Two sides of a triangle measure 5
units and 3 units. The perimeter
of the triangle is 12 units. What is
the measure of the third side?

Answer:

try this link

Step-by-step explanation:

https://www3.nd.edu › WorkPDF

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MATH 10550, EXAM 1 SOLUTIONS 1. If f(2) = 5, f(3) = 2, f(4) = 5, g(2 ...

Answer:

no he is not correct

Step-by-step explanation:

Answer:

225 u²

Step-by-step explanation:

The area of the larger square is 625 u². We know that area of square is the square of side. So ,

⇒ a² = 625 u²

⇒ a = √625 u²

⇒ a = 25 u .

Similarly finding the side of second square as ,

⇒ a'² = 400 u²

⇒ a' = √400 u²

⇒ a' = 20 u

If we see these are the hypontenuse and base of a right a Angled triangle formed between the square. The measure of perpendicular will be the side lenght of third square.

⇒ h² = p² + b²

⇒( 25u)² = p² + (20u)²

⇒ p² = 625 - 400 u²

⇒ p² = 225 u²

This p² is only the area of square .

Answer:

225 units

Step-by-step explanation:

Answer:

See below.

Step-by-step explanation:

y^2 - 6y + 9 can be changed correctly into y^2 - 2(y)(3) + 3^2.

Up to here, it's correct.

The right side above shows a polynomial that is the square of a binomial.

It factors into (y - 3)^2.

The correct factorization is (y - 3)^2.

The incorrect factorization of the student's solution is the product of a sum and difference.

The product of a sum and a difference is the correct factorization for a difference of squares.

For example, y^2 - 9 is the same as y^2 - 3^2 and is a difference of squares.

It factors into (y + 3)(y - 3), a product of a sum and a difference.

Answer:

n=1

Step-by-step explanation:

4/5n-3/5=1/5n

4n/5-3/5=1/5n

4n/5-3/5=n/5

4n-3/5=n/5

4n-3=n

-3=n-4n

-3=-3n

1=n

n=1

Answer:

n=1

isolate the n's on one side and isolate the 3/5 to the other

4/5n-1/5n = 3/5

3/5n = 3/5

n=1

Option (d) W = 162 is the correct answer.

The question asks us to evaluate the work done between point 1 and point 2 for the conservative field F, where F = (y + z) i + x j + x k, P 1(0, 0, 0), P 2(9, 10, 8).

Step-by-step solution: Let us find the work done (W) between point 1 and point 2 using line integral of vector field F. The formula for line integral of vector field F along the curve C is as follows:$$W=\int_C{F\cdot dr}$$Since we know the points, let us find the curve C, which is the line joining the two points P1 and P2. Let P1 be the initial point and P2 be the final point. The equation of the line in vector form is given by:$$r=t{(x_2 - x_1 )\over ||\overrightarrow{P_1P_2}||} + P_1$$Where t varies from 0 to 1.Now, let's substitute the given values:$${\overrightarrow{P_1P_2}} = \left\langle {9 - 0,10 - 0,8 - 0} \right\rangle = \left\langle {9,10,8} \right\rangle $$Hence,$${\overrightarrow{P_1P_2}} = ||\overrightarrow{P_1P_2}|| = \sqrt {9^2 + 10^2 + 8^2}  = \sqrt {245} $$Let the position vector be r(t) = xi + yj + zk. Then, the vector dr = dx i + dy j + dz k.Substitute r(t) and dr in the formula of line integral. Then,$$W = \int_C {F\cdot dr}  = \int_0^1 {\left\langle {y + z,x,x} \right\rangle \cdot \left\langle {\frac{{dx}}{{dt}},\frac{{dy}}{{dt}},\frac{{dz}}{{dt}}} \right\rangle dt} $$On integrating with respect to t, we get,$$W = \int_0^1 {((y + z)\frac{{dx}}{{dt}} + x\frac{{dy}}{{dt}} + x\frac{{dz}}{{dt}})dt} $$We know that x = 0, y = 0, z = 0 at P1 and x = 9, y = 10, z = 8 at P2.Substituting these values in the above integral, we get,$$W = \int_0^1 {((y + z)\frac{{dx}}{{dt}} + x\frac{{dy}}{{dt}} + x\frac{{dz}}{{dt}})dt} $$On integrating, we get the value of W as:$$W = \int_0^1 {(8t + 10t)(\frac{{9}}{{\sqrt {245} }})dt}  + \int_0^1 {(9t)(\frac{{10}}{{\sqrt {245} }})dt}  + \int_0^1 {(9t)(\frac{8}{{\sqrt {245} }})dt} $$Simplifying further, we get,$$W = \frac{{18}}{{\sqrt {245} }}\int_0^1 {t(8 + 10)dt}  + \frac{{72}}{{245}}\int_0^1 {t^2 dt}  = \frac{{18}}{{\sqrt {245} }}\int_0^1 {18tdt}  + \frac{{72}}{{245}}[\frac{{{t^3}}}{3}]_0^1 $$On evaluating the integral and simplifying, we get the final answer.$$W = \frac{{81}}{{\sqrt {245} }}$$

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Answer: About 2477.16 feet

Step-by-step explanation:

Answer:

Step-by-step explanation:

the equation in the point slope form is

and reducing the equation (slope-intercept form)

Step-by-step explanation:

first we calculate the slope of the line with the formula:

where  is a point where the line passes, and  is another point where the line passes.

Since we have the following points:

(8, -2)

(5,5)

we conclude that

now we substitute this values to find the slope:

to find the equation now that we know the slope we use the point-slope equation:

and we subtitute the slope and the values of  and :

we reduce this equation:

the equation in the point slope form is

and reducing the equation (slope-intercept form)

The student's suggested algorithm for subtracting numbers is incorrect. The algorithm produces the correct result in this specific case (72 - 38), but it does not work consistently for all subtraction problems.

The student's algorithm suggests subtracting the ones digit first and then subtracting the tens digit. While this approach may give the correct answer in some cases, it does not work for all subtraction problems. Subtraction is an operation where we need to consider the place value of the digits being subtracted.

In the case of 72 - 38, the student's algorithm produces the correct result of 34. However, if we apply the same procedure to a different subtraction problem, such as 43 - 29, we would get an incorrect result of 14 instead of the correct answer, 14. The student's algorithm fails to consider borrowing or regrouping when subtracting digits from different place values.

As a teacher, it is important to guide the student in understanding the standard algorithm for subtraction, which involves subtracting digits starting from the rightmost place value and borrowing when necessary. By teaching the correct procedure, students can consistently obtain accurate results for subtraction problems. It is crucial to explain the limitations of the student's suggested algorithm and emphasize the importance of understanding and applying the appropriate method for subtracting numbers.

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Answer:

Step-by-step explanation:

134-(-80)=134+80=214

Answer:

Option (1)

Step-by-step explanation:

By applying tangent rule in ΔABD,

tan(30°) = [tex]\frac{\text{Opposite side}}{\text{Adjacent side}}[/tex]

             = [tex]\frac{AB}{BD}[/tex]

BD = [tex]\frac{AD}{\text{tan}(30)}[/tex]

BD = [tex]\frac{200}{\frac{1}{\sqrt{3} } }[/tex]

BD = 200√3 ft

By applying tangent rule in ΔABC,

tan(60°) = [tex]\frac{AB}{BC}[/tex]

[tex]\sqrt{3}=\frac{200}{BC}[/tex]

BC = [tex]\frac{200}{\sqrt{3}}[/tex]

Since, CD = BD - BC

CD = 200√3 - [tex]\frac{200}{\sqrt{3}}[/tex]

     = 346.41 - 115.47

     = 230.94 ft

     ≈ 230.9 ft

Therefore, Option (1) will be the correct option.

Answer:

230.9 ft

Step-by-step explanation:

person above said it was correct answer

Answer:

8

Step-by-step explanation:

10+8-3+5-12=

The subset of items that should be carried is (2, 4) and (4, 2).

The last 9 digits of my mobile number are 904202527.

So, when I sort them in descending order, I get 975422000.

Therefore, W (backpack capacity) = 9. N = 4 items as follows: (Wi, vi) = (3, 7), (1, 5), (2, 4), (4, 2).

To find the subset of items that LM30 should choose so that the total value carried is maximized, and the total weight carried is less than or equal to the backpack capacity, we can use the 0/1 Knapsack algorithm.

Here are the steps:

Step 1: Create a table with (N+1) rows and (W+1) columns.

Step 2: Initialize the first row and first column with 0.

Step 3: For each item (i), fill the values in the table as follows:- If the weight of the item (wi) is greater than the current backpack capacity (j), copy the value from the cell above (same column).- If the weight of the item (wi) is less than or equal to the current backpack capacity (j), find the maximum value between:- The value in the cell above (same column)- The value in the cell (i-1, j-wi) + vi

Step 4: The maximum value that can be carried in the backpack is the value in the last cell (N, W).

Step 5: To find the subset of items that should be carried, start from the last cell (N, W) and trace back through the table by checking which cells contributed to this value.

For our case, the table would look like this:

Table 1The last cell (N, W) is 11, so the maximum value that can be carried in the backpack is 11.

To find the subset of items that should be carried, we can start from the last cell (N, W) and trace back through the table by checking which cells contributed to this value.

We can see that the cells (2, 6) and (4, 2) contributed to this value.

Therefore, the subset of items that should be carried is: (2, 4) and (4, 2).

Thus, LM30 should choose the items with weight 2 and 4, and values 4 and 2, respectively, to carry in his backpack so that the total value carried is maximized, and the total weight carried is less than or equal to the backpack capacity of 9.

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Answer:

-30C -  -5.56C

Answer:

the answer is A.

Step-by-step explanation:

Answer:

x= 11/7 + 3y/7

Step-by-step explanation:

Answer:

y=11 -7/3x

Step-by-step explanation:

subtract the 7

bring the seven to the other side

then divide by 3

How do you reconcile a bank statement?

Step 1: Adjust the bank statement balance. All your transactions for the month may not be on your bank statement. ...

Step 2: Adjust the check register balance. Your bank statement may include items that you didn't record in the check register. ...

Step 3: Compare the adjusted balances.

Answer is f(x, y, z) = xy + y² - xz - yz + C

Given field, F is F = (y - z) i + (x + 2y - z) j - (x + y) k

To find potential function f,

we need to find the antiderivative of each component of F, with respect to its respective variable.

The antiderivative of the x-component is

∫ (y - z) dx= xy - xz + C1

The antiderivative of the y-component is

∫ (x + 2y - z) dy= xy + y² - yz + C2

The antiderivative of the z-component is:

∫ -(x + y) dz= -xz - yz + C3

Therefore, potential function f is

f(x, y, z) = xy + y² - xz - yz + C.

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Answer:

The circumference of a circle is 2*pi*r or pi*diameter. The circumference is 19pi

The code simulates predictions using linear regression models on input data (xk, yk) and stores the predictions in the list "predictions".

The code snippet provided performs a simulation using linear regression models on input data (xk, yk) to generate predictions. Here is a step-by-step explanation:

Initialize a list called "predictions" to store the predicted values.

Iterate over the list of models. For each model:

Use the model to predict the values of y for the given input data xk. Append the predicted values to the "predictions" list.

By using the linear regression models, the code generates predictions based on the provided input data (xk). Each model in the "models" list is applied to the input data, and the predicted values for y are stored in the "predictions" list.

It's worth noting that the code assumes the existence of a linear regression model called "linear regression()" which is used to make predictions. The input data (xk, yk) is expected to be in a format compatible with the linear regression models for accurate prediction generation.

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Answer:

90,000

Step-by-step explanation:

10^4=10,000.

2*10,000=20,000

7*10,000=70,000

20,000+70,000=90,000

Answer:

900 and 172 for edg 2020-2021

Step-by-step explanation:

Answer:

1. 112 cm

2 135 ft

3 53.67

Step-by-step explanation:

Answer:i

Step-by-step explanation:

The overall limit of the expression (e^x sin x) as x approaches 5x is undefined.

To find the limit of (e^x sin x) as x approaches 5x, we can substitute 5x into the expression and evaluate the result.

lim (e^x sin x)    (substituting 5x for x)

x→5x

= lim (e^(5x) sin (5x))

x→5x

Now, let's analyze the behavior of the function as x approaches 5x. As x approaches 5x, the value of x becomes much larger, approaching infinity. In this case, we can examine the limits of the individual components.

1. Limit of e^(5x) as x approaches infinity:

lim e^(5x) = ∞

x→∞

Exponential functions grow exponentially as their input approaches infinity, so the limit of e^(5x) as x approaches infinity is infinity (∞).

2. Limit of sin (5x) as x approaches infinity:

lim sin (5x) = DNE

x→∞

The sine function oscillates between -1 and 1 as its input increases indefinitely. Therefore, it does not approach a specific limit as x approaches infinity.

Combining these results, we have:

lim (e^(5x) sin (5x))

x→∞

Since the limit of e^(5x) is ∞ and the limit of sin (5x) does not exist, the overall limit of the expression (e^x sin x) as x approaches 5x is undefined.

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Answer:

They are both correcte

Step-by-step explanation:

Imagine a pizza with 6 slices

Half of 6 slices is 3 slices, or 3/6

If you simplify 3/6, you will get 1/2

So, both fractions are equal, but in different forms.

For better context see images below!

Answer:

Step-by-step explanation:

if An = n+4

then A14 = 14+4 = 18

that's all .....have fun