Type of bacteria that attacks the throat- causing fever sore throat rash

Answer: The reason why it's not safe for a double decker bus to carry standing passengers is because the center of gravity is raised causing increase in instability of the bus.

Explanation:

A double decker bus is a type of bus that has double decks and usually used by transportation companies for a transport business. Stability is the ability of an object to remain in its state of equilibrium after being distrubed. Stable objects are very difficult to lose balance while unstable object lose their balance easily.

For an object to be stable it must have:

--> a wide base and

--> a low center of gravity.

Therefore when an object has a wide base and a low center of gravity, it is more stable than an object that has a narrow base and a high center of gravity. Center of gravity is the average weight location of an object.

When passengers are left standing on the upper deck of the double decker bus, this INCREASES the center of gravity. This makes the center of gravity of the bus to be outside the base or edge on which it balances. The weight upon having a turning effect will cause the bus to topple and fall which can be dangerous to the lives of the passengers. Therefore it is advisable for passengers to seat while the bus is in motion to help reduce the center of gravity.

Answer:

The maximum height above its initial position is:

[tex]h_{max}=1.53\: m[/tex]

Explanation:

Using momentum conservation:

[tex]m_{b}v_{ib}=m_{B}v_{fB}+m_{b}v_{fb}[/tex] (1)

Where:

Let's find v(fb) using equation (1)

[tex]m_{b}(v_{ib}-v_{fb})=m_{B}v_{fB}[/tex]

[tex]v_{fB}=\frac{m_{b}(v_{ib}-v_{fb})}{m_{B}}[/tex]

[tex]v_{fB}=\frac{0.1(900-300)}{2}[/tex]

[tex]v_{fB}=30\: m/s[/tex]

We need to find the maximum height, it means that all kinetic energy converts into gravitational potential energy.

[tex]\frac{1}{2}m_{B}v_{fB}=m_{B}gh_{max}[/tex]

[tex]h_{max}=\frac{1}{2g}v_{fB}[/tex]

[tex]h_{max}=\frac{1}{2(9.81)}30[/tex]

[tex]h_{max}=1.53\: m[/tex]

I hope it helps you!

The maximum height above its initial position is:  [tex]h_{max}[/tex]=1.53m

Simple harmonic motion is the periodic motion or back and forth motion of any object with respect to its equilibrium or mean position. The restoring force is always acting on the object which try to bring it to the equilibrium.

Using momentum conservation:

[tex]m_bv_{1b}=m_Bv_{fB}+m_bv_{fb}[/tex]

Where:

m(b) is the mass of the bullet

m(B) is the mass of the block

v(ib) is the initial velocity of the bullet

v(fb) is the final velocity of the bullet

v(fB) is the final velocity of the block

Now for finding the value of final velocity VfB

[tex]m_b(v_{1b}-v_{fb})=m_Bv_{fB}[/tex]

[tex]v_{fB}=\dfrac{m_b(v_{1b}-v_{fb})}{m_B}[/tex]

[tex]v_{fB}=\dfrac{0.1(900-{300})}{2}[/tex]

[tex]v_{fB}=30\ \frac{m}{s}[/tex]

We need to find the maximum height, it means that all kinetic energy converts into gravitational potential energy.

[tex]\dfrac{1}{2}m_Bv_{fB}=m_Bv_{fB}[/tex]

[tex]h_{max}=\dfrac{v_{fB}}{2g}[/tex]

[tex]h_{max}=\dfrac{30}{2\times 9.81}[/tex]

[tex]h_{max}=1.53\ m[/tex]

Thus the maximum height above its initial position is:  [tex]h_{max}[/tex]=1.53m

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Complete question:

Part A:) The fictional rocket ship Adventure is measured to be 50 m long by the ship's captain inside the rocket.When the rocket moves past a space dock at 0.5c , space-dock personnel measure the rocket ship to be 43.3 m long. The rocket ship Adventure travels to a star many light-years away, then turns around and returns at the same speed. When it returns to the space dock, who would have aged less: the space-dock personnel or ship's captain?

Part B: What is the momentum of a proton traveling at 0.62 c ?

Answer

a)Who would have aged less=The Captain would have aged less

b) [tex]p=3.96*10^{-19}kgm/s[/tex]

Explanation:

From the question we are told that

Length measured by captain [tex]l_c=50m[/tex]

Speed of rocket past tje space dock [tex]V=0.5c[/tex]

Length measured by space-dock personnel [tex]l_c=43.3m[/tex]

a)

Generally time moves slower when moving at speed of light, due to time dilation or variation.

Who would have aged less=The Captain would have aged less

b)

Generally the equation for Relativistic Momentum  is mathematically given as

[tex]p=\frac{m*v}{1 - v^2/c^2}[/tex]

[tex]p=\frac{1.67*10^2-27*0.62*3.0*10^8)}{\sqrt{ 1 -0.6^2}}[/tex]

[tex]p=3.96*10^{-19}kgm/s[/tex]

We can't tell what RATING is printed on the package of bulbs, but right now, the bulb is dissipating IxE= 30 watts of heat and light.

Answer: I am pretty sure it is (b) what is the value of mass suspended at the end of the spring.

Explanation:

Answer:

its D I hope this helps you

Explanation:

Net force on the car= mass of the car × acceleration

F=1×10^3×4.5

=4.5×10^3 N

Answer:

zhvshshisvdiscdoscd if vdidg

Answer:

a. 451.58 N b. 1806.34 N

Explanation:

(a) Suppose a horizontal wind blows with a speed of 11.2 m/s outside a large pane of plate glass with dimensions 4.00 m X 1.50 m. Assume the density of air to be constant at 1.20 kg/m3. The air inside the building is at atmospheric pressure. What is the total force exerted by air on the window pane?

Using Bernoulli's equation

P₁ + 1/2ρv₁² + ρgh₁ = P₂ + 1/2ρv₂² + ρgh₂ where P₁ = pressure of air in building = atmospheric pressure = 1.013 × 10⁵ N/m², ρ = density of air = 1.20 kg/m³, v₁ = speed of air in building = 0 m/s(since it is still), h₁ = h₂ = h = height of building, P₂ = pressure on the outside of window pane, v₂ = speed of air outside window pane = 11.2m/s and g = acceleration due to gravity

So, since h₁ = h₂ = h

P₁ + 1/2ρv₁² + ρgh = P₂ + 1/2ρv₂² + ρgh

P₁ + 1/2ρv₁² = P₂ + 1/2ρv₂²

Also, v₁ = 0m/s

So, P₁ + 1/2ρ(0 m/s)² = P₂ + 1/2ρv₂²

P₁ + 0 = P₂ + 1/2ρv₂²

P₁ = P₂ + 1/2ρv₂²

P₁ - P₂ = 1/2ρv₂²

So the net pressure on the window is ΔP = P₁ - P₂ = FA where F is the total force on the window pane and A is the area of the window pane = 4.00 m × 1.50 m = 6.00 m²

So, P₁ - P₂ = 1/2ρv₂²

ΔP = 1/2ρv₂²

F/A = 1/2ρv₂²

F = 1/2ρAv₂²

Substituting the values of the variables into the equation, we have

F = 1/2ρAv₂²

F = 1/2 × 1.20 kg/m³× 6.00 m² × (11.2 m/s)²

F = 1/2 × 1.20 kg/m³ × 6.00 m² × 125.44 m²/s²

F = 451.584 N

F ≅ 451.58 N

(b) What force is experienced by the window pane from air if the airspeed outside is now 22.4m/s

When v₂ = 22.4 m/s, F is

F = 1/2ρAv₂²

F = 1/2 × 1.20 kg/m³× 6.00 m² × (22.4 m/s)²

F = 1/2 × 1.20 kg/m³ × 6.00 m² × 501.76 m²/s²

F = 1806.336 N

F ≅ 1806.34 N

Answer: 4.3cm

Explanation:

just took the test

Answer:

it's the second one;

if the frequency increases, wavelength decreases

Explanation:

we know, v=f×lamda(wave length)

so for constant velocity Frequency f is inversely proportional to lamda

i.e.

fα 1/lamda

so as the f increases lamda decreases and vise versa

A true relationship between the various wave components is if frequency increases, wavelength decreases.

The frequency is the reciprocal of the time period of the wave.

The wavelength is the distance between the two adjacent crest of the wave.

If the wavelength decreases, the number of cycles will increase in a certain time.

Hence, a true relationship between the wave components is if frequency increases, wavelength decreases.

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Answer:

a) 1.092 m/s

b) 0.33 m

c) 0.25 m

Explanation:

To start with, from the formula of wave, we know that

v = f λ, where

v = velocity of wave

f = frequency of the wave

λ = wavelength of the wave

Again, on another hand, we know that

T = 1/f, where T = period of the wave

From the question, we are given that

t = 2.7 s

d = 0.66 m

λ = 5.9 m

Period, T = 2 * t

Period, T = 2 * 2.7

Period, T = 5.4 s

If T = 1/f, then f = 1/T, thus

Frequency, f = 1/5.4

Frequency, f = 0.185 hz

Remember, v = f λ

v = 0.185 * 5.9

v = 1.092 m/s

Amplitude, A = d/2

Amplitude, A = 0.66/2

Amplitude, A = 0.33 m

If the other distance travelled by the boat is 0.5, then Amplitude is

A = 0.5/2

A = 0.25 m

Answer:

400 g

Explanation:

The computation of the number of grams in the original sample is shown below:

Given that

half-life = 5.26 years

total time of decay = 15.8 years

final amount = 50.0 g

Now based on the above information  

number of half-lives past is

=  15.8 ÷ 5.26

= 3 half-lives

Now

3 half-lives = 1 ÷ 8 remains = 50.0 g

So, the number of grams would be

= 50.0 g × 8

= 400 g

Answer:

a)speed of light.

a)speed of light×time=distance.

Explanation:

light has a constant speed of 299,792,458m/s

This distance is analyzed quantitatively by LIDAR (Light Detection And Ranging) stations, which bounce laser pulses off the retroreflecting mirrors installed on the Moon by the Apollo astronauts.

Lidar is a method of determining ranges that involves using a laser to target an object or a surface and measuring the time it takes for the reflected light to return to the receiver.

LiDAR is a type of remote sensing technology. LiDAR technology collects measurements by using a laser pulse. These are employed in the production of 3D models and maps of objects and environments.

Lidar, which stands for light detection and ranging, has been around for quite some time. It employs lasers to ping off objects and return to the laser source, measuring distance by timing the travel, or flight, of a light pulse.

LIDAR (Light Detection And Ranging) stations analyze this distance quantitatively by bouncing laser pulses off the retroreflecting mirrors installed on the Moon by the Apollo astronauts.

Thus, this way, the distance can be calculated.

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This statement is not true:

"Wavelength is the distance from the wave crest to the wave trough."

The others listed are true.

Answer:

1) 1.67eV

2) 505nm

Explanation:

The maximum kinetic energy of photoelectrons ,

 KEmax=λhc−W=(0.3×10−6)(1.6×10−19)(6.62×10−34)(3×108)eV−2.46eV=1.67eV

If λ0 is the cut-off wavelength, W=λ0hc

or λ0=Whc=2.46×1.6×10−19(6.62×10−34)(3×108)=5.05×10−7m=505×10−9=505nm

We know that the work function is the minimum photon energy for taking place of photoelectric effect. 

Answer:

50000 μT

Explanation:

From the given information:

the diameter of the loop = 1.0 mm = 0.001 m

no of turns (N) = 200

current (I) = 0.199 A

radius = d/2 = 0.001/2

= 5 × 10⁻⁴ m

Recall that;

the magnetic field at the centre of circular wire is:

[tex]= \dfrac{\mu I N}{2R}[/tex]

[tex]= \dfrac{4 \pi \times 10^{-7} \times 200 \times0.199}{2\times 5\times 10^{-4}}[/tex]

= 0.05 T

= 50000 μT

Since the centre of the earth's magnetic field is given to be equal to the magnetic field produced by the wire, then:

the earth's magnetic field = 50000 μT

Answer:

shorter than,

shorter than

1) option B. Emmy observes that Albert's ship is shorter than her own ship.

2) option B. Albert observes that Emmy's ship is shorter than her own ship

Explanation:

Applying the principle of length contraction where the length of a moving object is seen as being contracted (shorter than its real length),the length of the object in the rest frame does not appear to change.

In this case, the space racer in his own ship measures a reduced length of the other ship flying past it at a high but constant speed. Moreover, the space racer in a ship measures the real length of his own ship and not a contracted length.

Therefore, Emmy will observe that Albert's ship is shorter than her own ship while Albert will also observe that Emmy's ship is shorter than his own ship. It is the principle of length contraction that holds

Given:

We know,

→ [tex]W = 2 \pi f[/tex]

By substituting the values,

        [tex]= 2 \pi \times 4.0[/tex]

        [tex]= 8 \pi \ rad/s[/tex]

hence,

→ [tex]T = m \omega^2 R[/tex]

       [tex]= 0.02(8 \pi)^2 (0.50)[/tex]

       [tex]= 6.31654 \ N[/tex]

or,

       [tex]= 6.3 \ N[/tex]  

Thus the answer above is right.

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Answer:

Protons have positive charge

Electrons have negative charge

Neutrons have no charge

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Answer:

please give me brainlist and follow

Explanation:

Infrared radiation

The infrared part of the electromagnetic spectrum covers the range from roughly 300 GHz to 400 THz (1 mm – 750 nm). It can be divided into three parts: Far-infrared, from 300 GHz to 30 THz (1 mm – 10 μm). The lower part of this range may also be called microwaves or terahertz waves.

Answer:

C. Organs

Explanation:

Organs are groups of tissues that work together to perform a particular job.

hope this helps and is right; p.s. i really need brainliest :)

Answer: D. "I think the proper procedure is to check two forms of

identification for each patient."

Explanation: took the quiz

Answer:

principal stresses :б1 = 32.62mPa  б2 = 31.38mPa

Max Shear stress : 16.31 mPa

Orientation of max principle plane = 44.43°

Orientation of minimum principal plane = 134.43°

Explanation:

Given data:

Torque = 50 N-m

weight = 80 kgs

half of weight is subjected to each leg

radius of bone = 10 mm = 0.010 m

a) Determine the principal stresses and shear stress

first calculate the max shear stress ( this will occur in the outermost element

= 16T / π*d^3   where : T = 50 , d = 0.020 m

hence max shear stress = 32 mPa

next determine compressive stress

= ( 40*g)  / π/4*d^2 . where : d = 0.020 m , g = 9.81

hence compressive stress = 1.24 mPa

draw and calculate the radius of Mohr's circle

radius of Mohr's circle = 32.0060

Hence principal stresses = 32.0060 ± 0.62

б1 = 32.62mPa  

б2 = 31.38mPa

attached below is the remaining part of the solution

Answer:351

Explanation:trust

A musical note has a frequency and the wavelength of the note. The speed of the sound of that note will be 351m/s. The correct option is G.

The frequency is the number of cycle per second.

The wavelength is related to frequency and speed as

f = v/λ

Given is the frequency f = 512Hz and wavelength λ= 0.685m, then the speed of note will be

v =512 Hz x 0.685m

v =350.72 m/s

Speed is approximately 35 m/s.

Thus,  the correct option is G.

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Answer:

1) 0.01(1500) = 0.05F

F = 300 N

2) 2000/125 = 16

3) 100(800/2400) = 33.3%

4) 2000/15 = 133 N

Explanation:

Answer:

The loss in rotational kinetic energy due to the collision is 36.585 J.

Explanation:

Given;

mass of the disk, m₁ = 1.64 kg

radius of the disk, r = 0. 61 m

angular velocity of the disk, ω₁ = 17.6 rad/s

mass of the rod, m₂ = 1.51 kg

length of the rod, L = 1.79 m

angular velocity of the rod, ω₂ =  5.12 rad/s (clock-wise)

let the counter-clockwise be the positive direction

let the clock-wise be the negative direction

The common final velocity of the two systems after the collision is calculated by applying principle of conservation of angular momentum ;

m₁ω₁  + m₂ω₂ = ωf(m₁ + m₂)

where;

ωf is the common final angular velocity

1.64 x 17.6    + 1.51(-5.12) = ωf(1.64 + 1.51)

21.1328 = ωf(3.15)

ωf = 21.1328 / 3.15

ωf = 6.709 rad/s

The moment of inertia of the disk is calculated as follows;

[tex]I_{disk} = \frac{1}{2} mr^2\\\\I_{disk} = \frac{1}{2} (1.64)(0.61)^2\\\\I_{disk} = 0.305 \ kgm^2[/tex]

The moment of inertia of the rod about its center is calculated as follows;

[tex]I_{rod} = \frac{1}{12} mL^2\\\\I_{rod} = \frac{1}{12} \times 1.51 \times 1.79^2\\\\I _{rod }= 0.4032\ kgm^2[/tex]

The initial rotational kinetic energy of the disk and rod;

[tex]K.E_i = \frac{1}{2} I_{disk}\omega _1 ^2 \ \ + \ \ \frac{1}{2} I_{rod}\omega _2 ^2 \\\\K.E_i= \frac{1}{2} (0.305)(17.6) ^2 \ \ + \ \ \frac{1}{2} (0.4032)(-5.12) ^2\\\\K.E_i = 52.523 \ J[/tex]

The final rotational kinetic energy of the disk-rod system is calculated as follows;

[tex]K.E_f = \frac{1}{2} I_{disk}\omega _f ^2 \ \ + \ \ \frac{1}{2} I_{rod}\omega _f ^2\\\\K.E_f = \frac{1}{2} \omega _f ^2(I_{disk} + I_{rod})\\\\K.E_f = \frac{1}{2} (6.709) ^2(0.305+ 0.4032)\\\\K.E_f = 15.938 \ J[/tex]

The loss in rotational kinetic energy due to the collision is calculated as follows;

[tex]\Delta K.E = K.E_f \ - \ K.E_i\\\\\Delta K.E = 15.938 J \ - \ 52.523 J\\\\\Delta K.E = - 36.585 \ J[/tex]

Therefore, the loss in rotational kinetic energy due to the collision is 36.585 J.