simple events as
P(A) = | A | / | sample space |
where | A | = 11
sample space = 16
P(A) = 11 / 16
∴ P(B) = 6/16 = 3/8
and P(C) = 4/16 = 1/4
Help ASAP I will give you brainlist. I only need help with 5
Answer:
a) = 7/10
b)= 9/10
c)= 1 1/10
Step-by-step explanation:
a) green and a 2 = 1/2 + 1/5 = 0.7 = 7/10
b) red and an even number = 1/2 + 2/5 = 0.9 = 9/10
c) green and a prime number = 1/2 + 3/5 = 1.1 = 1 1/10
Martha buys a gold necklace priced at $62 . If the sales tax is 10%, what will be the total cost including tax? Show your work
Answer:
$78.12
Step-by-step explanation:
10÷62×100%
=16.12
Therefore price of gold necklace ($62) + 10% tax ($16.12) will be equal to total cost which is $78.12
a tree is standing 35 feet high. tom is attempting to align a 40 foot ladder to the tree to get his cat out. find the angle that the ladder will make with the ground.
Answer:
61º
Step-by-step explanation:
sin= opp/hyp
sin∅ = 35/40
∅ = arcsin35/40
use calculator
∅ = 61.044975628140152
∅ ≈ 61º
Find the value of x to the nearest tenth.
Step-by-step explanation:
p^2+b^2=h^2
or, 16+9=h^2
or, 25=h^2
or h=5
again, p^2 +b^2=h^2
or, 25+b^2=36
or, b^2=11
or. b=√11 therefore b=x=√11
please answer both thanks
A consumer advocacy group is doing a large study on car rental practices. Among other things, the consumer group would like to estimate the mean monthly mileage, , of cars rented in the U.S. over the past year. The consumer group plans to choose a random sample of monthly U.S. rental car mileages and then estimate using the mean of the sample. Using the value miles per month as the standard deviation of monthly U.S. rental car mileages from the past year, what is the minimum sample size needed in order for the consumer group to be confident that its estimate is within miles per month of
Answer:
The minimum sample size needed 64 monthly U.S. rental car mileages.
Step-by-step explanation:
Note: This question is not complete as all the important data are omitted. The complete question is therefore provided before answering the question as follows:
A consumer advocacy group is doing a large study on car rental practices. Among other things, the consumer group would like to estimate the mean monthly mileage, u, of cars rented in the U.S. over the past year. The consumer group plans to choose a random sample of monthly U.S. rental car mileages and then estimate u using the mean of the sample. Using the value 850 miles per month as the standard deviation of monthly U.S. rental car mileages from the past year, what is the minimum sample size needed in order for the consumer group to be 95% confident that its estimate is within 175 miles per month of u?
The explanation of the answer is now given as follows:
The minimum sample size needed can be calculated using the following sample size formula:
n = ((Z * S) / E)^2 ………………………… (1)
Where:
n = sample size or minimum sample size = ?
Z = Confidence interval at 95% = 1.645
S = Standard deviation = 850
E = Accepted magnitude of error = 175
Substituting all the relevant values into equation (1), we have:
n = ((1.645 * 850) / 175)^2 = (1,398.25 / 175)^2 = 7.99^2 = 63.8401, or 64.
Therefore, the minimum sample size needed 64 monthly U.S. rental car mileages.
1
5. Monica put $600 in a savings account that pays an interest rate of 3.5%.
She collected $120 in interest
Answer:
pls complete your question. what exactly are we supposed to calculate?
Please! Help, Also please show you’re work! will give brainliest to all who gives me the best answer
Answer:
Hope this helps. If it doesn't then I apologize.
A company wants to select 1 project from a set of 4 possible projects. Which of the following constraints ensures that only 1 will be selected?
a. X1 + X2 + X3 + X4 = 1
b. X1 + X2 + X3 + X4 = 1
c. X1 + X2 + X3 + X4= 1
d. X1 + X2 + X3+ X4= 0
Given:
A company wants to select 1 project from a set of 4 possible projects.
Consider the options are:
a. [tex]X_1+X_2+X_3+X_4=1[/tex]
b. [tex]X_1+X_2+X_3+X_4\leq 1[/tex]
c. [tex]X_1+X_2+X_3+X_4\geq 1[/tex]
d. [tex]X_1+X_2+X_3+X_4\geq 0[/tex]
To find:
The constraints that ensures only 1 will be selected.
Solution:
It is given that the company wants to select 1 project from a set of 4 possible projects. It means the sum of selected projects must be equal to 1.
[tex]X_1+X_2+X_3+X_4=1[/tex]
Therefore, the correct option is (a).