Answers
#21
initial velocity=u=5m/sTime=t=2sAcceleration=a=1.3m/s²According to first equation of kinematics
v=u+atv=5+1.3(2)v=5+2.6v=7.6m/s#22
#a
v1=2+3(3)=2+9=11m/sv2=-8-4(3)=-20m/sv3=1-5(3)=-14m/sThe order is
v2<V3<v1#b
for speed find absolute velocity
S1=|11|=11m/sS2=|-20|=20m/sS3=|-14|=14m/sSo order is
S1<S3<S2
Answer:
See below ~
Explanation:
Question 21 :
⇒ v = u + at
⇒ v = 5 + 1.3 (2)
⇒ v = 5 + 2.6
⇒ v = 7.6 m/s
=============================================================
Question 22 : At t = 3
Subpart (a)
⇒ Object 1 : v = 2 + 3(3) = 11 m/s
⇒ Object 2 : v = -8 - 4(3) = -20 m/s
⇒ Object 3 : v = 1 - 5(3) = -14 m/s
⇒ Hence, their velocities are in the order : Object 2 < Object 3 < Object 1
Subpart (b)
⇒ Object 1 : v = | 2 + 3(3) | = 11 m/s
⇒ Object 2 : v = | -8 - 4(3) | = 20 m/s
⇒ Object 3 : v = | 1 - 5(3) | = 14 m/s
⇒ Hence, their speeds are in the order : Object 1 < Object 3 < Object 2
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Answers
Answer:
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