Two towers of height 40 m and 30 m respectively support a transmission line conductor at water crossing. The horizontal distance between the towers is 300 m. If the tension in the conductor is 1590 kg, find the clearance of the conductor at a point mid-way between the supports. Weight of conductor is 0·8 kg/m. Bases of the towers can be considered to be at the water level.

Answers

Answer 1

The sag in the tensioned cable depends on the weight of the cable and

the applied tension.

The clearance midway between the support is approximately 29.34 meters

Reasons:

The given parameters are;

Height of the towers are; h₁ = 40 m and h₂ = 30 m

Horizontal distance between the towers, l = 300 m

The tension in the conductor, T = 1,590 kg

Weight of the conductor, w = 0.8 kg/m

Required:

The clearance space of the conductor mid-way between the support

Solution:

The distance, x₁, to the lowest point on the conductor, from the tower, h₁, is given by the formula;

[tex]\displaystyle x_1 = \mathbf{ \frac{l}{2} -\frac{T \cdot h}{w \cdot l}}[/tex]

Where;

h = h₂ - h₁ = 40 m - 30 m = 10 m

Which gives;

[tex]\displaystyle x_1 = \frac{300}{2} -\frac{1590 \times 10}{0.8 \times 300} = \mathbf{83.75}[/tex]

The sag at the lowest point is give by the formula;

[tex]\displaystyle d_1 = \mathbf{ \frac{W \cdot x_1^2}{2 \cdot T}}[/tex]

Therefore;

[tex]\displaystyle d_1 = \frac{0.8 \times 83.75^2}{2 \times 1590} = \frac{4489}{2544} \approx 1.765[/tex]

The lowest point sag, s₁ = 30 m - 1.765 m = 28.235 m

The distance of the midpoint from the lowest point, x, is therefore;

[tex]\displaystyle x = \frac{l}{2} - x_1 = \frac{300}{2} - 83.75 = \mathbf{ 66.25}[/tex]

Which gives;

[tex]\displaystyle d_x = \frac{0.8 \times 66.25^2}{2 \times 1590} = \frac{53}{48} \approx 1.104[/tex]

The clearance midway between the support ≈ 28.235 + 1.104 ≈ 29.34

The clearance midway between the support ≈ 29.34 m

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describe an experiment that can be used to determine the resistance of a metallic conductor

Answers

Answer:

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An experiment used to determine the resistance of a metallic conductor is the resistance of a metallic conductor at different temperatures.

What is Resistance?

Resistance is the property of a conductor to oppose the flow of charges through it which is numerically given as the ratio of the potential difference across its length to the current flowing through it.

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How to calculate work in chemistry.

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Answer:

look on the bottom

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Is it only the math or the physics/physical concepts that you don't get?

In this problem, you have a constant pressure of 1.00 atm.  This being the case, it is an isobaric system (constant pressure), and so you have the equation that work (W) = -pressure(P) x change in volume (∆V)

This is written as W = -P∆V and is known as pressure-volume work.

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In this problem, the gas is being compressed, i.e. the volume decreases, and so work is being done ON the system. Thus, the sign of W is positive (+).  This comes out automatically because of negative sign in front of P∆V,                                                                                                                                                                                           So,                                                                                                                                       we have W = -P∆V and substituting values, we have

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Answers

For the honeybee that circles a field looking for a flower upon which to land, we have:

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Answers

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Answers

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Answer:

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Answers

Answer:

calculate it by using formula w=m×g

The mass of an object if its weight on earth is 1150N is 117.347 kg.

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g= [tex]9.8[/tex] [tex]m/s^2[/tex]

Using the formula

m=W/g

m=1150/9.8

m=117.347 kg

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